In a survey conducted by a retail store, 58% of the sample respondents said they prefer to shop at places with loyalty cards.


96


If the margin of error is 3. 4%, the expected population proportion that prefers to shop at places with loyalty cards is between


and


%.

The missing side length of the rectangle is 7.75 inches when x is equal to 3. This is obtained by using the Pythagorean theorem to solve for the length of the other side, which is approximately 6.3 inches.

Using the Pythagorean theorem, we can find the missing side length of the rectangle

a² + b² = c²

where c is the length of the diagonal and a and b are the lengths of the sides.

Plugging in the values given, we get

(2x)² + b² = (8x)²

4x² + b² = 64x²

b² = 60x²

b = √(60x²) = √(60)x

When x = 3, the missing side length is

b = √(60)(3) = 7.75 in. (rounded to the nearest tenth of an inch)

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--The given question is incomplete, the complete question is given

"Find an equivalent expression for the missing side length of the rectangle.

then find the missing side length when x = 3. round to the nearest tenth of an inch.

8x in. is a diagonal of rectangle

2x in. is one side of rectangle

? in. is other side at base "--

Answer:

The radius of the basketball is 20 cm.

Step-by-step explanation:

The formula for the volume of a sphere is V = (4/3)πr^3, where V is the volume and r is the radius.

We are given that the volume of the basketball is 11488.2 cm, so we can set up the equation:

Simplifying, we get:

Dividing both sides by (4/3)π, we get:

Taking the cube root of both sides, we get:

Rounding to the nearest whole number, the radius of the basketball is 20 cm.

To find the annual rate at which the car depreciated, we need to use the formula for exponential decay:

A(t) = P(1 - r)^t

where A(t) is the current value of the car after t years, P is the initial value of the car, and r is the annual rate of depreciation.

We know that P = $15,500 and A(t) = $8,400, so we can plug in these values to solve for r:

$8,400 = $15,500(1 - r)^t

Divide both sides by $15,500:

0.54 = (1 - r)^t

Take the logarithm of both sides:

log(0.54) = t*log(1 - r)

Solve for r:

log(0.54)/t = log(1 - r)

1 - r = 10^(log(0.54)/t)

r = 1 - 10^(log(0.54)/t)

Plugging in t = 7 (since the car has depreciated for 7 years), we get:

r = 1 - 10^(log(0.54)/7) ≈ 9.35%

Therefore, the car depreciated at an annual rate of approximately 9.35%.

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Answer:

423.9

Step-by-step explanation:

To solve this problem you need to use the formula for surface area. This formula can either be used with the radius or the diameter. I prefer using diameter because it is easier to remember and it is easier to calculate. The formula writes as follows: [tex]SA=d\pi h+d\pi ^{2}\\\\[/tex]. To use this formula all we have to do is insert the values into the formula and solve.

[tex]SA=d\pi h+d\pi ^{2}\\\\SA=(9)\pi(6)+\pi(9) ^{2}\\\\SA=54\pi+81\pi\\\\SA=54\pi+81\pi\\\\SA=135\pi\\\\SA=423.9[/tex]

423.9 is our answer.

The solution of initial value problem, y = 9/t - 1, t ≠ 0.

We can begin by rearranging the equation and separating the variables:

t^2 dy/dt - yt = t + 1

dy/(y+1) = (t+1)/t^2 dt

Integrating both sides, we get:

ln|y+1| = -1/t + t/t + C

ln|y+1| = -1/t + C

|y+1| = e^C /t

Using the initial condition y(1) = 8, we can find the value of C:

|8+1| = e^C /1

e^C = 9

C = ln 9

Substituting back into the general solution, we have:

|y+1| = 9/t

We can now solve for y in terms of t:

y+1 = ±9/t

If we take the positive sign, we get:

y = 9/t - 1

If we take the negative sign, we get:

y = -9/t - 1

Thus, the general solution to the initial value problem is:

y = 9/t - 1 or y = -9/t - 1

Using the initial condition y(1) = 8, we can see that the correct solution is:

y = 9/t - 1

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Using mathematical operations, each box of a dozen donuts should cost $3.40.

The basic mathematical operations used to determine the cost of a dozen donuts include multiplication and addition.

Firstly, the total cost of 12 donuts is computed by multiplication, while the total cost of the donuts per box (including the cost of the box) is obtained by addition.

