Rationalise the denominator of 5/√(3-√5)
Pls send the answer by today​

Answers

Answer 1

Answer:

[tex]\dfrac{5(3+\sqrt{5})\sqrt{3-\sqrt{5}}}{4}[/tex]

[tex]\textsf{or}\quad \dfrac{5\sqrt{3+\sqrt{5}}}{2}[/tex]

Step-by-step explanation:

[tex]\textsf{Given expression}:\dfrac{5}{\sqrt{3-\sqrt{5}}}[/tex]

Method 1

[tex]\textsf{Multiply by the conjugate}\quad \dfrac{\sqrt{3-\sqrt{5}}}{\sqrt{3-\sqrt{5}}}:[/tex]

[tex]\implies \dfrac{5}{\sqrt{3-\sqrt{5}}} \times \dfrac{\sqrt{3-\sqrt{5}}}{\sqrt{3-\sqrt{5}}}=\dfrac{5\sqrt{3-\sqrt{5}}}{(\sqrt{3-\sqrt{5}})(\sqrt{3-\sqrt{5}})}[/tex]

Simplify the denominator using the radical rule [tex]\sqrt{a} \sqrt{a} =a[/tex]:

[tex]\implies (\sqrt{3-\sqrt{5}})(\sqrt{3-\sqrt{5}})=3-\sqrt{5}[/tex]

Therefore:

[tex]\implies \dfrac{5\sqrt{3-\sqrt{5}}}{(\sqrt{3-\sqrt{5}})(\sqrt{3-\sqrt{5}})}= \dfrac{5\sqrt{3-\sqrt{5}}}{3-\sqrt{5}}[/tex]

[tex]\textsf{Multiply by the conjugate}\quad \dfrac{3+\sqrt{5}}{3+\sqrt{5}}:[/tex]

[tex]\implies \dfrac{5\sqrt{3-\sqrt{5}}}{3-\sqrt{5}} \times \dfrac{3+\sqrt{5}}{3+\sqrt{5}}=\dfrac{5\sqrt{3-\sqrt{5}}(3+\sqrt{5})}{(3-\sqrt{5})(3+\sqrt{5})}[/tex]

Simplify the denominator:

[tex]\implies (3-\sqrt{5})(3+\sqrt{5})=9+3\sqrt{5}-3\sqrt{5}-5=4[/tex]

Therefore:

[tex]\implies \dfrac{5(3+\sqrt{5})\sqrt{3-\sqrt{5}}}{4}[/tex]

Method 2

[tex]\textsf{Multiply by the conjugate}\quad \dfrac{\sqrt{3+\sqrt{5}}}{\sqrt{3+\sqrt{5}}}:[/tex]

[tex]\implies \dfrac{5}{\sqrt{3-\sqrt{5}}} \times \dfrac{\sqrt{3+\sqrt{5}}}{\sqrt{3+\sqrt{5}}}=\dfrac{5\sqrt{3+\sqrt{5}}}{(\sqrt{3-\sqrt{5}})(\sqrt{3+\sqrt{5}})}[/tex]

Simplify the denominator using the radical rule [tex]\sqrt{a} \sqrt{b} =\sqrt{ab}[/tex]:

[tex]\implies (\sqrt{3-\sqrt{5}})(\sqrt{3+\sqrt{5}})=\sqrt{(3-\sqrt{5})(3+\sqrt{5})[/tex]

[tex]\implies\sqrt{(3-\sqrt{5})(3+\sqrt{5})}=\sqrt{9-5}=\sqrt{4}=2[/tex]

Therefore:

[tex]\implies \dfrac{5\sqrt{3+\sqrt{5}}}{2}[/tex]

Answer 2

[tex]\huge\color{pink}\boxed{\colorbox{Black}{♔︎Answer♔︎}}[/tex]

To rationalise:-

[tex] \frac{5}{ \sqrt{3 - \sqrt{5} } } [/tex]

There is a formula in math if there is root in denominator

for example

[tex] \frac{1}{ \sqrt{a - b} } [/tex]

we can say rationalize by multiplying √(a-b) in numerator and denominator both

[tex] \frac{1}{ \sqrt{a - b} } \times \frac{ \sqrt{a - b} }{ \sqrt{a - b} } \\ \frac{ \sqrt{a - b} }{a - b} [/tex]

In here

[tex] \frac{5}{ \sqrt{3 - \sqrt{5} } } \times \frac{ \sqrt{3 - \sqrt{5} } }{ \sqrt{3 - { \sqrt{5} } } } \\ \frac{5( \sqrt{3 - \sqrt{5} }) }{3 - \sqrt{5} } [/tex]

but still here is root to remove this we have to multiply

3 + √5 in numerator and denominator.

