Hi there!
Recall Faraday's Law:
[tex]\epsilon = N\frac{d\Phi_B}{dt}[/tex]
ε = Induced emf (V)
N = Number of Loops
φ = Magnetic Flux (Wb)
t = time (s)
Thus, the induced emf is equivalent to the number of loops of the coil times the rate of change of the magnetic flux bounded by the area of the coil, so:
[tex]\epsilon = 2 \cdot \frac{47 - (-65)}{0.38} = 2 \cdot \frac{112}{0.38} = 589.47V =\boxed{ 5.9 \times 10^2 V}}[/tex]
**This is the magnitude of the induced emf. With Lenz's Law, however, the answer would be negative, which just indicates it is a resistive emf.
A trailer is pulling a car with a force of 900N on a level road. The car is moving at 70 km/h how much work is done by the trailer on the car in 15mm?
Answer:
W=F⋅l=F⋅vt=900(N)⋅19.44(m/s)⋅900(s)=15.75⋅10
6 (J)
Explanation:
When trying to simplify and find the equivalent resistance you
should first simplify resistors in_before
simplifying those in_
Answer:When trying to simplify and find the equivalent resistance you
should first simplify resistors in PARALLEL before
simplifying those in SERIES
Explanation: hope this helps:)
When scientists look at very distant galaxies through powerful telescopes, they see the galaxies as they were millions or billions of year ago. Why is this?
Answer:
speed of light
Explanation:
the sun's light is 8 mins behind imaging that a billion fold
6.
What happens at the condensation point?
Answer:
Condensation point is when the temperature at which a vapor condenses into a liquid without a change in the temperature of the substance.
Answer ASAP and only if you know its correct
this is science btw also, brainliest to the correct answer
Answer:
the answer is B
Explanation:
its b
13. What happens to the number of times you must rotate a screw in order to drive it into
an object when you increase the number of threads on the screw?
a. You must rotate the screw more times and apply a stronger force
b. You must rotate the screw more times but can apply a smaller force
c. You will rotate the screw less times but must apply a stronger force
d. You will rotate the screw less times and can apply a smaller force
14. What do you
hvor
Answer:
B
Explanation:
PLS HELP! VERY URGENT! Choose three answers in the question below. I will give five stars the thanks and BRAINLIEST! I will give 50 point for this one! And brainly, this is only my assignment and its just one question.
Answer:
sawing a board in half
dissolving sugar in water
a block of ice subliming
Explanation:
Answer: Dissolving sugar in water, burning a match, and sawing a board in half
Explanation: Dissolving sugar in water is an example of a physical change. Here's why: A chemical change produces new chemical products. In order for sugar in water to be a chemical change, something new would need to result. A chemical reaction would have to occur.
When a match burns, it undergoes a chemical change. Matches use sulfur, phosphate and a friction agent held together by a binding agent. With a match, heat ignites the phosphorous on the head of the match
cutting of wood is a physical change because only physical property of wood is changed and no new substance is formed. the properties of wood remains the same. burning of wood is a chemical change as new substances are formed that is smokes and CO2. it is different from wood.
I hope this is the correct answer im pretty sure because I've finished that quiz or test already
A p.d. of 6 V is applied across a 2 resistor. What current flows?
Answer: current is 3 A.
Explanation:
V = 6V
R = 2Ω
I = ?
∴ V = IR
I = V/R
I = 6V/2Ω
I = 6/2
I = 3 A ...answer...
hope that helps...
Answer:
3 amps
Explanation:
V = IR
V/R = I
6/2 = 3 amps
Which standing wave has exactly three antinodes?
A.
B.
C.
D.
Answer:
Explanation:
C looks good, b/c antinodes are where the waves is at a max displament.
The wave has exactly three antinodes is option C.
What number of antinodes are in 3 status waves?
As in all status wave styles, each node is separated through an antinode. This sample with 3 nodes and two antinodes is known as the second one harmonic and is depicted within the animation.
Where are the antinodes?The other of a node is an anti-node, a factor where the amplitude of the status wave is at most. those occur midway among the nodes. In a full wavelength of a status wave, there are two loops. So, there should be nodes midway of every of the two loops.
What's a wave in technology?Wave, propagation of disturbances from location to vicinity in a ordinary and prepared manner. maximum acquainted are floor waves that journey on water, however sound, mild, and the movement of subatomic particles all exhibit wavelike residences.
