The pulley shown in the attached diagram has a diameter of 30 centimeters and a mass of 19 kilograms. The pulley is a solid disk with an axle through its center.

(a.) What is the moment of inertia of the pulley?

(b.) What is the magnitude of the net torque on the pulley about its axis

(c.) What is the direction of the net torque on the pulley?

(d.) What is the magnitude of the angular acceleration of the pulley?

(e.) What is direction of the angular acceleration?

this is the correct answer

Sorry, I don't know but I think the correct answer is the first option.

Answer:

D gravity

Explanation:

please mark me brainliest

Answer:

D. The force that the branch applies to the kitten

Explanation:

I just took the quiz and got it correct!

Answer:

Explanation:

Appears to be the vertexes of a triangle.

AB = √(-6 - (-2))² + (3 - 4)²) = √17

AC = √(-6 - (-8))² + (3 - 3)²) = 2

BC = √(-2 - (-8))² + (4 - 3)²) = √37

Answer:

wool maybe, I was a bit confused in silk and wool but wool

Answer:

whatttttttttttt

Explanation:

the ಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠ

Answer:

here your answer

i am sorry if wrong

Answer:

[tex]\boxed {\boxed {\sf C. \ 20 \ m/s }}[/tex]

Explanation:

We are asked to find the initial speed of a car.

We are given the final speed, the time, and the acceleration, so we will use the following kinematic equation:

[tex]v_f=v_i+at[/tex]

We know the final speed is 40 meters per second, the acceleration is 4 meters per second squared, and the time is 5 seconds.

Substitute the values into the formula.

[tex]40 \ m/s = v_i+(4 \ m/s^2 * 5 \ s)[/tex]

Multiply inside the parentheses.

[tex]40 \ m/s =v_i+ 20 \ m/s[/tex]

We are solving for the initial speed, so we must isolate the variable [tex]v_i[/tex].  

20 meters per second is being added to [tex]v_i[/tex]. The inverse operation of addition is subtraction. Subtract 20 m/s from both sides of the equation.

[tex]40 \ m/s - 20 \ m/s = v_i + 20 \ m/s - 20 \ m/s[/tex]

[tex]40 \ m/s - 20 m/ s = v_i[/tex]

[tex]20 \ m/s=v_i[/tex]

The initial speed of the car is 20 meters per second and choice C is correct.

Explanation:

this is actually not as simple as it sounds here.

quite some energy is lost in the deformation of the bodies of car and truck, and it also needs more energy to get a standing object going than to accelerate an already moving object.

but assuming the simple described circumstances, then the energy and impulse of the moving truck of 5000 kg is transferred to a new combined system of car and truck of now 5000 + 3000 = 8000 kg.

so, the 20m/s inertia energy of the truck is now distributed to the truck/car combination.

since the same energy has to move now more mass, it is clear that the combined speed will be lower.

20×5000 = x×8000

20×5 = x×8

x = 100/8 = 12.5 m/s

that is the resulting speed of the combined truck/car object.

Answer:

Explanation:

The 25.0 kg mass has momentum before the collision of

p = 25.0(3.0) = 75 kg•m/s

If all this momentum gets transferred into a 5.0 kg mass, the velocity of the 25.0 kg mass will be zero and the velocity of the 5.0 kg mass will be

75 / 5.0 = 15.0 m/s

Getting this to occur will require an addition of a significant amount of energy via an internal explosion or release of spring potential energy. This can be shown by looking at kinetic energies.  

Initial system kinetic energy is ½(25.0)3.0² = 112.5 Joules

After the collision, system kinetic energy is ½(5.0)25² = 1,562.5 Joules

so 1562.5 - 112.5 = 1450 Joules of energy must be released during the collision to complete this scenario.

The most efficient energy transfer without energy release is an ideal elastic collision. Had these two masses been in such a collision with the given initial conditions, the 5 kg mass would have moved away at 5.0 m/s taking with it 5(5) = 25 kg•m/s of momentum leaving the 25 kg mass with 75 - 25 = 50 kg•m/s of momentum and a velocity of 50/25 = 2.0 m/s. Both masses are now traveling in the same direction as the original velocity, but at different speeds. Notice kinetic energy is conserved in elastic collisions

½(25)2² + ½(5.0)5² = 112.5 Joules.

The only time one mass can transfer its entire momentum to another mass without additional energy addition or subtraction is when the two colliding masses are identical in magnitude. Think pool balls colliding on a table.

