tan(x)>(3^1/2)+1 Range for x( 0

Answer:

B

Step-by-step explanation:

using the diamond factoring method:

2x^2-12x+x-6

2x(x-6) + (x-6)

(2x+1)(x-6)

B

To determine how many triangles are represented by the angles a=120 degrees, a=250 degrees, and b=195 degrees, we need to use the triangle inequality theorem. This theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

First, we need to determine which angle corresponds to which side. Let's assume that angle a is opposite to the longest side, and angle b is opposite to the shortest side. Therefore, we have: a = 250 degrees (longest side) a = 120 degrees b = 195 degrees (shortest side) Next, we need to use the triangle inequality theorem to determine which combinations of sides can form a triangle. For any two sides a and b, the third side c must satisfy the following condition: c < a + b Using this condition, we can determine the valid combinations of sides: - a + b > c: This is always true, since a and b are the longest and shortest sides, respectively. - a + c > b: This is true for all values of c, since a is the longest side. - b + c > a: This is true only when c > a - b.

Substituting the given values, we get: c > a - b c > 250 - 195 c > 55 Therefore, any side c that is greater than 55 can form a triangle with sides a and b. We can use this condition to count the number of valid triangles: - If c = 56, then we have one triangle. - If c = 57, then we have two triangles (c can be either adjacent side). - If c = 58, then we have three triangles (c can be any of the three sides). Continuing this pattern, we can count the number of triangles for each value of c: c = 56: 1 triangle c = 57: 2 triangles c = 58: 3 triangles c = 59: 4 triangles c = 60: 5 triangles c = 61: 6 triangles c = 62: 7 triangles c = 63: 8 triangles c = 64: 9 triangles c = 65: 10 triangles c = 66: 11 triangles c = 67: 12 triangles c = 68: 13 triangles c = 69: 14 triangles c = 70: 15 triangles c > 70: 16 triangles (since all three sides can form a triangle) Therefore, there are 16 possible triangles that can be formed with the given angles and side lengths.

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Light travels at a constant speed of approximately 3 x 10⁸ meters per second in a vacuum, which is also known as the speed of light.

The speed of light is a fundamental constant in physics and is denoted by the symbol "c". In a vacuum, such as outer space, light travels at a constant speed of approximately 299,792,458 meters per second, which is equivalent to 3 x 10⁸ meters per second (to three significant figures).

In the question, we were given the distance that light travels in one year (9.45 x 10¹⁵ meters) and the number of seconds in one year (3.15 x 10⁷ seconds). To find how far light travels per second, we simply divided the distance per year by the time per year.

To find how far light travels per second, we need to divide the distance it travels in a year by the number of seconds in a year:

Distance per second = Distance per year / Time per year

Distance per second = 9.45 x 10¹⁵ meters / 3.15 x 10⁷ seconds

Distance per second = 3 x 10⁸ meters per second (approx.)

Therefore, light travels approximately 3 x 10⁸ meters per second, which is also known as the speed of light.

It is worth noting that the speed of light is an extremely important quantity in physics and has many implications for our understanding of the universe. For example, the fact that the speed of light is constant in all reference frames is a key component of Einstein's theory of relativity. Additionally, the speed of light plays a crucial role in astronomy and cosmology, as it allows us to measure the distances between celestial objects and study the behavior of light over vast distances.

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Valterri would finish 1.1776 minutes (or 70.656 seconds) faster than if he raced at his Day 1 rate, if he raced at his Day 2 rate for the entire 64-lap race

To calculate how much faster Valterri would finish the full race if he raced at his Day 2 rate compared to his Day 1 rate, we need to first calculate his time difference per lap.

On Day 1, Valterri's rate was 3.2, which means he completed each lap in 1/3.2 or 0.3125 minutes (18.75 seconds).

On Day 2, his rate was 3.4, so he completed each lap in 1/3.4 or 0.2941 minutes (17.65 seconds).

The time difference per lap between Day 1 and Day 2 is 0.3125 - 0.2941 = 0.0184 minutes (or 1.104 seconds).

