Nikkita sold her old textbooks for $54 a piece. When she was done, she had $324, but she still had 8 textbooks left. How many textbooks did she start with?

Answers

Answer 1

Answer:

14 :D

Step-by-step explanation:

First we must divide!!

324/54 = 6

Now we add :)

6 + 8 = 14

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Related Questions

When rotating the figure you turn it around at a point this can be any coordinate point like the origin which is at?

Answers

Answer:

Yes, if you know the coordinates of a point PP in your original figure as (x,y)(x,y), you can figure out the coordinates of PP following rotation and given by (x′,y′)(x′,y′) as

x′=−yx′=−y

y′=xy′=x

Need ASAP!
What is the exact value of TanA

Answers

Answer:

See below

Step-by-step explanation:

Ina right traingle   tan (angle) = (opposite side) / (adjacent side)

So  tan A  = sqrt (161)/8       exactly

Math and experimental probability for this irrady stuff………

Answers

Answer:

so whats the question now?

Step-by-step explanation:

4. The statement abc = cab is an example of which property of multiplication?
a. Commutative
b. Inverse
c. Identity
d. Associative

Answers

Answer:A, commutative

Step-by-step explanation: The commutative property of multiplication states that

the order in which we multiply numbers does not change the product.

Answer:

A. Commutative

Step-by-step explanation:

I believe it's a because you didn't use +/- so I assumed it was multiplication in which case, the commutative property of multiplication, which states that the order we multiply in does not affect the product.

Which equation correctly uses the law of cosines to solve for the missing side length of trianglepqr? 62 = p2 82 – 2(p)(8)cos(39°) p2 = 62 82 – 2(6)(8)cos(39°) 82 = 62 p2 – 2(6)(p)cos(39°) p2 = 62 62 – 2(6)(6)cos(39°)

Answers

The equation that correctly uses the law of cosines to solve for the missing side length of trianglepqr is 8^2 = 7^2 +11^2 - 2(7)(11) cos <P

The cosine rule formula

For us to use the cosine formula, an angle must be situated between two sides of the triangle.

According to the rule;

c^2 = a^2 + b^2 - 2ab cos C

From the given diagram, if cos<P is the reference angle, then;

a = 11

b = 7

c = 8

Substiute

8^2 = 7^2 +11^2 - 2(7)(11) cos <P

Hence the equation that correctly uses the law of cosines to solve for the missing side length of trianglepqr is 8^2 = 7^2 +11^2 - 2(7)(11) cos <P

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What is the VOLUME of this figure?
9 cm
7 cm
8 cm
10 cm
12 cm

Answers

Answer:

1390 cm^3

Step-by-step explanation:

9 x 7 x 10 = 630 cm^3 for the rectang prism top

area * 10 for the bottom

8 x ( 12 + 7)/2   * 10 = 760 cm^3  for the trap base

total = 1390 cm^3

True or false? pls help me get this right​

Answers

I believe the answer is false
False! You can use the area and radius

calculate the total perimeter and area of the shaded ring​

Answers

Answer:

be specific

Step-by-step explanation:

which shaded eing

100 Points!!!
Polynomial Identities

Part 1. Pick a two-digit number greater than 25. Rewrite your two-digit number as a difference of two numbers. Show how to use the identity (x − y)2 = x2 − 2xy + y2 to square your number without using a calculator.

Part 2. Choose two values, a and b, each between 8 and 15. Show how to use the identity a3 + b3 = (a + b)(a2 − ab + b2) to calculate the sum of the cubes of your numbers without using a calculator.

