A: The data provides convincing evidence, at α=0.02 level, that the glucose drug is effective in reducing mean glucose level.
B: The 98% confidence interval for the difference in mean reduction of glucose level between placebo and drug groups is 3.5 to 13.7 mg/dL, supporting the effectiveness of the glucose drug
A: To test whether the glucose drug is effective in producing a reduction in mean glucose level, we will use a two-sample t-test with equal variances assuming normality of the differences.
Let μA be the true mean reduction in glucose level for the placebo group and μB be the true mean reduction in glucose level for the glucose drug group. The null hypothesis is H0: μA - μB = 0, and the alternative hypothesis is Ha: μA - μB < 0
Using the given data, the sample mean reduction for the placebo group is 9.7 mg/dL and for the glucose drug group is 18.3 mg/dL. The pooled sample standard deviation is 8.064 mg/dL, and the t-statistic is calculated to be:
t = (xB - xA) / (sP × √(1/nA + 1/nB))
= (18.3 - 9.7) / (8.064 × √(1/10 + 1/10))
= 2.551
where xA and xB are the sample means, sP is the pooled sample standard deviation, and nA and nB are the sample sizes.
B: To create a 98% confidence interval for the difference in the placebo and the new drug, we will use the formula:
CI = (xB - xA) ± tα/2,sP × √(1/nA + 1/nB)
where xA and xB are the sample means, sP is the pooled sample standard deviation, nA and nB are the sample sizes, and tα/2,sP is the t-value corresponding to a 98% confidence level with 18 degrees of freedom.
Using the values from Part A, we have:
CI = (18.3 - 9.7) ± 2.101 × 8.064 × √(1/10 + 1/10)
= 8.6 ± 5.103
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The correct question is:
Twenty middle-aged men with glucose readings between 90 milligrams per deciliter and 120 milligrams per deciliter of blood were selected randomly from the population of similar male patients at a large local hospital. Ten of the 20 men were assigned randomly to group A and received a placebo. The other 10 men were assigned to group B and received a new glucose drug. After two months, posttreatment glucose readings were taken for all 20 men and were compared with pretreatment readings. The reduction in glucose level (Pretreatment reading − Posttreatment reading) for each man in the study is shown here.
Group A (placebo) reduction (in milligrams per deciliter): 12, 8, 17, 7, 20, 2, 5, 9, 12, 6
Group B (glucose drug) reduction (in milligrams per deciliter): 29, 31, 13, 19, 21, 5, 24, 12, 8, 21
Part A: Do the data provide convincing evidence, at the α = 0.02 level, that the glucose drug is effective in producing a reduction in mean glucose level?
Part B: Create and interpret a 98% confidence interval for the difference in the placebo and the new drug.
A survey asked students whether they have any siblings and pets. The survey
data are shown in the relative frequency table.
Pets
No pets
Total
Siblings
0.3
0.45
0.75
OA. 30%
OB. About 67%
O C. 75%
D. 40%
Given that a student has a sibling, what is the likelihood that he or she also
has a pet?
The likelihood that he or she has a pet given that a student does not have a sibling is 60%. Therefore, the correct option is option D.
Let A denote the event that a student does not have a sibling.
Let B denote the event that a student has a pet.
Then A∩B will denote the event that the student does not have a sibling but he has a pet.
Let P denote the probability of an event in this question.
Then, we have to find the conditional probability of event B which means the likelihood of event B occurring based on the occurrence of event A.
P(B|A)
We know that:
[tex]P(B|A) = \frac{P(A\cap B)}{P(A)}[/tex]
Also from the table, we have:
P(A)=0.25
and P(A∩B)=0.15
Hence,
[tex]P(B|A) = \frac{0.15}{0.25}[/tex]
[tex]P(B|A) = \frac{3}{5}[/tex]
[tex]P(B|A) = 0.6[/tex]
which in percentage is:
0.6 * 100 = 60 %
Therefore, the likelihood that he or she has a pet too is 60% and the correct option is option D.
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Mrs Marcus combines her books and magazines then divides them among 10 different tables. If a represents the number of books and d represents the number of magazines Mrs. marcus has, write an expression to show how many books would be on each table.
