Seismic waves carry energy from earthquakes through the earth's crust. Seismic waves are...

- transverse waves only

- longitudinal waves only

- neither transverse nor longitudinal waves

- both transverse and longitudinal waves

Answer:

T = 51.25°C

Explanation:

Applying the law of conservation of energy, we get:

where,

m₁ = mass of cold water = 175 g

m₂ = mass of hot water = 125 g

T = Final temperature of the mixture = ?

Therefore,

[tex](175\ g)(T-20^oC) = (125\ g)(95^oC-T)\\\\T-20^oC = (0.7143)(95^oC-T)\\\\T(1+0.7143) = 20^oC+67.86^oC\\\\T = \frac{87.86^oC}{1.7143}[/tex]

T = 51.25°C

Answer:

A) a snowboarder who increases speed when traveling downhill

A snowboarder who increases speed when traveling downhill will have negative acceleration.

What is acceleration ?

Acceleration is described as the rate of change of velocity with time.

                                                       [tex]a&=\frac{\Delta v}{\Delta t}[/tex]

Here, as the snowboarder is traveling in negative y direction therefore the final velocity will be great than initial velocity with negative sign. It should be noted that velocity and acceleration are vector quantities i.e. depends upon the direction in which they have been applied.

Also negative acceleration is denoted as the situation when the object moves in the direction that is opposite to its direction of velocity.

In the above situation, the force is being applied to travel downhill(speeding up in the negative direction) in the opposite direction which exemplifies negative acceleration.

Thus, option A is the correct answer.

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Answer:

Magnetic field in Tesla: 1.65*10^−10 T,   0,   3.09*10^−10 T

Explanation:

Given data:

i = 4.8 A ,

dBx = 1.65*10^-10 T

dBy = 0 T

dBz = 3.09 * 10^-10 T

Attached below is the detailed solution

Answer:

A. The average kinetic energy decreased.

Explanation:

When an object gains heat, which is a form of energy, the atoms within the object would in turn gain energy in the form of kinetic energy. Similarly, as the temperature of an object decreases, in other words losing heat energy, the atoms within the object would lose kinetic energy as a result.

The flux of light from an isotropic source depend on the distance r from the source by  r-2.

What is isotropic source?

An isotropic source is a source of radiation or sound that emits energy in all directions equally. This type of source is usually assumed to have uniform power density in all directions, making it a simplifying assumption when analyzing a system. Examples include a point source in free space, such as a light bulb, or a sound source in a room.

The flux of light from an isotropic source (a source that radiates uniformly in all directions) decreases as the inverse square of the distance from the source. This means that the flux of light from the source decreases according to the equation F = 1/r2, where F is the flux of light, and r is the distance from the source. Therefore, the flux of light from an isotropic source decreases with the distance r from the source according to the equation F = r-2.

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Answer:

70

Explanation:

you do 10+20=30

100-30=70

Kinetic energy is the type of energy that is acting in it when the ball is rolling down the ramp along with many forces such as rolling tangential force and gravitational force.

Rolling motion of any object occurs when the object starts sliding in a different methods from the other objects such as when the objects starts to roll from the ramp or any other sloppy surface and it rolls down due to the gravitational force and with many other forces such as the rolling tangential force. many forces are acting on the object at the same moment and we are just seeing the gravitational force which is playing a major portion. Hence by this information we can consider that the ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form. also by this we tend to know that the Kinetic energy is the type of energy that is acting in it when the ball is rolling down the ramp.

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The statement is false. The capacitor doesn't charge Q exponentially decays to zero when the RELAY is thrown to position N.O.

As a capacitor charges, its voltage also rise.

V = Q/C

where Q = charge, V = voltage and C = capacitance

If the circuit contains a battery, a resistor and a capacitor all connected in series, then the following are true.

The battery voltage is fixed. And the capacitor voltage is rising. This clearly means that the current through the resistor is dropping.

I = (Vbatt - Vcap)/R

Since the current is dropping, then the rate at which charge is deposited on one plate and removed from the other one continuously drops.

So the charging of the capacitor also slows down because of the rising voltage.

But here the rise in the voltage is slowing down because of the rate of charges that are accumulating and leaving continuously is slowing down.

The slower rise in voltage causes a further slowing in the rate of charge movement which further slows down the rise in voltage which causes an even slower rate of charge movement.

A capacitor is referred as an electrical device which stores electrical charge when it is connected across the source of potential difference.

The total charge that the capacitor can be stored when it is placed across a potential V is given by

Q=CV

where C is the capacitance of the capacitor.