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If two runners are running in a 500 meter dash and runner #1 finishes in 25 seconds and runner #2 finishes in 27 seconds. What are the speeds of both runners? Which one is faster
For two runners running in a 500 meter dash and runner, the speeds of both runners is mathematically given as
v1=25m/s
v2=20m/s
and the first runner is faster
What are the speeds of both runners?Generally, the equation for the speed is mathematically given as
v=d/t
Therefore, for first runner
v=500/20
v1=25m/s
For 2nd runner
v=500/25
v2=20m/s
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B. A 20kg wagon is pulled up a 30° incline at an acceleration of 2.5ms?. The force pulling the wagon is parallel to the incline and its value is 182N. Determine the value of the co-efficient of kinetic friction. [5]
The value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.
Coefficient of the kinetic frictionThe value of coefficient of kinetic friction is calculated as follows;
F - Ff = ma
F - μmgcosθ = ma
where;
F is applied forceμ is coefficient of kinetic frictionm is mass of the wagona is acceleration of the wagon182 - μ(20 x 9.8 x cos30) = 20(2.5)
182 - 169.74μ = 50
182 - 50 = 169.74μ
132 = 169.74μ
μ = 132/169.74
μ = 0.78
Thus, the value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.
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An ideal gas initially is allowed to expand isothermally until its volume of 1.6 L and pressure is 5 kPa, undergoes isothermal expansion until its volume is 8 L and its pressure is 1 kPa.
1. Calculate the work done by the gas. Answer in units of kJ.
2. Find the heat added to the gas during this process. Answer in units of kJ.
(a) The work done by the gas during the isothermal expansion is -25.6 J.
(b) The heat added to the gas during this process is 25.6 J.
Net work done by the ideal gas against the external pressureThe net work done by the ideal gas in the isothermal expansion is calculated as follows;
W(net) = ΔP x ΔV
W(net) = ( 1 kPa - 5 kPa) x (8L - 1.6 L)
W(net) = -25.6 kPa.L
W(net) = -25.6 J
Head added to the gasThe heat added to the gas is calculated as follows;
W = -Q
-25.6 J = -Q
Q = 25.6 J
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a ballon holds 24L at 45 k . find the volume if the temperature is increased to 911 k
what is dollar effect
Answer:
Above is correct
A scientist thinks that a certain chemical is a mutagen. She exposes plant cells to a large amount of this chemical in the laboratory.
Which statement best provides evidence that the substance is a mutagen?
By 2005, the world's tallest building will be the International Finance Center in Taipei,
Republic of China. Suppose a 1.00 C charge is placed at both the base and the top of the
International Finance Center. If the magnitude of the electric force stretching the building
is 4.48 x 104N, how tall is the International Finance Center?
Electric field refers to the region in space where the influence of a charge is felt, the height of the building is 447 m.
What is electric field?
The term electric field refers to the region in space where the influence of a charge is felt.
Since we know that;
E = F/q = 4.48 x 104N/1C = 4.48 x 10^4 N/C
E = Kq/r^2
4.48 x 10^4 = 9 * 10^9 * 1/r^2
r = √9 * 10^9/4.48 x 10^4
r = √2 * 10^5
r = 447 m
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cart a having a mass of 150 kg initially moving to the right at a speed of 8 m/s collides with cart b with a mass of 150 kg, initially moving to the right at 6 m/s after a collision cart a continues to move to the right but with a speed of 5 m/s
a. what is the speed of cart b after collision
b. what is the total momentum of the system before and after collision
The speed of cart b is 6m/s while the total momentum of the systmen is 4200 kg m/s
Conservation of Linear MomentumGiven Data
Mass of cart one M1 = 150kgInitial Velocity U1 = 8m/sFinal VelocityV1 = 5 m/sMass of cart two M2 = 150kg
Velocity U2 = 6m/s
Applying the principle of conservation of linear momentum we have
M1U1+M2U2 = M1V1+ M2V2
a. what is the speed of cart b after collision
substituting our given data we have
150*8+ 150*6 = 150*5+150*V2
1200 + 900 = 1200+ 150V2
2100 - 1200 = 150V2
900 = 150V2
Divide both sides by 150
V2 = 900/150
V2 = 6m/s
b. what is the total momentum of the system before and after collision
Total Momentum in the system is
Total momentum = Momentum before Impact+ Momentum after Impact
Total momentum = M1U1+M2U2 + M1V1+ M2V2
Total momentum = 1200 + 900 + 1200+ 900
Total momentum = 4200 kg m/s
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Answer ASAP and only if you know its correct
this is science btw
Answer: It is brighter
Explanation: We are getting closer to the light because the earth is expanding.
the answer is it is brighter cause the light from the object is known as blueshift
How do I go about this?