To find out how much faster Valterri would finish the full race if he raced at his Day 2 rate, we need to multiply this time difference per lap by the number of laps in the race.

The race has 64 laps, so:

Time difference = 0.0184 x 64 = 1.1776 minutes (or 70.656 seconds)

Therefore, if Valterri raced at his Day 2 rate for the entire 64-lap race, he would finish 1.1776 minutes (or 70.656 seconds) faster than if he raced at his Day 1 rate.

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The volume of the rectangular prism is 31.5 in³.

From the diagram, we know that the height of the rectangular prism is 9 cubes. We can see the length is 7 cubes and the width is 4 cubes. Each cube is half an inch. Therefore we multiply every side by 1/2.

Height = 9 × (1/2)

Height = 4.5 inches

Length = 7 × (1/2)

Length = 3.5 inches

Width = 4 × (1/2)

Width = 2 inches

Volume = L × W × H

Volume = 3.5 × 2 × 4.5

Volume = 31.5 inches³

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The sine function for the graph is given as follows:

y = sin(3x).

(a one should be placed on the green blank).

The standard definition of the sine function is given as follows:

y = Asin(Bx).

For which the parameters are given as follows:

The function oscillates between y = -1 and y = 1, for a difference of 2, hence the amplitude is obtained as follows:

2A = 2

A = 1.

The period is of 2π/3 units, hence the coefficient B is given as follows:

B = 3.

Then the equation is:

y = sin(3x).

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Answer:

Step-by-step explanation:

The volume of the pyramid with a square base of side length 16.6 meters and a height of 9.1 meters is approximately 836.6 cubic meters.

To find the volume of a pyramid with a square base, you'll need to know the side length of the base and the height of the pyramid. In this case, the side length of the square base is 16.6 meters, and the height of the pyramid is 9.1 meters. Here's a step-by-step explanation to calculate the volume:

1. Find the area of the square base: Since the base is a square, you'll need to multiply the side length by itself.
Area = side_length × side_length
Area = 16.6 m × 16.6 m
Area ≈ 275.56 m²

2. Calculate the volume of the pyramid: To find the volume, you'll multiply the area of the base by the height of the pyramid and divide the result by 3.
Volume = (Area × Height) / 3
Volume ≈ (275.56 m² × 9.1 m) / 3
Volume ≈ 836.626 m³

3. Round the answer to the nearest tenth of a cubic meter:
Volume ≈ 836.6 m³

So, the volume of the pyramid with a square base of side length 16.6 meters and a height of 9.1 meters is approximately 836.6 cubic meters.

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So, the final answer is:

(1/2)(-√(4 - x^2) / x) + C. To evaluate the integral ∫dx / (x^2√(4-x^2)), we will use the trigonometric substitution x = 2sin(θ). This substitution is chosen because it simplifies the expression under the square root, as 4 - x^2 becomes 4 - 4sin^2(θ) which can be factored into 4cos^2(θ).

Now, we need to find dx in terms of dθ. Differentiating x with respect to θ, we get:

dx/dθ = 2cos(θ) => dx = 2cos(θ)dθ

Substituting x = 2sin(θ) and dx = 2cos(θ)dθ into the integral:

∫(2cos(θ)dθ) / ((2sin(θ))^2√(4(1-sin^2(θ))))
= ∫(2cos(θ)dθ) / (4sin^2(θ)√(4cos^2(θ)))

Simplifying the integral, we get:

= (1/2) ∫(cos(θ)dθ) / (sin^2(θ)cos(θ))
= (1/2) ∫dθ / sin^2(θ)

Now, use the identity csc^2(θ) = 1/sin^2(θ) and integrate:

= (1/2) ∫csc^2(θ) dθ
= (1/2)(-cot(θ)) + C

To find cot(θ), we draw a right triangle with the opposite side x, the adjacent side √(4 - x^2), and the hypotenuse 2:

cot(θ) = adjacent / opposite = √(4 - x^2) / x

So, the final answer is:

(1/2)(-√(4 - x^2) / x) + C

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Answer:

8x - 16 = 40

8x = 56

x = 7

Hope this helps! :D

The integral value of  [tex]e ^{-x cos2x}[/tex] under the given condition is 1/4.

