Need help ASAP!!

All exponential functions can be written in many forms. Write the function
f(t) = 750(0.65) ^t\35 in the form f(t) =ab^t. Round all coefficients to four decimal
places.

The equation's solution's quadratic function is [tex]f(x)=15x^{2} -11x-14[/tex].

A quadratic issue in mathematics is a specific type of issue that entails squaring, or multiplying, a variable by itself. This terminology is based on the notion that the area of a square is the product of the length of its sides. Quadratum, the Roman word meaning square, is where the word "quadratic" originates.

Definitions: x ax2 + bx + c = 0 is a quadratic equation, which is a 2nd polynomial formula in a single variable. a 0. Given that it is a second quadratic issue, which is ensured by the algebraic fundamental theorem, there can only be one solution. The answer could be simple or complicated.

The solution of the function are :

[tex]x=\frac{7}{5} and x=-\frac{2}{3}[/tex]

Finding such values:

[tex]5x=7[/tex]⇒[tex]5x-7[/tex]

[tex]3x=-2[/tex]⇒[tex]3x+2[/tex]

Multiplying them:

[tex]f(x)=(5x-7)(3x+2)\\[/tex]

[tex]f(x)=15x^{2} -11x-14[/tex] so this is the function.

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Answer:

73.6

Step-by-step explanation:

lets say that x is our number.

x * 0.05 = 23

x * 0.01 = 4.6

just solving one of these equations will give us x = 460.

now, 16% of 460 is 460 * 0.16 = 73.6

Answer:

D

Step-by-step explanation:

i did the quiz

The percentage of the total that she spent in fruit is 10%.

We know that Jane spent a total of $20 at the grocery shop, and we know that she spent $2 in fruit.

We want to find the percentage of the total that she spend on fruit, to get this, we need to take solve the equation:

Percentage = 100%*(amount that she pend on fruit)/(total amount)

Replacing the values that we know there we will get:

P = 100%*($2/$20)

P = 100%*1/10 = 10%

She spent 10% of the total amount in fruit.

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Therefore, Conner's starting weight was 3 kg. Therefore, the starting price of the toys was $7.50.

An equation is a mathematical statement that shows that two expressions are equal. It typically contains one or more variables, which are placeholders for unknown or varying quantities. The equation may also contain constants, which are known values that do not change.

Here,

31. Let's assume that Conner's starting weight was x kg. According to the given condition, he lifted 2 more kg each week, which means he lifted (x+2) kg on the second week, (x+4) kg on the third week, and so on. Therefore, he lifted (x+12) kg on the seventh week. We know that Conner lifted 15 kg on the seventh week, so we can set up an equation:

x + 12 = 15

Solving for x, we get:

x = 3

Answer: 3 kg

32. Let's assume that the starting price of the toys was x dollars. According to the given condition, the price of the toys was marked down by $0.25 every hour, which means the price of the toys was (x-0.25) dollars after the first hour, (x-0.5) dollars after the second hour, and so on. Therefore, the price of the toys was (x-2) dollars after the eighth hour. We know that the price of the toys was $5.50 after the eighth hour, so we can set up an equation:

x - 2 = 5.5

Solving for x, we get:

x = 7.5

Answer: $7.50

33.  Let's assume that Grayson started earning at a base hourly rate of x dollars. Then, we can use the given information to form an equation that relates his earnings for one day (in dollars) with his hourly rate (in dollars/hour):

Total earnings for one day = base hourly rate + (number of hours worked) * (hourly increase in rate)

Since we know that Grayson earned $45 in one day and that his hourly rate increases by $3 every hour, we can substitute these values into the equation:

45 = x + (number of hours worked) * 3

Simplifying this equation, we get:

(number of hours worked) * 3 = 45 - x

(number of hours worked) = (45 - x) / 3

We can now use the fact that Grayson worked for a full day (i.e., 24 hours) to solve for the base hourly rate x:

24 * x + 3 * (1 + 2 + ... + 23) = 45

Simplifying the sum of the first 23 integers, we get:

24 * x + 3 * (276) = 45

24 * x + 828 = 45

24 * x = 45 - 828

24 * x = -783

x = -32.625

Since a negative base hourly rate doesn't make sense in this context, we can conclude that there is no solution to this problem. Perhaps there was an error in the given information or assumptions made.

