Therefore , the solution of the given problem of circle comes out to be since the numbers 1, 2, and 3 cannot be dispersed evenly around the circle with the necessary amount of gaps.
What is circle?Each element of the aeroplanes creates a circle when viewed from this new angle and at a distance. (center). Its structure is composed of surfaces and undulating regions that contrast with one another. Additionally, it rotates equally within the centre in all directions. Every ultimate extent of a circular or restricted double sphere is the same as the sphere's "center."
Here,
One potential twin circle that we can create is as follows:
=> 1 2 1 3 2 5 4 5 4 3
Here, the first twin pair 1 is divided into three pairs, with the second twin pair 2 being divided into two pairs, the third twin pair being divided into three pairs, and so on. This satisfies the criteria of the puzzle, and we can verify that every twin pair appears precisely twice.
When the numbers are reversed, a second potential twin circle results:
=> 3 4 5 4 5 2 3 1 2 1
As a result, there is no such twin circle since the numbers 1, 2, and 3 cannot be dispersed evenly around the circle with the necessary amount of gaps.
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what is the volume of a sphere with a radius of 2.5 ? answer in terms of pi
Answer:
Of course, I can assist you with your question. The volume of a sphere with a radius of 2.5 can be calculated using the formula (4/3)*pi*(2.5^3). This results in an answer of approximately 65.45 cubic units in terms of pi.
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EDIT: The volume of a sphere with a radius of 2.5 can be calculated using the formula V = (4/3)πr^3. Plugging in the value of r as 2.5, we get V = (4/3)π(2.5)^3. Simplifying this expression, we get V = 65.45π/3. Thus, the answer in terms of π is 65.45/3π or approximately 21.82π. None of the given options matches the calculated answer.
An office manager orders one calculator or one calendar for each of the office's 80 employees. Each calculator costs $12, and each calendar costs $10. The entire order totaled $900.
Part A: Write the system of equations that models this scenario.
Part B: Use substitution method or elimination method to determine the number of calculators and calendars ordered. Show all necessary steps.
The system of equations is.
x + y = 80
12x + 10y = 900
And the solutions are y = 30 and x = 50
How to write and solve the system of equations?Let's define the two variables:
x = number of calculators.
y = number of calendars.
With the given information we can write two equations, then the system will be:
x + y = 80
12x + 10y = 900
Now let's solve it.
We can isolate x on the first equation to get:
x = 80 - y
Replace that in the other equation to get:
12*(80 - y) + 10y = 900
-2y = 900 - 960
-2y = -60
y = -60/-2 = 30
Then x = 50
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Solve for a.
5
a = [?]
3
a
evaluate the square root
before entering your
answer.
pythagorean theorem: a2 + b2 = c2
By evaluating square root and using Pythagorean Theorem the value of a is a= 3.33 (rounded to two decimal places)
The given expression is 5/3, which can be simplified as follows:
a = 5/3
To evaluate the square root of a, we can rewrite it in terms of exponents:
a = (5/3)¹/₂
Using a calculator, we get:
a ≈ 1.83
Next, we can use the Pythagorean Theorem to find the value of c, given that a = 3.33 and b = 4.66:
a² + b² = c²
(3.33)² + (4.66)² = c²
11.0889 + 21.7156 = c²
32.8045 = c²
c ≈ 5.72
Therefore, the final answer is a = 3.33 and c ≈ 5.72.
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Given that f(x) = (h(x))10 = h(-1) = 3 h'(-1) = 6 Calculate f'(-1).
The final value is f'(-1) = 16,777,2160.
We can use the chain rule and the power rule of differentiation to find f'(-1).
Recall that the chain rule states that if f(x) = g(h(x)), then f'(x) = g'(h(x)) h'(x). Applying this rule to f(x) = (h(x))^10, we get:
f'(x) = 10(h(x))^9 h'(x)
Now, we can substitute x = -1 into the above equation, since we are asked to find f'(-1). Thus, we have:
f'(-1) = 10(h(-1))^9 h'(-1)
We are given that h(-1) = 3 and h'(-1) = 6, so we can substitute these values to get:
f'(-1) = 10(3)^9 (6)
Simplifying, we get:
f'(-1) = 16,777,2160
Therefore, f'(-1) = 16,777,2160
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A portion of a truss vehicle bridge has steel
beams that form an isosceles triangle with the
dimensions shown. A pedestrian handrail is
attached to the side of the bridge so that it is
parallel to the road.