The integral of  [tex]e ^{-x cos2x}[/tex]  from 0 to infinity can be solved using integration by parts.

Let u = cos(2x) and dv = [tex]e^{(-x)dx}[/tex].

Then du/dx = -2sin(2x) and v = [tex]-e^{(-x)}[/tex].

Using integration by parts, we get:

∫[tex]e^{(-x)cos(2x)dx}[/tex] = [tex]-e^{(-x)cos(2x)/2}[/tex] + ∫[tex]e^{(-x)sin(2x)dx}[/tex]

Now, let u = sin(2x) and dv = [tex]e^{(-x)dx}[/tex]

Then du/dx = 2cos(2x) and v =[tex]-e^{(-x)}[/tex].

Using integration by parts again, we get:

∫[tex]e^{(-x)cos(2x)dx}[/tex] = [tex]-ex^{(-x)cos(2x)/2}[/tex] - [tex]e^{(-x)sin(2x)/4}[/tex] + C

here

C = constant of integration.

Therefore, the integral of [tex]e^{(-x)cos(2x)}[/tex] from 0 to infinity is

= [tex]-e^{(0)(cos(0))/2}[/tex] - [tex]e^{(0)(sin(0))/4 }[/tex]+[tex]e^{ (-infinity)(cos(infinity))/2}[/tex] + [tex]e^{(-infinity)(sin(infinity))/4.}[/tex]

Simplifying this expression gives us:

∫[tex]e^{(-x)cos(2x)dx }[/tex]

= 1/4

The integral value of  [tex]e ^{-x cos2x}[/tex] under the given condition is 1/4.

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The area of the shaded region is 5 sq units and the percentage of the shaded region is 83.33%

The area of the shaded region is the difference between the area of the rectangle and the area of the clear region

Assuming the following dimensions

So, we have

Shaded = 3 * 2 - 2 * 1/2 * 1 * 1

Evaluate

Shaded = 5

This is calculated as

Percentage = Shaded/Rectangle

So, we have

Percentage = 5/(3 * 2)

Evaluate

Percentage = 83.33%

Hence, the percentage of the shaded region is 83.33%

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Base on the word problem, Bernard is currently 21.25 years old. When Hector turns 18, he will be (18 - 17) = 1 year older than his current age. At that time, Bernard will be (21.25 + 1) = 22.25 years old.

Let's start by assigning variables to represent the current ages of Bernard and Hector. Let B be Bernard's current age and H be Hector's current age. Then we can write two equations based on the given information:

"When Bernard was as old as Hector is now, Bernard's age was 4 times Hector's age then." This means that Bernard is currently (B - H) years older than Hector, and that the age difference between them has remained constant over time. So, we can write: B - (B - H) = 4(H - (B - H)).

Simplifying this equation, we get: B - B + H = 4(2H - B)

Simplifying further, we get: 5H - 4B = 0, or B = (5/4)H.

"When Hector will be as old as Bernard is now, the sum of their ages will be 51." This means that when Hector is (B - H) years older than his current age, their sum of ages will be 51. So, we can write: B + (B - H + (B - H)) = 51.

Simplifying this equation, we get: 3B - 2H = 51.

Now we have two equations with two variables. We can substitute the expression for B from the first equation into the second equation, and solve for H:

3B - 2H = 51

3(5/4)H - 2H = 51

(15/4)H = 51

H = 17

So, Hector is currently 17 years old. To find out how old Bernard will be when Hector turns 18, we can use the expression we found earlier for B in terms of H:

B = (5/4)H

B = (5/4)(17)

B = 21.25

So, Bernard is currently 21.25 years old. When Hector turns 18, he will be (18 - 17) = 1 year older than his current age. At that time, Bernard will be (21.25 + 1) = 22.25 years old.

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In summary, we can say that there is a significant difference in the mean scores of the graduates in the two commercial institutes.