An expression to show how many books would be on each table is a/10
To find out how many books would be on each table, we need to divide the total number of books by the number of tables.
First, let's express the total number of books in terms of a and d. Since we are not given any specific numbers for a and d, we can simply use variables to represent them. Therefore, the total number of books is given by a.
Next, we need to divide a by 10, the number of tables. This gives us the expression:
a/10
So, the above expression shows how many books would be on each table if Mrs. Marcus combines her books and magazines and then divides them among 10 different tables.
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Complete question is:
Mrs. Marcus combines her atlases and dictionaries and then divides them among 10 different tables. If a represents the number of atlases and d represents the number of dictionaries Mrs. Marcus has, write an expression to show how many books would be on each table.
The frequency table below shows a student’s quiz scores. One data value in the table is missing. If the mean of the data set is 2.2, what is the score for the missing data item? A. 0 B. 1 C. 2 D. 3
Answer:
B. 1
Step-by-step explanation:
Let's use the formula for finding the mean of a set of data:
mean = (sum of all data values) / (number of data values)
We know that the mean is 2.2, and we have all the other data values except for one. Let's call the missing value "x". The total number of data values is 10 (since there are 10 scores listed in the frequency table). So we can set up an equation:
2.2 = (sum of all 10 data values, including x) / 10
Multiplying both sides by 10, we get:
22 = sum of all 10 data values, including x
We can then subtract the sum of the known data values from both sides to find the missing value:
22 - (01 + 12 + 23 + 31 + 42 + 51) = x
22 - (0 + 2 + 6 + 3 + 8 + 5) = x
x = 22 - 24 = -2
However, a quiz score cannot be negative, so we made a mistake somewhere. Checking the frequency table, we see that there are no scores of 0 or 1, so the missing score must be 0 or 1. Let's try both possibilities:
If the missing score is 0:
2.2 = (01 + 12 + 23 + 31 + 42 + 51 + 0*1) / 10
2.2 = 18 / 10
2.2 = 1.8
This is not true, so the missing score cannot be 0.
If the missing score is 1:
2.2 = (01 + 12 + 23 + 31 + 42 + 51 + 1*?) / 10
2.2 = (18 + ?) / 10
22 = 18 + ?
? = 4
So the missing score is 1, and the answer is B.
Answer:
Answer is B
Total scores/total frequency =mean
54/24=2,25
If you added a score of 1
55/25=2,2
Step-by-step explanation:
hope that helps you
The scatter plot shows the number of households, in millions, that have cable television over eight consecutive years.
Scatter plot with x axis labeled Time in Years and y axis labeled Number of Households with points at 1 comma 3 and 8 tenths, 2 comma 5 and 8 tenths, 3 comma 6 and 2 tenths, 4 comma 7 and 5 tenths, 5 comma 7 and 2 tenths, 6 comma 8 and 3 tenths, 7 comma 9 and 3 tenths, and 8 comma 8 and 5 tenths.
A) y = −2.78x + 33.6
B) y = −2.78x + 48.5
C) y = 2.78x + 33.6
D)y = 2.78x + 48.5
The equaltion for the line of best fit would be,
y = 0.67x + 4.05
The points on the scatter plot are: (1, 3.8), (2, 5.8), (3, 6.2) , (4, 7.5) , (5, 7.2), (6, 8.3), (7, 9.3), and (8, 8.5 )
First we find the mean of the x-values and mean of the y-values.
The mean of the x-values would be,
[tex]\bar{X}[/tex] = (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8) / 8
[tex]\bar{X}[/tex] = 4.5
and the mean of the y-values would be,
[tex]\bar{Y}[/tex] = (3.8 + 5.8 + 6.2 + 7.5 + 7.2 + 8.3 + 9.3 + 8.5) / 8
[tex]\bar{Y}[/tex] = 7.075
The sum of squares (SSX) = 42
And the sum of products (SP) = 28.2
Regression Equation would be,
y = mx + c
m = SP/SSX
= 28.2/42
= 0.67143
And the y-intercept would be,
c = 4.05357
So, the equation for the line of best fit would be,
y = 0.67143x + 4.05357
Number of Households = 0.67143 (time) + 4.05357
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Find the complete question below.
