Lower Bound: 20 - 29.67 ≈ -9.67
Upper Bound: 20 + 29.67 ≈ 49.67.
How to solveThe conversion of MAD to the standard deviation for normal distributions can be obtained using the given relationship:
Standard Deviation (σ) = MAD / 0.6745
For both distributions, the MAD holds a value of $20, thus arriving at σ ≈ 29.67.
There are two normal distributions now defined by their parameters as follows:
Mean (µ1) = $100 and Standard Deviation (σ1) = 29.67
Mean (µ2) = $120 and Standard Deviation (σ2) = 29.67.
Since both distributions share an equivalent standard deviation, we can perform a comparison of means to determine the overlap between them.
4
Typically there is observed moderate overlapping within one standard deviation from the difference in means.
The calculation of the difference in means indicates µ2 - µ1 = 120 - 100 = 20. Taking one standard deviation (which equates to 29.67) into consideration with respect to the difference of the means leads us to this range:
Lower Bound: 20 - 29.67 ≈ -9.67
Upper Bound: 20 + 29.67 ≈ 49.67.
It's noteworthy that negative values would not make sense within this context leading us to assume that the approximate overlap range is situated between $0 and $50 resulting in these normal distributions manifesting a sensible amount of overlap therein.
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The Complete Question
When comparing two normal distribution graphs with a mean of $100 and $120 respectively, and both having a MAD of $20, at what range do you see a moderate amount of overlap between the two distributions?
The rate of change dP/dt of the number of students who heard a rumor is modeled by a logistic differential equation. The maximum capacity of the school is 732 students. At 12 PM, the number of students who heard the rumor is 227 and is increasing at a rate of 24 students per hour. Write a differential equation to describe the situation. dP/dt =?
The differential equation to describe the situation is:
dP/dt = 0.000508 * P * (1 - P/732)
We can write a logistic differential equation to describe the rate of change of students who heard the rumor. The equation is:
dP/dt = k * P * (1 - P/M)
where dP/dt is the rate of change in the number of students who heard the rumor, k is a constant, P is the number of students who have heard the rumor at a given time, and M is the maximum capacity of the school (732 students).
At 12 PM, P = 227 and dP/dt = 24 students per hour. We can plug these values into the equation:
24 = k * 227 * (1 - 227/732)
Now, solve for k:
k ≈ 0.000508
So, the differential equation to describe the situation is:
dP/dt = 0.000508 * P * (1 - P/732)
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evaluate the integral tan inverse v(x+2 ) dx by making substitution
and then table of integrals
To evaluate the integral of tan inverse v(x+2) dx, we need to make a substitution. Let u = x + 2, then du/dx = 1 and dx= du. Therefore, the final answer is: ∫ tan inverse v(x+2) dx = (x+2) tan inverse v(x+2) - tan inverse v(x+2) / v'(x+2) + C
Substituting this back into the integral, we get:
∫ tan inverse v(x+2) dx = ∫ tan inverse v(u) du
Using the formula from the table of integrals, we have:
∫ tan inverse v(u) du = u tan inverse v(u) - ∫ u / (1 + v(u)^2) du
Substituting back u = x + 2, we get:
∫ tan inverse v(x+2) dx = (x+2) tan inverse v(x+2) - ∫ (x+2) / (1 + v(x+2)^2) dx
Now, we can use another substitution, let t = v(x+2), then dt/dx = v'(x+2) and dx = dt / v'(x+2).
Substituting this back into the integral, we get:
∫ (x+2) / (1 + v(x+2)^2) dx = ∫ (x+2) / (1 + t^2) dt / v'(x+2)
Using the formula from the table of integrals, we have:
∫ (x+2) / (1 + t^2) dt = tan inverse t + C
where C is the constant of integration.
Substituting back t = v(x+2), we get:
∫ (x+2) / (1 + v(x+2)^2) dx = tan inverse v(x+2) / v'(x+2) + C
Therefore, the final answer is:
∫ tan inverse v(x+2) dx = (x+2) tan inverse v(x+2) - tan inverse v(x+2) / v'(x+2) + C
where C is the constant of integration.
To evaluate the integral of tan inverse v(x+2) dx using substitution, we'll first make a substitution:
Let u = x+2. Then, du = dx.
