Answer:
x-5=0
10=2x
(1/2)x=10
x>2=25
Step-by-step explanation:
all of these are x=5
the ones that are wrong are 11-x=3 and 1+x=5
i already have the chart filled out i just need some help with the conclusion
.
.chart:
Location
Timeline
Human Impact Measurements
Recommendation to Decrease Human Impact
New York City
Water Pollution
(in parts per million)
50 years ago
625ppm
create gardens on all of the rooftops
Present Day
893ppm
Future Development Impact
843ppm
Amazon Rainforest
Levels of CO2
(in parts per million)
50 years ago
CO2 levels: 318 ppm
Limit the amount of timber that can be removed per year
Present Day
CO2 levels: 402 ppm
Future Development Impact
CO2 levels: 378 ppm
Sahara Desert
Loss of land by Erosion
(in meters)
50 years ago
Erosion: 1.2 meters
Build better enclosures to decrease overgrazing by livestock
Present Day
Erosion: 3.5 meters
Future Development Impact
Erosion: 2.6 meters
.Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please write in complete sentences.
.
When recommending solutions to decrease human impact, which location were you able to make the greatest positive impact? Please explain your selection by using data from the simulation.
.
What recommendations would you give to your local community to help to decrease the local effects of human impact on the environment? List 2 recommendations and how they will positively impact your community.
.
What recommendations would you give to the global governments to help decrease the global effects of human impact on the environment? List 2 recommendations and how they will positively impact our planet.
tell me if i missed anything! and please give me good answers!
This report highlights the impact of human activity on three different locations: New York City, the Amazon Rainforest, and the Sahara Desert. The measurements were taken 50 years ago, in the present day, and the predicted future development impact.
## New York City
Water pollution in parts per million (ppm) was measured in New York City. Fifty years ago, the water pollution was 625ppm, and presently, it has increased to 893ppm. The predicted future development impact is 843ppm. To decrease human impact on this location, it is recommended to create gardens on all of the rooftops. The plants will help absorb some of the pollutants and reduce runoff into waterways.
## Amazon Rainforest
CO2 levels in parts per million (ppm) were measured in the Amazon Rainforest. Fifty years ago, the CO2 levels were 318ppm, and presently, it has increased to 402ppm. The predicted future development impact is 378ppm. To decrease human impact on this location, it is recommended to limit the amount of timber that can be removed per year. The Amazon Rainforest is often referred to as the "lungs of the planet" due to its ability to absorb carbon dioxide and produce oxygen. By limiting deforestation, the amount of carbon dioxide released into the atmosphere will decrease, and the rainforest will continue to produce oxygen, benefiting both the local and global environment.
## Sahara Desert
The loss of land by erosion in meters was measured in the Sahara Desert. Fifty years ago, the erosion was 1.2 meters, and presently, it has increased to 3.5 meters. The predicted future development impact is 2.6 meters. To decrease human impact on this location, it is recommended to build better enclosures to decrease overgrazing by livestock. Overgrazing leads to soil compaction, which makes it difficult for vegetation to grow and prevents the soil from holding water. By implementing better enclosures, the livestock will be limited to a smaller area, allowing the vegetation to recover and hold the soil in place.
## Conclusion
In conclusion, all three locations experienced an increase in human impact over the years. By analyzing the data, the location that could benefit the most from decreasing human impact is the Amazon Rainforest. Limiting the amount of timber that can be removed per year will have a positive impact on this location. However, it is important to continue monitoring all three locations to ensure that the human impact is decreasing and not increasing.
## Recommendations for Local Communities
To decrease the local effects of human impact on the environment, two recommendations are:
1. Reduce the use of single-use plastics, such as straws and bags, to decrease pollution. Single-use plastics are a major source of pollution in our oceans, and by reducing our reliance on them, we can help reduce the amount of plastic that ends up in our waterways.
2. Plant more trees and vegetation to increase the amount of oxygen in the air. Trees and plants produce oxygen through photosynthesis, which helps clean the air we breathe. By planting more trees and vegetation in our communities, we can help reduce the amount of pollution in the air and create a healthier environment for ourselves and future generations.
## Recommendations for Global Governments
To decrease the global effects of human impact on the environment, two recommendations are:
1. Invest in renewable energy sources, such as solar and wind power, to decrease the use of fossil fuels. Fossil fuels are a major contributor to greenhouse gas emissions, which are responsible for climate change. By investing in renewable energy sources, we can decrease our reliance on fossil fuels and reduce our carbon footprint.
