Please help!! Correct answer gets brainliest!!

The problem states that Bert split all his cookies evenly among 4 contestants, so the total number of cookies Bert had can be found by multiplying the number of cookies each contestant received by the number of contestants:

4 * 24 = 96

Therefore, Bert had a total of 96 cookies to start with.

We can also write an equation to represent the problem, where c represents the number of cookies Bert had to start with:

c / 4 = 24

This equation states that the number of cookies Bert had divided by the number of contestants (4) is equal to the number of cookies each contestant received (24).

To solve for c, we can multiply both sides of the equation by 4:

c = 4 * 24

c = 96

So the solution confirms that Bert had 96 cookies to start with.

Answer:

2^6 = 64

Step-by-step explanation:

2^6 = 2⁶ = 2*2*2*2*2*2

= 64

After answering the presented question, we can conclude that As a range result, the class breadth in this frequency distribution table is one.

The variable's range is calculated by taking its maximum observed value and subtracting its minimum observed value (minimum). Possible range or variational bounds: a variety of steel costs; a variety of styles; The scope or magnitude of a method or action: perception. The maximum or anticipated range of a weapon's projectile. A list or set's range is the number between the lowest and maximum. Align all of the numbers before identifying the region. Next, subtract (reduce) the lowest number from the highest number. The solution includes the range of the list. The solution specifies the range of the list.

To calculate the class width, we must first determine the range of values within each class interval.

The class intervals are as follows:

[tex]0-1\s2-3\s4-5\s6-7[/tex]

8-9

0-1 interval range: 1-0 = 1

2-3 interval range: 3-2 = 1

5-4 = 1 interval range of 4-5

7-6 = 1 interval range of 6-7

8-9 interval range: 9-8 = 1

The intervals all have the same range of one.

To calculate the class width, subtract the upper limit of the first interval from the lower limit of the first interval.

Higher limit of first interval - Lower limit of first interval = class width

1 - 0 class width

1 class width

As a result, the class breadth in this frequency distribution table is one.

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Answer:

--------------------------

Find the scale factor by dividing the corresponding sides of the given figures:

The area is the product of two dimensions therefore the ratio of areas of similar figures is the square of the scale factor. Let the area of the smaller figure be A, then we got the ratio:

Answer: 18 in²

Step-by-step explanation:

Answer:

Your answer is 4cm.

Step-by-step explanation:

simple calculation

x (12+x) π = 32 π

x = 4cm

Therefore, the probability of randomly arranging the digits 3, 4, 5, 6, and 7 to form a three-digit number that is even and greater than 700 is 0.1.

Probability refers to the likelihood or chance that a particular event or outcome will occur. It is a mathematical concept that quantifies the degree of uncertainty associated with an event or situation. Probability is typically expressed as a number between 0 and 1, where 0 indicates that an event is impossible, and 1 indicates that it is certain to occur.

by the question.

Therefore, the total number of five card hands that have exactly one ace and no picture cards been 4 * (36 choose 4) = 253,440.

The total number of five card hands is (52 choose 5) = 2,598,960.

Therefore, the probability of being dealt exactly one ace and no picture cards in a five-card poker hand is 253,440 / 2,598,960, which simplifies to 0.097%.

2.There are a total of 5! = 120 possible arrangements of the digits 3, 4, 5, 6, and 7. To form a three-digit number, we need to use three of these digits, so there are 5 x 4 x 3 = 60 possible three-digit numbers we can form.

To be greater than 700, the first digit must be either 6 or 7. If we choose 7 as the first digit, there are 4 x 3 = 12 ways to choose the remaining two digits. If we choose 6 as the first digit, there are 4 x 3 = 12 ways to choose the second and third digits, since we can't repeat digits. Therefore, there are 12 + 12 = 24 three-digit numbers greater than 700.

To be even, the last digit must be either 4 or 6. If we choose 6 as the first digit, there are 2 ways to choose the last digit (either 4 or 6), and 3 ways to choose the middle digit (since we can't repeat digits). This gives us a total of 2 x 3 = 6 even numbers starting with 6.

If we choose 7 as the first digit, there are no even numbers we can form, since the last digit can only be 4 or 6 and we've already used the 6 digit. Therefore, the total number of even three-digit numbers greater than 700 is 6.