Now, we can rewrite the integral as:
∫tan^(-1)(v(u)) du
Next, we'll look up the integral of tan^(-1)(v(u)) in a table of integrals. Unfortunately, there isn't a direct formula for this specific integral. However, we can use integration by parts to proceed further.
Let I = ∫tan^(-1)(v(u)) du. Let's choose:
f(u) = tan^(-1)(v(u)) and df(u) = du,
g'(u) = 1 and dg(u) = u du.
Using integration by parts formula:
I = f(u)g(u) - ∫g(u)df(u)
I = u*tan^(-1)(v(u)) - ∫u(1/(1+v^2(u))) du
Now, we'll need to substitute back x+2 for u:
I = (x+2)*tan^(-1)(v(x+2)) - ∫(x+2)(1/(1+v^2(x+2))) dx
This integral doesn't have a simple closed-form solution, so the final answer will remain in the form shown above.
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a small plane leaves an airport and flies north at 240 mi/hr. a jet leaves the airport 30 minutes later and follows the small plane at 360 mi/hr. how long does it take the jet to overtake the small place?
According to the distance, it will take the jet 1 hour to overtake the small plane.
Let's first calculate the distance traveled by the small plane in the time it takes for the jet to overtake it. Since the small plane is flying for an extra 30 minutes, its travel time is "t + 0.5" hours. Therefore, the distance traveled by the small plane is:
Distance of small plane = Speed of small plane x Time of small plane
Distance of small plane = 240 x (t + 0.5)
Now, let's calculate the distance traveled by the jet in "t" hours:
Distance of jet = Speed of jet x Time of jet
Distance of jet = 360 x t
Since both planes are at the same point at the time of overtaking, we can set the distances traveled by both planes equal to each other:
240 x (t + 0.5) = 360 x t
We can solve for "t" using algebra:
240t + 120 = 360t
120 = 120t
t = 1
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a norman window is a window with a semicircle on top of a regular rectangular window as shown in the diagram.what should the dimensions of the rectangular part of the norman window be to allow in as much light as possible if there is only 12 ft of framing material available
The width should be 12 feet and the height should be 6 feet.
Let's assume that the rectangular part of the window has a width of x feet. Since the semi-circle at the top is half the width of the rectangle, its radius will also be x/2 feet. Therefore, the height of the rectangle can be expressed as 12 - x/2, since we have a total of 12 feet of frame material available.
To find the area of the rectangle, we can multiply its length and width together: A = x(12 - x/2) = 12x - x²/2. To maximize this area, we can take its derivative with respect to x and set it equal to 0:
dA/dx = 12 - x = 0
x = 12
So the width of the rectangle should be 12 feet, and its height would be 12 - (12/2) = 6 feet. This would maximize the amount of light entering the rectangular part of the window, given the 12 feet of frame material available.
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In an effort to eat healthier, Bridget is tracking her food intake by using an application on her phone. She records what she eats, and then the
application indicates how many calories she has consumed. One Monday, Bridget eats 10 medium strawberries and 8 vanilla wafer cookies as an
after-school snack. The caloric intake from these items is 192 calories. The next day, she eats 20 medium strawberries and 1 vanilla wafer cookie as an after-school snack. The caloric intake from these items is 99 calories.
a. Write a system of equations for this problem situation. Let S represent the number of calories in one strawberry and let W represent the number of calories in one vanilla wafer cookie.
The equation _____ represents the calories Bridget ate on Monday and the equation _____ represents the calories she ate the next day.
b. Solve the system of equations using the substitution method. Check your work.
The number of calories in each strawberry is ____
And the number of calories in each vanilla wafer cookie is ____. The solution is ____.
PLEASE HELP ME
The equation 10S + 8W = 192 represents the calories Bridget ate on Monday and the equation 20S + 1W = 99 represents the calories she ate the next day.
The number of calories in each strawberry is 4, and the number of calories in each vanilla wafer cookie is 19.
a. We have two equations for the two days, using S for the number of calories in a strawberry and W for the number of calories in a vanilla wafer cookie:
On Monday:
10S + 8W = 192
On Tuesday:
20S + 1W = 99
b. To solve the system of equations using the substitution method, first solve one of the equations for one of the variables. We'll choose the second equation and solve for W:
W = 99 - 20S
Now substitute this expression for W in the first equation:
10S + 8(99 - 20S) = 192
Expand and simplify:
10S + 792 - 160S = 192
Combine like terms:
-150S = -600
Now divide by -150:
S = 4
Now that we have the value for S, substitute it back into the expression for W:
W = 99 - 20(4)
W = 99 - 80
W = 19
So the number of calories in each strawberry is 4, and the number of calories in each vanilla wafer cookie is 19. The solution is (S, W) = (4, 19).