1 dozen = 12 donuts

The cost unit of a donut = $0.27

The total cost of donuts = $3.24 ($0.27 x 12)

The cost per square foot of cardboard = $0.16

The total cost of a dozen donuts and the box = $3.40 ($3.24 + $0.16)

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The length of the phone is approximately 6.08 inches, so you can buy a case that fits this size.

To find the length, x, of the phone, we can use trigonometry. We know that the bottom of the phone is 4 inches from the base of the wall, so we can use the tangent function to find the length of the phone.

tangent(52 degrees) = opposite/adjacent

The opposite side is x (the length of the phone) and the adjacent side is 4 inches.

So,

tangent(52 degrees) = x/4

Multiplying both sides by 4, we get:

4 * tangent(52 degrees) = x

Using a calculator, we find that:

x ≈ 6.08 inches

Therefore, the length of the phone is approximately 6.08 inches, so you can buy a case that fits this size.

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The triangle has two sides with equal lengths (AB and AC) and one side with a different length (BC). This makes it an isosceles triangle.

Triangle ABC has vertices A(0,0), B(0,3), and C(3,0).

To determine the type of triangle, we can find the lengths of the sides using the distance formula:

AB = sqrt((0-0)^2 + (3-0)^2) = sqrt(0 + 9) = 3

BC = sqrt((3-0)^2 + (0-3)^2) = sqrt(9 + 9) = sqrt(18) = 3√2

AC = sqrt((3-0)^2 + (0-0)^2) = sqrt(9 + 0) = 3

The triangle has two sides with equal lengths (AB and AC) and one side with a different length (BC). This makes it an isosceles triangle.

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The experimental and theoretical probability of the name Fred being chosen is 0.11 and 0.167  respectively.

The question is asking for the experimental and theoretical probabilities of choosing the name Fred when six different names are put into a hat and a name is chosen 100 times.

To find the experimental probability of choosing the name Fred, divide the number of times Fred is chosen by the total number of trials (100 times). In this case, Fred is chosen 11 times.

Experimental probability of choosing Fred = (number of times Fred is chosen) / (total number of trials)
= 11 / 100
= 0.11 or 11%

For the theoretical probability, since there are six different names in the hat and each name has an equal chance of being chosen, the probability of choosing Fred is:

Theoretical probability of choosing Fred = 1 / 6
≈ 0.167 or 16.67%

If the number of names in the hat were different, the theoretical probability would change because the denominator (total number of names) would be different. For example, if there were 5 names instead of 6, the theoretical probability of choosing Fred would be 1/5 or 20%.

The experimental probability would also likely change since the outcomes of the trials would be different with a different number of names.

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The number of 3-teams is different, and there is at least one 2-team and one 3-team, fulfilling the requirements.

a) To list all different 3-teams that the friends (A, B, C, D, E) could enter, we can find all the possible combinations of choosing 3 friends out of 5. These combinations are:

1. ABC
2. ABD
3. ABE
4. ACD
5. ACE
6. ADE
7. BCD
8. BCE
9. BDE
10. CDE

b) To maximize the number of teams with exactly two 3-teams and at least one 2-team, we can form the following teams:

1. ABC (3-team)
2. ADE (3-team)
3. BC (2-team)

Here, we have formed 1 two-team and 2 three-teams.

c) To maximize the number of teams with exactly three 3-teams and at least one 2-team, we can form the following teams:

1. ABC (3-team)
2. ADE (3-team)
3. BCE (3-team)
4. CD (2-team)

Here, we have formed 1 two-team and 3 three-teams.

d) The friends want to enter 8 teams, including at least one 2-team and at least one 3-team. We can find three ways of doing this with a different number of 3-teams in each case:

1. Two 3-teams: ABC, ADE (3-teams); BC, BD, BE, CD, CE, DE (2-teams)
2. Three 3-teams: ABC, ADE, BCE (3-teams); AC, AD, AE, BD, BE, CD (2-teams)
3. Four 3-teams: ABC, ADE, BCE, BCD (3-teams); AB, AC, AD, AE (2-teams)

In each case, the number of 3-teams is different, and there is at least one 2-team and one 3-team, fulfilling the requirements.

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The human heart beats approximately 4.1975 x 10⁸ times in one year and it expressed in scientific notation.

According to the question, the average human heart beats 1.15 x 10⁵ times a day. We need to find out how many times the heart beats in one year, which is 3.65 x 10² days.