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The velocity of the ball is 1 m/s which starts with a speed of 2.0 m/s and slows at a constant rate of 0.5 m/s².

According to the data given:

Speed of the ball: 2.0 m/s

Acceleration: 0.50 m/s²

Time is 2.0 s

The ball starts rolling up the hill with a speed of 2m/s (u=2 m/s²) and it decelerates at a constant rate of 0.5 m/s² (a = -0.5 m/s², minus because it decelerates).

The equation for calculating velocity is:

v = u + a x t,  t represents time here

So, ball's velocity after 2 seconds is:

v = 2m/s + (-0.5m/s² x 2s)

v = 2m/s + (-1m/s)

v = 1m/s

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Answer:

write: I think that we can only see one side of the moon  because  the  moon rotates and spins on its axis at the same rate that the Moon orbits the Earth.

hope this is wht ur looking for. :)

Explanation:

Answer:

-3.2m

Explanation:

To find the distance of the 25N weight from the pivot, we can use the concept of moments. The moment of a force is the product of the force and the perpendicular distance from the pivot to the line of action of the force.

The total moment about the pivot due to the weights on side A is:

Moment_A = (10N * 4m) + (30N * 2m) = 80Nm

The moment of the 25N weight on side B must be equal and opposite to the total moment of the weights on side A, so we can set up the following equation:

Moment_B = -80Nm

We can solve for the distance of the 25N weight from the pivot by rearranging the equation to solve for x:

x = Moment_B / 25N = -80Nm / 25N = -3.2m

So the distance of the 25N weight from the pivot is -3.2m. This means that the weight is 3.2m to the left of the pivot, since the pivot is taken as the origin for the purpose of calculating moments.

The acceleration in Case A is four times that of Case B.

Acceleration is the rate of change of velocity of an object. It is the measure of how quickly an object changes its velocity over time, represented by the equation a = (v-u)/t, where a is the acceleration, v is the final velocity, u is the initial velocity, and t is the time. Acceleration can be either positive or negative; a positive acceleration indicates an increase in velocity while a negative acceleration indicates a decrease in velocity.

This is because the acceleration of an object in uniform circular motion is given by the equation a = v^2/r, where a is the acceleration, v is the speed, and r is the radius of the circle. Because the speed in Case A is half that of Case B, the acceleration will be one-fourth that of Case B. However, because the radius in Case A is two times that of Case B, the acceleration will be four times that of Case B.

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Answer: 3,370 N/C

Explanation:

acellus

[tex]\large{\colorbox{yellow}{\color{blue}{

Sugar can was a crop that did not grow in most climates.}}}[/tex]

The quarterback also touches the ball on almost every offensive play, and is almost always the offensive player that throws forward passes.

The quarterback (sometimes abbreviated "QB") is a position in gridiron football, also referred to as the "signal caller" Quarterbacks typically line up directly behind the offensive line and are part of the offensive platoon.

In contemporary American football, the quarterback is typically regarded as the offensive coordinator and is frequently in charge of calling the play in the huddle. The quarterback almost always delivers forward passes for the offence and touches the ball on practically every offensive play.

A sack occurs when the quarterback is beaten behind the line of scrimmage. In contemporary American football, the starting quarterback is typically the offensive coordinator, and his or her accomplishments or shortcomings can have a big impact on the team's performance.

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The offensive player who delivers forward passes almost always is the quarterback, who touches the ball on almost every offensive play as well.

In gridiron football, the quarterback, sometimes known as the "signal caller," is one of the positions. As a member of the offensive platoon, quarterbacks often line up directly behind the offensive line.

The quarterback is frequently in charge of calling the play in the huddle and is generally considered as the offensive coordinator in modern American football. In almost every offensive play, the quarterback touches the ball and almost always completes forward throws for the offense.

The quarterback is tackled behind the line of scrimmage, which results in a sack. Currently, the starting quarterback in American football is Usually, the offensive coordinator, and his or her successes or failures, can have a significant effect on the team's performance.

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The speed of the astronaut after launching our feline superhero is 1.4 m/s.

The speed of the astronaut is determined from the principle of conservation of linear momentum.

Pi = Pf

where;

86vₓ = 4.8 x (25 cos40)

86vₓ = 91.9

vₓ = 91.9 / 86

vₓ = 1.07 m/s

The vertical component of the speed;

86vy = 4.8 x (25 sin40)

86vy = 77.1

vy = 77.1 / 86

vy = 0.9 m/s

The resultant speed of the astronaut is calculated as;

v = √ ( vₓ² + vy² )

v =  √ ( 1.07² + 0.9² )

v = 1.4 m/s

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Answer:

3.33 m/s

Explanation:

(3.0 km)(1000 m/km) = 3000 m

Avg. Speed = distance/time = 3000 m/900 s = 3.33 m/s

The student with a 59-kg mass moves to the right with a velocity of 1.46 m/s.