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pleaseeeeee help asapppp
The table shows the purchases made by two customers at a meat counter. you want to buy 2 pounds of sliced ham and 3 pounds of sliced turkey. can you determine how much you will pay? explain.
The cost of purchasing 2 pounds of sliced ham and 3 pounds of sliced turkey from the meat counter is $30.95.
The table provided shows the purchases made by two customers at a meat counter. To determine how much you will pay for 2 pounds of sliced ham and 3 pounds of sliced turkey, you need to first look at the prices listed in the table. For sliced ham, the price per pound is $4.99, and for sliced turkey, the price per pound is $6.99.
To calculate the cost of 2 pounds of sliced ham, you can multiply the price per pound ($4.99) by the number of pounds (2), which gives you a total cost of $9.98. Similarly, to calculate the cost of 3 pounds of sliced turkey, you can multiply the price per pound ($6.99) by the number of pounds (3), which gives you a total cost of $20.97.
Therefore, the total cost for 2 pounds of sliced ham and 3 pounds of sliced turkey would be $9.98 + $20.97 = $30.95.
In conclusion, by using the prices listed in the table, it is possible to determine the cost of purchasing 2 pounds of sliced ham and 3 pounds of sliced turkey from the meat counter. It is important to remember to multiply the price per pound by the number of pounds needed for each item, and then add the costs together to get the total price.
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ķojo and kofta were given 38000 to share. kojo had 7500 more than kofta find each of their shares Show working
Answer:
Kofta receives $15,250 and Kojo receives $22,750.
Step-by-step explanation:
Let x represent the amount of money that Kofta has.
x + (x +7,500) = 38,000
- 7,500 - 7,500
___________________
x + x = 30,500
2x = 30,500
÷ 2 = ÷2
-------------------
x = 15,250
Therefore, Kofta has $15,250.
Let k represent the amount of money that Kojo has.
k + 15,250 = 38,00
k = 38,000 - 15,250
k = $22,750
Therefore, Kojo has $22,750
(1 point) Evaluate the line integral Sc 2y dx + 2x dy where is the straight line path from (4,3) to (9,6). Jc 2g dc + 2z du =
the value of the line integral ∫_C 2y dx + 2x dy along the straight line path from (4,3) to (9,6) is 84.
To evaluate the line integral ∫_C 2y dx + 2x dy along the straight line path from (4,3) to (9,6), follow these steps:
Step:1. Parametrize the straight line path: Define a vector-valued function r(t) = (1-t)(4,3) + t(9,6) = (4+5t, 3+3t), where 0 ≤ t ≤ 1. Step:2. Calculate the derivatives: dr/dt = (5,3). Step:3. Substitute the parametric equations into the line integral: 2(3+3t)(5) + 2(4+5t)(3). Step:4. Calculate the line integral: ∫(30+30t + 24+30t) dt, where the integration is from 0 to 1. Step:5. Combine the terms and integrate: ∫(54+60t) dt from 0 to 1 = [54t + 30t^2] from 0 to 1.
Step:6. Evaluate the integral at the limits: (54(1) + 30(1)^2) - (54(0) + 30(0)^2) = 54 + 30 = 84.
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Pls, answer this, 5 points and brainliest for the one who answers first!
Answer: C
Step-by-step explanation:
f moved left 4 spaces in x direction to get to g
so take opposite sign
f(x+4)
On March 1 a commodity's spot price is $60 and its August futures price is $59. On July 1 the spot price is $64 and the
August futures price is $63. 50. A company entered into futures contracts on March 1 to hedge its purchase of the
commodity on July 1. It closed out its position on July 1. What is the effective price (after taking account of hedging) paid
by the company?
The effective price paid by the company after taking account of hedging would be $63.50, which is the August futures price on July 1. Calculate the profit or loss on the futures contracts and subtract that from the spot price on July 1, to determine the effective.