Hi there!
(a)
Recall that:
[tex]W = F \cdot d = Fdcos\theta[/tex]
W = Work (J)
F = Force (N)
d = Displacement (m)
Since this is a dot product, we only use the component of force that is IN the direction of the displacement. We can use the horizontal component of the given force to solve for the work.
[tex]W =248(56)cos(30) = 12027.36 J[/tex]
To the nearest multiple of ten:
[tex]W_A = \boxed{12030 J}[/tex]
(b)
The object is not being displaced vertically. Since the displacement (horizontal) is perpendicular to the force of gravity (vertical), cos(90°) = 0, and there is NO work done by gravity.
Thus:
[tex]\boxed{W_g = 0 J}[/tex]
(c)
Similarly, the normal force is perpendicular to the displacement, so:
[tex]\boxed{W_N = 0 J}[/tex]
(d)
[tex]F_{f} =\mu_k N[/tex]
In this instance, the normal force is equivalent to the downward force of gravity and the vertical component of the applied force.
[tex]N = F_g + F_A sin(30)\\\\N = mg + F_A sin(30)\\\\N = 56(9.8) + 248sin(30) = 672.8 N[/tex]
Since the force of friction resists the applied force (assigned the positive direction), the work due to friction is NEGATIVE because energy is being LOST. Thus:
[tex]W_f = -\mu_k Nd\\W_f = - (0.1)(672.8)(56) = -3767.68J[/tex]
In multiples of ten:
[tex]\boxed{W_f = -3770 J}[/tex]
(e)
Simply add up the above values of work to find the net work.
[tex]W_{net} = W_A + W_f \\\\W_{net} = 12027.36 + (-3767.68) = 8259.68 J[/tex]
Nearest multiple of ten:
[tex]\boxed{W_{net} = 8260 J}}[/tex]
(f)
Similarly, we can use a summation of forces in the HORIZONTAL direction. (cosine of the applied force)
[tex]F_{net} = F_{Ax} - F_f[/tex]
[tex]W = F_{net} \cdot d = (F_{Ax} - F_f)[/tex]
[tex]W = (F_Acos(30) - \mu_k N)d\\W = (248cos(30) - 0.1(672.8)) * 56 \\\\W = 8259.68 J[/tex]
Nearest multiple of ten:
[tex]\boxed{W_{net} = 8260 J}[/tex]
Help me balance ittt
Answer:
CH4 + 2O2 -> CO2+2H20 Here we add 2 in front of H2O and 2 in front of O2
Two boats - Boat A and Boat B - are anchored a
distance of 4.1 meters apart. The incoming water
waves force the boats to oscillate up and down,
making five complete cycles every 26.1 seconds.
When Boat A is at its peak, Boat B is at its low point.
There are never any waves between the two boats.
The vertical distance between Boat A and Boat B at
their extreme is 6.9 meters. Determine the wavelength
(in meters), frequency (in Hertz), and speed (in
meters/second) of the wave. (HINT: begin with a
diagram.)
Answer:
the wave length is 7.6 inches
Explanation:
What happens to light when it enters a lens?
Question 9 options:
It speeds up.
It is reflected.
It is refracted.
It becomes brighter.
Answer:
It is refracted.
Explanation:
Answer:
It is refracted
Explanation:
The light changes direction when it enters and exits the prism. When white light is shone through a triangular prism, a rainbow of light is seen on the opposite side of the prism.
What is the voltage of the following circuit?
Answer:
v = 48
Explanation:
follow the formula v = i x r add up all the resistors an multiply it by the current
A disk-shaped platform has a known rotational inertia. The platform is mounted on a fixed axle and rotates in a horizontal plane, as shown above. A student wishes to determine the frictional torque exerted on the platform by the axle as the platform rotates. The student has access to equipment that would usually be found in a school physics laborator
The frictional torque exerted on the platform by the axle as the platform rotates will be;
[tex]\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2][/tex]
What is torque?Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force. Torque is a force that acts in a turn or twist.