The scatter plot shows the number of households, in millions, that have cable television over eight consecutive years.
Scatter plot with x axis labeled Time in Years and y axis labeled Number of Households with points at 1 comma 3 and 8 tenths, 2 comma 5 and 8 tenths, 3 comma 6 and 2 tenths, 4 comma 7 and 5 tenths, 5 comma 7 and 2 tenths, 6 comma 8 and 3 tenths, 7 comma 9 and 3 tenths, and 8 comma 8 and 5 tenths.
Solve the following system of equations.
The solutions for the system of equations " 3x²-2y²+5=0 and 2x²-y²+2=0" are :
First Solution : x = 1, y = 2
Second Solution : x = 1, y = -2
Third Solution : x = -1, y = 2
Fourth Solution : x = -1 , y = 2.
In order to solve the system of equations 3x²-2y²+5=0 and 2x²-y²+2=0, we use substitution method;
From the second equation, we solve for y² in terms of x²:
The second equation is : 2x² - y² + 2 = 0;
We get, y² = 2x² + 2
Substitute this expression for y² into the first equation:
We get,
3x² - 2(2x² + 2) + 5 = 0
3x² - 4x² - 4 + 5 = 0
-x² + 1 = 0
x² = 1
We get, x = ±1
Substitute these values of x into the equation for y²:
y² = 2x² + 2
For x = 1, y² = 4,
Which means the solution set is (1,2) and (1,-2),
For x = -1, y² = 4
the solution set is (-1,2) and (-1,-2).
Therefore, the solutions to the system of equations are (1, 2), (1,-2), (-1,2) and (-1, 2).
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Work out the largest integer value that x could take if
x+7<13
Answer:
The answer is going to 5
Step-by-step explanation:
I hope this helps you
e) Write a proof to show AABC ~ ACFD.
f) What is the longest cart that can pass through the second doorway?
Explain.
Some of the factory's products are long fragile rods that are carried through
the door by hand. The first door is 72 inches west of the start of the second
door. Assume the rod has zero width and BA = 13 in.
Answer:
Step-by-step explanation:
no
What does |23| mean?
Someone help I have no idea how to do this, it would help if I could get a step by step
Answer: x=3
Step-by-step explanation:
shaded part is 5/6 of the full circle, so just make an equation.
5/6 pi r^2(formula to find area)=15/2 pi(area given)
cancel out pi and simplify
r^2=9
r=+-3 but cant be negative so r=3
The area of a rectangular shaped rug is 81 square feet. If the rug is 9 ft long, what is ire perimeter?
The perimeter of the rug is 36ft
What is perimeter?Perimeter is the total length around the outside of a shape. The perimeter can be found by adding all the sides of the shape.
Perimeter of a rectangle is expressed as ;
P = 2(l+w)
The area of the rug is 81ft²
area = l× w
length = 9ft
width of the rug = 81/9 = 9ft
Therefore the perimeter of the rug will be
P = 2(l+w)
P= 2( 9+ 9)
P = 2 × 18
P = 36 ft
therefore the perimeter of the rectangular rug is 36ft
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A quality expert can test 18 units in 32 minutes. If there are 400 units to be tested, about how long will it take to test them?
It will take about 711.12 minutes or approximately 11.85 hours to test all 400 units.
To find out how long it will take to test 400 units, we need to use the information given in the problem. We know that the quality expert can test 18 units in 32 minutes. We can use this information to find out how long it will take to test one unit.
First, we need to find out how many units can be tested in one minute:
18 units / 32 minutes = 0.5625 units per minute
This means that the quality expert can test 0.5625 units per minute. To find out how long it will take to test one unit, we can divide 1 by 0.5625:
1 / 0.5625 = 1.7778 minutes per unit
So it takes about 1.7778 minutes to test one unit. To find out how long it will take to test 400 units, we can multiply this value by 400:
1.7778 minutes per unit * 400 units = 711.12 minutes
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McKenzie painted a yellow rectangle that measured 8 1/2 in. wide and 11 in. long for part of a mural she was working on. She also painted a
purple rectangle that was 1/4 the size of the yellow rectangle. What is the area of the purple rectangle that McKenzie painted?
Answer:
23.375 in^2
Step-by-step explanation:
To find the area of a rectangle or square, you need to multiple the length by the width.