[tex] \frac{5( \sqrt{3 - \sqrt{5} }) }{3 - \sqrt{5} } \times \frac{3 + \sqrt{5} }{3 + \sqrt{5} } \\ \frac{5( \sqrt{3 - \sqrt{5} })(3 + \sqrt{5} ) }{ {3}^{2} - { (\sqrt{5} )}^{2} } \\ \frac{5( \sqrt{3 - \sqrt{5} })(3 + \sqrt{5}) }{9 - 5} \\ \frac{5( \sqrt{3 - \sqrt{5} } )(3 + \sqrt{5}) }{4} [/tex]


Related Questions

What is the sum of the diagonals in a rectangle whose area is 25v3 and whose width is 5?

Answers

Answer:

Sum of diagonals = 20 units

Step-by-step explanation:

[tex]A(rectangle)=25\sqrt 3\: units^2\\w(rectangle) =5\: units[/tex]

To find: Sum of diagonals

[tex]A(rectangle)=l(rectangle)\times w(rectangle) [/tex]

[tex]\implies l(rectangle)=\frac{A(rectangle)}{w(rectangle)}[/tex]

[tex]\implies l(rectangle)=\frac{25\sqrt 3}{5}[/tex]

[tex]\implies l(rectangle)={5\sqrt 3}\: units[/tex]

Let the diagonals of the rectangle be [tex]d_1\:\&\:d_2\: units[/tex]

Diagonals of a rectangle are equal in measure.

[tex]\implies d_1=d_2=\sqrt{l(rectangle)^2+w(rectangle)^2}[/tex]

(By Pythagoras Theorem)

[tex]\implies d_1=d_2=\sqrt{(5\sqrt 3)^2+(5)^2}[/tex]

[tex]\implies d_1=d_2=\sqrt{75+25}[/tex]

[tex]\implies d_1=d_2=\sqrt{100}[/tex]

[tex]\implies d_1=d_2=10\: units[/tex]

[tex]Sum \:of \:diagonals = d_1+d_2[/tex]

[tex]\implies Sum \:of \:diagonals = 10+10[/tex]

[tex]\implies Sum \:of \:diagonals = 20\: units[/tex]

Twice a number is 500 more than six times the number. What is the number?

Answers

Answer:

-125

Step-by-step explanation:

Twice a number is x*2

x*2 = 500 + x*6

=> x = -125

Find the value of x.
17
X-4

Answers

Answer:

x = 12.5

Step-by-step explanation:

17 = 2(x - 4)

17 = 2x - 8

17 + 8 = 2x - 8 + 8

25 = 2x

12.5 = x

Below are the marks obtained by 7 students out of 40 questions on a maths test.
11, 27, 10, 27, 14, 33, 11
Find the mean absolute deviation.
(If the answer is a decimal, round it to the nearest tenth.)

Answers

Answer: according to my calculator, the answer is 8.5714285714286 i hope this is correct lol,

Step-by-step explanation: Hope this helps ^_^

Some of Mr. Edward's students want to buy him a gift. If each of
them pays $2, they will be short of $4 for the gift. If each of them
pays $3, there will be an extra $3. How much does the gift cost?

Answers

Answer:

It depends on how many students there are in Mr. Edwards class

Step-by-step explanation:

Round your answers to 2 decimal places
use 3. 14 for

Answers

Answer:

3

Step-by-step explanation:

0.1 rounds to 0 and 0.04 also rounds to zero. Therefore, the answer is 3.

(3y+2)(y–1) simplify??

Answers

Answer:

[tex]\boxed{\sf{3y^2-y-2}}[/tex]

Step-by-step explanation:

Given:

Isolate the term of y from one side of the equation.