So, the probability of randomly selecting an even three-digit number greater than 700 is 6/60 = 1/10 or 0.1.

3.There is a total of C (52, 3) = 22,100 possible ways to choose 3 cards from a deck of 52 cards.

To get one queen and two kings, we need to choose one of the four queens and two of the four kings. There are C(4, 1) ways to choose one queen, and C(4, 2) = 6 ways to choose two kings. Therefore, there are 4 x 6 = 24 ways to choose one queen and two kings.

So, the probability of getting one queen and two kings is 24/22,100 or approximately 0.0011 (rounded to four decimal places).

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Answer:the scale factor of dilation from circle P to Q is 2.5

for among us

Step-by-step explanation:

The similar circles P and Q can be made equal by dilation and translation

The horizontal distance between the center of circles P and Q is 11.70 units

The scale factor of dilation from circle P to Q is 2.5

The horizontal distance between their centers?

From the figure, we have the centers to be:

P = (-5,4)

Q = (6,8)

The distance is then calculated using:

d = √(x2 - x1)^2 + (y2 - y1)^2

So, we have:

d = √(6 + 5)^2 + (8 - 4)^2

Evaluate the sum

d = √137

Evaluate the root

d = 11.70

Hence, the horizontal distance between the center of circles P and Q is 11.70 units

The scale factor of dilation from circle P to Q

We have their radius to be:

P = 2

Q = 5

Divide the radius of Q by P to determine the scale factor (k)

k = Q/P

k = 5/2

k = 2.5

Hence, the scale factor of dilation from circle P to Q is 2.5

Thus, the solution set of the given absolute value inequalities is found as: 0 ≥ x ≥ -1

The comparison of the connection here between variable and its value is a compound inequality. In a compound inequality, a variable is compared across two ranges which may provide the variable's range by satisfying either one or both of the limitations .

The given absolute value inequalities :

|(x+1)/2 - x/2| < 1/2

Removing the modulus sign will for 2 equations:

(x+1)/2 - x/2 < 1/2  and  (x+1)/2 - x/2 < - 1/2

Simplifying each:

(x+1)/2 - x/2 < 1/2  

x/2 + 1/2 - x/2 < 1/2

Both values will get cancelled:

0 < 0

But 0 = 0

and  (x+1)/2 - x/2 > - 1/2

x/2 + 1/2 - x/2 > -1/2

0 > -1 (correct)

here also the terms are getting completely cancelled to

Thus, the solution set of the given absolute value inequalities is found as: 0 ≥ x ≥ -1

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Complete question:

Find the set of the solutions of the following absolute value inequalities.

|(x+1)/2 - x/2| < 1/2

The given expression [tex]g^2/3h[/tex] is equivalent to the option (c) [tex]8g^2/24h[/tex]as we have multiplied 8 in both numerator and denominator.

The given expression is [tex]g^2/3h[/tex].

Now, to further simplify the expression, we can multiply both numerator and denominator by 8. This gives us:

[tex](g^2/3h) * (8/8)[/tex]

Simplifying further, we get:

[tex](8g^2)/(24h)[/tex]

Therefore, the expression equivalent to [tex]g^2/3h[/tex] is [tex](8g^2)/(24h)[/tex].

Thus, the given expression [tex]g^2/3h[/tex] is equivalent to the option (c) [tex]8g^2/24h[/tex] as we have multiplied 8 in both numerator and denominator.

The numerator is the top part of a fraction, which represents the number of equal parts being considered. It is the value that is above the fraction bar and represents the quantity being divided into equal parts.

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The complete question is :

Which expression is equivalent to [tex]g^2/3h[/tex]?

Click on the correct answer.

(A) [tex]g^2+5/3h+5[/tex]

(B) [tex]6g^2/15h[/tex]

(C) [tex]8g^2/24h[/tex]

A water bottle

Step-by-step explanation:

It's a water bottle because you cannot measure volume with a dollr bill or postage stamp.

Using graphing technology, we have came to know that the range οf the given functiοn is f(x )≤ 7.

The set οf all resulting values οf a functiοn is called the range οf a functiοn.

Fοr example if the functiοn is f(x)= 2x.