Answer:

I don't understand it.....

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question

m = 75 kg

v = 52 m/s

We have

[tex]k = \frac{1}{2} \times 75 \times {52}^{2} \\ = \frac{1}{2} \times 75 \times 2704 \\ = 75 \times 1352 \\ = 101400[/tex]

We have the final answer as

Hope this helps you

Answer:

Abcdfeghijklmnopqrstuvwxyz

Explanation:

They are in order

Answer:

So as sunlight continued to enter the box and the walls continued to warm, heat built up inside and increased the temperature.

Answer:an iron-nickel alloy or nickel -iron alloy abbreviated FeNi or NiFe is a group of alloys consisting primarliy of the elemtns nickel and iron.

Explanation:

Answer:

Iron and nikel are example of "Metal" materials.

Answer:

They are the same.

Both have potential energy of M g H   and that is the energy that will be converted to kinetic energy for each twin,

Answer:

Explanation:

ASSUMING the clay is moving horizontally and friction is negligible.

momentum is mass times velocity

9a)

m₁v + m₂(0) = m₁vf + m₂vf

            m₁v = (m₁ + m₂)vf

               vf = m₁v / (m₁ + m₂)

9b)

ASSUMING the positive direction is also the original direction of the clay ball

m₁v + m₂vb = (m₁ + m₂)vf

vf = (m₁v + m₂vb) / (m₁ + m₂)

9c)

vf = (0.37(25) + 4.6(3.4)) / (0.37 +4.6)

vf = (9.25 + 15.64) / 4.97

vf = 5.0080482897...

vf = 5.0 m/s

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

Answer:

mas lalo kang tinatamaran magaral

below the Antarctic Circle.

Let's see

[tex]\\ \sf\longmapsto \overrightarrow{drag}[/tex]

[tex]\\ \sf\longmapsto \overleftarrow{Thrust}[/tex]

[tex]\\ \sf\longmapsto Lift\:Force\uparrow[/tex]

[tex]\\ \sf\longmapsto Acceleration\:due\:to\: gravity\downarrow[/tex]

Net force is 0

Answer:

Explanation:

a) A is accurate because the half of the Moon that is facing the sun is it by the sun, and the other half is dark.

The most accurate diagram of the Sun and Moon is: a. A is accurate because the half of the Moon that is facing the sun is it by the sun, and the other half is dark.

A Moon can be defined as the natural satellite of planet Earth that shines due to the Sun's reflected light (sunlight), as it revolves around the Earth from west to east in 29½ days.

Based on astronomical information, there are four (4) primary Moon phases and these are:

In conclusion, diagram A is the most accurate because half of the Moon that faced the Sun is lit by the Sun while the other half is dark.

Read more on Moon here: brainly.com/question/1286910

From your previous question

[tex]\\ \sf\longmapsto F=ma[/tex]

[tex]\\ \sf\longmapsto F=30(12)[/tex]

[tex]\\ \sf\longmapsto F=360N[/tex]

Answer:

Capsule : solid

Suspension : liquid

lotion : semisolid

Explanation:

(a) The minimum angle the string can make with the horizontal is 4.4 ⁰.

(b) The rocks speed at the minimum angle is 165.7 m/s.

The given parameters;

The net force on the string is calculated as follows;

[tex]Tsin(\theta) = mg\\\\Tcos(\theta) = \frac{mv^2}{r} \\\\\frac{Tsin(\theta)}{Tcos(\theta)} = \frac{mg r}{mv^2} \\\\tan(\theta) = \frac{rg}{v^2} \\\\v^2 = \frac{rg}{tan (\theta)} \\\\v = \sqrt{\frac{rg}{tan (\theta)}}[/tex]

The minimum angle the string can make with the horizontal is calculated as follows;

[tex]Tsin(\theta) = mg\\\\sin(\theta) = \frac{mg}{T} \\\\sin(\theta) = \frac{0.94 \times 9.8}{120} \\\\sin(\theta) = 0.0767\\\\\theta = sin^{-1} (0.0767)\\\\\theta = 4.4 \ ^o[/tex]

The rocks speed at the minimum angle is calculated as follows;

[tex]v = \sqrt{\frac{rg}{tan(\theta)} } \\\\v = \sqrt{\frac{1.3 \times 9.8}{tan(4.4)} } \\\\v = 165.7 \ m/s[/tex]

Learn more here:https://brainly.com/question/20102400