A
24 feet
28.5 feet
30 feet
What is the height, x, of the handrail above th
road to the nearest tenth of a foot?
Answer:
3.5 feet
Step-by-step explanation:
You want the difference in height between similar isosceles triangles, one with height of 30 ft and a base of 24 ft, the other with a side length of 28.5 ft.
RelationsWe can find the side length of the larger triangle using the Pythagorean theorem. It will be ...
longer side = √(30² +12²) ≈ 32.311 ft
Similar trianglesThen the length x is the difference between the altitudes of the triangles. The altitudes are proportional to the side lengths, so we have ...
(30 -x)/28.5 = 30/32.311
x = 30-(28.5)(30/32.311) = 30(1 -28.5/32.311) ≈ 3.538 ≈ 3.5 . . . . feet
The hand rail is about 3.5 feet above the bridge deck.
TrigonometryWe recognize that the distance from the hand rail to the top of the triangle is the product of the given side length (28.5 ft) and the cosine of the angle between the side and the altitude.
The tangent of that angle is the ratio of its opposite side (12 ft) to its adjacent side (30 ft), or θ = arctan(12/30).
The value of x is the difference of the altitudes of the triangles, so is ...
x = 30 -28.5·cos(arctan(12/30)) ≈ 3.5 ft
We find this easier to compute.
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A population has a proportion of 0. 62 and a standard deviation of sample proportions of 0. 8. A sample of size 40 was taken from this population. Determine the following probabilities. Illustrate each on the normal curve shown below each part.
a. ) The probability the sample has a proportion between 0. 5 and 0. 7
b. ) The probability the sample has a proportion within 5% of the population proportion
c. ) The probability that the sample has a proportion less than 0. 50
d. ) The probability that the sample has a proportion greater than 0. 80
The probability that a) the sample has a proportion between 0.5 and 0.7 is 0.780. b) The probability that the sample has a proportion within 5% is 0.819. c) The probability that the sample has a proportion less than 0.50 is 0.001. d) The probability that the sample has a proportion greater than 0.80 is 0.000.
a) To calculate this probability, we first need to standardize the interval (0.5, 0.7) using the formula: z = (p - P) / (σ / √(n))
where p is the sample b, P is the population proportion, σ is the standard deviation of sample proportions, and n is the sample size. Substituting the values, we get:
z1 = (0.5 - 0.62) / (0.8 / √(40)) = -2.24
z2 = (0.7 - 0.62) / (0.8 / √(40)) = 1.12
Using the standard normal table or calculator, the area between -2.24 and 1.12 is 0.780. Therefore, the probability that the sample has a proportion between 0.5 and 0.7 is 0.780.
b) The probability that the sample has a proportion within 5% of the population proportion is 0.819. We can find the range of sample proportions within 5% of the population proportion by adding and subtracting 5% of the population proportion from it, which gives: P ± 0.05P = 0.62 ± 0.031
The interval (0.589, 0.651) represents the range of sample proportions within 5% of the population proportion. To calculate the probability that the sample proportion falls within this interval, we standardize it using the formula above and find the area under the standard normal curve between -1.55 and 1.55, which is 0.819.
c) The probability that the sample has a proportion less than 0.50 is 0.001. To calculate this probability, we standardize the value of 0.50 using the formula above and find the area to the left of the resulting z-score, which is: z = (0.50 - 0.62) / (0.8 / √(40)) = -4.46
Using the standard normal table or calculator, the area to the left of -4.46 is 0.001. Therefore, the probability that the sample has a proportion less than 0.50 is 0.001.
d) The probability that the sample has a proportion greater than 0.80 is 0.000. To calculate this probability, we standardize the value of 0.80 using the formula above and find the area to the right of the resulting z-score, which is: z = (0.80 - 0.62) / (0.8 / √(40)) = 5.60
Using the standard normal table or calculator, the area to the right of 5.60 is very close to 0.000. Therefore, the probability that the sample has a proportion greater than 0.80 is 0.000.
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Find the slope of the curve y = x^3 -10x at the given point P(2, -12) by finding the limiting value of the slope of the secants through P. (b) Find an equation of the tangent line to the curve at P(2, - 12). (a) The slope of the curve at P(2, -12) is
The equation of the tangent line to the curve at P(2, -12) is y = 2x - 16.