By entering into futures contracts on March 1, the company was able to lock in the price of $59 for the commodity, when the spot price was $60 and the futures price was $59, the difference between the futures price and the spot price on March 1 was $1 ($60 - $59), so the company had to pay an extra $1 per unit to hedge its purchase.
When the spot price increased to $64 on July 1, the company was still able to purchase the commodity at the lower hedged price of $59, plus the cost of the futures contract, which resulted in an effective price of $63.50. Overall, hedging helped the company mitigate the risk of price volatility and ensured a more predictable cost for the commodity purchase.
Effective price = Spot price - Profit from futures contracts
Effective price = $64 - $0.50(The difference between the futures price and the spot price on July 1 was $0.50 ($64 - $63.50))
Effective price = $63.50 per unit
Therefore, the effective price paid by the company after taking into account hedging was $63.50 per unit.
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In the diagram shown, segments AE and CF are both perpendicular to DB. DE=FB, AE=CF. Prove that ABCD is a parallelogram.
Given:- ABCD is a parallelogram, and AE and CF bisect ∠A and ∠C respectively. To prove:- AE∥CF Proof:- Since in a parallelogram, opposite angles are equal.
What is a Parallelogram?A parallelogram is a geometric shape that has four sides and four angles. It is a type of quadrilateral, which means it has four sides, and its opposite sides are parallel to each other.
The opposite sides of a parallelogram are also equal in length. The opposite angles of a parallelogram are also equal in measure.
The shape of a parallelogram looks similar to a rectangle, but it differs from a rectangle in that its angles are not necessarily right angles. A square is a special case of a parallelogram in which all four sides are equal in length and all four angles are right angles
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Complete the proof that the point (, −3) does or does not lie on the circle centered at the origin and containing the point (5, 0).
the radius of the circle is
The radius of the circle is 5.
To complete the proof, we need to find the radius of the circle centered at the origin and containing the point (5, 0). We can use the distance formula to find the distance between the origin (0, 0) and the point (5, 0):
distance = √((5 - 0)^2 + (0 - 0)^2) = √25 = 5
Therefore, the radius of the circle is 5.
Now, to determine whether the point (, −3) lies on the circle, we need to find the distance between the origin and the point (, −3):
distance = √((-3 - 0)^2 + (0 - 0)^2) = √9 = 3
Since the distance between the origin and the point (, −3) is not equal to the radius of the circle, which is 5, we can conclude that the point (, −3) does not lie on the circle centered at the origin and containing the point (5, 0).
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Use linear approximation to approximate √125.04 as follows Let f(x) = ³√ x, and find the linearization of f(x) at x = 125 in the form y = mx+ b Note: The values of m and bare rational numbers which can be computed by hand. You need to enter expressions which give m and b exactly You should not have a decimal point in the answers to either of these parts m= b = Using these values, find the approximation Also, for this part you should be entering a rational number, not a decimal approximation ²√ 125.04≈
To approximate √125.04 using linear approximation, first find the linearization of f(x) = ³√x at x = 125. Then use the point-slope form of the equation to find the equation of the tangent line and plug in x = 125.04 to get the approximation.
To approximate √125.04 using linear approximation and the function f(x) = ³√x, first find the linearization of f(x) at x = 125 in the form y = mx + b. Calculate f(125) and f'(x).Calculate f'(125): Use the point-slope form of the equation
1: Calculate f(125) and f'(x).
f(125) = ³√125 = 5
f'(x) = (1/3)x^(-2/3)
2: Calculate f'(125).
f'(125) = (1/3)(125)^(-2/3) = 1/15
3: Use the point-slope form of the equation y - y1 = m(x - x1) to find the equation of the tangent line.
y - 5 = (1/15)(x - 125)
4: Rearrange to find y in terms of x.
y = (1/15)(x - 125) + 5
5: Determine the values of m and b.
m = 1/15
b = (1/15)(-125) + 5
6: Plug in x = 125.04 to approximate √125.04.
²√125.04 ≈ (1/15)(125.04 - 125) + 5
The linearization of f(x) at x = 125 is y = (1/15)x + b, with m = 1/15 and b = (1/15)(-125) + 5. Using these values, the approximation of √125.04 is (1/15)(125.04 - 125) + 5.