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Answer:

[tex]\large\boxed{\tt f(2) = 10}[/tex]

Step-by-step explanation:

[tex]\textsf{For this problem, we are asked to evaluate the function given x.}[/tex]

[tex]\textsf{Note that because x is given, all that's needed to be done is substitution.}[/tex]

[tex]\large\underline{\textsf{Substitute;}}[/tex]

[tex]\tt f(2)= 3x^{3} -5x-4[/tex]

[tex]\tt f(2)= 3(2)^{3} -5(2)-4[/tex]

[tex]\large\underline{\textsf{Evalulate;}}[/tex]

[tex]\tt f(2)= 3(2 \times 2 \times 2) -10-4[/tex]

[tex]\tt f(2)= 3(8) -10-4[/tex]

[tex]\tt f(2)= 24-14[/tex]

[tex]\large\boxed{\tt f(2) = 10}[/tex]

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{f(x) = 3x^3 - 5x - 4}\\\\\mathsf{f(x) = 3(2)^3 - 5(2) - 4}\\\\\mathsf{f(x) = 3(2^3) - 5(2) - 4}\\\\\mathsf{f(x) = 3(2\times2\times2) - 5(2) - 4}\\\\\mathsf{f(x) = 3(4\times2) - 5(2) - 4}\\\\\mathsf{f(x) = 3(8) - 5(2) - 4}\\\\\mathsf{f(x) = 24 - 5(2) - 4}\\\\\mathsf{f(x) = 24 - 10 - 4}\\\\\mathsf{f(x) = 14 - 4}\\\\\mathsf{f(x) = 10}\\\\\\\huge\text{Therefore your answer should be:}\\\\\huge\boxed{\mathtt{f(x) = 10}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

The list of set of dimensions for fencing the building around a rectangular plot of land is 14.5 meters and 29 meters.

Area of a rectangle

area of rectangle = lw

where

l = length

w = width

Therefore,

perimeter = 2w+ l

58 = 2w + l

l = 58 - 2w

Hence,

area = w(58 - 2w)

380 = 58w - 2w²

-2w² + 58w - 380 = 0

-w² + 29w - 190 = 0

The dimension w can be found as follows;

w = - b / 2a

where

a = -1

b = 29

w = - 29 / 2 ×  -1

w = 14.5 meters

Then,

l = 58  - 2w

l = 58 - 2(14.5)

l = 29 meters

Therefore, the dimensions are 14.5 meters and 29 meters.

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By comparing this form to the available choices, we can observe that option B provides the equation that best fits the graph: y²/9 - x²/4 = 1.

What is equation ?

A mathematical equation is a statement that demonstrates the equality of two expressions, usually by placing an equal sign before them. It depicts a connection connecting more than one variable and can be applied to situations to uncover unknown values. Variables, constants, plus mathematical operations including addition, subtract, multiplication, and division are frequently used in algebra equations. Equations include the following: 2x + 3 = 7 y = mx + b , a² + b² = c²

given

The hyperbola graph seen in the figure includes a transverse axis along the y-axis and a centre at (0,0).

The separation between the foci is 8 units, while the separation between the vertices is 6 units.

The equation for this hyperbola's standard form is:

(y - k)²/a² - (x - h) (x - h)²/b² = 1

where (h,k) designates the hyperbola's centre and (a,b) designates the distances between it and its vertices and co-vertices.

By comparing this form to the available choices, we can observe that option B provides the equation that best fits the graph: y²/9 - x²/4 = 1.

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The assumptions and conditions for inference can be checked by options a, b, c, and d.

The assumptions and conditions for inference are checked while making statistical inferences about a population parameter based on sample statistics. These assumptions are made to ensure that the sample accurately reflects the population from which it was drawn. The correct options from the given alternatives are:

a. The residual plot and the scatterplot show consistent variability.

b.The residuals look random.

c. The scatterplot looks straight enough.

d. The residuals are nearly normal.