The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.
Work done by the frictional torque = Change in the rotational kinetic energy of the wheel
[tex]\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2][/tex]
Where,
[tex]\rm T_f[/tex] is the frictional torque
[tex]\rm \omega[/tex] is the final angular velocity
[tex]\rm \omega_0[/tex] is the initial angular velocity
[tex]\rm \theta[/tex] is the angular displacement
Hence, the frictional torque exerted on the platform by the axle as the platform rotates will be;
[tex]\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2][/tex]
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what kingdom are true bacteria in
Answer: Kingdom Monera
Think of the human body composition. Why do humans sink much slower than a boulder weighing the same mass? What makes humans less dense?
Answer:
because of the oxygen in our bodies.
Miguel is holding a 5 kg box.
How much force is the box exerting on him? In what direction?
How much force is he exerting on it? In what direction?
hope this answer helps...!!!
A 3m plank AB of mass 20kg has a center of gravity 2m from end A and rests on supports R1 and R2 both 0,5m from either end. It also carries a 10kg block at end A. Calculate the reactions at R1 and R2
Answer:
130.7 N
Explanation:
a. The flow of energy from Earth's interior to the surface is about 50 terawatt (1 terawatt = 1e12 joule/sec). This is the energy that gives Earth an active surface geology (hot springs, volcanoes, plate tectonics, etc). Roughly half of this geothermal is from the energy produced by radioactive decay, and roughly half is from the energy left from the formation of the hot Earth.
Estimate how much geothermal energy reaches Earth’s surface in one day (in Joule).
b. Estimate humanity’s current consumption of energy in one day (in Joule).
c.Assuming 100% efficiency of extracting geothermal energy, estimate the ratio of geothermal energy to human's current annual world consumption of energy.
A) The amount of geothermal energy that reaches Earth's surface in one day is : 43.2 * 10¹⁷ joules
B) Humanity's current consumption of energy is; 71.4 GJ per individual.
C) Ratiois ; 60.5 * 10⁶ Joules
Given data :
Amount of energy flow = 50 terawatt = 50*10¹² joule/sec.
Determine the geothermal energy that reaches the earthSince the geothermal energy reaches the earth in a single day
Energy = power * time
Time = 24 hours ( 1 day ) = 86400 secs.
Energy = 50*10¹² joule/sec * 86400 secs
= 43.2 * 10¹⁷ joules
B) Estimating humanity's current consumption of energy in one day.Humanity's current consumption of energy in one day is estimated to be 71.4 GJ per individual.
C) Determine the ratio of geothermal energy to human's current annual consumptionGeothermal energy / human current annual consumption
= 43.2 * 10¹⁷ Joules / 71.4 * 10⁹ Jolues
= 60.5 * 10⁶ Joules
Hence we can conclude that A) The amount of geothermal energy that reaches Earth's surface in one day is : 43.2 * 10¹⁷ joules
B) Humanity's current consumption of energy is; 71.4 GJ per individual.
C) Ratiois ; 60.5 * 10⁶ Joules
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How to calculate Density of tetragonal unit cell by formula?
Answer:
[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]
The formula of Density for a random unit cell is as follows -
[tex]Density = \frac{ Z _{effective} \times M }{N _{a} \times a {}^{3} } \\ [/tex]
where ,
★ [tex]Z _{effective}[/tex] = number of atoms in a unit cell
★ M = molar mass
★ [tex] N _{a} = Avogadro's \: Number = 6 × 10^{23}[/tex]
★ a = edge length
now ,
In a tetragonal unit cell ,
the atoms are present over the corners as well as the at the body centre.
Therefore ,
[tex]Z _{effective} = contribution \: by \: the \: 8 \: corners \: + contribution \: by \: the \: body \: centre[/tex]
[tex]\implies \: (\frac{1}{8} \times 8) \: + \: 1 \\ \\ \implies \: 1 + 1 \\ \\ \implies2[/tex]
And ,
[tex]N _{a} = 6 \times 10 {}^{23} [/tex]
Substituting the values of the following in the formula of Density , we get
[tex]\bold\purple{Density = \frac{2 \times M}{6 \times 10 {}^{23} \times a {}^{3} }} \\[/tex]
hope helpful :D