The length: 8.5
Width: 11
8.5*11 = 93.5
Now we divide by 4
93.5/4
23.375
A boy has 30 spellings to learn.
12 words included an 5, 16 a T and 18 an E.
10 words had an E and a T, 6 words had an Sand aT and 5 words had an E and an S.
4 words had all three.
Probability that?
A • the first two spellings in the test both included only one of the three letters?
C• the first two spellings in the test both had an E and at least one other letter
Answer:
A
Step-by-step explanation:
Suppose that the function h is defined as follows.
For the given function h(x) the points can be plotted on,
(-1,-1)(0,0)(1,1)(2,2)The given function h(x) is having four conditions and each condition can be clearly discussed below:
Given that for the first condition, the x-axis is ranging from -1 [tex]\leq[/tex] x < 0, the y-axis point is present exactly at -1. Similarly, for the second condition, the x-axis is ranging from 0 [tex]\leq[/tex] x < 1, and the y-axis point is present at 0. For the third condition, the x-axis is ranging from 1 [tex]\leq[/tex] x < 2, and the y-axis point is at 1.Finally, for the fourth condition, the x-axis is ranging from 2 [tex]\leq[/tex] x < 3, and the y-axis point is at 2.From, the above analysis we plotted the graph and attaching below.
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Mrs Smith uses 5 lemons to make 2/3 gallon lemonade. How many gallons of lemonade can Mrs Smith make with 15 lemons?
Someone help i really need help with this
The equation which can be used to find the amount the admission tickets cost would be 4x + 25 = 175. The cost of the admission tickets would therefore be $ 37.50.
How to find the equation ?The total spent by Ms. Boi was $ 175.00 so this is what the entire equation would be equal to. The cost of admission tickets will be denoted as x because they are the unknown figure.
There are 4 tickets purchased so the equation would be:
4 x Cost of tickets - Parking cost = Total spent
4 x - 25 = 175
The cost of each admission ticket is:
4 x - 25 = 175
x = 150 / 4
x = $ 37.50
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given h(t)=4t and k(t)=t+5t−1 , determine the expressions that are equal to these combinations of h(t) and k(t) . h(t)+k(t) h(t)−k(t) h(t)+k(t)h(t)−k(t) t2+t+4t2+9t−4 −t2+9t−4t2+t+4 t2+4t+4t2−1 −t2+t+4t2−t −t2+4t−6t2−1 t2+9t−4t2−t
The expressions are written as;
h(t)+k(t) = 10t - 1
h(t)−k(t) = -2t + 1
How to determine the expressionsNote that algebraic expressions are described as expressions that are made up of coefficients, variables, terms, constants and factors.
These expressions are made up of arithmetic operations, which includes;
AdditionMultiplicationDivisionBracketParenthesesSubtractionFrom the information given, we have that;
h(t)=4t
k(t)=t+5t−1
To determine the value of h(t) + k(t), we have;
4t + t + 5t - 1
add the like terms, we get;
10t - 1
To determine h(t) = k(t)
4t- t - 5t + 1
add like terms
-2t + 1
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please help for this question
The dilation of the object is given by the coordinates:
(-6,-8)
(-2, 0)
(-2, -8)
A dilation is a function f from a metric space M into itself that fulfills the identity d=rd for all locations x, y in M, where d is the distance between x and y and r is some positive real integer.
For the first dilation
Original points are
(2,1)
(4,5)
(4,1)
Multiply by scale factor
(2,1) x 2 = (4,2)
(4,5) x 2 = (8, 10)
(4,1) x 2 = (8, 2)
This given us the coordinates of triangle B).
For the second dilation
(2,1)
(4,5)
(4,1)
Adjust for the center of dilation which is (5,5)
(2,1) less (5,5) = (-3, -4)
(4,5) less (5,5) = (-1, 0)
(4,1) less (5,5) =(-1, -4)
Multiply the New original point by scale factor
(-3, -4) x 2 = (-6,-8)
(-1, 0) x 2 = (-2, 0)
(-1, -4) x 2 = (-2, -8)
Thus, the new coordinates of the dilated triangle C are:
(-6,-8)
(-2, 0)
(-2, -8).