A residual plot is a graphical tool used to check the assumptions of a simple linear regression model. The scatterplot is the most common method for visualizing the relationship between two quantitative variables. The assumptions of linear regression are that the residuals are normally distributed, have constant variance (homoscedasticity), and are independent of one another. If the residuals are not normally distributed, have heteroscedasticity or the observations are dependent, then the linear regression model may not provide accurate predictions.

The scatterplot should also show the residual plot as random if we want to make valid inferences from a simple linear regression model. If the scatterplot shows any pattern, it indicates that the model does not capture all of the relationships between the variables, which may result in incorrect conclusions when making inferences from the model.The residuals should also be nearly normal for making valid inferences from a simple linear regression model.

It is possible to check whether the residuals are approximately normal by creating a histogram or a normal probability plot of the residuals. If the distribution of residuals is non-normal, the statistical inference may not be accurate.

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The points (5, 0), (0, 5), (-5, 0) and (0, -5) all lie on a circle with center (0, 0) and radius 5.

The equation of a circle with center (0, 0) and radius 5 can be written as (x - 0)2 + (y - 0)2 = 52.

In Quadrant I, the point (5, 0) lies on the circle. This can be seen by substituting x = 5 and y = 0 in the equation of the circle.

5² + 0² = 25

In Quadrant II, the point (0, 5) lies on the circle. This can be seen by substituting x = 0 and y = 5 in the equation of the circle.

0² + 5² = 25

In Quadrant III, the point (-5, 0) lies on the circle. This can be seen by substituting x = -5 and y = 0 in the equation of the circle.

(-5)² + 0² = 25

In Quadrant IV, the point (0, -5) lies on the circle. This can be seen by substituting x = 0 and y = -5 in the equation of the circle.

0² + (-5)² = 25

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h is equal to the sum of f and 3, divided by 3 times g. The given equation is 3gh = f + 3, and we are asked to solve for h. To solve for h, we need to isolate h on one side of the equation.

First, we can simplify the left-hand side of the equation by dividing both sides by 3g:

(3gh)/(3g) = (f + 3)/(3g)

This simplifies to:

h = (f + 3)/(3g)

Now we have isolated h on the left-hand side of the equation. This means that the solution for h is given by the right-hand side of the equation, which is (f + 3)/(3g).

Therefore, h is equal to the sum of f and 3, divided by 3 times g. This is a general formula that will give us the value of h for any given values of f and g, as long as they are not equal to zero.

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The probability that the sample mean is between 50.9 and 51.5 is approximately 0.0998.

We can use the central limit theorem to find the probabilities of the given events. According to the central limit theorem, if we take random samples of size n from a population with mean μ and standard deviation σ, the sample means will be approximately normally distributed with mean μ and standard deviation σ/√n.

a. To find the probability that the sample mean is greater than 53, we first calculate the z-score of the sample mean:

[tex]$z=(x-\mu) /(\sigma / \sqrt{n})=(53-50) /(19 / \sqrt{ } 64)=1.684$[/tex]

Using a standard normal distribution table or calculator, we find that the probability of a z-score being greater than 1.684 is 0.0455. Therefore, the probability that the sample mean is greater than 53 is approximately 0.0455.

b. To find the probability that the sample mean is less than 53, we use the same formula and calculate the z-score:

[tex]$z=(x-\mu) /(\sigma / \sqrt{ } n)=(53-50) /(19 / \sqrt{ } 64)=1.684$[/tex]

The probability of a z-score being less than 1.684 is 1 - 0.0455 = 0.9545. Therefore, the probability that the sample mean is less than 53 is approximately 0.9545.

c. To find the probability that the sample mean is less than 47, we again use the formula for the z-score:

[tex]$z=(x-\mu) /(\sigma / \sqrt{ } n)=(47-50) /(19 / \sqrt{ } 64)=-1.684$[/tex][tex]$z 1=(47.5-50) /(19 / \sqrt{ } 64)=-0.842$[/tex]

The probability of a z-score being less than -1.684 is the same as the probability of a z-score being greater than 1.684, which we found to be 0.0455. Therefore, the probability that the sample mean is less than 47 is approximately 0.0455.

d. To find the probability that the sample mean is between 47.5 and 51.5, we first calculate the z-scores of the two endpoints:

[tex]z_1[/tex] = (47.5 - 50) / (19/√64) = -0.842

[tex]z_2[/tex]= (51.5 - 50) / (19/√64) = 0.842

Using a standard normal distribution table or calculator, we find that the probability of a z-score being between -0.842 and 0.842 is 0.6603. Therefore, the probability that the sample mean is between 47.5 and 51.5 is approximately 0.6603.

e. To find the probability that the sample mean is between 50.9 and 51.5, we first calculate the z-scores of the two endpoints:

[tex]z_1[/tex]= (50.9 - 50) / (19/√64) = 0.674

[tex]z_2[/tex] = (51.5 - 50) / (19/√64) = 0.842

Using a standard normal distribution table or calculator, we find that the probability of a z-score being between 0.674 and 0.842 is 0.0998. Therefore, the probability that the sample mean is between 50.9 and 51.5 is approximately 0.0998.

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Answer:

Step-by-step explanation:

Sup? Pay attention closely (or not XD)

Short answer: 0.0308 or 3.08%

We use the combination formula C = n!/(r! * (n-r)!) for each brand. It basically tells us the number of ways to select a certain number of cars:

1) Fords: C(5, 2) = 5! / (2! * (5 - 2)!) = 10 ways to pick 2 Fords

2) Chevrolets: C(7, 3) = 7! / (3! * (7 - 3)!) = 35 was to pick 3 Chevys

3) Dodges: C(4, 1) = 4! / (1! * (4 - 1)!) = 4 ways to pick 1 Dodge

4) Hondas: C(3, 1) = 3! / (1! * (3 - 1)!) = 3 ways to pick 1 Honda

5) Toyotas: C(4, 2) = 4! / (2! * (4 - 2)!) = 6 ways to pick 2 Toyotas

Then you multiply all them results. Peep this:

10*35*4*3*6 = 25,200 ways to pick your target cars from each brand in total (sheesh)

Now how many ways would it be to pick 9 out of the 23 cars??

Use your best friend combination problem to solve this!

C(23, 9) = 23! / (9! * (23 - 9)!) = 817,190 (sheesh)

Now divide! 25,200/817,190 = 0.0308 or 3.08%

Thanks for listening to my TED talk. Hope this helps.

More than 1 triangles can be constructed with the angles 110°, 50°, and 20°.

Three non-collinear points are connected with straight line segments to create the two-dimensional geometric shape known as a triangle. The triangle's three points are referred to as its vertices, and the line segments that link them as its sides. Triangles are named based on their sides and angles.  

In the given triangles,

angles are 110, 50 and 20.

we can construct on triangle by using these angles.

Now, 110 angle subtend longest side, 20 subtend shortest side as well as, 50 subtend third side.

Sides length are not mentioned.

So, we can construct one infinite triangle by scaling the length of sides.

Hence, More than 1 triangles can be constructed with the angles 110, 50, and 20.

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The height of Red hill is 513.8 feet.

What does mean by the angle of elevation?

The angle of elevation is the angle created between the line of sight and the horizontal. The angle created is an angle of elevation if the line of sight is upward from the horizontal line. This angle eventually develops above the surface. The angle of elevation is made in such a way that it is above the observer's eye, as the name suggests.

Given:

Distance from the parking lot to the foot of the hill = 740feet

The angle of elevation from a parking lot and the foot of the hill is 25 and 55 degrees respectively.

For easy understanding, assume triangle edges with alphabets as shown in the figure.

Now, let's take ΔACD,

CotD = DC/AC

Cot 55 = y/x ⇒ 0.7 =y/x

⇒ y = 0.7x

In ΔABC

Tan B = AC/BC

Tan 25 = x/(740+y)    (y = 0.7x )

0.467 = x/(740+0.7x )

x = 0.467(740+0.7x )

  = 345.5 + 0.326x

0.6731x = 345.5

∴ x = 513.8 feet

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The relationships between angle pairs are based on their position or on their orientation in relation to each other.