Fοr the given set οf values x={ 1,2,3 and sο οn} the range will be {2,4,6 and sο οn}

Given functiοn is f(x)= -|x|+7

The range οf an absοlute function οf the fοrm -c| [tex]ax+b[/tex]| is f(x) ≤ k

here k=7

sο the range will be f(x) ≤ 7

Hence range οf the given functiοn  will be f(x) ≤ 7.

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we can estimate the cost of a $50 textbook in 8 years to be approximately $32.78.

What is logarithms?

Logarithms are mathematical functions that are used to solve equations involving exponents. Specifically, a logarithm is the inverse operation of exponentiation. Just as exponentiation involves raising a base to a power, logarithms involve finding the power to which a base must be raised to produce a given value.

The logarithm of a number y with respect to a base b is written as logb y, and it is defined as the exponent to which the base b must be raised to produce the number y. In other words, if [tex]b^x = y[/tex], then logb y = x.

According to the question:
In Exercise 36(a), we found that the value of a dollar decreases by 26% over 5 years. We can use this information to answer the following questions:

(a) To estimate the cost of the same house in 10 years, we need to solve the equation:

0.74t = 105,000

where t is the time in years. Solving for t, we get:

[tex]t = log(105,000) / log(0.74) = 17.9[/tex]

So it will take approximately 17.9 years for the value of the dollar to decrease by 26% enough to make the $105,000 house cost the same as it does today. Therefore, we can estimate the cost of the same house in 10 years to be:

[tex]$105,000 * (1 / 0.74)^(10/17.9) = $211,775.22[/tex]

(b) To estimate the cost of a $50 textbook in 8 years, we need to find the value of k in the exponential function:

[tex]V(t) = V(0) * e^kt[/tex]

where V(0) is the initial value (in this case, $50), t is the time in years, and V(t) is the value after t years. We know that the value of a dollar decreases by 26% over 5 years, so we can use this information to find k:

[tex]0.74 = e^(k*5)[/tex]

Taking the natural logarithm of both sides, we get:

ln(0.74) = 5k

Solving for k, we get:

k ≈ -0.064

So the exponential function for the value of a dollar over time is:

[tex]V(t) = $50 * e^{-0.064t}[/tex]

To estimate the cost of the textbook in 8 years, we can plug in t = 8 into this function and solve:

[tex]V(8) = $50 * e^{-0.064*8} = $32.78[/tex]

Therefore, we can estimate the cost of a $50 textbook in 8 years to be approximately $32.78.


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let's keep in mind that arc's get their angle value from the central angle they cover, so in this case whatever angle value the arcAFB has, will also be the same for the ∡AFB.

Check the picture below.

The recursive relationship that describes how the number of Marco's followers is changing each day is Pt = Pt-1 + 32.

It should be noted that after 5 days, Marco will have 597 followers.

The relationship is Pt = Pt-1 + 32 where Pt is the number of followers on day t and Pt-1 is the number of followers on the previous day.

In this case, to calculate how many followers Marco will have after 5 days, we can use this recursive relationship starting with P0 = 437 (the initial number of followers):

P1 = P0 + 32 = 437 + 32 = 469

P2 = P1 + 32 = 469 + 32 = 501

P3 = P2 + 32 = 501 + 32 = 533

P4 = P3 + 32 = 533 + 32 = 565

P5 = P4 + 32 = 565 + 32 = 597

Therefore, after 5 days, Marco will have 597 followers.

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To find the length and width of each room on the blueprint, we need to use the given scale of 1 in. : 4 ft. This means that every 1 inch on the blueprint represents 4 feet in the actual house.

To find the length and width of each room on the blueprint, we can multiply the actual length and width of each room by 1/4 (or divide by 4). This gives us:

Living room: Length = 12 ft. ÷ 4 = 3 in., Width = 8 ft. ÷ 4 = 2 in.

Kitchen: Length = 16 ft. ÷ 4 = 4 in., Width = 16 ft. ÷ 4 = 4 in.

Office: Length = 16 ft. ÷ 4 = 4 in., Width = 8 ft. ÷ 4 = 2 in.

Bedroom: Length = 20 ft. ÷ 4 = 5 in., Width = 20 ft. ÷ 4 = 5 in.

Bedroom: Length = 10 ft. ÷ 4 = 2.5 in., Width = 20 ft. ÷ 4 = 5 in.

Bathroom: Length = 16 ft. ÷ 4 = 4 in., Width = 8 ft. ÷ 4 = 2 in.