To calculate the total number of heartbeats in one year, we can multiply the number of heartbeats in a day by the number of days in a year. Therefore, we have:

Total number of heartbeats in one year = 1.15 x 10⁵ beats/day x 3.65 x 10² days/year

= (1.15 x 3.65) x (10⁵ x 10²) beats/year

= 4.1975 x 10⁸ beats/year

This number may seem large, but it is necessary for the heart to pump blood throughout the body to keep us alive and healthy.

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To find the effective interest rate that Hannah is being offered, we need to take into account the compounding period, which is daily in this case. The effective annual interest rate (EAR) can be calculated using the formula:

EAR = (1 + APR/n)^n - 1

where APR is the annual percentage rate, and n is the number of compounding periods per year.

For the first 30 days, Hannah is offered a 0% APR, so the EAR for this period is simply 0.

After 30 days, Hannah is offered a 12.22% APR compounded daily, which means that there are 365 compounding periods per year. Therefore, the EAR for this period can be calculated as follows:

EAR = (1 + 0.1222/365)^365 - 1

   ≈ 0.1267

So the effective interest rate that Hannah is being offered is approximately 12.67%.

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The cone will hold approximately 198 cubic inches of water. The correct answer is option B.

To find how much water a cone with a diameter of 6 inches and a height of 21 inches will hold, we need to calculate the volume of the cone. We can use the formula for the volume of a cone: V = (1/3)πr^2h, where V is the volume, r is the radius, and h is the height.

1. Since the diameter is 6 inches, the radius (r) is half of that: r = 6/2 = 3 inches.

2. The height (h) is given as 21 inches.

3. Use 3.14 for π.

Now, plug the values into the formula:

V = (1/3) * 3.14 * (3^2) * 21

4. Calculate the square of the radius: 3^2 = 9

5. Multiply the values: (1/3) * 3.14 * 9 * 21 ≈ 197.64

6. Round the answer to the nearest whole number: 198 cubic inches.

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Mariah cycles a distance of 8.6 miles, which is more than 8 miles, hence more than 2/3 of the cycling portion of the triathlon.

A triathlon is  described as an endurance multisport race consisting of swimming, cycling, and running over various distances.

The coordinates are given as follows:

Suppose that we have two points,  and . The distance between them is given by:

distance = √(x2 - x1)² + (y2-y1)²

We substitute in the equation

Hence the distance between her house and the library is:

D = 8.6 miles.

She cycles a distance of 8.6 miles, which is more than 8 miles, hence more than 2/3 of the cycling portion of the triathlon.

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The length of BC rounded to 3 significant figures is 6.98.

Since ∠cab = 90°, we can use the Pythagorean Theorem to find the length of AB.

Let's call BC = x, then we have:

sin(65°) = AB/BC

AB = sin(65°) * BC

In right triangle ABC, we have:

AB^2 + BC^2 = AC^2

(sin(65°) * BC)^2 + BC^2 = 8.9^2

Solving for BC, we get:

BC = 8.9 / sqrt(sin^2(65°) + 1)

BC ≈ 6.98

Therefore, the length of BC rounded to 3 significant figures is 6.98.

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The value of the tangent segment b is 20.15.

The secant-tangent power theorem, also known as the tangent-secant theorem, states that if a tangent and a secant are drawn from a common external point to a circle, then the product of the length of the secant segment and its external part is equal to the square of the length of the tangent segment.

It is expressed as:

( tangent segment )² = External part of the secant segment + Secant segment.

From the diagram:

Tangent segment = WX = b

External part of the secant segment = YX = 14

Secant segment = ZX = 15 + 14 = 29

Plug these values into the above formula and solve for b.

( tangent segment )² = External part of the secant segment + Secant segment.

b² = 14 × 29

b² = 406

b = √406

b = 20.15

Therefore, the value of b is 20.15.

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The probability of selecting an M&M that is not red is 11/15.To find the probability of selecting an M&M that is not red, we need to first find the total number of M&Ms in the bag,

It is the sum of the number of M&Ms of each color: 4 + 8 + 6 + 12 = 30.

Next, we need to find the number of M&Ms that are not red, which is the sum of the number of M&Ms of all other colors: 4 + 6 + 12 = 22.

Therefore, the probability of selecting an M&M that is not red is 22/30, which can be simplified by dividing both the numerator and the denominator by 2:

22/30 = 11/15

So the probability of selecting an M&M that is not red is 11/15.