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The entire graph of the function g is shown in the figure below.
Write the domain and range of g as intervals or unions of intervals.
domain=
range =
For the given function 'g':
domain = (-4, -2) ∪ (1, 3]
range = (-5, 4]
If the function is defined as f(x) = y, then the values of x for which the value of function exists, the set of that values is said to be the domain of the function f.
If the function is defined as f(x) = y, then the set of all possible values of the function that is the set of all possible values of y is said to be the range of the function f.
Here given the graph of 'g'.
From the graph we can see that for -4 < x < -2 and 1 < x [tex]\le[/tex] 3 the function has graph.
So the domain = (-4, -2) ∪ (1, 3]
And it is clear that the value of y lies between -5 < y [tex]\le[/tex] 4.
So the range = (-5, 4].
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The expression 5(2) gives the number of leaves on a plant as a function
of the number of weeks since it was planted.
What does 2 represent in this expression?
Choose 1 answer:
B
The plant was planted 2 weeks ago.
There were initially 2 leaves on the plant.
The number of leaves is multiplied by 2 each week.
C: the number of leaves is multiplied by 2 each week
Step-by-step explanation
The proper expression ought to be 5(2) ^ t =5(2)^{t}
where t speak to the number weeks after it planted.
On the off chance that we put to the time(t) we are going know how numerous clears out at first are. The calculation will be:
5(2)^{t}= 5(2)^{0} =5
This appear that coefficient 5 decide how much the takes off at first are.
Let see how the number going for distinctive esteem of t. On the off chance that its 1 week after plant, the leaf will ended up:
5(2)^{t}= 5(2)^{1} = 10
At that point the number of takes off 2 weeks after planted will be:
5(2)^{t}= 5(2)^{2}= 20
The number keeps twofold each week since coefficient 2 speaks to the proportion of the development of the work and the proportion decides how much takes off duplicated each week.
So, the reply will be C.
Which equations are true for x = –2 and x = 2? Select two options x2 – 4 = 0 x2 = –4 3x2 + 12 = 0 4x2 = 16 2(x – 2)2 = 0
Step-by-step explanation:
x = -2 or x = 2
x + 2 = 0 or x - 2 = 0
(x + 2) (x - 2) = 0
x² - 4 = 0
#CMIIWAnna saved $20 in a jar each month for 2 3/4 years. she spent 75% of her savings on a computer. how much money did anna have left in the jar
Anna has $165 left in the jar. The solution has been obtained by using the arithmetic operations.
What are arithmetic operations?All real numbers are supposed to be explained by the four fundamental operations, often known as "arithmetic operations." In mathematics, operations like quotient, product, sum, and difference occur after operations like division, multiplication, addition, and subtraction.
We are given that Anna saved $20 in a jar each month for 2 complete years and for 9 months of next year.
So, total months = 9 + 12 + 12 = 33
Now, using the multiplication operation, we get
⇒ Total money saved = 33 * 20
⇒ Total money saved = $660
It is given that she spent 75% of her savings on computer.
So, using the subtraction operation, we get
⇒ Amount left = 660 - 75%
⇒ Amount left = $165
Hence, Anna has $165 left in the jar.
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3d *5d*2=?
Please what is 3d times 5d times 2
Answer:
[tex]30d^2[/tex]
Step-by-step explanation:
Two coins are tossed. Assume that each event is equally likely to occur.
a) Use the counting principle to determine the number of sample points in the sample space.
b) Construct a tree diagram and list the sample space.
c) Determine the probability that no tails are tossed.
d) Determine the probability that exactly one tail is tossed.
e) Determine the probability that two tails are tossed.
f) Determine the probability that at least one tail is tossed.
Question content area bottom
Part 1
a) There is/are --------- sample point(s) in the sample space.
a. There are 4 sample points in the sample space.
What are the probability values for the toss?a) There are 4 sample points in the sample space.
b) The tree diagram and sample space are:
HH (two heads)
HT (one head, one tail)
TH (one head, one tail)
TT (two tails)
c) The probability that no tails are tossed (two heads) is 1/4 or 0.25.
d) The probability that exactly one tail is tossed (HT or TH) is 1/2 or 0.5.
e) The probability that two tails are tossed is 1/4 or 0.25.
f) The probability that at least one tail is tossed (HT, TH, or TT) is 3/4 or 0.75.