Therefore, the length and width of each room on the blueprint are:

Living room: 3 in. x 2 in.

Kitchen: 4 in. x 4 in.

Office: 4 in. x 2 in.

Bedroom: 5 in. x 5 in.

Bedroom: 2.5 in. x 5 in.

Bathroom: 4 in. x 2 in.

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a) The unit rate for cups of milk per muffin is 1/18 cup of milk per muffin.

b) The unit rate for muffins per cup of milk is 18 muffins per cup of milk.

What are the muffins?

(a) To find the unit rate for cups of milk per muffin, we need to divide the total amount of milk by the number of muffins:

2/3 cup of milk / 12 muffins = (2/3) ÷ 12 cup of milk per muffin

We can simplify this fraction by multiplying the numerator and denominator by 3:

(2/3) ÷ 12 = 2 ÷ (3 x 12) = 2 ÷ 36 = 1/18

So the unit rate for cups of milk per muffin is 1/18 cup of milk per muffin.

b) To find the unit rate for muffins per cup of milk, we need to divide the number of muffins by the total amount of milk:

12 muffins / (2/3 cup of milk) = 12 ÷ (2/3) muffins per cup of milk

To divide by a fraction, we can multiply by its reciprocal:

12 ÷ (2/3) = 12 x (3/2) = 36/2 = 18

So the unit rate for muffins per cup of milk is 18 muffins per cup of milk.

A muffin is a type of small, individual-sized baked good that is usually round in shape and has a slightly sweet taste. Muffins can be made with a variety of ingredients, including flour, sugar, eggs, butter, milk, and baking powder. They can also be flavored with various fruits, nuts, spices, or chocolate chips.

Muffins can be eaten for breakfast, as a snack, or as a dessert. They are often served warm and can be eaten plain or with butter, jam, or honey. Muffins are a popular baked good and are commonly found in coffee shops, bakeries, and grocery stores.

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Complete question is:  Hannah is making muffins. The recipe calls for 2/3 cup of milk to make 12 muffins.

a) The unit rate for cups of milk per muffin is 1/18 cup of milk per muffin.

b) The unit rate for muffins per cup of milk is 18 muffins per cup of milk.

For the given measurements of 5mg, 10kL, 2.5g, 100mm, the base unit is 10kL as per the metric system.

The most widely used measurement unit is a standard unit. As the units used are standardised, everyone can understand an object's size, weight, and perhaps other characteristics.

The Metric System is currently used in the majority of nations. The Imperial Units of Measuring, often known as the US Standard Measurement System, are used in the US.

Given units :

5mg, 10kL, 2.5g, 100mm

In this, standard measurement units or base units if 10 kilo litres or 10 KL.

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By using sum of sequence the value of (3+6+9+...+57) is 570, which is option C).

What is sum of the sequence ?

The sum of a sequence is the total result of adding up all the numbers in the sequence. The method for finding the sum of a sequence depends on whether the sequence is arithmetic or geometric.

For an arithmetic sequence, in which each term is obtained by adding a fixed number (called the common difference) to the previous term, the sum of the first n terms can be found using the formula:

[tex]Sn = n/2(2a + (n-1)d)[/tex]

where a is the first term, d is the common difference, and n is the number of terms.

For a geometric sequence, in which each term is obtained by multiplying the previous term by a fixed number (called the common ratio), the sum of the first n terms can be found using the formula:

[tex]Sn = a(1-r^n) / (1-r)[/tex]

where a is the first term, r is the common ratio, and n is the number of terms.


According to the question:
We can notice that each number in the sequence 3, 6, 9, ..., 57 is 3 times the corresponding number in the sequence 1, 2, 3, ..., 19.

So, we can find the sum of the sequence 3, 6, 9, ..., 57 by finding the sum of the sequence 1, 2, 3, ..., 19 and then multiplying by 3.

The sum of the sequence 1, 2, 3, ..., 19 is:

1 + 2 + 3 + ... + 19 = (19/2)(1 + 19)/2 = 190

Multiplying by 3, we get:

3 + 6 + 9 + ... + 57 = 3(1 + 2 + 3 + ... + 19) = 3(190) = 570

Therefore, the value of (3+6+9+...+57) is 570, which is option C).

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Answer:

The length of XY is 32.