(a) To find the slope of the curve y = x^3 - 10x at the given point P(2, -12), we need to find the derivative of the function y with respect to x, and then evaluate it at x = 2.
Step 1: Find the derivative, dy/dx
y = x^3 - 10x
dy/dx = 3x^2 - 10
Step 2: Evaluate the derivative at x = 2
dy/dx (2) = 3(2)^2 - 10 = 12 - 10 = 2
The slope of the curve at P(2, -12) is 2.
(b) To find an equation of the tangent line to the curve at P(2, -12), we'll use the point-slope form of the equation: y - y1 = m(x - x1).
Step 1: Use the slope found in part (a) and the given point P(2, -12).
m = 2
x1 = 2
y1 = -12
Step 2: Plug the values into the point-slope equation.
y - (-12) = 2(x - 2)
y + 12 = 2x - 4
Step 3: Rearrange the equation to get the final form.
y = 2x - 4 - 12
y = 2x - 16
The equation of the tangent line to the curve at P(2, -12) is y = 2x - 16.
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why is 101 not in the sequence of 3n-2
101 is not in the sequence of 3n-2 because it cannot be obtained by multiplying a positive integer n by 3 and subtracting 2 from the product.
The sequence 3n-2 is a set of numbers obtained by taking a positive integer n, multiplying it by 3 and then subtracting 2 from the product. For example, if n = 1, then 3n-2 = 1. If n = 2, then 3n-2 = 4. If n = 3, then 3n-2 = 7, and so on.
Now, you may wonder why the number 101 is not in the sequence of 3n-2. To understand this, we need to determine whether there exists a positive integer n such that 3n-2 is equal to 101.
Let's start by assuming that such an n exists. Then we can write:
3n-2 = 101
Adding 2 to both sides, we get:
3n = 103
Dividing both sides by 3, we get:
n = 103/3
This means that n is not a whole number, which contradicts our assumption that n is a positive integer. Therefore, there cannot exist any positive integer n such that 3n-2 equals 101.
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Question number 5. What is the relation called
Answer:
This relation is a function.
Algebraically, this function is written as
y = 5x.
Use the information given to answer the question.
The save percentage for a hockey goalie is determined by dividing the number of shots
the goalie saves by the total number of shots attempted on the goal.
Part B
During the same season, a backup goalie saves t shots and has a save percentage of
0.560. If the total number of shots attempted on the goal is 75, exactly how many shots
does the backup goalie save?
14 shots
21 shots
37 shots
42 shots
the backup goalie saved 42 shots. Answer: 42 shots. We can start by setting up an equation using the information given
what is equation ?
An equation is a mathematical statement that asserts that two expressions are equal. It is typically written with an equal sign (=) between the two expressions. For example, the equation 2x + 3 = 7 is a statement that asserts that the expression 2x + 3 is equal to 7.
In the given question,
We can start by setting up an equation using the information given:
save percentage = (number of shots saved / total number of shots attempted)
For the backup goalie, we know that their save percentage is 0.560, and we also know the total number of shots attempted on the goal is 75. Let's let the number of shots saved by the backup goalie be represented by the variable "t". Then we can write:
0.560 = t / 75
To solve for t, we can cross-multiply:
0.560 * 75 = t
t = 42
Therefore, the backup goalie saved 42 shots. Answer: 42 shots.
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Find the equation of the tangent line to the curve (a lemniscate) 2(x^2+y^2) = 25 (z^2-y^2) at the point (-3, -1)
The equation of the tangent line to the lemniscuses 2(x²+y²) = 25 (z²-y²) at the point (-3, -1) is y = (16/25)x + 23/25.
To find the equation of the tangent line to a curve, we need to take the derivative of the equation of the curve and evaluate it at the given point.
First, let's rewrite the equation of the lemniscate in terms of x and y:
2(x² + y²) = 25(z² - y²)
Dividing both sides by 25, we get:
(x² + y²) / (25/2) = (z² - y²) / 12.5
Now, we can take the partial derivatives with respect to x and y:
∂/∂x [(x² + y²) / (25/2)] = (2x) / (25/2) = (4x) / 25
∂/∂y [(x² + y²) / (25/2)] = (2y) / (25/2) = (4y) / 25
Next, we need to find the value of z at the point (-3, -1). To do this, we can substitute x = -3 and y = -1 into the equation of the lemniscate:
2((-3)² + (-1)²) = 25(z² - (-1)²)
20 = 25(z² + 1)
z^2 = 19/25
z = ±sqrt(19)/5
Since we want the tangent line at the point (-3, -1), we'll use z = -sqrt(19)/5.
