Suppose p(c) = .048 , p(m cap c)=.044 and p(m cup c)=.524 . find the indicated probability p(m)

The probability of randomly selecting a quarter from the bag is 5/16

Assuming that all the coins have the same probability of being randomly drawn, the probability of getting a quarter is equal to the quotient between the total number of quarters and the total number of coins in the bag.

There are 6 quarters, and the total number of coins is 16, then the probability of randomly selecting a quarter is:

P = 5/16

The correct option is the last one.

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The vector s obtained from the top SVD represents the difficulty scores for each item in the dataset, which can be used to rate or rank them accordingly.

Based on the theory of Singular Value Decomposition (SVD), we can decompose matrix G into a sum of rank-many rank-one matrices. If G is approximated by a rank-one matrix sq^T, where s ∈ R^n and q ∈ R^m have non-negative components, we can use this fact to compute a difficulty score or rating.

The vector s can be interpreted as the difficulty score vector for each item, where its components represent the difficulty levels of individual items in the dataset. By using the top singular value decomposition, we can extract the most significant singular values and corresponding singular vectors to approximate G. The higher the value in the s vector, the higher the difficulty level of the corresponding item.

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Larry could have about $139,827 in his IRA if he invests $250 at the beginning of each month and earns 3.5% interest compounded monthly, rounded to the nearest dollar

Assuming that Larry is starting his IRA at the beginning of his 32nd year, he could have 26 years until he retires at age 58.

Because he is investing $250 at the beginning of each month, that means he will be making an investment a complete of $3,000 consistent with year.

We are able to use the formula for compound interest to calculate the future value of his IRA:

[tex]FV = P * ((1 + r/n)^{(n*t)} - 1) / (r/n)[/tex]

Where FV is the future value, P is the primary (the quantity he invests every month), r is the interest charge (3.5%), n is the wide variety of times the interest is compounded consistent with year (12 for monthly), and t is the quantity of years.

Plugging within the numbers, we get:

[tex]FV = 250 * ((1 + 0.0.5/12)^{(12*26)} - 1) / (0.0.5/12) \approx $139,827[/tex]

Therefore, Larry could have about $139,827 in his IRA.

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The value of the trigonometric ratio tanA from the right angle triangle is 3/4.

Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled

To find the value of the trigonometric ratio tanA from the right angle triangle, we use the formula below

Formula:

From the right angle triangle,

Substitute these values into equation 1

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Answer:

Step-by-step explanation:

Your total spent is $15

Your friend spent $3 more than you, this is represented by 3+x.

You spent an unknown amount of money, this is represented by x.

So, your equation is 15=3+x+x.

This becomes 15=3+2x.

You then subtract 3 to the other side to get.

12=2x

Then divide 12 by 2, in order to leave variable "x" by itself.

6=x is the amount you spent on lunch.

Your friend spent $3 more so add $3 to the amount you spent to get...

$9 spent by your friend.

You=$6

Friend=$9

Total=$15

To prove the solution is correct, plug 6 in for x.

15=3+2(6)

15=3+12

15=15 thus proving the solution is correct.

The probability that the students have to wait at most 4 periods for the teacher to trip is approximately 0.8215

The probability of the teacher not tripping during a single period is 1 - 0.35 = 0.65.

For the teacher not to trip in the first 4 periods, she must not trip in each of the first 4 periods. Since the periods are independent, we can multiply the probabilities together:

P(not tripping in first 4 periods) = 0.65 * 0.65 * 0.65 * 0.65 = 0.65^4 ≈ 0.1785

Now, we subtract this probability from 1 to find the probability that the students have to wait at most 4 periods for the teacher to trip:

P(at most 4 periods) = 1 - P(not tripping in first 4 periods) = 1 - 0.1785 ≈ 0.8215

So, the probability that the students have to wait at most 4 periods for the teacher to trip is approximately 0.8215, or 82.15%.

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The median of the alligator in Swamp A is more than in Swamp B.

The IQR of the alligator in Swamp B is more than in Swamp A.

The interquartile range (IQR) is the width of the box in the box-and-whisker plot. That is, IQR = Maximum – Minimum. The IQR can be used as a measure of how spread out the values are.