Step-by-step explanation:

3x + 1 = 8x - 24

1 = 5x - 24

5x = 25

x = 5

3(5)+1 = 16

16*2 = 32

The length of XY is 32.

Answer:

x + 4

Step-by-step explanation:

When factored x^2 -16 is (x + 4)(x - 4)

When factored x^2 + 2x - 8 is (x - 2)(x + 4)

The common expression is x + 4

Part A:

The required graph of the function is described.

The vertex of the function is (7,0)

The domain is : (-∝ , ∝) and

The range is : [0,∝), {yIy ≥ 0}

Part B:

The transformation which occurs from f(x) to h(x) is a vertical shift up to 2 units.

Expressions separated by an equal sign are functions. Both dependent and independent variables are present.

Given Part A:

given the function is g(x) = I x - 7 I

hence from the function, vertex = (h,k)

h = 7 and k = 0

(h,k) = (7,0)

Find the domain by finding where the function is defined.

therefore, domain =  (-∝ , ∝) , where {xIx ∈ R}

The range is the set of values that corresponds with the domain.

therefore, range =  [0,∝), {yIy ≥ 0}

Part B:

given the parent function is:  f(x) = |x|

which is transformed to h(x) = |x| + 2

To find the transformation, compare the function to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x axis or y axis, and if there is a vertical stretch.

Parent function = f(x) = |x|

Horizontal shift = none

Vertical shift = up 2 units.

Reflection about the x axis = none

hence from the function we can determine the vertex (h,k)

= (0,2)

Find the domain by finding where the function is defined.

therefore, domain =  (-∝ , ∝) , where {xIx ∈ R}

The range is the set of values that corresponds with the domain.

therefore, range = [2,∝) ,  {yIy ≥ 2}

Hence, we get the required answers.

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Based on the probability distribution, the score that is most likely is 3, since it has the highest probability of 0.48.

Answer:

first box, first box, second box

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

given a quadratic equation in standard form

ax² + bx + c = 0

then

sum of roots = - [tex]\frac{b}{a}[/tex]

product of roots = [tex]\frac{c}{a}[/tex]

2x² + 8x - 14 = 0 ← is in standard form

with a = 2 , b = 8 , c = - 14

sum of roots = - [tex]\frac{b}{a}[/tex] = - [tex]\frac{8}{2}[/tex] = - 4

product of roots = [tex]\frac{c}{a}[/tex] = [tex]\frac{-14}{2}[/tex] = - 7

The journal entries to record the transactions for the year is showed below.

1. Journal Entries:

a. Raw materials purchased on account:

Raw Materials Inventory   $162,000

Accounts Payable              $162,000

b. Raw materials used in production (direct and indirect):

Work in Process Inventory   $128,000

Manufacturing Overhead   $13,000

Raw Materials Inventory    $141,000

c. Costs for employee services (direct labor, indirect labor, sales commissions, administrative salaries):

Work in Process Inventory   $159,000

Manufacturing Overhead   $225,000

Sales Commissions Expense   $28,000

Administrative Salaries Expense   $50,000

d. Rent for the year (factory operations and selling/administrative activities):

Manufacturing Overhead   $13,100

Selling and Administrative Expenses   $5,500

Rent Payable                        $18,600

e. Utility costs incurred in the factory:

Manufacturing Overhead   $20,000

Cash                                          $20,000

f. Advertising costs incurred:

Selling and Administrative Expenses   $15,000

Cash                                          $15,000

g. Depreciation recorded on equipment (factory operations and selling/administrative activities):

Depreciation Expense (Factory)   $13,100

Depreciation Expense (Selling and Administrative)   $4,900

Accumulated Depreciation                      $18,000

2. T-Accounts:

a. Raw Materials Inventory:

Beginning balance: $10,400

Purchases: $162,000

Direct Materials Used: $128,000

Ending balance: ?

b. Work in Process Inventory:

Beginning balance: $4,800

Direct Labor: $159,000

Manufacturing Overhead: ?

Direct Materials Used: $128,000

Ending balance: ?

c. Finished Goods Inventory:

Beginning balance: $8,100

Cost of Goods Manufactured: $217,000

Ending balance: ?

d. Manufacturing Overhead:

Beginning balance: $0

Rent: $13,100

Utilities: $20,000

Depreciation (Factory): $13,100

Applied to Jobs: ?