According to the law of conservation of momentum, The overall momentum of two or more bodies acting on one another in an isolated system stays constant unless an external force is introduced.

The student with a mass of 48 kg moves to the left with a velocity of 1.8 m/s.

Let the student with a mass of 59 kg moves to the left with a velocity of v m/s.

As no external force applied,

48 kg × 1.8 m/s + 59 kg × v = 0

v = - 1.8 × (48/59) m/s

= - 1.46 m/s.

Hence, the velocity of the second bay is 1.46 m/s in right direct.

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Answer:

a. Thus, the tension in the cord causes no change in angular momentum.

b. 0.112 N

c. -0.048 J

Explanation:

a) Explain if the tension force causes the change of angular momentum.

A centripetal force F initially acts on the block to keep at at a radius of 0.5 m and speed of 0.9 m/s.

When the cord is pulled, the tension causes a change in the centripetal force to a new value at a radius of 0.23 m.

But since the force is applied in the radial direction and not perpendicular to the radius, there is no torque applied (since torque τ = rFsinθ and θ = 0 thus τ = rFsin0 = 0)and thus, there is tangential acceleration α (since α = τ/I where I = rotational inertia of block)and thus no change in angular speed ω (since α = Δω/Δt, α = 0 ⇒ Δω/Δt ⇒ Δω = 0).

Since there is a no change in angular speed, there is thus no change in angular momentum.

Thus, the tension in the cord causes no change in angular momentum.

b) What is the tension in the cord in the final situation when the block moving in a circle with smaller radius.

The centripetal force in the cord is equal to the tension at the smaller radius.

We find the angular speed of the block from v = rω where v = initial tangential speed of block at r = 0.5 m = 0.9 m/s and r = 0.5 m.

So, ω = v/r = 0.9 m/s ÷ 0.5 m = 1.8 rad/s

The centripetal force at radius r = 0.23 m is F = mrω² where m = mass of block = 0.150 kg, r = distance = 0.23 m and ω = angular speed = 1.8 rad/s

So, F = 0.150 kg × 0.23 m × (1.8 rad/s)²

F = 0.150 kg × 0.23 m × 3.24 rad²/s²

F = 0.11178 kgmrad²/s²

F ≅ 0.112 N

c) How much work was done by the person who pulled on the cord

From work-kinetic energy principles, the work done by the tension equals the kinetic energy change of the block.

ΔK = W

1/2m(v₂² - v₁²) = W where m = mass of block = 0.150 kg, v₁ = initial speed of block = 0.9 m/s, v₂ = final speed of block distance r = 0.23 m,

Since the tangential speed v ∝ r the radial distance,

v₂/v₁ = r₂/r₁

v₂ = (r₂/r₁)v₁

= 0.23 m × 0.9 m/s ÷ 0.5m

= 0.207 m²/s ÷ 0.5 m

= 0.414 m/s

So, W = 1/2m(v₂² - v₁²)

W = 1/2 × 0.150 kg((0.414 m/s)² - (0.9 m/s)²)

W = 1/2 × 0.150 kg((0.1714 m/s)² - (0.81 m/s)²)

W = 1/2 × 0.150 kg((-0.6386 m²/s²)

W = 1/2 × -0.09579 kgm²/s²)

W = -0.0479 kgm²/s²

W = -0.0479 J

W ≅ -0.048 J

Answer:

9798687564=-=-=97858

Explanation:oy 8gyf86 r = 76y

The mass of planet is 3.886×10^25 kg. The radius of planet is 1. 2x10^7m.

Complete Resolution. If the acceleration caused by gravity on the surface of the earth is given by the formula g, then the acceleration caused by gravity on a planet with a mass half that of the earth and a radius equal to that of the earth is given by the formula g/2. Where G = 6.67 ×10^-11 N m2/kg2 (Newton's gravitational constant).

As a result, acceleration due to gravity (a) depends on the gravitational constant (G), the mass of the Earth (M), and the radius of the Earth (R), but not on the mass of the body (m).