Answers

Let's see

#a

Take 28

(28)²(30-2)²30²-2(30)(2)+2²900-120+4780+4784

#2

Take 9,10

9³+10³(9+10)(9²-9×10+10²)(19)(81-90+100)19(181-90)19(91)1729

Answer:

Two-digit number greater than 25:   32

Rewrite 32 as the difference of 2 numbers: 40 - 8

Therefore, x = 40  and  y = 8

[tex]\begin{aligned}\implies (40-8)^2 & =40^2-2(40)(8)+8^2\\ & = (4 \cdot 10)^2-(80)(8)+64\\ & = 4^2 \cdot 10^2-640+64\\ & = 16 \cdot 100-640+64\\ & = 1600-640+64\\ & = 960+64\\ & = 1024\end{aligned}[/tex]

Let a = 10

Let b = 11

[tex]\begin{aligned}\implies 10^3+11^3 & =(10+11)(10^2-10 \cdot 11+11^2)\\& = 21(100-110+121)\\ & = 21(-10+121)\\ & = 21(111)\\& = 21 (100 + 10 + 1)\\ & = (21 \cdot 100)+(21 \cdot 10)+(21 \cdot 1)\\ & = 2100 +210+21\\ & = 2310 + 21\\ & = 2331\end{aligned}[/tex]


What is the value of p?

Answers

Imaybe if you add the negative numbers that have p you could get the answer

Form a quadratic function f(x) for which f(1)=0, f(−1)=−4, and f(2)=5.

Answers

Answer:

[tex]f(x)=x^2+2x-3[/tex]

Step-by-step explanation:

[tex]\textsf{General form of a quadratic function}:f(x)=ax^2+bx+c[/tex]

Equation 1

[tex]\begin{aligned}f(1) &=0\\ \implies a(1)^2+b(1)+c &=0\\ a+b+c &=0 \end{aligned}[/tex]

Equation 2

[tex]\begin{aligned}f(-1) &=-4\\ \implies a(-1)^2+b(-1)+c &=-4\\ a-b+c &=-4 \end{aligned}[/tex]

Equation 3

[tex]\begin{aligned}f(2) &=5\\ \implies a(2)^2+b(2)+c &=5\\ 4a+2b+c &=5 \end{aligned}[/tex]

Add Equation 1 and Equation 2:

[tex]\begin{array}{r l}a+b+c & =0 \\+\quad a-b+c & =-4 \\\cline{1-2} 2a+2c & =-4 \end{array}[/tex]

[tex]\implies a+c=-2[/tex]

Substitute [tex]a+c=-2[/tex] into Equation 1 and solve for b:

[tex]\begin{aligned}\implies a+b+c &=0\\ b-2 &=0\\ b &=2\end{aligned}[/tex]

Substitute [tex]a=-2-c[/tex]  and  [tex]b=2[/tex]  into Equation 3 and solve for c:

[tex]\begin{aligned} \implies 4a+2b+c&=5\\ 4(-2-c)+2(2)+c &=5\\-8-4c+4+c &=5\\ -3c &=9\\ c &=-3\end{aligned}[/tex]

Substitute found value of c into [tex]a=-2-c[/tex] and solve for a:

[tex]\implies a=-2-(-3)=1[/tex]

Therefore, a = 1, b = 2 and c = -3

Substitute the found values into the general form of a quadratic function to form the final equation:

[tex]f(x)=x^2+2x-3[/tex]

Complete the two column proof
Given angle to an angle five are supplementary
Prove: I || m

Answers

Answer:

Step-by-step explanation:

Find the third fourth and eleventh terms of the sequence described by the rule A(n)=-2+(n-1)(5)

Answers

Answer:

8,13,48

Step-by-step explanation:

Third = A(3) = -2 + (3-1)(5) = -2 + 10 = 8

Fourth = A(4) = -2 +(4-1)(5) = -2 + 15 = 13

Eleventh = A(11) = -2 + (11-1)(5) = -2 + 50 = 48

The volume of a right cone is 27\piπ units^3
3
. If its height is 9 units, find its circumference in terms of \piπ.

Answers

that is the circumference of its circular base.

[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ h=9\\ V=27\pi \end{cases}\implies 27\pi =\cfrac{\pi r^2 (9)}{3}\implies 27\pi =3\pi r^2 \\\\\\ \cfrac{27\pi }{3\pi }=r^2\implies 9=r^2\implies \sqrt{9}=r\implies \underline{3=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{circumference of a circle}\\\\ C=2\pi r\qquad \qquad \qquad C=2\pi (\underline{3})\implies C=6\pi[/tex]

The circumference of the cone will be;

⇒ 6π

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The volume of a right cone = 27π units³

And, The height = 9 units

Now,

Since, We know that;

The volume of cone = πr²h / 3

⇒ 27π = π × r² × 9 / 3

⇒ 27 = r² × 3

⇒ r² = 27/3

⇒ r² = 9

⇒ r = 3

Since, The circumference of the cone = 2πr

                                                            = 2 × π × 3

                                                            = 6π

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what is y 12y - 19= 6y+1=

Answers

Answer:

Y= 10/3 or 3.333....