2. Implement policies to decrease deforestation and promote reforestation to decrease the loss of wildlife habitats and increase the amount of oxygen in the air. Deforestation is a major contributor to climate change, as it releases carbon dioxide into the atmosphere and reduces the amount of oxygen produced by trees. By implementing policies to decrease deforestation and promote reforestation, we can help mitigate the effects of climate change and create a healthier environment for all living beings.
A farmer is studying the amount of solid particles in a small pond. He determines that the average density of particles in the water is 100 milligrams per liter. The pond contains 200,000 liters of water. What is the total mass in KILOGRAMS of the particles in the pond?
(1000 milligrams = 1 gram and 1000 grams = 1 kilograms)
A.
0.2 kg
B.
20 kg
C.
200 kg
D.
20,000 kg
Answer:
Step-by-step explation: Revised 8/15. F001. Surface area of a pond, acres = Length, ft x Width, ft. 43560. F002. Volume
Solve for x. Round to the nearest tenth.
x =
Determine if the information given represents a liner,exponetial, or quadratic function and explain why.
Answer:
linear
Step-by-step explanation:
this is a linear function!
linear functions follow y = mx+b, where m is the slope and b is the y-intercept
let's write our y = mx+b equation
for each value that x increases, y increases by DOUBLE that amount. slope is y/x, so since y increases by 2 and x increases by 1, the slope is 2/1 which is 2.
the y-intercept is where the line passes the x axis, or when x is 0. in this table, it gives you your y-intercept, which is -6
your equation is y=2x+(-6); which simplified to y=2x-6
if you plug in the y and x values, you'll get the same thing. i hope this helped!
I have a barn that is a regular hexagon, as shown. Each side of the barn is 100 feet long. I tether my burro to point A with a 150 foot rope. Find the area of the region in which my burro can graze. Round your answer to nearest foot squared.
The area of the region in which the burro can graze will be 833 pi square feet.
What is the value of the area?Each interior vertex angle of a regular hexagon is (n - 2)·180°/n = (6 - 2)·180°o/6 = 120°
I'll break up the area into three sections.
There is one major section, going 150' along one side in a circular arc to 150' along the adjacent side.
Since the interior angle is 120°, the exterior angle will be 240°.
The area of this section will be: (240°/360°)·pi·radius2 = (2/3)·pi·1502 = 15,000 pi
Then, on each end, around the corner of the barn, the goat can go in a circular arc with radius = 50'.
This angle will be 60°, or one-sixth or a circle.
The area of each section will be (1/6)·pi·502 = 416 2/3 pi
Total area: 15,000 pi + 416 2/3 pi + 416 2/3 pi = 833 1/3 pi square feet.
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Please help me with my trig hw
Based on the family the graph below belongs to, which equation could represent the graph?
On a coordinate plane, a curve starts at (0, 2) and curves up and to the right in quadrant 1.
y = 2 Superscript x Baseline 3
y = log (2 x) + 3
y = 2 x squared + 2
y = StartFraction 1 Over 2 x EndFraction + 2
Answer:
Second option [tex]y=\text{log}(2\text{x})+3[/tex]
Solution:
Based on the family of graphs shown in the attached file, the equation could represent the graph is [tex]y=\text{log}(2\text{x})+3[/tex]
This graph is the graph of the function [tex]y=\text{log}(\text{x})[/tex] stretched horizontally by a factor of 2 and translated 3 units upward.
Answer:
B
Step-by-step explanation:
Edge 2023
Hey can someone please help me with this math question!! As soon as possible!
The values of x that could make the triangle into different types of triangles are:
Right triangle - 10 Acute triangle - 9Obtuse triangle - 11How to find the values of x ?For a triangle to be valid, the sum of the lengths of any two sides must be greater than the length of the third side.
Right Triangle:
A triangle is a right triangle if it satisfies the Pythagorean theorem: a² + b² = c², where c is the longest side (hypotenuse).
6² + 8² = x²
36 + 64 = x²
100 = x²
x = 10
Acute Triangle:
A triangle is acute if the sum of the squares of the two shorter sides is greater than the square of the longest side. Since we already know that the right triangle has x = 10, we can choose a value for x that is less than 10 to form an acute triangle.