Given:

Radius of planet (r) =  1. 2x10^7m

Acceleration due to gravity (g) = 18 m/s^2

The acceleration due to gravity at the surface of the planet is,

[tex]g=G\frac{M}{r^2}[/tex]

Where, G = Universal gravitational constant

[tex]G= 6.67*10^-11N.m^2/kg^2[/tex]

[tex]M=\frac{g*r^2}{G}[/tex]

[tex]M=\frac{18*(1.2*10^7)^2}{6.67*10^-11}[/tex]

M =3.886×10^25 kg

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Answer:

Sound is produced when an object vibrates, creating a pressure wave. This pressure wave causes particles in the surrounding medium (air, water, or solid) to have vibrational motion. As the particles vibrate, they move nearby particles, transmitting the sound further through the medium. The human ear detects sound waves when vibrating air particles vibrate small parts within the ear.

In many ways, sound waves are similar to light waves. They both originate from a definite source and can be distributed or scattered using various means. Unlike light, sound waves can only travel through a medium, such as air, glass, or metal. This means there’s no sound in space!

Explanation:

The linear diameter of an object with an angular diameter of 25 arcseconds and a distance of 65 km will be 0.067 meters.

Linear Diameter = (Angular Diameter ×Distance) / 206264.81.

In this case, the linear diameter would be 0.067 meters.

To put this into context, a linear diameter of 0.067 meters is approximately equal to 6.7 centimeters, or 2.6 inches. To put this another way, it is approximately the size of a large grape. As such, it is incredibly small and would be difficult to see with the  eye.

Therefore the linear diameter of the object is 0.067 meters

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Answer:

his acceleration rate is -0.00186 m/s²

Explanation:

Given;

initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)

time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s

final position of the car, x₁ = 150 miles = 241,350 m

time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s

The initial velocity is calculated as;

u = 160, 900 m / 3,600 s

u = 44.694 m/s

The final velocity is calculated as;

v = 241,350 m / 6,000 s

v = 40.225 m/s

The acceleration is calculated as;

[tex]a = \frac{\Delta V}{\Delta t} = \frac{v- u}{t_1 - t_ 0} = \frac{40.225 - 44.694}{6000-3600} = -0.00186 \ m/s^2\\\\[/tex]

Therefore, his acceleration rate is -0.00186 m/s²

Answer:

all of the above are correct

In order to hit the target, the archer should aim the arrow so that it follows a parabolic trajectory.

The archer should aim the arrow slightly higher than the target, so that the arrow will arc downward and reach the target. Additionally, the archer should take into account other factors such as wind speed and direction, as these can affect the trajectory of the arrow.

The parabolic trajectory is a curve created when an object is thrown or shot in the air at an angle, then follows the path of a parabola. The parabolic trajectory allows for the object to travel in an arc and reach a certain distance, such as a target.

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electromagnetic wave 7.5 * 10 14 HZ

Answer:

Electromagnetic waves are categorized according to their frequency f or, equivalently, according to their wavelength λ = c/f. Visible light has a wavelength range from ~400 nm to ~700 nm. Violet light has a wavelength of ~400 nm, and a frequency of ~7.5*1014 Hz.

Explanation:

The 5000 N-m work was done on the object.

The formula Work = Force * Distance can be used to compute work. The joule (J) or Newton-meter (N-m) is the SI unit for work. When 1 N of force pushes an item a distance of 1 m, the work done is equal to 1 joule.

There are several instances of work being done in our daily lives. A student holding a backpack on his back or his shoulder full of books, a horse pulling a plow across the field, a father pushing a supermarket cart in a mall, and many more examples come to mind.

Given:

Load force = 1000 N

Load distance = 5.00 m

Effort distance = 20.0 m

[tex]Work=Load*Load distance[/tex]

[tex]Work=1000*5.00[/tex]

[tex]Work=5000N-m[/tex]

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Answer:

Work = Work out

Work in = 5 N * d     where d is the distance the handle travels

Work out = 50 N * 7 m = 350 Joules

d = 50 N * 7m / 5 N = 70 m

This is the distance traveled by the force of 5 N

A man lifts a bucket of water from a well that is 7 meters deep. The bucket and water together weigh 50 Newtons. He turns the crank handle with a force of 5 Newtons. The effort force is 70 Newtons.

If a force is applied for a machine to move or change the position of the object is known as Effort force.

The effort force formula can be described as,

Fe = Fl. dl / de

Fe is effort force (N, lb)

Fl is load force (N, lb) (note that weight is a force)

dl is distance from load force to fulcrum (m, ft)

de is distance from effort force to fulcrum (m, ft)

Here, the given data to find the effort force is,

Fl =50 Newtons

dl = 7 meters

de = 5 Newtons.

Substituting all the values, we get,

Fe = 350/5

Fe = 70 Newtons.

Thus, the effort force is 70 Newtons.

Hence, Option A is the correct answer.

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