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Construct a square, and a regular Pentagon with equal side equal to 0. 5 inch.
To construct a square and a regular pentagon with equal side lengths of 0.5 inch, we need to use basic geometric constructions.
How can I create a square and a regular pentagon with equal side lengths of 0.5 inch?To construct a square and a regular pentagon with equal side length of 0.5 inch, follow these steps:
(a) Construct a Square:
Draw a horizontal line segment of length 0.5 inch.From the endpoints of the line segment, draw two perpendicular lines of length 0.5 inch each, meeting at the endpoints of the original line segment.From the endpoints of these new line segments, draw two more perpendicular lines of length 0.5 inch each, meeting at the endpoints of the second line segment.Connect the endpoints of the four line segments to form a square.
(b) Construct a Regular Pentagon:
Draw a circle with a radius of 0.5 inch. This will be the circumcircle of the pentagon.Draw a horizontal line through the center of the circle.Mark the points where the line intersects the circle. These will be the vertices of the pentagon.Draw a line segment connecting two adjacent vertices of the circle.Using a compass, copy the length of this line segment to the next vertex, and connect the two vertices to form a line segment of the pentagon.Repeat this process for all five vertices of the circle to form the regular pentagon.
A geometric construction is a method of drawing a figure using only a straightedge (an unmarked ruler) and a compass.
For the square, we start by drawing a horizontal line segment of length 0.5 inch. We then draw two perpendicular lines of length 0.5 inch each, meeting at the endpoints of the original line segment.
These two new line segments represent the adjacent sides of the square. We then repeat this process to create the remaining two sides of the square, and connect all four endpoints to form the complete square.
For the regular pentagon, we need to construct a circle with a radius of 0.5 inch. This will be the circumcircle of the pentagon, meaning that all five vertices of the pentagon will lie on the circle.
We draw a horizontal line through the center of the circle, and mark the points where the line intersects the circle. These five points will be the vertices of the pentagon.
We then draw line segments connecting adjacent vertices, using a compass to copy the length of each line segment from the previous one.
This process will create all five sides of the pentagon, and the figure will be a regular pentagon with equal side lengths of 0.5 inch.
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A dealer paid $10,000 for a boat at an auction. At the dealership, a salesperson sold the boat for 30% more than the auction price. The salesperson received a commission of 25% of the difference between the auction price and the dealership price. What was the salesperson’s commission?
The commission of the salesperson is $750 if he received a commission of 25% of the difference between the auction price and the dealership price.
The salesperson's commission can be calculated by first finding the dealership price, which is 30% more than the auction price of $10,000.
30% of $10,000 = $3,000
Dealership price = $10,000 + $3,000 = $13,000
Next, we need to find the difference between the dealership price and the auction price
$13,000 - $10,000 = $3,000
The salesperson's commission is 25% of this difference
25% of $3,000 = $750
Therefore, the salesperson's commission is $750.
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Which pair of transformations moves quadrilateral 1 to quadrilateral 2?
o a. reflect it over the line y = -3, then rotate it 90° counterclockwise about the origin
o b. reflect it over the x-axis, then rotate it 180° about the origin
o c. rotate it 90° counterclockwise about point (-3,-3), then translate it 8 units to the right
o d translate it 8 units to the right, then reflect it over the line y=-3
c. rotate it 90° counterclockwise about point (-3,-3), then translate it 8 units to the right
How does quadrilateral 1 move to quadrilateral 2?The correct pair of transformations that moves quadrilateral 1 to quadrilateral 2 is option d: translate it 8 units to the right, then reflect it over the line y = -3.
First, by translating it 8 units to the right, all points of quadrilateral 1 will shift horizontally to the right by 8 units, maintaining their relative positions.
Next, reflecting it over the line y = -3 will result in a vertical flip of the shape. This reflection will change the orientation of the quadrilateral while keeping the translated positions intact.
Together, these two transformations will precisely move quadrilateral 1 to quadrilateral 2. Therefore, option d is the correct choice.
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Write a system of inequalities whose solution is the set of all points in quadrant I not including the axis's.