To determine if there is a significant difference between the mean scores of the graduates in the two commercial institutes, we can perform an independent samples t-test. Here's how to approach it:

Step 1: State the hypotheses:

Null hypothesis (H0): The mean scores of the graduates in the two commercial institutes are equal.

Alternative hypothesis (Ha): The mean scores of the graduates in the two commercial institutes are significantly different.

Step 2: Set the significance level:

The significance level (α) is given as 1%, which corresponds to a critical value of 0.01.

Step 3: Calculate the test statistic:

The test statistic for an independent samples t-test is calculated using the following formula:

t = (mean1 - mean2) / √[(S1^2 / n1) + (S2^2 / n2)]

Given:

Mean of the first group (mean1) = 65

Standard deviation of the first group (S1) = 15

Sample size of the first group (n1) = 35

Mean of the second group (mean2) = 70

Standard deviation of the second group (S2) = 10

Sample size of the second group (n2) = 35

Plugging in the values, we can calculate the test statistic:

t = (65 - 70) / √[(15^2 / 35) + (10^2 / 35)]

t = -5 / √[225/35 + 100/35]

t = -5 / √[325/35]

t ≈ -5 / 1.787

t ≈ -2.8 (rounded to one decimal place)

Step 4: Determine the critical value and compare:

Since the significance level (α) is 1%, the critical value for a two-tailed test is ±2.61 (obtained from a t-distribution table or a statistical software).

Since the calculated test statistic (-2.8) is greater than the critical value (-2.61) in absolute value, we reject the null hypothesis.

Step 5: Interpret the result:

Based on the test, we have sufficient evidence to conclude that there is a significant difference between the mean scores of the graduates in the two commercial institutes at the 1% level of significance.

In summary, we can say that there is a significant difference in the mean scores of the graduates in the two commercial institutes.

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To withdraw $3,200 quarterly at an interest rate of 4.5% for 18 years, the account balance needs to be approximately $178,311. This is calculated using the formula for the present value of an annuity, where the payment, interest rate, time period, and compounding frequency are considered.

To find the account balance needed, we need to use the present value of an annuity formula.

Convert the annual interest rate to a quarterly rate: 4.5% / 4 = 1.125%

Convert the number of years to the number of quarters: 18 years * 4 quarters per year = 72 quarters

Calculate the present value of the annuity using the formula:

PV = PMT * (1 - (1 + r)⁻ⁿ) / r

where PV is the present value, PMT is the regular withdrawal amount, r is the quarterly interest rate, and n is the number of quarters.

Plugging in the values, we get

PV = 3200 * (1 - (1 + 0.01125)⁻⁷²) / 0.01125

= 3200 * (1 - 0.2717) / 0.01125

= 178,311.11

Round the answer to the nearest dollar: $178,311

Therefore, the account needs to hold $178,311 to make regular withdrawals of $3200 per quarter for 18 years at a quarterly interest rate of 4.5%.

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The value of the variables are;

x = 52

y = 30

from the information given, we have simultaneous equations ;

−7y−4x=1

7y−2x=53

Make 'y' the subject from equation 1 , we have;

y = 1 + 4x/-7

Substitute the value into equation 2, we get;

7(1 + 4x/-7) - 2x = 53

expand the bracket

7 + 28x/-7 - 2x= 53

7 + 28x + 14x = 53(-7)

then, we have;

7 + 42x =,-371

collect the like terms

42x = 364

x = 52

Substitute the value

y =  1 + 4x/-7

y = 1+ 4(52)/-7

y = 30

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In scientific notation, the difference between (8.64 x 10^20) and (7.83 x 10^20) is expressed as 8.1 x 10^19.

To find the difference between (8.64 x 10^20) and (7.83 x 10^20), we subtract the second number from the first:

8.64 x 10^20 - 7.83 x 10^20 = 0.81 x 10^20

Since the difference is less than one, we express the answer in scientific notation by moving the decimal point one place to the left and increasing the exponent by one:

0.81 x 10^20 = 8.1 x 10^19

Therefore, the difference between (8.64 x 10^20) and (7.83 x 10^20) expressed in scientific notation is 8.1 x 10^19.