Angles are measured in degrees, and the measure of an angle determines its size. However, the relationships between angle pairs are not solely based on their measures. The position of two angles in relation to each other, such as whether they share a vertex or lie on the same line or plane, can determine their relationship. Additionally, the orientation of the angles can also play a role in their relationship, such as whether they are adjacent, vertical, complementary, supplementary, or congruent. Understanding these relationships is important in geometry and can help in solving problems and proving theorems.

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Jimmy's living space really gauges 24 feet by 16 feet in light of the fact that every 2 cm on the size attracting is equal to 8 feet.

We can utilize this scale variable to decide the genuine dimensions of the rectangle room in the event that each 2 cm on the scale attracting relates to 8 feet.

We should initially sort out the number of 2 cm units there that are in the scale drawing's length and expansiveness.

Length: 6 cm ÷ 2 cm = 3 units

Width: 4 cm ÷ 2 cm = 2 units

Thus, the size drawing is 3 by 2 units.

Next, we can interpret the dimensions of the scale bringing into genuine dimensions utilizing the scale variable of 2 cm = 8 feet:

Length: 3 units times 8 feet for every unit approaches 24 feet

Width: 2 units times 8 feet for every unit approaches 16 feet

Jimmy's living space really gauges 24 feet by 16 feet in light of the fact that each 2 centimeters on the size attracting is comparable to 8 feet.

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Answer:

below

Step-by-step explanation:

assuming r=5 and center (0,0)

1.) point at (0,0) for center

2.) point at (5,0)

3.) point at (0,5)

4.) point at (-5,0)

5.) point at (0,-5)

trace around points 2-5 to get the 4pt circle

Answer:

-17 9/10

Step-by-step explanation:

a. The marginal density of Y1 is fY1(y1) = [tex]2e^{-(4+y1)[/tex], y1 > 0.

b. The conditional density of Y2 given Y1 = y1 is f(y2|y1) = 1, y2 > y1 and y1 > 0.

c.  Y1 and Y2 are not independent

  (a) E(Y2|Y1=y1) does not exist.

  (b) V(Y2|Y1=y1) does not exist.

(a) To find the marginal density of Y1, we integrate the joint density over all possible values of Y2:

fY1(y1) = ∫f(y1, y2) dy2 from y2=y1 to y2=∞

= [tex]\int\limits2e^{-(4+y1)[/tex]dy2 from y2=y1 to y2=∞

= [tex]-2e^{-(4+y1)[/tex] [from y2=y1 to y2=∞]

= [tex]2e^{-(4+y1)[/tex], y1 > 0

So the marginal density of Y1 is fY1(y1) = 2e^-(4+y1), y1 > 0.

(b) To find the conditional density of Y2 given Y1 = y1, we use the formula:

f(y2|y1) = f(y1,y2) / fY1(y1) for y1 > 0 and y2 > y1

= 0 otherwise

Substituting the given joint and marginal densities, we get:

f(y2|y1) = [tex]2e^{-(4+y1)[/tex]  / [tex]2e^{-(4+y1)[/tex]) = 1, y2 > y1 and y1 > 0

= 0 otherwise

So the conditional density of Y2 given Y1 = y1 is f(y2|y1) = 1, y2 > y1 and y1 > 0.

(c) To check if Y1 and Y2 are independent, we need to verify if f(y1,y2) = fY1(y1)fY2(y2) for all y1 and y2. We have:

fY2(y2) = ∫f(y1,y2) dy1 from y1=0 to y1=y2

= ∫ [tex]2e^{-(4+y1)[/tex]) dy1 from y1=0 to y1=y2

= - [tex]2e^{-(4+y2)[/tex]  +  [tex]2e^{-4[/tex]

fY1(y1)fY2(y2) = 4e⁻⁸ exp[-(y1+y2)], y1 > 0 and y2 > 0

Clearly, f(y1,y2) is not equal to fY1(y1)fY2(y2) for all y1 and y2, so Y1 and Y2 are not independent.

(a) Using the formula for conditional expectation, we have:

E(Y2|Y1=y1) = ∫y2 f(y2|y1) dy2 from y2=y1 to y2=∞

= ∫y2 dy2 from y2=y1 to y2=∞

= ∞

So E(Y2|Y1=y1) does not exist.