The set of all points in quadrant I not including the axis's can be represented by the following system of inequalities:
x > 0
y > 0
Inequalities are useful in modeling situations where there are constraints or limitations. For illustration, in real- life scripts, there may be limited coffers or capacity, or certain variables must fall within a specific range. Systems of inequalities are frequently used to represent these constraints or limitations graphically. One common operation of systems of inequalities is in optimization problems, where the thing is to maximize or minimize a particular function subject to certain constraints.
In these situations, the doable region, or the set of all points that satisfy the constraints, is frequently represented as a shadowed region on a graph. The optimal result is also set up by relating the point( s) within this region that maximize or minimize the function.
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Kaleb’s mom owns a confidence store. He is helping her replace the tile floor. The tile costs $2.00 per ft squared.
How much will the tile cost?
Answer:
425
Step-by-step explanation:
212,5*2=425
Peter eats 3 carrot sticks, with 1 cup of peanut butter, p, every day before lacrosse practice. he practices 4 days a week.
select all the equivalent expressions that represents how much peter eats before practice in one week.
To find out how much Peter eats in one week (which is 7 days), we need to multiply this expression by 7.
How much Peter eats before practice in one week?Peter eats 3 carrot sticks and 1 cup of peanut butter before lacrosse practice every day, so in one day he eats:
3 + p
To find out how much he eats in one week (which is 7 days), we need to multiply this expression by 7:
7(3 + p)
Distributing the 7, we get:
21 + 7p
So the equivalent expressions that represent how much Peter eats before practice in one week are:
3 + 4p + 3p
4(3 + p)
21 + 7p
7(3p + 1)
So the correct answers are:
4(3 + p)
21 + 7p
7(3p + 1)
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Square root 2/3 + square root 6
Answer:
[tex] \sqrt{ \frac{2}{3} } + \sqrt{6} \\ = \frac{ \sqrt{2} }{ \sqrt{3} } + \sqrt{6} \\ = \frac{ \sqrt{2} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } + \sqrt{6} \\ = \frac{ \sqrt{6} }{3} + \sqrt{6} \\ = \frac{ \sqrt{6} }{3} + \frac{3 \sqrt{6} }{3} \\ = \frac{ 4\sqrt{6} }{3} [/tex]
The area of a rooftop can be
expressed as (x + 9)2. The rooftop
is a rectangle with side lengths
that are factors of the expression
describing its area. Which expression
describes the length of one side of
the rooftop?
The expression that describes the length of one side of the rooftop is therefore: x - 9.
What is expression?In mathematics, an expression is a combination of one or more variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. An expression can be as simple as a single variable or constant, or it can be a more complex combination of variables and operations.
Here,
The expression for the area of the rooftop is (x + 9)², where x is a variable representing the length of one side of the rectangle. To find the factors of this expression, we can expand it using the identity (a+b)² = a² + 2ab + b².
Expanding (x + 9)², we get:
(x + 9)² = x² + 18x + 81
Now, we need to find the factors of this expression that are also factors of the length of the sides of the rectangle. Since the sides of the rectangle must have a common factor of x, we can factor out x from the expression:
x² + 18x + 81 = x(x + 18) + 81
The factors of (x + 9)² are x(x + 18) + 81, (x + 9)(x + 9), (x - 9)(x - 9), and -(x + 9)(x + 9).
Since we are looking for factors that represent the length of one side of the rooftop, we can eliminate the negative factor and the factor (x + 9)(x + 9), since the sides of a rectangle must be positive.
That leaves us with x(x + 18) + 81 and (x - 9)(x - 9).
The expression describes the length of one side of the rooftop: x - 9
This is because the sides of a rectangle must be positive, and (x - 9) is a factor of (x + 9)² that represents a positive length.
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Building a campfire you start by stacking kindling wood to form a pentagonal pyramid that is 27 centimeters tall. the base area is 965 square centimeters. what is the volume of the campfire pyramid
The volume of the campfire pyramid is approximately 8,175 cubic centimeters. This is found by using the formula for the volume of a pyramid and plugging in the given values for the height and base area of the pentagonal pyramid.
The formula for the volume of a pyramid is
V = (1/3) * base_area * height
where V is the volume, base_area is the area of the base, and height is the height of the pyramid.
In this case, the height of the pyramid is given as 27 cm, and the base area is given as 965 square cm. To find the volume, we can plug these values into the formula
V = (1/3) * 965 cm² * 27 cm
V = 8,175 cm³
Therefore, the volume of the campfire pyramid is 8,175 cubic centimeters.