Let's take x = 9:
6² + 8² > 9²
36 + 64 > 81
100 > 81
Obtuse Triangle:
A triangle is obtuse if the sum of the squares of the two shorter sides is less than the square of the longest side. We can choose a value for x that is greater than 10 to form an obtuse triangle.
Let's take x = 11:
6² + 8² < 11²
36 + 64 < 121
100 < 121
The possible values of x for each triangle type are:
Right Triangle: x = 10
Acute Triangle: x = 9
Obtuse Triangle: x = 11
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You are paid 1.5 times your normal hourly rate for each hour you work over 32 hours in a week. You work 33 hours this week and earn 545.38 . What is your normal hourly rate?
The normal hourly rate is 16.28 units
What is unit rate?
A unit rate is the cost for only one of anything. This is expressed as a ratio with a denominator of 1. For instance, if you covered 70 yards in 10 seconds, you did so at an average speed of 7 yards per second. Although both of the ratios—70 yards in 10 seconds and 7 yards in one second—are rates, only the latter is a unit rate.
Let r be your rate you get paid per hour normally.
Total = 33 hours
Extra hour = 33 -32 = 1 hour
We have
32r + 1.5r = 545.38
=> 33.5r = 545.38
=> r = 545.38 /33.5 = 16.28
The normal hourly rate is 16.28 units
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4x+8y+2 in y
intercept form
Answer:
e
Step-by-step explanation:
i have an upcoming exam
I need help with inequalities
can someone give me problems then put the answers below?
Thanks
Please at least 5
Reward- Brainliest and 25 Tokens
Problems:
Solve for x: 2x - 5 > 9x + 2
Solve for x: 3x + 2 < 7x - 5
Solve for x: 4x + 3 < 2x - 1
Solve for x: -2x - 4 > -8x + 3
Solve for x: 5x + 1 < 2x + 7
Answers:
x < -0.7
x > 1.75
x < -1
x < 0.875
x < 1.2
Answer:
Example 1
Solve 3x − 5 ≤ 3 − x.
Solution
We start by adding both sides of the inequality by 5
3x – 5 + 5 ≤ 3 + 5 − x
3x ≤ 8 – x
Then add both sides by x.
3x + x ≤ 8 – x + x
4x ≤ 8
Finally, divide both sides of the inequality by 4 to get;
x ≤ 2
Example 2
Calculate the range of values of y, which satisfies the inequality: y − 4 < 2y + 5.
Solution
Add both sides of the inequality by 4.
y – 4 + 4 < 2y + 5 + 4
y < 2y + 9
Subtract both sides by 2y.
y – 2y < 2y – 2y + 9
Y < 9 Multiply both sides of the inequality by −1 and change the inequality symbol’s direction. y > − 9
Solving linear inequalities with subtraction
Let’s see a few examples below to understand this concept.
Example 3
Solve x + 8 > 5.
Solution
Isolate the variable x by subtracting 8 from both sides of the inequality.
x + 8 – 8 > 5 – 8 => x > −3
Therefore, x > −3.
Example 4
Solve 5x + 10 > 3x + 24.
Solution
Subtract 10 from both sides of the inequality.
5x + 10 – 10 > 3x + 24 – 10
5x > 3x + 14.
Now we subtract both sides of the inequality by 3x.
5x – 3x > 3x – 3x + 14
2x > 14
x > 7
Solving linear inequalities with multiplication
Let’s see a few examples below to understand this concept.
Example 5
Solve x/4 > 5
Solution:
Multiply both sides of an inequality by the denominator of the fraction
4(x/4) > 5 x 4
x > 20
Step-by-step explanation:
Hope this helps :3
What is the area of this trapezoid?
Answer:
8*7=56 + 8*3=24 = 80_squared
Step-by-step explanation:
Justin is standing on a bridge, and his eye level is 28 feet above the surface of the water. If he spots a fish on the surface of the water 75 feet downstream from the point he is standing above, what is the angle of depression from his eye level to the fish?
Assuming that the 75 feet measurement is the distance from where Justin is at the ground level to the fish (and not the diagonal distance from his location to the fish), the angle is given by arctan(28/75) = 28.472 degrees. This is probably the right answer.
If the 75 feet measurement is the diagonal distance, the angle is arcsin(28/75) = 21.921 degrees.