(b) Using the formula for conditional variance, we have:

V(Y2|Y1=y1) = E(Y2²|Y1=y1) - [E(Y2|Y1=y1)]²

= ∫y2² f(y2|y1) dy2 - (∞)²

= ∫y2² dy2 from y2=y1 to y2=∞ - (∞)^²

= ∞

So V(Y2|Y1=y1) does not exist.

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The inverse of the function is  [tex](1/4)^{x/5}[/tex].

What is an inverse function?

A function that reverses the effects of another function is called an inverse function. When y=f(x) and x=g, a function g is the inverse of a function f. (y). Applying f and then g is equivalent to doing nothing, in other words. This can be expressed as g(f(x))=x in terms of the relationship between f and g.

Here, we have

Given: equation y = log(1/4)x⁵

A function g is the inverse of function f if for y = f(x), x = g(y)

y = log(1/4)x⁵

Replace x with y

x = log(1/4)y⁵

Solve for y, we get

y = [tex](1/4)^{x/5}[/tex]

Hence, the inverse of the function is  [tex](1/4)^{x/5}[/tex].

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Therefore, the answer is D. Block 1 IQR: 20; Block 2 IQR: 5. Therefore, the answer is B. Block One: 25, Block Two: 100. Therefore, the answer is B. Block 1 is skewed right, Block 2 is skewed left. Therefore, the answer is option A: mean: 76.5, standard deviation: 21.6.

In statistics, the mean (or arithmetic mean) is a measure of central tendency of a set of numerical data. It is calculated by adding all the values in the dataset and dividing by the number of values. The mean is often used as a representative value for a dataset, as it provides a single value that summarizes the entire dataset. However, it can be affected by extreme values (outliers) in the dataset.

Here,

1. To find the interquartile range (IQR) for each block, we first need to determine the quartiles. We can do this by finding the median (Q2) of each block, and then finding the median of the lower half (Q1) and upper half (Q3) of the data.

For Block 1:

Q1: median of {25, 60, 70, 75, 80} = 70

Q2: median of {85, 85, 90, 95, 100} = 90

Q3: median of {70, 75, 80, 85, 90} = 80

IQR = Q3 - Q1 = 80 - 70 = 10

For Block 2:

Q1: median of {70, 70, 75, 75, 75} = 75

Q2: median of {75, 75, 80, 80, 85} = 80

Q3: median of {80, 85, 100, 75, 75} = 82.5

2. To identify outliers, we can use the 1.5 x IQR rule. Any data point that is more than 1.5 x IQR above Q3 or below Q1 is considered an outlier.

For Block 1:

Q1 = 70

Q3 = 80

IQR = 10

1.5 x IQR = 15

The only data point that is more than 15 above Q3 is 100, so it is an outlier.

For Block 2:

Q1 = 75

Q3 = 82.5

IQR = 8

1.5 x IQR = 12

There are no data points that are more than 12 above Q3 or below Q1, so there are no outliers.

3. To determine if each block's data is symmetric, skewed left, or skewed right, we can examine the shape of the distribution.

For Block 1, the data is:

Highest at 100, with several values clustered around the upper end of the range.

No values below 25, which suggests a lower boundary.

Median is 90.

No values are particularly isolated from the rest of the data.

This suggests that Block 1 is skewed right.

For Block 2, the data is:

Highest at 75, with several values clustered around the middle of the range.

No values below 70, which suggests a lower boundary.

Median is 80.

No values are particularly isolated from the rest of the data.

This suggests that Block 2 is skewed left.

4. To find the mean of Block 1, we add up all the scores and divide by the number of scores:

mean = (25 + 60 + 70 + 75 + 80 + 85 + 85 + 90 + 95 + 100) / 10

mean = 765 / 10

mean = 76.5

To find the standard deviation of Block 1, we need to first calculate the variance.