Now, we can evaluate the partial derivatives at (-3, -1, -sqrt(19)/5):
(4(-3)) / 25 = -12/25
(4(-1)) / 25 = -4/25
So, the slope of the tangent line is:
m = ∂z/∂x × -12/25 + ∂z/∂y × -4/25
m = (2x / (25/2)) × (-12/25) + (2y / (25/2)) × (-4/25)
m = -24x/125 - 8y/125
m = -24(-3)/125 - 8(-1)/125
m = 72/125 + 8/125
m = 80/125
m = 16/25
Finally, we can use the point-slope form of a line to find the equation of the tangent line:
y - (-1) = (16/25)(x - (-3))
y + 1 = (16/25)(x + 3)
y = (16/25)x + 48/25 - 25/25
y = (16/25)x + 23/25
So the equation of the tangent line to the lemniscuses 2(x²+y²) = 25 (z²-y²) at the point (-3, -1) is y = (16/25)x + 23/25.
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everyone pls answer the questions I posted they are urgent
Answer:
unfortunately there's no questions to be answered
(PLEASE HELP + POINTS)
Select the correct graph.
Smith's Produce sells packages of pre-cut vegetables. The company has a tolerance level of less than or equal to y grams for a 250-gram
package. Which graph could be used to determine the variance levels that would result in a package of vegetables being rejected because of
its weight, X?
(Picture of graphs)
The answer of the given question based on the graph could be used to determine the variance levels that would result in a package of vegetables is histogram.
To determine the variance levels that would result in a package of vegetables being rejected because of its weight, X, consider the following:
1. The company has a tolerance level of less than or equal to y grams for a 250-gram package. This means that the graph must represent a relationship between the weight of the package (X) and the tolerance level (y).
2. Since the package is rejected if it weighs more than the allowed tolerance, the graph should show that as the weight (X) increases, the acceptance range decreases (y decreases).
3. The graph should ideally have a boundary line that represents the maximum tolerance level (y). Any points above this line would represent rejected packages.
Based on these criteria, you should select the graph that best represents this relationship between the weight of the package (X) and the tolerance level (y), where packages with a weight exceeding the tolerance level are rejected.
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Don buys a car valued at $23,000. When the car was new, it sold for $30,000. If the car depreciates exponentially at a rate of 6% per year, about how old is the car?
Answer:
Around 3 years
Step-by-step explanation:
6% of 30000 is 1800. I subtracted 1800 from 30000 until it got down too 24000 so im assuming that's how old
Unit 7: Right Triangles & Trigonometry Homework 4: Trigonometry Ratios & Finding Missing Sides #’s 10&11
The value of the sides are;
x = 20.4
x = 13.84
How to determine the valueThere are six different trigonometric identities. They include;
sinetangentcosinecosecantsecantcotangentGiven that the ratios are;
sin θ = opposite/hypotenuse
cos θ = adjacent/hypotenuse
tan θ = opposite/adjacent
Using the tangent identity, we have;
tan 64 = 42/x
cross multiply the values
x = 42/2. 050
x = 20. 4
Using the sine identity;
sin 70 = 13/x
cross multiply the values
x = 13/0. 939
x = 13. 84
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Write an equation for the circle graphed below.
-4
-2
6
4
2
-2
-4
-6
2
Answer:
[tex]\left(x\:+\:1\right)^2\:+\:y^2=25[/tex]
Step-by-step explanation:
The equation of a circle with radius r and center at (a, b) is given by
(x - a)² + (y - b)² = r²
Let's first find the radius
The circle intersects the x axis at two points (-6, 0) and (4, 0)
The diameter is therefore the absolute difference between the x values:
|-6 - 4| same as |4 - (-6)| = 10
The radius r = 5 (half of diameter)
Now, let's find the center point of the circle. This will lie midway between (-6, 0) and (4, 0)
Midpoint (xm, ym) between two points(x1, y) and (x2, y2) :
xm = (x1 + x2)/2 = (-6 + 4)/2 = -1
ym = (y1 + y2)/2 = (0 + 0)/2 = 0
So the center (a, b) = (-1, 0) with a = -1, b = 0
The equation of the circle therefore is
(x - a)² + (y - b)² = r²
( x - (-1) )² + (y - 0)² = 25
(x + 1)² + y² = 25
To find a and b take any point (x, y) and plug these
Assume that a cell is a sphere with radius 10-3 or 0.001 centimeter, and that a cell’s density is 1.1 grams per cubic centimeter. koalas weigh 6 kilograms on average. how many cells are in the average koala? hippos weigh 1,400 kilograms on average. how many cells are in the average hippo? solution
There would be 1.302 x 10¹² cells in koala, and there are 3.04 x 10^17 cells in the average hippo.