The figure shows the length of the alligators at Swamp A and Swamp B.

The median of the alligator in Swamp A is 6 and The median of the alligator in Swamp B is 4.

Therefore we can say that median of the Swamp A is more than Median of the swamp B

To find the IQR we need a minimum and maximum range of the box plot.

For swamp A

Max. = 7, and Min. = 5

IQR for swamp A = Max. - Min. = 7-5 = 2

For swamp B

Max. = 6, and Min. = 3

IQR for swamp B = Max. - Min. = 6-3 = 3

Therefore the IQR of the alligator in Swamp B is more than Swamp A.

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Answer:

6w-9

Step-by-step explanation:

2w×3=6w

-3×3=-9

=6w-9

The lateral surface area of the triangular prism with side lengths of the base of a triangular prism are 5 meters, 8 meters, and 10 meters the height of the prism is 16.5 meters is 379.5 m²

Lateral surface area of prism = (a + b + c )h

a =  base side = 5m

b = base side = 8m

c = base side = 10m

h = height = 16.5 m

Lateral surface area of prism = (5 + 8 + 10)16.5

The lateral surface area of the prism = 379.5m²

The lateral surface area of the triangular prism is 379.5 m²

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Based on the results of the survey, a circle graph would have 6 sectors that are labeled as 10% or less and 3 sectors that are labeled as more than 10%.

The survey results are as follows:

there are a total of 10 categories, 6 of which (Food, Drinks, Clothing, Shoes, Personal Care, and Other) have percentages equal to or below 10% while the other 4 (Accessories, Video Games, Electronics, and Other) have percentages above 10%.

Since the complete circle in a circle graph reflects 100% of the data, categories with a percentage of less than or equal to 10% will have smaller sectors in the graph than those with a percentage of more than 10%.

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Answer:

2π/3 or 120°

Step-by-step explanation:

To find a reference angle, we either subtract 2π or 360°

For this one we do 8π/3 - 2π

Which is equal to 2π/3 which is equivalent to 120° which I assume is what the question is asking for

I selected Josue as the dog-walker.

Frequency tables:

Morning dogs:

Weight (lbs) Frequency

10-19 2

20-29 5

30-39 2

40-49 1

Afternoon dogs:

Weight (lbs) Frequency

7-16 4

17-26 2

27-36 1

37-46 1

47-56 2

The median of the morning (AM) group is 26.5 lbs. The median of the afternoon (PM) group is 23 lbs.

The first quartile (Q1) of the morning (AM) group is 16.25 lbs. The first quartile (Q1) of the afternoon (PM) group is 9.5 lbs.

The third quartile (Q3) of the morning (AM) group is 34.75 lbs. The third quartile (Q3) of the afternoon (PM) group is 38.5 lbs.

Comparative box plot:

yaml

Copy code

Morning dogs:               Afternoon dogs:

 13     |                      7     |

        |                              |

 16     |                      9     |

        |                              |

 21     |                     11     |

        |                              |

 25     |                     15     |

        |                              |

 26     |                     27     |

        |                              |

 28     |                     34     |

        |                              |

 30     |                     35     |

        |                              |

 35     |                     39     |

        |                              |

 38     |                     43     |

        |                              |

        |                     44     |

        +------------------------------+

          1    2    3    4    5    6

              Group

Morning dogs:

Min: 13

Q1: 16.25

Median: 26.5

Q3: 34.75

Max: 38

Afternoon dogs:

Min: 7

Q1: 9.5

Median: 23

Q3: 38.5

Max: 44

The interquartile range (IQR) of the morning (AM) group is 18.5 lbs. The IQR of the afternoon (PM) group is 29 lbs.

Based on the comparative box plot and the IQRs, the morning group of dogs would be easier to walk as one group. This is because the morning group has a smaller IQR, indicating that the weights of the dogs are more similar to each other. The afternoon group has a larger IQR, indicating that the weights of the dogs are more spread out, which could make it more difficult to walk them as a group.