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The value of angle x = 114°.

From the figure, it is clear that The interior angle of a triangle is 39°, by the law of opposite angle.

The sum of the interior angle of a triangle is 180°

37° + 39° + ∠unknown1 = 180°

∠unkonown1 = 180° - 37° - 39°

∠unknown1 = 104°

The sum of the exterior angle and the interior angle is 180°.

∠unknown2+ ∠unknown 1= 180°

∠unknown2 = 180° - 104°

∠unknown2 = 76°

The sum of the interior angle of a triangle is 180°

∠unknown3 + ∠unknown2 + 38 = 180

∠unknown3 + 76° + 38 = 180

∠unknown3= 66°

The sum of the exterior angle and the interior angle is 180°.

∠X + <unknown3 = 180°

∠X = 180° - 66°

∠X = 114°

The value of the angle x is 114°.

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The error in the calculation is that n/360 should be equal to the central angle of the sector in degrees divided by 360. However, the given value of 115/225 is not the correct central angle. To find the correct central angle, we need to use the formula for the area of a sector:

Area of sector XZY = (central angle/360) x πr^2

We know that the area of circle ⊙Z is 255 square feet, so we can find the radius:

πr^2 = 255
r^2 = 81.11
r ≈ 9 feet

Now we can solve for the central angle:

Area of sector XZY = (central angle/360) x π(9)^2
Area of sector XZY = (central angle/360) x 81π
Area of sector XZY = (central angle/360) x 254.47

Since the area of sector XZY is not given, we cannot use the given equation n/360 = 115/225 to find the central angle. Instead, we need to use the formula above and solve for the central angle. Let A be the area of sector XZY:

A = (n/360) x 254.47
n/360 = A/254.47
n = 360A/254.47

Now we can substitute the given area of circle ⊙Z and solve for the area of sector XZY:

255 = (n/360) x πr^2
255 = (n/360) x π(81)
255 = (n/360) x 254.47
n = (360 x 255)/254.47
n ≈ 360.15

Note that n should be rounded to the nearest integer since it represents the central angle in degrees. Therefore, the central angle is approximately 360 degrees. Now we can use this value to find the area of sector XZY:

Area of sector XZY = (360/360) x π(9)^2
Area of sector XZY = 81π
Area of sector XZY ≈ 254.47 ft^2

Therefore, the area of sector XZY should be approximately 254.47 square feet.

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The transformations that have occurred from the original parent function ()=√య to the given function ()=2√x+4 are: vertical stretch by a factor of 2 and a vertical shift upward by 4 units.

The transformations that have occurred from the original parent function ()=√x to the given function ()=2√x+4 are: vertical stretch by a factor of 2 and a vertical shift upward by 4 units. The square root function (√x) has been multiplied by 2, resulting in a steeper curve, and then shifted vertically upwards by 4 units.

From the original cupcake company function g(x), the new function h(x)=2√x+2య+4 involves additional transformations. It starts with the transformations from part (a), which are a vertical stretch by a factor of 2 and a vertical shift upward by 4 units.

Annndditionally, the function is further transformed by a horizontal compression by a factor of 1/2, achieved by dividing the x-values by 2. Finally, a vertical shift upward by 2 units is applied. These transformations modify the shape, position, and scale of the original function to represent the changes in Mrs. Galicia's cupcake company's earnings.

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The approximate length of the base of the triangle is 5 units.

Given that, the area of a hexagon is about 65 square units. You decompose the figure into 6 triangles.

A regular hexagon can be decomposed into 6 equal triangles,

So, the area of each triangle is 65/6 = 10.8 square units

The height of one triangle is about 4.3 units.

We know that, the area of a triangle is 1/2 ×Base×Hieght

Now, 10.8=1/2 ×Base×4.3

21.6=Base×4.3

Base=21.6/4.3

Base=5.02

Therefore, the approximate length of the base of the triangle is 5 units.