To find the number of cells in the average koala, we first need to find the volume of the koala in cubic centimeters, since we know the density of the cell and can use that to find the mass of the koala in grams.
The average weight of a koala is 6 kilograms, which is equivalent to 6,000 grams. We can use the density of the cell to find the volume of the koala:
Density = Mass / Volume
1.1 g/cm³ = 6,000 g / Volume
Volume = 6,000 g / 1.1 g/cm³
Volume = 5,454.54 cm³
Next, we need to find the volume of one cell:
Volume of cell = 4/3 * π * (0.001 cm)³
Volume of cell = 4.188 x 10⁻⁹ cm³
Finally, we can divide the volume of the koala by the volume of one cell to find the number of cells in the average koala:
Number of cells = 5,454.54 cm³ / (4.188 x 10⁻⁹ cm³)
Number of cells = 1.302 x 10¹²
Therefore, there are approximately 1.302 x 10¹² cells in the average koala.
To find the number of cells in the average hippo, we can follow the same process. The average weight of a hippo is 1,400 kilograms, which is equivalent to 1,400,000 grams. Using the density of the cell, we can find the volume of the hippo:
Density = Mass / Volume
1.1 g/cm^3 = 1,400,000 g / Volume
Volume = 1,400,000 g / 1.1 g/cm³
Volume = 1,272,727.27 cm³
Dividing the volume of the hippo by the volume of one cell, we get:
Number of cells = 1,272,727.27 cm³ / (4.188 x 10⁻⁹ cm³)
Number of cells = 3.04 x 10¹⁷
Therefore, there are approximately 3.04 x 10¹⁷ cells in the average hippo.
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What is the equation for fahrenheit to celcius
Answer:
I believe it is
F = (9/5 x °C) + 32
Lizzie came up with a divisibility test for a certain number m ≠ 1 : Break a positive integer n into two-digit chunks, starting from the ones place. (For example, the number 354764 would break into the two-digit chunks 35, 47, and 64 ) Find the alternating sum of these two-digit numbers, by adding the first number, subtracting the second, adding the third, and so on. (In our example, this alternating sum would be 35-47+64 = 52 ) Find m and show that this is indeed a divisibility test for n (by showing that n is divisible by m if and only if the result of this process is divisible by m)
If and only if the alternating sum of the two-digit chunks of a number n is divisible by m, then n is divisible by m.
What value of m makes the alternating sum of two-digit chunks of a positive integer n divisible by m?Let's denote the two-digit chunks of n as a₁a₂, a₃a₄, ..., where a₁, a₂, a₃, a₄, ... are the digits from the ones place onward.
The alternating sum of these two-digit numbers is given by a₁a₂ - a₃a₄ + a₅a₆ - a₇a₈ + ...
We can rewrite n as (a₁a₂ × 100) + (a₃a₄ × 10) + (a₅a₆ × 1) + ...
The alternating sum expression can be written as (a₁a₂ × 100) - (a₃a₄ × 10) + (a₅a₆ × 1) - ...
If n is divisible by m, we have n ≡ 0 (mod m).
Rewriting n in terms of the alternating sum, we get (a₁a₂ × 100) - (a₃a₄ × 10) + (a₅a₆ × 1) - ... ≡ 0 (mod m).
Factoring out each two-digit chunk, we have (a₁a₂ - a₃a₄ + a₅a₆ - ...) ≡ 0 (mod m).
This implies that n is divisible by m if and only if the result of the alternating sum process is divisible by m.
m is the value that makes the alternating sum of the two-digit chunks of n a divisibility test for n.