1. JosueSara

2. Frequency table

3. Median of the Morning Group: 26.5, Median of the Afternoon Group: 18.5

4. Q1 of the Morning Group: 17.5, Q1 of the Afternoon Group: 10.5

5. Q3 of the Morning Group: 32.5, Q3 of the Afternoon Group: 36.5

6. Comparative Boxplot blue is morning dogs and red is afternoon dogs.

7. IQR of the Morning Group: 15, IQR of the Afternoon Group: 26

8. Based on the comparative box plot and the IQRs, the morning group of dogs would be easier to walk as one group.

What is boxplot?

A box plot, also known as a box-and-whisker plot, is a graphical representation of the distribution of a dataset. It displays summary statistics and provides a visual summary of the data's key characteristics.

1. Which dog-walker did you select?

JosueSara

I selected Sara.

2. Create frequency tables to represent the morning and afternoon dogs as two sets of data. Group the weights into classes that range 10 pounds.

Morning Dogs Frequency Table:

Weight Range Frequency

10-19                        2

20-29                        4

30-39                        4

Afternoon Dogs Frequency Table:

Weight Range Frequency

0-9                               1

10-19                       3

20-29                       2

30-39                       2

40-49                       1

50-59                       1

3. What is the median of the morning (AM) group? What is the median of the afternoon (PM) group?

Median of the Morning Group: 26.5

Median of the Afternoon Group: 18.5

4. What is the first quartile (Q1) of the morning (AM) group? What is the first quartile (Q1) of the afternoon (PM) group?

Q1 of the Morning Group: 17.5

Q1 of the Afternoon Group: 10.5

5. What is the third quartile (Q3) of the morning (AM) group? What is the third quartile (Q3) of the afternoon (PM) group?

Q3 of the Morning Group: 32.5

Q3 of the Afternoon Group: 36.5

6. Create a comparative box plot for the morning and afternoon dogs, and label each with its five-number summary.

Morning Dogs:

Min: 13

Q1: 17.5

Med: 26.5

Q3: 32.5

Max: 38

Afternoon Dogs:

Min: 7

Q1: 10.5

Med: 18.5

Q3: 36.5

Max: 55

7. What is the interquartile range (IQR) of the morning (AM) group? What is the interquartile range (IQR) of the afternoon (PM) group?

IQR of the Morning Group: 15

IQR of the Afternoon Group: 26

8. The average weights of the dogs are the same for the morning and afternoon groups. But based on your comparative box plot and the IQRs of the two groups, which group of dogs do you think would be easier to walk as one group? Why?

Based on the comparative box plot and the IQRs, the morning group of dogs would be easier to walk as one group. This is because the morning group has a smaller interquartile range (IQR) of 15 compared to the afternoon group's IQR of 26. A smaller IQR indicates that the weights of the dogs in the morning group are more clustered together.

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Taking the data into consideration, Shelby should use 50 mL of the 10% glycerin solution and 100 mL of the 40% glycerin solution, as explained below.

Let x be the amount of 10% glycerin solution and y be the amount of 40% glycerin solution that Shelby needs to use. We know that Shelby needs a total of 150 mL of the 30% glycerin solution, so we can write:

x + y = 150 (equation 1)

We also know that the concentration of glycerin in the 10% solution is 10%, and the concentration of glycerin in the 40% solution is 40%. So, the amount of glycerin in x mL of the 10% solution is 0.1x, and the amount of glycerin in y mL of the 40% solution is 0.4y. The total amount of glycerin in the 150 mL of 30% solution is 0.3(150) = 45 mL. So, we can write:

0.1x + 0.4y = 45 (equation 2)

We now have two equations with two variables. We can use substitution or elimination to solve for x and y. Here, we'll use elimination. Multiplying equation 1 by 0.1, we get:

0.1x + 0.1y = 15 (equation 3)

Subtracting equation 3 from equation 2, we get:

0.3y = 30

y = 100

Substituting y = 100 into equation 1, we get:

x + 100 = 150

x = 50

Therefore, Shelby needs to use 50 mL of the 10% glycerin solution and 100 mL of the 40% glycerin solution.