To do that, we can use the formula:

variance = (sum of (each score - mean)²) / (number of scores - 1)

First, we'll find the sum of (each score - mean)²:

(25 - 76.5)² = 2562.25

(60 - 76.5)² = 270.25

(70 - 76.5)² = 42.25

(75 - 76.5)² = 2.25

(80 - 76.5)² = 12.25

(85 - 76.5)² = 71.25

(85 - 76.5)² = 71.25

(90 - 76.5)² = 182.25

(95 - 76.5)² = 379.25

(100 - 76.5)² = 562.5

Next, we'll add up these values:

2562.25 + 270.25 + 42.25 + 2.25 + 12.25 + 71.25 + 71.25 + 182.25 + 379.25 + 562.5 = 3154.5

Now we can plug this into the variance formula:

variance = 3154.5 / 9

variance = 350.5

Finally, to get the standard deviation, we take the square root of the variance:

standard deviation = √(350.5)

standard deviation = 18.7 (rounded to one decimal place)

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Answer: Prime Numbers

The correct graph will display the inequalities with appropriate lines (solid or dashed) and shading that demonstrates the solution set where all inequalities are satisfied simultaneously.

To determine which graph represents the system of inequalities, consider the following steps:

1. Identify the inequalities involved in the system. They typically include one or more linear inequalities, which can be expressed as Ax + By ≤ C, Ax + By ≥ C, Ax + By < C, or Ax + By > C.

2. Graph each inequality separately, using solid lines for "≤" and "≥" inequalities and dashed lines for "<" and ">" inequalities. Solid lines represent the points that satisfy the inequality, while dashed lines indicate that points on the line do not.

3. Shade the regions that satisfy each inequality. For inequalities with "≤" or "<", shade the region below the line, adeterminationnd for those with "≥" or ">", shade the region above the line.

4. Observe the overlapping shaded regions, as this represents the solution set for the system of inequalities.

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Answer:

Solution- x = 5 Equation- x + 4 = 9

Step-by-step explanation:

I hope this helps you understand.

The expression that is equal to 18x²y⁶ can be found to be D. 3²x²y⁴ × 2 y².

3x³y⁴ has a different power for both x and y compared to the original expression (18x²y⁶). 9xy has a different coefficient and different powers for x and y compared to the original expression (18x²y⁶).

3x³y + √√2 not only has different powers for x and y but also has an additional square root term, making it different from the original expression (18x²y⁶).

3²x²y⁴ × 2 y² on the other hand, can be simplified such that it becomes 18x²y⁶.

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Options include:

Answer:

x = 32°

Step-by-step explanation:

The definition of tangent means that the angle formed by the line and the circle is a 90° angle. We can also see that the two segments connected to the center have equal angles because they are both radii of the circle. They form a triangle and the angle measurements are 61°, 61° and 58°. We have two angle measurements of the overall triangle, 58°, 90° (from the tangent), and x°.

The sum of the angles of any triangle is 180°. Therefore, we can form an equation to calculate the value of x.

58 + 90 + x = 180

x = 180 - 90 - 58

x = 32°

Answer:

x = 32°

Step-by-step explanation:

To find:-

Answer:-

As we know that angle made by tangent on the centre is a right angle . So here [tex]\angle[/tex]OBC will be 90° ( as CB is tangent on the circle.) Again we know that the angles opposite to equal sides are equal . Therefore here OB and OA are radii of the circle which are equal. So we can say that;

[tex]\sf:\implies \red{ \angle OBA = \angle OAB = 61^o}\\[/tex]

Again we know that the angle sum property of a triangle is 180° . Therefore in ∆OBA ,

[tex]\sf:\implies 61^o + 61^o + \angle AOB = 180^o \\[/tex]

[tex]\sf:\implies 122^o + \angle AOB = 180^o \\[/tex]

[tex]\sf:\implies \angle AOB = 180^o - 122^o \\[/tex]

[tex]\sf:\implies \angle AOB = 58^o\\[/tex]

Finally look into the ∆OBC ,

[tex]\sf:\implies \angle BOC + \angle OCB + \angle CBO = 180^o\\[/tex]

[tex]\sf:\implies 58^o + 90^o + x = 180^o \\[/tex]

[tex]\sf:\implies 148^o + x = 180^o \\[/tex]

[tex]\sf:\implies x = 180^o - 148^o \\[/tex]

[tex]\sf:\implies \red{ x = 32^o }\\[/tex]

Hence the value of x is 32°.