We know this from a relation of right triangle trigonometry. Tell me if you need more clarification.
What is the equation of the line that passes through the point (-3,4)(−3,4) and has a slope of -2−2?
Answer:
slope intercept form= y=2x+2
point form= y+4=2*(x+3)
Step-by-step explanation:
Answer y = -2x -2 is your equation of the line crossing those points
Step by step
To find your equation of the line, use slope (-2) and the points (-3, 4) and point slope formula y- y1 = m (x - x1)
y - 4 = -2 ( x - -3)
Simplify
y - 4 = -2x -6
Add 4 to each side to isolate y
y -4 +4 = -2x -6 +4
Simplify
y = -2x -2 is your equation of the line crossing those points
15 points! please help me out!
Answer: 260 ft^2
Step-by-step explanation:
Find the area of the triangle: 0.5*height*base = 0.5*10*20 = 100 ft^2
Find the area of the rectangle: 20*8 = 160 ft^2
Add them together: 160+100 = 260 ft^2
A fair coin is tossed 7 times. Compute the probability of tossing 7 heads in a row.
Enter your response as a reduced fraction.
Answer:
1/128
Step-by-step explanation:
The probability of tossing a head is 1/2.
Each toss is an independent event.
We toss 7 times and get a head each time.
1/2 * 1/2* 1/2* 1/2* 1/2* 1/2* 1/2
1/128
A plane flies horizontally at an altitude of 5 km and passes directly over a tracking telescope on the ground. When the angle of elevation is /6, this angle is decreasing at a rate of /3 rad/min.
How fast is the plane traveling (in km/min) at that time? (Round your answer to two decimal places.)
Answer:
# rad u cant take 67 from it its going 35 mps
Step-by-step explanation:
3/2 equals 4x x=
?????
Answer:
0.375
Step-by-step explanation:
3/2 equals 1 and a half, and 1 and a half divided by 4 will get you 0.325
Answer:
4x - 2 = 3x + 1. Solution We substitute the value 3 for x in the equation and see if the left-hand member equals the right-hand member. 4(3) - 2 = 3(3) + 1.
Jacque is using a soup can for a school project and wants to paint it. If the can is 11 cm tall and has a diameter of 9 cm, at least how many square centimeters of paint is needed? Approximate using π = 3.14.
374.45 cm2
139.50 cm2
699.44 cm2
438.03 cm2
Answer:
The surface area of the soup can is given by the formula:
SA = 2πr² + 2πrh
where r is the radius of the circular ends of the can, h is the height of the can, and π is approximately 3.14.
The radius of the can is half of the diameter, so r = 4.5 cm.
Therefore, the surface area of the can is:
SA = 2π(4.5)² + 2π(4.5)(11)
SA = 2π(20.25) + 2π(49.5)
SA = 40.5π + 99π
SA = 139.5π
Approximating π as 3.14, we get:
SA ≈ 139.5 × 3.14
SA ≈ 438.03 cm²
Therefore, at least 438.03 square centimeters of paint are needed to cover the can.
So, the answer is 438.03 cm2.
I Hope This Helps!
Find the range of the data below
Answer:
81 is the answer
Step-by-step explanation:
87-6 range is highest and lowest number subtracted hope this helps:)
Find the probability of exactly 3 successes
in 6 trials of a binomial experiment in
which the probability of success is 75%.
P = [?]%
The prοbability οf exactly 3 successes in 6 trials οf a binοmial experiment with a prοbability οf success οf 75% is 31.1%, rοunded tο the nearest tenth οf a percent.
What is the prοbability?Prοbability is the study οf the chances οf οccurrence οf a result, which are οbtained by the ratiο between favοrable cases and pοssible cases.
Tο find the prοbability οf exactly 3 successes in 6 trials οf a binοmial experiment, we use the fοrmula:
The prοbability οf r successes in n trials is [tex]\rm _nC_r(p)^r(q)^{n-r[/tex], where p is the prοbability οf success οn a given trial and q = 1-p.
In this prοblem, n = 6, r = 3, p = q = 0.75
Sο, P(3 successes in 6 trials) = [tex]\rm _6C_3(0.75)^3(0.75)^3[/tex] = 0.13184 ≈ 13.2%
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WANT POINTS??