(3y+2)(y-1)

Use the foil method.

[tex]\underline{\text{FOIL METHOD:}}[/tex]

[tex]\Longrightarrow: \sf{\left(A+B\right)\left(C+D\right)=AC+AD+BC+BD}[/tex]

(3y+2)(y-1)=3yy+3y(-1)+2y+2(-1)

Solve.

[tex]\sf{3yy=3y^2}\\\\\\\sf{3y(-1)=-3y}\\\\\\\sf{2(-1)=-2}[/tex]

[tex]\sf{3y^2-3y+2y-2}[/tex]

Add or subtract the numbers from left to right.

Solutions:


[tex]\sf{-3y+2y=-y}[/tex]

[tex]\Longrightarrow: \boxed{\sf{3y^2-y-2}}[/tex]

Therefore, the correct answer is 3y²-y-2.

I hope this helps. Let me know if you have any questions.

Answer:

3y^2-y-2

Step-by-step explanation:

(3y+2)(y–1)

Use the FOIL method

First 3y * y = 3y^2

outer  3y * -1 = -3y

inner  2 * y = 2y

last  2 * -1 = -2

Add them together

3y^2 -3y +2y -2

Combine like term

3y^2-y-2

I WILL GIVE BRAINLIEST!!!!!

Answers

Answer:

See below

Step-by-step explanation:

Inscribed angles encompass twice as many degrees of arc as their angle measure

 soo    2* {   6x-5   +  x+17 } = 360

             shows x = 24      then ROP = x+17 = 41 degrees

A softball has a volume of about 29 cubic inches. Find the radius of the softball. Round your answer to the nearest tenth

Answers

Volume of a Sphere = 4/3(pi)r^3 = 4.187 r^3
(29)in^3= 4.187 r^3

r = 2in [to the nearest tenth]

I need help asap pls

Answers

Answer:

Circumference = 25.14 cm

Area = 50.28 cm²

Step-by-step explanation:

∴ Circumference = 2πr

⇒C = (2) (22/7) (4)

⇒C = 25.14 cm

∴ Area = πr²

⇒A = (22/7) (4)²

⇒A = 50.28 cm²

Hope that helps...

You are trying to help Rhonda understand the concept of a 5% slack in the line. You explain that having a 5% slack means that the length is 5% longer than it would be if it were completely straight. You compare ️ABC to Figure DEF, where curve DE is 5% longer than line segment AB.

Enter curve DE, given the curve is 5% longer than line segment АВ.​

Answers

The length of the hypotenuse AB is equal to the sum of the square of other two sides AC and BC. The measure of the curve DE is 10.5 units

Pythagoras theorem

The theorem states that the length of the hypotenuse AB is equal to the sum of the square of other two sides AC and BC.

According to the theorem;

AB^2 = AC^2 + BC^2

AB^2 = 6^2 + 8^2

AB^2 = 36 + 64

AB = 10

If the curve DE is 5% longer than line segment АВ, the measure of curve DE is given as;

DE = 1.05 * 10
DE = 10.5

Hence the measure of the curve DE is 10.5 units

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What is the following product? startroot 30 endroot times startroot 10 endroot

Answers

Answer:

Hello there! 10 square of 3

The TV chef didn't know the first thing about cooking. He was just hired for his wavy blonde hair and charming British accent. So last Tuesday, while the gullible audience thought the chef was mixing up a world-renowned hollandaise sauce, he was actually just mixing a 5 ounce sauce containing 50% tangy mustard with another sauce containing 75% tangy mustard to get a sauce containing 70% tangy mustard. How many ounces of the 75% tangy mustard sauce must the chef have used?​

Answers

The number or amount of ounces of the 75% tangy mustard sauce must the chef have used is: 20 ounces .

Number of ounces

First step

Since 5 ounce sauce containing 50% tangy

Hence:

5 oz×.50 tangy

=2.50 oz-tangy

Second step

(5+x)×0.7=3.5+0.7x

Third step

2.50+0.75x=3.5+0.7x

Collect like term

0.75x-0.7x=3.5-2.50

0.05x=1

Divide both side by 0.05

x=1/0.05

x=20 ounces

Therefore the number of ounces of the 75% tangy mustard sauce must the chef have used is: 20 ounces .