In other words, there is an 11/15 chance that the selected M&M will be blue, orange, or green, and a 4/15 chance that it will be red.It is important to note that this assumes that each M&M is equally likely to be selected, and that the bag is well-mixed so that each M&M has an equal chance of being chosen.

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The test statistic for the hypothesis about a consumer activist decides to test the authenticity of the claim is t = 1.38.

In a hypothesis test, a test statistic—a random variable—is computed from sample data. To decide whether to reject the null hypothesis, you can utilise test statistics. Your results are compared to what would be anticipated under the null hypothesis by the test statistic. The p-value is computed using the test statistic.

A test statistic gauges how closely a sample of data agrees with the null hypothesis. Its observed value fluctuates arbitrarily from one random sample to another. When choosing whether to reject the null hypothesis, a test statistic includes information about the data that is important to consider. The null distribution is the sample distribution of the test statistic for the null hypothesis.

Sample size, n = 20

Sample mean, x = 14.8 pounds

Sample standard deviation, s = 2.6

The null hypothesis is,

[tex]H_o[/tex]: μ ≤ 14

The alternative hypothesis is,

[tex]H_a[/tex] : μ > 14

t-test statistic is defined as:

[tex]t = \frac{x - \mu}{\frac{s}{\sqrt{n} } }[/tex]

[tex]= \frac{14.8 - 14}{\frac{2.6}{\sqrt{20} } }[/tex]

= [tex]\frac{0.8}{0.581}[/tex]

= 1.377

t = 1.38.

Therefore, the test statistic for the hypothesis is 1.38.

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Complete question"

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than 14 pounds. A consumer activist decides to test the authenticity of the claim. She follows the progress of 20 women who recently joined the weight-reduction program. She calculates the mean weight loss of these participants as 14.8 pounds with a standard deviation of 2.6 pounds. The test statistic for this hypothesis would be Multiple Choice -1.38 1.38 1.70 -1.70 O O

The math fact that 4 x 6 = 24 helps Matt remember that 6 x 4 = 24, and Sadie arrived at the answer 10 for 6 + 4 by incorrectly adding the numbers in reverse order.

Matt knows that 6 x 4 = 24. This helps him remember that 4 x 6 and 6 x 4 are both equal to 24.

The math fact that Matt can remember based on 4 x 6 = 24 is that multiplication is commutative. This means that the order of the numbers being multiplied doesn't affect the result. So, if 4 multiplied by 6 equals 24, it also implies that 6 multiplied by 4 would give the same result of 24.

Sadie arrived at the answer 10 for 6 + 4 by mistakenly swapping the order of the numbers and performing the addition incorrectly. The correct sum for 6 + 4 is indeed 10. Sadie's error demonstrates the importance of following the correct order of operations, where addition should be performed after ensuring the numbers are in the correct order.

As for Sadie's answer of 6 + 4 = 10, it is not directly related to the multiplication fact that Matt knows.

It is possible that Sadie used a different math fact or strategy to arrive at that answer.

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The vector parametric equation for the circle C is r(t) = <8cos(t), 8sin(t)> for 0 ≤ t ≤ 2π.

To find a vector parametric equation r(t) for the circle C with radius 8, centered at the origin, starting at the point (8, 0)

and traveling counterclockwise for 0 ≤ t ≤ 2π, follow these steps:

Write down the equation for the circle centered at the origin with radius 8:

x² + y² = 64.

Parametrize the circle using trigonometric functions.

Since we are starting at (8, 0) and going counter clockwise,

we can use x = 8cos(t) and y = 8sin(t).

Write the parametric equation in vector form:

r(t) = <8cos(t), 8sin(t)>.

So the vector parametric equation for the circle C is r(t) = <8cos(t), 8sin(t)> for 0 ≤ t ≤ 2π.

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The answer is  (3.25, 2.75)

To find point B, we can use the fact that AB and BC form a 1:3 ratio. Let's start by finding the coordinates of point B.

First, we need to find the distance between A and C. We can use the distance formula for this:

[tex]d = \sqrt{ ((x2 - x1)^2 + (y2 - y1)^2)[/tex]

where  [tex](x1, y1) = (4, 2)[/tex]  and [tex](x2, y2) = (1, 5)[/tex]

[tex]d = \sqrt{((1 - 4)^2 + (5 - 2)^2)} = \sqrt{(9 + 9)} = \sqrt{(18)}[/tex]

Next, we need to find the distance between A and B, which we'll call x, and the distance between B and C, which we'll call 3x (since AB and BC are in a 1:3 ratio).