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Let ⋆ be the binary operation on z (set of integers) defined by
a ⋆ b = 2ab + 5
show that ⋆ is commutative. hint: show that a ⋆ b = b ⋆ a
solution:
show that ⋆ is associative. hint: show that (a ⋆ b) ⋆ c = a ⋆ (b ⋆ c)
solution:
a. let ⋆ be the binary operation on z (set of integers) defined by
a ⋆ b = a + b + ab
1. show that ⋆ is commutative. hint: show that a ⋆ b = b ⋆ a
solution:
2.show that ⋆ is associative. hint: show that (a ⋆ b) ⋆ c = a ⋆ (b ⋆ c)
solution:
Since the expression is the same, we can conclude that the binary operation ⋆ is associative.
To show that the binary operation ⋆ is commutative, we need to demonstrate that a ⋆ b is equal to b ⋆ a for any integers a and b.
Let's start by evaluating a ⋆ b:
a ⋆ b = 2ab + 5.
Now let's evaluate b ⋆ a:
b ⋆ a = 2ba + 5.
By comparing the expressions for a ⋆ b and b ⋆ a, we can see that they are indeed equal:
2ab + 5 = 2ba + 5.
Since the expression is the same, we can conclude that the binary operation ⋆ is commutative.
To show that the binary operation ⋆ is associative, we need to demonstrate that (a ⋆ b) ⋆ c is equal to a ⋆ (b ⋆ c) for any integers a, b, and c.
Let's evaluate (a ⋆ b) ⋆ c:
(a ⋆ b) ⋆ c = (2ab + 5) ⋆ c = 2(2ab + 5)c + 5 = 4abc + 10c + 5.
Now let's evaluate a ⋆ (b ⋆ c):
a ⋆ (b ⋆ c) = a ⋆ (2bc + 5) = 2a(2bc + 5) + 5 = 4abc + 10a + 5.
By comparing the expressions for (a ⋆ b) ⋆ c and a ⋆ (b ⋆ c), we can see that they are indeed equal:
4abc + 10c + 5 = 4abc + 10a + 5.
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Where should one start to learn maths if they're really bad at it
Consistent practice is key to improving your math skills over time.
How to learn math if you feel like you're really bad at it?If you feel like you're really bad at math, it's important to start with the basics. This might mean reviewing concepts like arithmetic, fractions, decimals, and percentages. You can find resources online or in books that can help you with this. Once you have a solid foundation, try to identify your strengths and weaknesses so you can focus your efforts on the areas where you need the most improvement. Find a learning style that works best for you, whether it's working independently, with a tutor, or in a study group. Finally, remember that consistent practice is key to improving your math skills over time. Don't give up, and don't be afraid to ask for help when you need it.
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Josie is trying to justify the area formula for a circle with circumference C and radius r. To start, she cut a circle into 8 congruent sectors. Then, she put the sectors together to make this figure. She noticed that the figure is approximately the shape of a parallelogram. Select all of the statements that could help Josie to justify the area formula for a circle.
The base of the parallelogram is approximately equal to the circumference of the circle.
How can Josie justify the area formula for a circle using the figure made from congruent sectors?The following statements could help Josie justify the area formula for a circle:
The figure formed by putting the congruent sectors together approximates the shape of a parallelogram The opposite sides of a parallelogram are parallel.The base of the parallelogram corresponds to the circumference of the circle, denoted as C.The height of the parallelogram corresponds to the radius of the circle, denoted as r.The area of a parallelogram can be calculated by multiplying the base by the height.By considering that the base of the parallelogram is the circumference (C) and the height is the radius (r), the area of the parallelogram represents the area of the circle.Therefore, the area of the circle can be calculated using the formula A = C × r, or in terms of the radius, A = πr².
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Paula works part time ABC Nursery. She makes $5 per hour watering plants and $10 per hour sweeping the nursery. Paula is a full-time student so she cannot work more than 12 hours each week but must make at least $60 per week.
Part A: Write the system of inequalities that models this scenario.
Part B: Describe the graph of the system of inequalities, including shading and the types of lines graphed. Provide a description of the solution set.
The system of inequalities that models this scenario are:
x + y ≤ 12 (she is unable to work more than 12 hours each week)5x + 10y ≥ 60 (she need to make at least $60 per week)What is the system of inequalities?Part A: Based on the question, we take x be the number of hours that Paula spends watering plants and also we take y be the number of hours she spends sweeping the nursery. Hence system of inequalities equation will be:
x + y ≤ 12 (she is unable to work more than 12 hours each week)
5x + 10y ≥ 60 (she need to make about $60 per week)
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Solve problems 1 and 4 ONLY with the rules given on the paper.