The graph shows g(x) = x2 − 8x + 15.
graph of parabola falling from the left, passing through 2 comma 3 to about 4 comma negative 1, and rising to the right, passing through 6 comma 3
What are the x-intercepts of g(x)?
(0, 3) and (0, 5)
(0, 4) and (0, 5)
(3, 0) and (5, 0)
(4, 0) and (5, 0)
Answer:
(3, 0) and (5, 0)
Step-by-step explanation:
Parabola equation is
g(x) = x²- 8x + 15
x-intercepts are the x-values when y = 0
Solve for x at g(x)=
==> x² - 8x + 15 = 0
This is a quadratic equation which has two solutions
Factoring x² - 8x + 15 gives (x - 3)(x - 5) which makes the quadratic equation
(x - 3)(x - 5) = 0
==> x - 3 = 0 giving x = 3 as one solution and x - 5 = 0 giving x = 5 as the other solution
At both intercepts, y = 0
So the correct answer is
(3, 0) and (5, 0)
Sue deposited $1,500 into two different accounts.
- She deposited $600 into an account that pays 7.5% simple interest.
- She deposited $900 into an account that pays 6% compounded annually.
If Sue does not deposit additional money into the accounts and she doesn't withdraw any
money from the accounts, which is closest to the total balance she will have in the two
accounts at the end of 5 years?
F $2,029.40
G $2,005.68
H $529.40
J $1,995.00
The total balance that Sue will have in the two accounts after 5 years can be calculated as follows:
Balance of the first account with simple interest:
FV = P(1 + rt)
FV = $600(1 + 0.075 x 5)
FV = $825
Balance of the second account with compounded interest:
FV = P(1 + r)^n
FV = $900(1 + 0.06)^5
FV = $1,286.87
Total balance = $825 + $1,286.87
Total balance = $2,111.87
The closest answer choice to this amount is F) $2,029.40, which is only off by a small margin. Therefore, the answer is F) $2,029.40.
Can you solve this question?
a) find the derivative=?
b) find the derivative=?
A. the derivative of y = log_a(x) is: y' = log_a(x) / (x ln(a))
B. the derivative of y = log_8(x) is: y' = 1 / (x ln(8 ln(10)))
a) Using the chain rule and the given identity, we have:
y = log_a(x)
ln(y) = ln(log_a(x))
ln(y) = ln(x) / ln(a)
y' / y = 1 / (x ln(a))
Multiplying both sides by y and simplifying, we get:
y' = y / (x ln(a))
y' = log_a(x) / (x ln(a))
Therefore, the derivative of y = log_a(x) is: y' = log_a(x) / (x ln(a))
b) Using the change of base formula for logarithms, we have:
y = log_8(x)
y = log(x) / log(8)
Using the chain rule, we have:
y' = (1 / (x ln(10))) * (1 / ln(8)) * d/dx [log(x)]
Using the chain rule for the natural logarithm, we have:
y' = (1 / (x ln(10))) * (1 / ln(8)) * (1/x)
Simplifying, we get:
y' = 1 / (x ln(8 ln(10)))
Therefore, the derivative of y = log_8(x) is:
y' = 1 / (x ln(8 ln(10)))
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2 logx 2 + logx 6 = 2
I really need this answer on properties of logarithms: practice
Answer:
Step-by-step explanation:
Simplify the expressionApply the logarithm power identityApply the logarithm product identitySimplify the expression2Exponentiate both sides
log10(4x8)=2log10(48)=2
48=102
x=258=258√
Solve for the tangent line of cos(x) at x= pi/4. Use the tangent line to estimate the value of cos(48).
The estimated value of cos(48) by using tangent line is found to be
0.99989.
Explain about the tangent line ?A straight line which thus touches a function only once is called a tangent line.
The first step is to calculate y when x=π/4. We will receive that target coordinate point as a result.
The required coordinate point is ( π/ 4, √(2) / 2)
The derivative of such function y is then discovered.
y ' = -sin(x)
Input the derivative with the value of x. This corresponds to the tangent line's slope.
y' = -sin(π/4)
y' = - √(2) / 2
The slope plus coordinate point are now entered into the gradient intercept form of the formula to obtain b.
y = mx + b
√(2) / 2 = (-√(2) / 2)(π / 4) + b
√(2) / 2 = (-π√(2) / 8) + b
(√(2) / 2) + (π√(2) / 8) = b
[4√(2) + π√(2)] / 8 = b
[(4 + π)√(2)] / 8 = b
The tangent line comes out to be:
y = (-√(2) / 2)x + [(4 + π)√(2) / 8]
Now , for cos(48).