Using the distance formula for AB:

[tex]x = \sqrt{\\((x2 - x1)^2 + (y2 - y1)^2)[/tex]

where [tex](x1, y1) = (4, 2)[/tex] and [tex](x2, y2) = (Bx, By)[/tex]

[tex]x = \sqrt{((Bx - 4)^2 + (By - 2)^2)[/tex]

Using the distance formula for BC:

[tex]3x = \sqrt{((x2 - x1)^2 + (y2 - y1)^2)[/tex]

where [tex](x1, y1) = (1, 5)[/tex] and [tex](x2, y2) = (Bx, By)[/tex]

[tex]3x = \sqrt{((Bx - 1)^2 + (By - 5)^2)[/tex]

Now we can set up an equation using the fact that AB and BC are in a 1:3 ratio:

[tex]x / 3x = 1 / 4[/tex]

Simplifying this equation, we get:

[tex]4x = 3(AB)[/tex]

[tex]4x = 3\sqrt{((Bx - 4)^2 + (By - 2)^2)[/tex]

And

[tex]9x = \sqrt{((Bx - 1)^2 + (By - 5)^2)[/tex]

Now we have two equations and two unknowns (Bx and By). We can solve for Bx in the first equation and substitute into the second equation:

[tex]Bx = (3\sqrt{((Bx - 4)^2 + (By - 2)^2))} / 4[/tex]

[tex]9x = \sqrt{((Bx - 1)^2 + (By - 5)^2)[/tex]

[tex]81((Bx - 4)^2 + (By - 2)^2) / 16 = (Bx - 1)^2 + (By - 5)^2[/tex]

Expanding the squares and simplifying, we get:

[tex]81Bx^2 - 648Bx + 1245 = 16Bx^2 - 32Bx + 266[/tex]

[tex]65Bx^2 - 616Bx + 979 = 0[/tex]

Using the quadratic formula, we get:

[tex]Bx = (616 ± \sqrt{(616^2 - 4(65)(979)))} / (2(65))[/tex]

[tex]Bx = (616 ± \sqrt{(223456))} / 130[/tex]

[tex]Bx = 3.25[/tex] or [tex]Bx = 10.2[/tex]

We can eliminate the solution Bx ≈ 10.2 because it is outside the segment AC. Therefore, the solution is:

B = (3.25, 2.75)

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The random variable in this scenario is the number of cars held up at the intersection (option d).

The data provided in the table shows the number of cars held up at the intersection during specific time intervals, ranging from 12:00 p.m. to 9:00 p.m. Based on this information, it is clear that the random variable in this scenario is the number of cars held up at the intersection.

To put it in mathematical terms, let X be the random variable representing the number of cars held up at the intersection during a specific time interval. The data provided in the table represents a sample of X, with each time interval being a different observation. The values of X can range from 0 to 25, with 17 being the threshold for intervention by a traffic officer.

Therefore, the answer to the question is d. the number of cars held up at the intersection. It is important to note that this random variable is discrete, as it takes on specific integer values.

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The meaning of the intercept of the regression line is option B- When 38. 7 pounds of nitrogen is added to the field, 0. 43 bushels of com are produced

We are given the equation of the experiment that tells a relationship.

y = 0.43x + 28.5

The linear regression line is an algebraic model to show the relationship between the two models by putting the value of one variable to get the value of the other.

A linear regression line can be represented as,

y = Ax + B

Here y is the dependent variable and x is the explanatory variable. A is the slope of the line and

B is the intercept here. In the given equation there are two variables given.

Variable x representsthe amount of nitrogen added, and the variable y represents the number of bushels of corn produced.

As putting the value of x, y increases with the value of number 0.43. Therefore, as we are increasing the value of the nitrogen by one unit, the number of bushels of corn produced is increasing by 0.43 units. Hence, for every 1 pound of nitrogen added to the field, the amount of corn yielded increases by 0.43 bushels.

Therefore option B is the correct option.

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The complete question is "An agricultural scientist collected data to study the relationship between the amount of nitrogen added to a cornfield and the number of

bushels of corn produced. This is the regression line of the data, where y is measured in bushels of corn and x is measured in pounds of

nitrogen.

y = 0.43x + 28.5

What is the meaning of the slope of the regression line?