The solution to the equations obtained using inverse trigonometric function values are;
1. x ≈ 0.65
4. x ≈ 0.95
What are trigonometric functions?Trigonometric functions indicates the relationships between the angles in a right triangle and two of the sides of the triangle. Trigonometric functions are periodic functions.
The value of x is obtained from the inverse trigonometric function of the output value of the trigonometric function, as follows;
The inverse function for sine is arcsine
The inverse function for cosine is arccosine
The inverse function for the tangent of an angle is arctangent
1. sin(x) = 0.6051
Therefore; x = arcsine(0.6051) ≈ 0.65 radians
The value of x in the interval [0·π, 2·π] is x ≈ 0.65
4. tan(x) = 1.3972
Therefore, x = arctan(1.3972) ≈ 0.95
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(1 point) Use the Integral Test to determine whether the infinite series is convergent. 00 n2 n=12 (n3 + 3) Fill in the corresponding integrand and the value of the improper integral. Enter inf for oo, -inf for -00, and DNE if the limit does not exist. Compare with dx = 00 By the Integral Test, 722 the infinite series n 12 (73+3) A. converges B. diverges
To use the Integral Test, we need to find an integral that is comparable to the series. We can do this by using a basic comparison test and comparing it to the p-series with p=2.
n^2 / (n^3 + 3) < n^2 / n^3 = 1/n
The series 1/n is a divergent p-series with p=1, so we can conclude that the original series is also divergent.
To find the corresponding integral, we can integrate the function 1/n^2:
∫(n=1 to ∞) 1/n^2 dn = [-1/n] (n=1 to ∞) = 1/1 - 0 = 1
Since the improper integral converges to 1, we can conclude that the infinite series is divergent by the Integral Test.
Hi there! To use the Integral Test to determine whether the given infinite series is convergent, first rewrite the series as a function:
f(x) = x^2 / (x^3 + 3)
Next, we need to check that the function is continuous, positive, and decreasing on the interval [1, ∞). This function satisfies these conditions.
Now, we will calculate the improper integral:
∫(from 1 to ∞) (x^2 / (x^3 + 3)) dx
Let's use substitution: u = x^3 + 3, so du = 3x^2 dx, and x^2 dx = (1/3)du.
Now, the integral becomes:
(1/3) ∫(from 1 to ∞) (1/u) du
This integral is the same as the integral of 1/u from 1 to ∞, which is a well-known improper integral that diverges (ln(u) evaluated from 1 to ∞ results in ∞).
Therefore, by the Integral Test, the infinite series ∑(from n=1 to ∞) (n^2 / (n^3 + 3)) diverges. So the correct answer is B. Diverges.
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Evaluate the integral ∫8(1-tan²(x)/sec² dx Note Use an upper-case "C" for the constant of integration
The integral ∫8(1-tan²(x)/sec² dx Note Use an upper-case "C" for the constant of integration is ∫8(1-tan²(x)/sec²(x)) dx = 8 tan(x) + C where C is the constant of integration.
To evaluate the integral ∫8(1-tan²(x)/sec²(x)) dx, we need to use trigonometric identities to simplify the integrand.
First, we use the identity tan²(x) + 1 = sec²(x) to rewrite the integrand as follows:
8(1 - tan²(x)/sec²(x)) = 8(sec²(x)/sec²(x) - tan²(x)/sec²(x))
Simplifying this expression by canceling out the common factor of sec²(x), we get:
8(sec²(x) - tan²(x))/sec²(x)
Next, we use the identity sec²(x) = 1 + tan²(x) to simplify the expression further:
8(sec²(x) - tan²(x))/sec²(x) = 8((1 + tan²(x)) - tan²(x))/sec²(x)
Simplifying the expression inside the parentheses, we obtain:
8/ sec²(x)
Therefore, the integral simplifies to:
∫8(1-tan²(x)/sec²(x)) dx = ∫8/ sec²(x) dx
We can now use the substitution u = cos(x) and du/dx = -sin(x) dx to transform the integral into a simpler form:
∫8/ sec²(x) dx = ∫8/cos²(x) dx = 8∫cos(x)² dx
Using the power-reducing formula cos²(x) = (1 + cos(2x))/2, we get:
8∫cos(x)² dx = 8/2 ∫(1 + cos(2x))/2 dx = 4(x + 1/2 sin(2x)) + C
Substituting back u = cos(x), we obtain:
∫8(1-tan²(x)/sec²(x)) dx = 8 tan(x) + C
where C is the constant of integration.