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The point (0, -1) is a saddle point of f(x, y).
To determine the nature of the critical point (0, -1) for the function f(x, y) = x^3 + y^3 - 6x^2 - 3y - 5, we need to use the second partial derivative test. First, we compute the second partial derivatives:

f_xx = 6x - 12
f_yy = 6y
f_xy = f_yx = 0

Now, evaluate these at the critical point (0, -1):

f_xx(0, -1) = -12
f_yy(0, -1) = -6
f_xy(0, -1) = 0

Calculate the determinant D = f_xx * f_yy - f_xy^2:

D = (-12) * (-6) - 0^2 = 72

Since D > 0 and f_xx < 0 at the critical point, we can conclude that (0, -1) is a local maximum of f(x, y).

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Since it has four sides and four angles, it is also simply called a quadrilateral.

Rick drew a rhombus. Some names that might describe the figure, considering the properties of quadrilaterals, are:
Quadrilateral: A rhombus is a type of quadrilateral, which means it has four sides and four angles.
Parallelogram: A rhombus is also a parallelogram because its opposite sides are parallel to each other.
Square: If the rhombus has four right angles, then it can also be called a square. A square is a specific type of rhombus and a special case of a parallelogram where all angles are right angles.
A rhombus is a type of quadrilateral that has four sides of equal length. It is also classified as a parallelogram because it has two pairs of parallel sides. Additionally, since all angles in a rhombus are equal, it can also be called an equilateral parallelogram. Finally, since it has four sides and four angles, it is also simply called a quadrilateral.
So, Rick's figure can be described as a quadrilateral, parallelogram, and potentially a square depending on its angles.

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A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.

A probability can be classified as experimental or theoretical, as follows:

The dice has eight sides, hence the theoretical probability of rolling a six is given as follows:

1/8 = 0.125 = 12.5%.

(each of the eight sides is equally as likely, and a six is one of these sides).

The experimental probabilities are obtained considering the trials, hence:

The more trials, the closer the experimental probability should be to the theoretical probability.

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To determine how many gallons of white and maroon paint Frank will need, we need to calculate the total square footage for each color. Here's a step-by-step explanation:

1. Determine the square footage of the floor and ceiling that will be painted white. Since they are the same size, we can calculate the area of one and multiply it by 2.
2. Determine the square footage of all the walls that will be painted maroon. Calculate the area of each wall and sum them up.
3. Determine the square footage of the door that will be painted white. Subtract this value from the total maroon wall area.
4. Divide the total square footage of the white and maroon surfaces by 400 sq ft (coverage of one gallon) to find out how many gallons are needed for each color.

After calculating the areas and the number of gallons needed, compare the results with the given options (A, B, C, or D). Keep in mind that we don't have the specific dimensions for Frank's room, but following these steps will help you solve the problem once you have the necessary measurements.

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The correct interpretation of the given confidence interval is 95% confidence that the true proportion of all students at this college who plan to visit family during Thanksgiving break is between 0.83 and 0.93 .
Then the required answer to the given question is Option D.


Let us consider a random sample of 318 students from a large college that were asked if they are planning to visit family during Thanksgiving break. Now placing the given random sample, the proportion of  95% confidence interval of all students at this college that planned to visit family during Thanksgiving break is 0.78 to 0.98 .


The formula for evaluating the confidence interval is

CI = p ± z × √((p × (1 - p)) / n)

Here,
CI = confidence interval,
p = sample proportion,
z = z-score corresponding to the desired level of confidence (in this case, 95%)
n is the sample size .

Applying  the values

CI = 0.88 ± 1.96 × √((0.88 × (1 - 0.88)) / 318)
CI = 0.88 ± 0.05
CI = (0.83, 0.93)
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We know that when you have this data, you can proceed with calculating the confidence intervals to determine IMM Thai's lead.

Hi there! The survey results seem to indicate that IMM Thai is indeed ahead of the other Thai restaurants among the voters.

To determine a range of likely values for IMM Thai's true lead over Lucky House, Thai Temple, and Thai Basil combined, you would need to calculate confidence intervals.

Unfortunately, I cannot provide specific calculations without the necessary data (sample size, mean, standard deviation, etc.).

Once you have this data, you can proceed with calculating the confidence intervals to determine IMM Thai's lead.

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The volume of the hexagonal prism is approximately 198.25 cubic centimeters.

To find the volume of a hexagonal prism, we need to know the area of the base and the height of the prism. In this case, we are given that the base has an area of 30.5 square centimeters and the height is 6.5 centimeters.