Step-by-step explanation:

12y-19= 6y+1

12y-6y = 1 +19

6y = 20

y = 20/6

y= 10/3 or 3.33..

 

HAVE A NICE TIME :)pls give a brainliest if it is CORRECT

Tell whether the relation is a function. Explain your reasoning.
{(-1, 7), (9, 4), (3, -2), (5, 3), (9, 1)}

Answers

The relation is not a function. In order for a relation to be a function, the x-inputs of all ordered pairs must not repeat, and if they do, they must have only one output. In this problem, however, (9,4) and (9,1) both have different outputs (y-values). Therefore, there is no function present.

A part of linear function g is graphed on the grid.

Which inequality best describes the domain and range of the part shown?

Answers

By looking at the graph, we can see that:

Domain: -7 ≤ x ≤ 6Range: -4 ≤ y ≤ 5.

How to find the domain and range of a function?

For a function:

y = f(x)

We define the domain as the set of the possible inputs x, and the range as the set of the possible outputs y.

Here, to find the domain, we need to see the range of "horizontal values" that the graph takes. We can see that it goes from -7 to 6, then the domain is:

-7 ≤ x ≤ 6

The range goes from -4 to 5, so the range is: -4 ≤ y ≤ 5.

Then the correct option is the first one.

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HELP PLEASE ILL GIVE BRAINLEST IF U HELP QUICK

Answers

[tex]\qquad\qquad\displaystyle \huge Answer[/tex]

Let's check if (3 , 6) is the point of intersection of the given lines ~

[tex] \qquad \displaystyle \: y = 4x - 2[/tex]

and

[tex] \qquad \displaystyle \: y = \frac{1}{2} x + 5[/tex]

If the point is the point of intersection of these two lines, then it should satisfy both the equations ~

let's try each of them, using x coordinate of point.

[tex] \qquad \displaystyle \: y = 4(3) - 2[/tex]

[tex] \qquad \displaystyle \: y = 12 - 2[/tex]

[tex] \qquad \displaystyle \: y = 10[/tex]

So, the point didn't actually satisfy one of the equation. hence we can infer that the given statement is wrong.

24. Find the area of the shaded region:



Answers

Answer:

A = 5x³ + 17x² - 35x - 30

Step-by-step explanation:

the shaded area (A) is calculated as

A = outer area - inner area

   = (5x + 3)(x² + 4x - 10) - 3x(2x - 1) ← distribute parenthesis

   = 5x³ + 20x² - 50x + 3x² + 12x - 30 - (6x² - 3x)

  = 5x³ + 23x² - 38x - 30 - 6x² + 3x ← collect like terms

  = 5x³ + 17x² - 35x - 30

Answer:

5x^3+ 17x^2- 35x-30 Or x=-4.63 or 1.9

Step-by-step explanation:

Area of rectangle =L×B

for smaller rectangle :

after applying the formula, the equation becomes:

6x^2 - 3x

For bigger rectangle:

Applying the same formula, the equation becomes:

5x^3+ 23x^2- 38x- 30

Area of shaded region =

Area of bigger rectangle- Area of smaller rectangle

= 5x^3+17x^2 -35x-30

going further solving the above equation

Area of shaded region: -4.96 or 1.9

Determine the solutions of the equation. what solution makes sense for the situation? x = what are the dimensions of the rectangle? width = inches length = inches

Answers

Answer:

Determine the solutions of the equation. What solution makes sense for the situation?

x = 8

width = 8inches

length = 13

Larissa is planning for a trip that will cost $2,145. She has $952.50 saved and is going to set aside ½ of her weekly salary from her part-time job. Larissa earns $265 per week. How many weeks will it take her to earn the rest of the money needed for the trip? With work shown

Answers

Answer:

9 weeks :)

Step-by-step explanation:

First we subtract :)

2145 - 952.50 = 1192.50

Now we divide :)

265/2 = 132.5

Now we divide 1 more time :)

1192.50/132.50 = 9

It will take 9 weeks :)

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a
A circle has a center of (-6,0) and passes
through the point (-1,3). What is its radius?