48° = π/180 * 48 radians
48° = 3.14/180 * 48 radians
48° = 0.01744*48 radians
48° = 0.83712 radians
So, cos(48) = cos( 0.83712 )
Using scientific calculator:
cos(48) = cos( 0.83712 ) = 0.99989
Thus, the estimated value of cos(48) by using tangent line is found to be
0.99989.
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Find the value of x. Then tell whether the side lengths for a pythagorean triple
The value of x, given the measurements of the other sides of the triangle, would be 8.
The side lengths of the triangle form a Pythagorean triple.
How to find the value of x in the triangle ?To determine if the side lengths form a Pythagorean triple, we need to apply the Pythagorean theorem.
Using the Pythagorean theorem, we get:
6^2 + x^2 = 10^2
36 + x^2 = 100
x^2 = 100 - 36
x^2 = 64
x = 8
To determine if the side lengths form a Pythagorean triple, we need to check if the Pythagorean theorem holds true. Plugging in the values, we get:
6^2 + 8^2 = 10^2
36 + 64 = 100
100 = 100
The theorem holds true so this is indeed a Pythagorean triple.
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The full question is:
Find the value of x. Then tell whether the side lengths form a Pythagorean triple.
10, 6
Draw the image of ABC under a dilation whose center is C and scale factor is 2.
To draw the image of ABC under a dilation whose center is C and scale factor is 2, there are several steps by which we can draw the triangle.
What are the steps to draw the image ?Draw the original ABC triangle. A, B, and C are the vertices.
Make a point C' that is twice as far away from C as any other point on the triangle ABC. Draw a ray from C through any vertex of the triangle to accomplish this. (say, B). Then, double the length of the ray to find point C'.
Connect point C' to each vertex of the triangle with lines. A' and B' are the points where these lines intersect the original triangle.
Your new triangle A'B'C' is the dilation of ABC with centre C and scale factor 2.
The sides of the new triangle A'B'C' are twice as long as the sides of the original triangle ABC, and the angle between any two corresponding sides in both triangles is the same.
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Find the measure of the arc. Assume that lines which appear to be tangent are tangent
Answer:
190°
Step-by-step explanation:
56 = (1/2)(x - 78)
112 = x - 78
190 = x
x = 190
Answer: 190°
I'm a pretty sure that the answer is 190°, Hope this helps (:
Determine whether the statement is always true, sometimes true, or never true. Give examples. Both sides of an equation can be multiplied by the same number without changing the solution of the equation. A number can be added to both sides of an equation changing the solution of the equation.
The solution of the equation is x = 2. If we had multiplied both sides by a different number, such as 3 or -4.
What is solution of the equation ?
The solution of an equation is the value(s) of the variable(s) that make the equation a true statement. In other words, it is the value(s) that satisfy the equation.
For example, consider the equation 3x + 4 = 13. To find the solution, we need to determine the value of x that makes the equation true. the solution of the equation 3x + 4 = 13 is x = 3.
According to the question:
The first statement, "Both sides of an equation can be multiplied by the same number without changing the solution of the equation" is always true.
Example: Consider the equation 3x = 6. If we multiply both sides of this equation by 2, we get:
2 * 3x = 2 * 6
6x = 12
The solution of the equation is x = 2. If we had multiplied both sides by a different number, such as 3 or -4, we would still get the same solution.
The second statement, "A number can be added to both sides of an equation changing the solution of the equation" is sometimes true.
Example: Consider the equation 2x = 4. If we add 3 to both sides of the equation, we get:
2x + 3 = 4 + 3
2x + 3 = 7
The solution of the equation is x = 2.5. Adding 3 to both sides did not change the solution.
However, if we add a number that is equal to or related to the variable, the solution will change. For example, if we add x to both sides of the equation 2x = 4, we get:
2x + x = 4 + x
3x = 4 + x
The solution of the equation is x = 4/2 = 2, which is different from the previous solution of x = 2. Therefore, the statement "A number can be added to both sides of an equation changing the solution of the equation" is sometimes true, depending on the number being added.
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