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The concentration of salt in the tank at the end of 10 minutes is 0.01 pounds per gallon

We can use the formula:

(concentration of salt in tank) * (gallons of water in tank) = (total pounds of salt in tank)

To solve this problem. At the beginning, the tank contains 500 gallons of salt-free water, so the total pounds of salt in the tank is 0. After 10 minutes, 20 gallons of brine have entered the tank, and 20 gallons of the mixture have left the tank. As a result, the amount of water in the tank remains constant at 500 gallons.

The amount of salt that enters the tank in 10 minutes is:

(0.25 lb/gal) * (2 gal/min) * (10 min) = 5 lb

The total pounds of salt in the tank after 10 minutes is:

0 + 5 = 5 lb

Therefore, the concentration of salt in the tank at the end of 10 minutes is

(concentration of salt in tank) * (500 gallons) = 5 lb

Solving for the concentration of salt in the tank, we get:

concentration of salt in tank = 5 lb / 500 gallons

Simplifying this expression, we get:

concentration of salt in tank = 0.01 lb/gal

Therefore, the concentration of salt in the tank at the end of 10 minutes is 0.01 pounds per gallon.

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To put the numbers in order from least to greatest, we can use the number line: -3.5 -2.1 -1 -0.5 0.5 2 4 4.2 5 5.8  Two numbers that are opposites and each more than 6 units away from 0 are -7 and 7.

First, let's put the numbers in order from least to greatest:

-3.5, -2.1, -1.5, -1, -0.5, 0.5, 3.5, 4, 4.2, 4.8, 5

Now, let's find two numbers that are opposites and each more than 6 units away from 0. One example would be -7 and 7. These numbers are opposites (since they have the same magnitude but different signs), and they are both more than 6 units away from 0.

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Answer:

∠ D = 38°

Step-by-step explanation:

given Δ ABC and Δ DEF are similar, then corresponding angles are congruent, so

∠ A and ∠ D are corresponding , so

∠ D = ∠ A = 38°

Both situations can be represented by the number line as they both involve values either greater than or less than 75.

The number line the teacher drew can represent both Brooke's and Eileen's situations.

In Brooke's situation, the number line can represent the amount of money Christopher needs to earn to buy a new bicycle. If he needs to earn more than $75, any point on the number line greater than 75 would represent the amount of money he has earned that is sufficient for purchasing the bicycle.

In Eileen's situation, the number line can represent the time left in Paul's flight. If Paul has less than 75 minutes left, any point on the number line less than 75 would represent the time remaining in his flight.

Both situations can be represented by the number line as they both involve values either greater than or less than 75.

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Answer:

  area ≈ 9.219 square units

Step-by-step explanation:

You want the approximate area under the curve y = -1/2x² +x +5 on the interval [1.5, 4] using 5 trapezoids.

The interval can be divided into 5 intervals of width ...

  (4 -1.5)/5 = 2.5/5 = 0.5

The "bases" of each trapezoid will be the function values at the ends of the intervals, for example, at x=1.5 and x=2. The "height" of each trapezoid is the width of the sub-interval, 0.5.

The area formula for a trapezoid applies:

  A = 1/2(b1 +b2)h

  A = 1/2(f(x) +f(x +0.5))·0.5 . . . . . for x = 1.5, 2, 2.5, 3, 3.5

The sum of the areas is computed in the attachment as ...

  area under the curve = 9.21875

__

Additional comment

The value of the integral is 445/48 ≈ 9.2708333...

To find the probability P(X < 4) for the given probability model, where X represents the number of cups of coffee an adult aged 18 or over drinks on average per day in the United States. The probabilities for each number of cups are given in the table:
- 2 cups: 0.36
- 3 cups: 0.19
- 4 or more cups: 0.11

To find P(X < 4), we need to sum the probabilities of X being 2 or 3 cups, as those are the only values less than 4:

P(X < 4) = P(X = 2) + P(X = 3)
P(X < 4) = 0.36 + 0.19

Now, we just need to add these probabilities together:

P(X < 4) = 0.55

So, the probability that a randomly chosen adult drinks fewer than 4 cups of coffee per day is 0.55 or 55% when expressed as a percentage.

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Answer: 9.33

Step-by-step explanation: if you add them up, it's 9.33