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Math extra credit can somebody help?

Answers

Okay you got me mad at you and then you too I got you something to say I don’t know how to do that but I’m not mad


Solve each equation.
a.8x=2/3
b.1 1/2=2x
c.5x=2/7
d.1/4x=5
e.1/5=2/3x

Answers

The guy above is right

What is the third quartile of this data set?


14, 18, 20, 21, 25, 32, 38, 42, 48


A. 42


B. 36


C. 40


D. 38

Answers

Answer:

40 so C would be your answer.

The third quartile of the data set is 38.

What is Quartile?

Quartiles are statistical measures that divide a dataset into four equal parts, each representing 25% of the data. They are used to analyze the distribution and spread of data.

There are three quartiles: the first quartile (Q1), the second quartile (Q2), and the third quartile (Q3).

To find the third quartile of a data set, we need to arrange the data in ascending order and then locate the value that divides the upper 25% of the data from the lower 75%.

Arranging the data set in ascending order:

14, 18, 20, 21, 25, 32, 38, 42, 48

The data set has 9 values, so the third quartile will be the value at the

(9 0.75)th position

= 6.75th position.

Since we can't have a fractional position, we round up to the nearest whole number, which is 7.

The value at the 7th position is 38. Therefore, the third quartile of the data set is 38.

Learn more about Quartile here:

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help plsssssssssssssss ​

Answers

Answer:   ASA

Explanation:

The arc markings for each angle show that we have two pairs of congruent angles (angle O = angle Q, angle M = angle R). This takes care of the two "A"s in "ASA". The tickmarks show us that the sides MO and RQ are the same length, so this takes care of the "S" of "ASA". Note the congruent sides are between the angles mentioned. The order is important.

Identify the relationship between the graphs of
these two equations.
2y = 6x + 5
6y=-2x + 1
Click on the correct answer.
parallel
perpendicular
neither

Answers

Perpendicular

This is because lines that are perpendicular have slopes that are the negative reciprocals of each other (for example: 5 and -1/5)


When you simplify each of the equations given, the equations are:

Y=3x + 5/2

Y=-1/3x + 1/6


Since the lines are are the form y=mx + b, and ‘m’ represents the slopes, the two slopes are 3 and -1/3 which are negative reciprocals of each other, therefore the lines are perpendicular

Factorise 4x^2-y^2 please help

Answers

Answer:

(2x + y)(2x - y)

Step-by-step explanation:

1. Simplify the square 4x²:

(2x)² - y²

2. Apple the difference of two squares formula x² - y² = (x + y)(x - y):

(2x + y)(2x - y)

hope this helps!

Please help. Will mark brainlyest!!

Answers

Answer:

D

Step-by-step explanation:

It goes 2 down. The ' mark shows that it is the new one

answer is B
the shape has moved 3 units down

please help me with the question​

Answers

Answer:

The answer is B.

Step-by-step explanation:

4x-7 = 2x+9

2x = 16

x = 8

And then we put x into the equations.

y = 32 - 7

y = 25

We then check it with the other equation just to make sure we are correct.

y = 16 +9

y = 25

Therefore, the answer is (8,25).

Record: 0/2 Score: 0 Penalty: 1 off
Complete: 79
Emily Trelow
Transforming Formulas
The formula to calculate the gravitational force between two objects is F₁ = GM₁M₂,
where M₁ and M₂ are the masses of the objects, G is the gravitational constant and
r is the distance between the objects. Solve for M₁ in terms of F, G, M₂ and r.
Answer: M₁ =
Submit Answer

Answers

Newton's Law of Gravitation:

Statement: According to this law, when two mass bodies are separated at finite distance then there must be an attractive force experience by them which is directly proportional to the product of their masses and inversely proportional to the square of their separation.

Consider two mass bodies m1 & m2 be kept at distance d. Then the force of attraction F is given as

                            [tex]Fam_{1}.m_{2}[/tex]

                                 [tex]Fa1/d^2[/tex]

Now, from above equations, we have

                          [tex]Fa\frac{m_{1}m_{2}}{d^2}[/tex]

or,                           [tex]F=G\frac{m_{1}m_{2}}{d^2}[/tex]

Here         [tex]G=6.67*10^{-11}Mm^2kg^{-2}[/tex]   is the universal gravitational constant.