O A. For every 0.43 pounds of nitrogen added to the field, the amount of corn yielded increases by 28.5 bushels.

OB. For every 1 pound of nitrogen added to the field, the amount of corn yielded increases by 0.43 bushels.

OC. For every 1 pound of nitrogen added to the field, the amount of corn yielded increases by 28.5 bushels.

OD. For every 28.5 pounds of nitrogen added to the field, the amount of corn yielded increases by 0.43 bushels."

Both ratios provided by Heather and Allen are correct, they are just inverse.

Heather says that the ratio of bass and violins to cellos is 10 to 5. Allen says the ratio of cellos to bass and violins is 1 to 2. To determine who is correct, let's compare the ratios.

1: Simplify Heather's ratio.

Heather's ratio is 10:5, which can be simplified by dividing both sides by 5. This gives a simplified ratio of 2:1 (bass and violins to cellos).

2: Compare the simplified ratios.

Heather's simplified ratio is 2:1, which represents the ratio of bass and violins to cellos. Allen's ratio is 1:2, which represents the ratio of cellos to bass and violins.

3: Analyze the results.

Heather's ratio (2:1) and Allen's ratio (1:2) are inverses of each other. Both ratios are correct, but they represent different perspectives: Heather is expressing the ratio of bass and violins to cellos, while Allen is expressing the ratio of cellos to bass and violins.

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The inequalities for which the ordered pair (-1,-9) is a solution are a and b

From the question, we have the following parameters that can be used in our computation:

The inequality expression y> -5/4x-3 and the list of options

To determine the ordered pairs of the inequality expression, we set x = -1 and then calculate the value of y

Using the above as a guide, we have the following:

y > -5/4(-1) -3

Evauate

y > -1.75 -- this is false because -9 < -1.75

For the list of options, we have

Graph (a) True

Graph (b) True

Hence, the inequalities for which the ordered pair (-1,-9) is a solution are a and b

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If An oil globe made of hand-blown glass of a diameter of 22.6. Therefore, the volume of the oil globe is approximately 5704.8 cm^3.

The volume of a spherical object can be calculated using the formula:

V = (4/3)πr^3

where V is the volume, π is the mathematical constant pi (approximately equal to 3.14159), and r is the radius of the sphere.

In this case, we are given the diameter of the oil globe, which is 22.6. The radius is half of the diameter, so we can calculate the radius as:

r = d/2 = 22.6/2 = 11.3 cm

Substituting this value of radius in the formula for the volume of a sphere, we get:

V = (4/3)π(11.3)^3

V = 5704.8 cm^3 (rounded to one decimal place)

Therefore, the volume of the oil globe is approximately 5704.8 cm^3.

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Answer:

2*Ab    Or AC

Step-by-step explanation:

No detail in question

The velocity v = ds/dt in terms of t and the position s is: [tex]v = 15t^{(3/2)} - 8t^{(1/2)} + 6[/tex] and [tex]s = 5t^{(5/2)} - 16t^{(3/2)} + 6t + 27[/tex] respectively.

To find the velocity v = ds/dt in terms of t and the position s, we first need to integrate the acceleration equation with respect to time to get the velocity equation:

d²s/dt² = 30 sqrt(t) – 12/ sqrt(t)

Integrating both sides with respect to t, we get:

ds/dt = 30/2 * t^(3/2) - 12 * 2/3 * t^(1/2) + C₁

where C₁ is the constant of integration.

Using the condition ds/dt = 12 when t = 1, we can solve for C₁:

12 = 30/2 * 1^(3/2) - 12 * 2/3 * 1^(1/2) + C₁

C₁ = 6

Substituting this value of C₁ back into the velocity equation, we get:

ds/dt = 15t^(3/2) - 8t^(1/2) + 6

Now, we can integrate the velocity equation to get the position equation:

s = 5t^(5/2) - 16t^(3/2) + 6t + C₂

where C₂ is the constant of integration.

Using the condition s = 16 when t = 1, we can solve for C₂:

16 = 51^(5/2) - 161^(3/2) + 6*1 + C₂

C₂ = 27

Substituting this value of C₂ back into the position equation, we get:

s = 5t^(5/2) - 16t^(3/2) + 6t + 27

Therefore, the velocity v = ds/dt in terms of t and the position s is: v = 15t^(3/2) - 8t^(1/2) + 6 and s = 5t^(5/2) - 16t^(3/2) + 6t + 27 respectively.

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