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Thereare6redmarblesand11orangemarblesinabag.Yourandomly choose one of the marbles. What is the probability of choosing a red marble
The probability of choosing a red marble is 6/17.
What is the probability of choosing a red marbleThe probability of an event occurring is the number of favorable outcomes divided by the total number of possible outcomes.
To calculate this probability, we can use the formula:
P(red marble) = number of red marbles / total number of marbles
In this case, we substitute the numbers we know:
P(red marble) = 6 / 17
So the probability of choosing a red marble is 6/17 or approximately 0.35.
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(6-x):(7-x)::(18-x):(22-x)
Using the property of proportionality for the equation (6-x) : (7-x) :: (18-x) : (22-x), then, x = ⁶/₇.
How did we get the value of x?Solving this problem by using the property of proportionality, which states that the ratio of the first two terms in a proportion is equal to the ratio of the last two terms. In this case:
(6-x) : (7-x) :: (18-x) : (22-x)
Solving for x, cross-multiply the ratios:
(6-x) x (22-x) = (7-x) x (18-x)
Expanding both sides:
132 - 28x + x² = 126 - 25x + x²
Simplifying, we get:
7x = 6
Therefore, x = ⁶/₇.
Thus, the solution to the proportion is:
(6-x) : (7-x) :: (18-x) : (22-x)
or
⁶/₇ : ¹/₇ :: ¹²/₇ : ¹⁶/₇
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The numbers of polio cases in the world are shown in the table for various years.
Year Number of polio cases (thousands)
1988 350
1992 138
1996 33
2000 4
2005 3.2
2007 1.3
PREDICT THE NUMBER OF POLIO CASES IN 2014
hint: The function F gives the number of thousands of polio cases
The value of t is given as 2.3 years.
How to solvewe get the table for function as
t f(t)
8 350
12 138
16 36
20 4
25 3.2
27 1.3
So it is better to model the data by using an exponential model
using a graphing calculator we get our model as
f(t)=a(b)^t
[tex]f(t)=\boldsymbol{3648.6915(0.7380)^t}[/tex]
we have an exponential decay, so we get a rate of decrease as
b=1-r
r=1-b=1-0.738=0.262=26.2\\%
So the number of polio cases is decreasing by 26.2% per year
The number of polio cases in 2014 is
t=2014-1980=34
f(34)=3648.6915(0.7380)^{34}=0.1991389
this is in thousands so we get the number of cases in 2014 approximately as
[tex]0.1191389*1000 \approx \boldsymbol{119} \textup{ cases}[/tex]
for 1 case of polio :
f(t)=0.001
3648.6915(0.738)^t=0.001
we get
[tex]t=\frac{\ln (\frac{0.001}{3648.6915})}{\ln(0.738)}\approx 50[/tex]
so we get year as
1980+50={2030},
to find half life
[tex]\frac{a}{2}=a(b)^t[/tex]
[tex]b^t=\frac{1}{2}[/tex]
[tex]0.738^t=\frac{1}{2}[/tex]
[tex]t=\frac{\ln (1/2)}{\ln (0.738)}\approx\boldsymbol{2.3} \textup{ years}[/tex]
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Amanda’s new job has a 50% employer match on the first 4% of her salary contributed to her 401(k). How much was deposited in Amanda’s account if she makes $61,000 a year and she took advantage of the entire contribution match?
Answer:
$2,440 + $1,220 = $3,660
Step-by-step explanation:
If Amanda makes $61,000 a year, and she contributes 4% of her salary to her 401(k), that would be:
$61,000 x 0.04 = $2,440
Since her employer has a 50% match on the first 4% of her salary, they would contribute:
$2,440 x 0.5 = $1,220
You are making scarves for presents. Each scarf needs 5/6 yd of fabric. How many yards of fabric do you need for 6 scarves?
Someone help i really need help with this
Step-by-step explanation:
step A is incorrect.
-40/5 does not equal to -40/-5.
-40/-5 is equal to 40/5 as we can simplify the negative 1 out.
Answer:
The correct answer is step A