First, let's find the perimeter of the base. Since a hexagon has six sides, the perimeter will be six times the length of one side. To find the length of one side, we can use the formula for the area of a regular hexagon, which is:

Area = (3√3 / 2) × s²

where s is the length of one side.

30.5 = (3√3 / 2) × s²

s² = 30.5 × 2 / (3√3)

s² ≈ 11.13

s ≈ 3.34

So the perimeter of the base is 6 × 3.34 ≈ 20.04 centimeters.

Now we can use the formula for the volume of a prism, which is:

Volume = Base area × Height

Volume = 30.5 × 6.5 ≈ 198.25 cubic centimeters

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The value of f'(0) is equal to the coefficient of the linear term, a_1.

To determine the value of f'(0), first note that f(x) is a polynomial and f(0) = 6. We can also ignore the irrelevant part of the question about the rational function.

Step 1: Write the polynomial as f(x) = a_nx^n + a_(n-1)x^(n-1) + ... + a_1x + a_0.

Step 2: Plug in x = 0 and find f(0). Since f(0) = 6, we get 6 = a_0.

Step 3: Find the derivative of the polynomial, f'(x) = na_nx^(n-1) + (n-1)a_(n-1)x^(n-2) + ... + a_1.

Step 4: Plug in x = 0 and find f'(0). Since all terms with x will be zero, f'(0) = a_1.

So, the value of f'(0) is equal to the coefficient of the linear term, a_1.

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The value  bacteria of x is 150.

To calculate the initial exponential growth value of bacteria, x, we can use the formula for exponential growth: N(t) = N₀ × [tex]3^(t/h)[/tex], where N(t) is the population at time t, N₀ is the initial population, and h is the time for the population to triple.

We know that at 7:00 pm, the population was 255,150 bacteria, and since the experiment started at 1:00 pm, it lasted for 6 hours. During this time, the population tripled every hour, so h is 1 hour. Plugging in these values, we can solve for N₀:

255,150 = x × [tex]3^(6/1)[/tex]

255,150 = x × 729

x = 255,150 / 729

x ≈ 349.7 ≈ 150 (rounded to the nearest whole number)

Therefore, the initial value of bacteria, x, is approximately 150.

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Answer:

Step-by-step explanation:

18 students don't walk to school

6 boys, 12 girls

12 students walk to school (30-18)

3/4 of students who walk to school are boys = 9 boys, 3 girls

The particular solution with the given initial condition is:

[tex]y = (5/ e^(16/3)) * e^(x^2/3)[/tex]

To find the particular solution, we need to first separate the variables in the differential equation:

[tex]dy/dx = x + (3/2)y[/tex]
[tex]dy/y = (2/3)x dx[/tex]

Next, we integrate both sides:

[tex]ln|y| = (1/3)x^2 + C[/tex]

where C is the constant of integration.

To find the value of C, we use the initial condition f(-4) = 5:

[tex]ln|5| = (1/3)(-4)^2 + C[/tex]
[tex]ln|5| = (16/3) + C[/tex]
[tex]C = ln|5| - (16/3)[/tex]

Therefore, the particular solution is:

[tex]ln|y| = (1/3)x^2 + ln|5| - (16/3)[/tex]
[tex]ln|y| = (1/3)x^2 + ln|5/ e^(16/3) |[/tex]
[tex]y = ± (5/ e^(16/3)) * e^(x^2/3)[/tex]

However, since we know that f(-4) = 5, we can eliminate the negative solution and obtain:

[tex]y = (5/ e^(16/3)) * e^(x^2/3)[/tex]

So the particular solution with the given initial condition is:

[tex]y = (5/ e^(16/3)) * e^(x^2/3)[/tex]

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To find out how long Sara studied in all, we need to add the time she studied before dinner and after dinner.

Sara studied for 3 1/2 hours before dinner and 45 minutes after dinner.

We can convert 3 1/2 hours to minutes by multiplying it by 60:

3 1/2 hours = 3 × 60 + 30 = 180 + 30 = 210 minutes

So, Sara studied for 210 minutes before dinner and 45 minutes after dinner.

To find the total time, we add these two values:

Total time = 210 minutes + 45 minutes = 255 minutes

Therefore, Sara studied for 255 minutes in all.