Ending balance: ?

e. Cost of Goods Sold:

Beginning balance: $0

Cost of Goods Manufactured: $217,000

Ending balance: ?

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1. The transformation of f is a reflection across the y-axis, followed by a shift of 8 units along the y-axis.

2. stretching by a factor of 2 along the y-axis

3. reflection

4. shift

5. reflection

6. stretch

7. stretch

8. reflection

The transformation of a function f represented by g is the process of modifying the function f to create a new function g. This can be done in a number of ways, such as shifting the graph, stretching it, or reflecting it in some way.

1. f(x) = √x, g(x) = √(x+1)+8, the transformation of f is a reflection across the y-axis, followed by a shift of 8 units along the y-axis.

2. f(x) = √x, g(x) = 2√(x - 1), the transformation of f is a stretching by a factor of 2 along the y-axis, followed by a shift by -1 along the x-axis.

3. f(x) = ³√x, g(x) = −³√x-1, the transformation of f is a reflection across the x-axis, followed by a shift of -1 along the x-axis.

4. f(x) = ³√x, g(x) = ³√(x +4)-5, the transformation of f is a shift of 4 units along the x-axis, followed by a shift of -5 units along the y-axis.

5. f(x) = x^½, g(x) =1/4(-x)^½, the transformation of f is a reflection across the y-axis, followed by a stretching by a factor of 1/4 along the y-axis.

6. f(x) = x^⅓, g(x) =1/3x^⅓+6, the transformation of f is a stretching by a factor of 1/3 along the y-axis, followed by a shift of 6 units along the y-axis.

7. f(x)= ⁴√x, g(x) =2 ⁴√(x+5)-4, the transformation of f is a stretching by a factor of 2 along the y-axis, followed by a shift of 5 units along the x-axis, followed by a shift of -4 units along the y-axis.

8. f(x)= ⁵√x, g(x) =⁵√(-32x)+3, the transformation of f is a reflection across the x-axis, followed by a stretching by a factor of 32 along the x-axis, followed by a shift of 3 units along the y-axis.

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19. The transformation of f is a reflection across the y-axis, followed by a shift of 8 units along the y-axis.

20. The transformation of f is a stretching by a factor of 2 along the y-axis

21. The transformation of f is a reflection across the x-axis.

22. The transformation of f is a shift of 4 units along the x-axis, followed by a shift of -5 units along the y-axis.

23. The transformation of f is a reflection across the y-axis.

24. The transformation of f is a stretching by a factor of 1/3 along the y-axis.

25. The transformation of f is a stretching by a factor of 2 along the y-axis.

26. The transformation of f is a reflection across the x-axis, followed by a stretching by a factor of 32 along the x-axis

The transformation of a function f represented by g is the process of modifying the function f to create a new function g. This can be done in a number of ways, such as shifting the graph, stretching it, or reflecting it in some way.

19. f(x) = √x, g(x) = √(x+1)+8, the transformation of f is a reflection across the y-axis, followed by a shift of 8 units along the y-axis.

20. f(x) = √x, g(x) = 2√(x - 1), the transformation of f is a stretching by a factor of 2 along the y-axis, followed by a shift by -1 along the x-axis.

21. f(x) = ³√x, g(x) = −³√x-1, the transformation of f is a reflection across the x-axis, followed by a shift of -1 along the x-axis.

22. f(x) = ³√x, g(x) = ³√(x +4)-5, the transformation of f is a shift of 4 units along the x-axis, followed by a shift of -5 units along the y-axis.

23. f(x) = x½, g(x) =1/4(-x½, the transformation of f is a reflection across the y-axis, followed by a stretching by a factor of 1/4 along the y-axis.

24. f(x) = x⅓, g(x) =1/3x⅓+6, the transformation of f is a stretching by a factor of 1/3 along the y-axis, followed by a shift of 6 units along the y-axis.

25. f(x)= ⁴√x, g(x) =2 ⁴√(x+5)-4, the transformation of f is a stretching by a factor of 2 along the y-axis, followed by a shift of 5 units along the x-axis, followed by a shift of -4 units along the y-axis.

26. f(x)= ⁵√x, g(x) =⁵√(-32x)+3, the transformation of f is a reflection across the x-axis, followed by a stretching by a factor of 32 along the x-axis, followed by a shift of 3 units along the y-axis.

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