Answers

Answer: 10

Step-by-step explanation:

Given that a circle has the center at

(6.0) and the circle passes through the point (2,−3).So the distance between these two points will give us the measure of the radius.So(x1,y1)=(6

So by using the distance formula the radius of the given circle is-r=√(x2−x1)2+(y2−y1)2r=√(2−6)2+(−3−0)2r=√16+9r=√25=5 unitsSo the diameter of the given circle is=2rd==2(5)d=10units

Let's see

Find distance between these points and radius

√(x_1-x_2)²+(y_1-y_2)²√(-6+1)²+(0-3)²√(-5)²+(-3)²√25+9√34 units

I WILL MARK BRAINLIEST

Answers

140

Multiple l times w times h

Scientific models can be used for a variety of different purposes. Which of the following statements about scientific models is not true?

a.
Scientific models can save money and lives.
b.
Scientific models allow scientists to test their predictions.
c.
Scientific models allow scientists to study systems that no longer exist.
d.
Scientific models are used rarely.

Answers

Answer:

D

Step-by-step explanation:

Characteristics of scientific models

They can save money and livesThey allow scientists to test their predictionsThey allow scientists to study systems that no longer existThey are widely used

Out of the given options, only D is an incorrect statement.

Answer:

D

Step-by-step explanation:

Just took the test

Find the surface area of the cone in terms of pi. 15cm 3cm

Answers

Answer:
Option a

Explanation :
check out my attached work
Hope it helps, let me know if you have any questions !
Have a nice rest of your day :)

A rectangular farm has an area of 58
square miles. If its length is 19
miles, what is its width?

Input your answer as a fraction.

Answers

Answer: 58/19 or 3¹/119

Step-by-step explanation: Area = 58

Length is 19 Width is Area/ Length

What value of x makes the equation true?

Answers

[tex]2(x - 9) = 9 \div ( - \frac{1}{3} ) \\ [/tex]

[tex]2(x - 9) = 9 \times ( - 3)[/tex]

[tex]2(x - 9) = - 27[/tex]

[tex] \frac{2(x - 9)}{2} = \frac{ - 27}{2} \\ [/tex]

[tex]x - 9 = - 13.5[/tex]

[tex]x - 9 + 9 = - 13.5 + 9[/tex]

[tex]x = - 4.5[/tex]

Thus option B is the correct answer.

help my little sister

Answers

Answer:

The answer would be 48 cm^2

Step-by-step explanation:

You have to do 9x4 and then add 6x2 to that.
9x4 is 36 and 6x2 is 12.
36+12 is 48. Hope this helps! :)

Answer:

The answer would be 48 cm^2

charlotte buys a rectangular rug with an area of 27/4 sqaure meters. The midth of the rug is 3/2 meters. What is the length, in meters, of the rug?

Answers

charlotte buys a rectangular rug with an area of 27/4 square meters.

The width of the rug is 3/2 meters. So the length of the rectangular rug is 9/2 meters.

What is the area of the rectangle?

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

charlotte buys a rectangular rug with an area of 27/4 square meters.

The width of the rug is 3/2 meters.

Area of the rectangular rug = 27/4 square meters

Let us assume the length of the rug = x meters

Then,

Area of the rug =  length × Width

[tex]27/4 = (3/2) \times x\\\\x = (27/4) \times (2/3) \\x = 9/2[/tex]

So the length of the rectangular rug is 9/2 meters.

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What's the circumference of a circle with a diameter of 25 inches

Answers

[tex]\bold{ANSWER:}[/tex]
C = 78.5 inches

[tex]\bold{EXPLANATIONS:}[/tex]
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