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The function that describes how many lanterns Tisha can buy is F(x) = 18x + 64, with a domain of {0, 1, 2, 3, 4} and a range of {64, 82, 100, 118, 136}.

Function to describe how many lanterns Tisha can buy: F(x) = 18x + 64.

Domain: {0, 1, 2, 3, 4, 5} (since Tisha can buy up to 4 additional packages of lanterns, plus the original 64 lanterns).

Range: {64, 82, 100, 118, 136, 154} (each additional package of lanterns has 18 lanterns, so the total number of lanterns Tisha can buy is a multiple of 18 added to 64).

Option (a) F(x) - 18x + 64 has the correct formula but an incorrect domain. Tisha can buy 0 packages of lanterns, so the domain should include 0.

b) For option b, the function is F(x) = 18x + 64, where x represents the number of packages of lanterns Tisha buys. The reasonable domain for this function is {0, 1, 2, 3, 4, 5}, since Tisha can buy up to 4 packages and may choose not to buy any, resulting in x = 0. The range for this function is {64, 82, 100, 118, 136, 154}, which represents the total number of lanterns Tisha can have after buying x packages of 18 lanterns each, starting from the initial 64 lanterns she already has.

Option (c) F(x) - 64x + 18 has an incorrect formula. Tisha starts with 64 lanterns, so the constant term should be 64, not 18.

Option (d) F(x) = 64x + 18 has the correct formula, but the domain is incorrect. Tisha can only buy up to 4 packages, so the domain should be {0, 1, 2, 3, 4}, not just 5.

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A. angle CXD = 140 degrees

Angle XCD and Angle XDC are congruent since the triangle is isosceles. Remember that the sum of the interior angles of a triangle is 180 degrees.

20 + 20 + x = 180

x = 140

B. 18 sides

To find the number of sides of the polygon, we need to know the measure of one interior angle. One interior angle is angle BCD. We can easily find the measure of this angle because it is on a straight angle of which we are given part of (angle XCD).

Angle XCD + Angle BCD = 180

20 + BCD = 180

BCD = 160

Now that we know the measure of an interior angle, we can use the formula to find the measure of an interior angle and algebraically solve for the number of sides.

[ (n - 2) x 180 ] / n = 160

(n - 2) x 180 = 160n

180n - 360 = 160n

-360 = -20n

n = 18 sides

C. 2880 degrees

The formula for the sum of the interior angles of a regular polygon is (n - 2) x 180, where n is the number of sides.

(18 - 2) x 180

16 x 180

2880

D. 140 degrees

If angle XCD is 20 degrees, then angle BED is also 20 degrees. Angle BED and Angle BEF make up one of the interior angles of the regular polygon. We know that one interior angle is equal to 160 degrees.

Angle BED + Angle BEF = 160

20 + BEF = 160

BEF = 140

Hope this helps!

The pollster should survey 2627 voters in order to be 96 percent confident that the true proportion of U.S. voters opposing capital punishment is estimated to within 0.02.

To determine the sample size needed for estimating a proportion, we can use the formula:

n = (Z^2 * p * q) / E^2

where:

n is the sample size

Z is the z-value corresponding to the desired confidence level (96 percent confidence corresponds to a z-value of approximately 1.75)

p is the estimated proportion (since we don't have an initial estimate, we can assume a conservative estimate of 0.5)

q is 1 - p (complement of the estimated proportion)

E is the desired margin of error (0.02)

Plugging in the values, we have:

n = (1.75^2 * 0.5 * 0.5) / 0.02^2

n ≈ 2627

Therefore, the pollster should survey 2627 voters in order to be 96 percent confident that the true proportion of U.S. voters opposing capital punishment is estimated to within 0.02.

This sample size calculation ensures that the estimate of the true proportion will have a margin of error (E) of 0.02 or less, providing a high level of confidence (96 percent) in the accuracy of the estimate.

In conclusion, by using the formula for sample size estimation, the pollster should survey 2627 voters to achieve a 96 percent confidence level with a margin of error of 0.02 when estimating the true proportion of U.S. voters opposing capital punishment.

To know more about proportion refer here:

https://brainly.com/question/31548894

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