PLS HALP!
Bisect line segment AB.
Steps.
1. Center your compass at A so that it measures more than half way to B. Draw arcs above and below segment AB.
2. Using the same compass measurement as step 1, center your compass at B. Draw two arcs above and below segment AB so that they intersect the arcs from step 1. Name these intersection points C and D.
3. Draw line CD.
4. Name the intersection of line segment AB and line segment CD, point M.
5. CD is a segment bisector of segment AB.

Answers

Answer:

Shown in the photo

Step-by-step explanation:

I just followed the steps. If you need more help let me know :)

Determine if the situation represents a proportional relationship. Explain your reasoning.

Aaron Rodgers can throw a football 44 yards in 2 seconds. Patrick Mahomes can throw

a football 84 yards in 3 seconds. Show your work.

Answers

Answer:

Step-by-step explanation:

44/2 is 22

84/3 is 28

Patrick Mahomes can throw more yards/sec

each morning, danai buys breakfast on her why to work. In the past thirty days, she bought a bagel on 6 days, a banana on 12 days, a doughnut on 3 days, and an orange on 9 days. If she bought one item per day, what is the probability that she bought either a banana or an orange? Show or explain your work and write you answer in the space provided.

Answers

Answer:

0.7 or 70%

Step-by-step explanation:

Total number of days

6 + 12 + 3 + 9 = 30

The number of days she bought a banana or orange

12 + 9 = 21

The probability of buying a banana or an orange is

P(b or o) = 21/30 = 0.7 = 70%

Answer:

[tex]\sf \dfrac{7}{10}=0.7=70\%[/tex]

Step-by-step explanation:

Given information:

Bagel bought on 6 daysBanana bought on 12 daysDoughnut bough on 3 daysOrange bought on 9 days

Total number of days = 30

Probability Formula

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

Probability of buying a banana:

[tex]\implies \sf P(Banana)=\dfrac{12}{30}[/tex]

Probability of buying an orange:

[tex]\implies \sf P(Orange)=\dfrac{9}{30}[/tex]

Therefore,

[tex]\implies \sf P(Banana) \: or \: P(Orange)=\sf \dfrac{12}{30}+\dfrac{9}{30}=\dfrac{21}{30}=\dfrac{7}{10}[/tex]

So the probability of buying either a banana or an orange is:

  [tex]\sf \dfrac{7}{10}=0.7=70\%[/tex]

A 5 metre long ladder is placed against a wall. It reaches
4.3 metres up the wall. What is the angle between the
ladder and the ground?
IS

Answers

given

5m long ladder placed against 4.3m up the wall.

to find:

the angle between the ladder and the ground.

solution:

Based on the given conditions, formulate: 

sin⁡x=4.3÷5

Evaluate the equation/expression:

x= 1.03527 or 2.10632

x= 1.03527°

or x= 2.10632°

Jim picks a five digit odd number. The second digit is less than 5. The fourth digit is a cube number. The first digit is a prime number. How many different numbers could he pick?

Answers

Answer:

3,000 numbers.

Step-by-step explanation:

First digit: 2, 3, 5, or 7 (primes)

Second digit: 0, 1, 2, 3, or 4 (less than 5)

Third digit: 0-9

Fourth digit: 0, 1, or 8 (cubic numbers)

Fifth digit: 1, 3, 5, 7, or 9 (odd numbers)

So we have 4 * 5 * 10 * 3 * 5 = 3,000 possible numbers.

Frank wants to find the area enclosed by the figure at the right. The figure has semicircular on each side of a 40-meter by 40 meter square. Find area enclosed by the figure. 3. 14

Answers

4,112.00 m2

Is the answer I think

AB is tangent to circle O at A. Find the length of radius r to the nearest tenth. A to B is 11. B to O is 8.
Please answer ASAP will mark as brainlist

Answers

Answer: 3.6

Step-by-step explanation:

dibujar esta parabola y= 3x^2

Answers

Allí está ojalá te ayude
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