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La suma de dos números es 15 y la suma de sus cuadrados es 113. ¿Cuáles son los números?
La suma de dos números es 15 y la suma de sus cuadrados es 113. Por lo tanto, los dos números son 7 y 8.
Para resolver este problema, podemos utilizar el método de sustitución. Si llamamos a los dos números "x" e "y", podemos plantear dos ecuaciones con la información que nos dan:
x + y = 15 (ecuación 1)
x² + y² = 113 (ecuación 2)
De la primera ecuación, podemos despejar a "y" para obtener:
y = 15 - x
Ahora, podemos sustituir este valor de "y" en la segunda ecuación:
x² + (15 - x)² = 113
Expandiendo y simplificando:
x² + 225 - 30x + x² = 113
2x^2 - 30x + 112 = 0
Esta es una ecuación cuadrática que podemos resolver utilizando la fórmula general:
x = (-b ± sqrt(b² - 4ac)) / 2a
Donde:
a = 2
b = -30
c = 112
Sustituyendo:
x = (-(-30) ± sqrt((-30)² - 4(2)(112))) / 2(2)
x = (30 ± sqrt(900 - 896)) / 4
x = (30 ± 2) / 4
Esto nos da dos posibles valores para "x":
x₁ = 8
x₂ = 7
Para encontrar los valores correspondientes de "y", podemos utilizar la ecuación que obtuvimos antes:
y = 15 - x
Así que:
y₁ = 15 - 8 = 7
y₂ = 15 - 7 = 8
Por lo tanto, los dos números son 7 y 8.
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As runners in a marathon go by, volunteers hand them small cone shaped cups of water. The cups have the dimensions shown. Abigail sloshes 2/3 of the water out of her cup before she gets a chance to drink any. What is the volume of water remaining in Abigail’s cup?
The volume of water remaining in Abigail’s cup can be found to be 25. 14 cm³ .
How to find the volume left ?First, find the volume of water in the cup when it is full. This would be the volume of the cup which is the formula of the volume of a cone :
Volume = ( 1 / 3 ) × π × r² × h
Volume = ( 1 / 3 ) × π × ( 3 cm )² × ( 8 cm )
Volume = 24π cm³
If Abigail too 2 / 3 to slosh on her face, the amount of water left would be :
= 24π cm³ - ( 1 - 2 / 3 )
= 24π cm³ - 1 / 3
= 8π cm³
= 25. 14 cm³
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Review Questions
1. A washer and a dryer cost $1004 combined. The washer costs $54 more than the dryer. What is the cost of the dryer?
Please use your work.
The calculated cost of the dryer is $475.
What is the cost of the dryer?Let's assume that the cost of the dryer is x dollars.
According to the problem, the cost of the washer is $54 more than the dryer.
Therefore, the cost of the washer is (x + $54).
We are given that the combined cost of the washer and the dryer is $1004. So we can set up the equation:
x + (x + $54) = $1004
Simplifying the equation:
2x + $54 = $1004
2x = $950
x = $475
Therefore, the cost of the dryer is $475.
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Marcus is responsible for maintaining the swimming pool in his community. He adds chemicals, when needed, to lower the pH of the pool.
-The maximum pH value allowed for the pool is 7. 8.
-The pool currently has a pH value of 6. 9.
-The pH value of the pool increases by 0. 05 per hour.
Write an inequality that can be used to determine x, the number of hours before Marcus will need to add chemicals to maintain the pH for the pool
An inequality that can be used to determine x, the number of hours before Marcus will need to add chemicals to maintain the pH for the pool would be 6.9 + 0.05x ≤ 7.8
To determine the number of hours (x) before Marcus will need to add chemicals to maintain the pool's pH, we can use an inequality with the given information.
-The maximum pH value allowed for the pool is 7.8.
-The pool currently has a pH value of 6.9.
-The pH value of the pool increases by 0.05 per hour.
The inequality for this scenario would be:
6.9 + 0.05x ≤ 7.8
This inequality states that the current pH value (6.9) plus the increase in pH per hour (0.05x) should be less than or equal to the maximum allowed pH value (7.8). This will help us determine the number of hours (x) before Marcus needs to add chemicals to maintain the pH for the pool.
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