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Lochlon transfers his investment into a money market account. The account now earns compound interest of 1. 95% annually with a maturity date of 5 years
The final amount Lochlon will earn on his investment after 5 years of compound interest is $1,104.36
How we calculate the compound interest?Compound interest is a type of interest calculation where the interest earned is added to the principal amount, and the resulting sum becomes the new principal for the next interest calculation. The formula for compound interest is:
A = [tex]P(1 + r/n)^(^n^t^)[/tex]
Where:
A is the final amount including the interest
P is the principal amount
r is the annual interest rate as a decimal
n is the number of times the interest is compounded per year
t is the time in years
In this case, Lochlon transferred his investment into a money market account that earns compound interest of 1.95% annually, with a maturity date of 5 years.
To find the final amount Lochlon will earn, we need to know the principal amount, the interest rate, the number of times the interest is compounded per year, and the time period.
Assuming Lochlon invests a principal amount of P dollars, with an annual interest rate of r = 1.95%, and the interest is compounded annually (n = 1) for a time period of 5 years (t = 5), the formula for calculating the final amount (A) is:
A = [tex]P(1 + r/n)^(^n^t^)[/tex]
= [tex]P(1 + 0.0195/1)^(^1^*^5^)[/tex]
= [tex]P(1.0195)^5[/tex]
if Lochlon invests $1,000, for example, then his final amount (A) after 5 years would be:
A = [tex]1000(1.0195)^5[/tex]
= 1000(1.10436)
= $1,104.36
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During an elbow flexion exercise, the relative angle at the elbow was 10 degrees at 0. 5s and 120 degrees at 0. 71s. What was the angular velocity of the elbow?
The angular velocity of the elbow during the elbow flexion exercise was approximately 523.81 degrees/s
To calculate the angular velocity of the elbow during an elbow flexion exercise, we'll use the information given about the relative angle at different times. Here's the step-by-step explanation:
First, find the change in relative angle: Δθ = Final angle - Initial angle = 120 degrees - 10 degrees = 110 degrees.
Next, find the change in time: Δt = Final time - Initial time = 0.71s - 0.5s = 0.21s.
Now, calculate the angular velocity: ω = Δθ / Δt = 110 degrees / 0.21s ≈ 523.81 degrees/s.
So, the angular velocity of the elbow during the elbow flexion exercise was approximately 523.81 degrees/s.
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The data set shown below represents the number of times some families went out for dinner the previous week. 4, 2, 2, 0, 1, 6, 3, 2, 5, 1, 2, 4, 0, 1 an unnumbered number line labeled numbers of dinners out. create a dot plot to represent the data. what can you conclude about the dot plot of the data set? check all that apply. the range of the number line should be 0 to 7 to represent the frequency. four families said they ate out twice the previous week. one family said they ate out 5 times the previous week. the data set is symmetrical. the median best represents the data set.
Answer: B, C, E
Step-by-step explanation: Other dude posted wrong answer.
If the range of f (x) = startroot m x endroot and the range of g (x) = m startroot x endroot are the same, which statement is true about the value of m?
The only possible value of m that would make the ranges of f(x) and g(x) the same is any positive real number.
The range of a function is the set of all possible output values. In this case, we are given that the ranges of two functions, f(x) and g(x), are the same.
The function f(x) = √(mx) has a domain of x ≥ 0, since the square root of a negative number is not a real number. The function g(x) = m√x has a domain of x ≥ 0 for the same reason.
To find the range of these functions, we need to consider the possible values of the input x. For f(x), as x increases, the output √(mx) also increases, and as x approaches infinity, so does the output. For g(x), as x increases, the output m√x also increases, and as x approaches infinity, so does the output.
Therefore, if the ranges of f(x) and g(x) are the same, this means that they both have the same maximum and minimum values, and these values are achieved at the same inputs.
In particular, if we consider the minimum value of the range, this is achieved when x = 0, since both functions are defined only for non-negative inputs. At x = 0, we have f(0) = g(0) = 0, so the minimum value of the range is 0.
To find the maximum value of the range, we need to consider the behavior of the functions as x approaches infinity. As noted above, both functions increase without bound as x increases, so the maximum value of the range is infinity.
Therefore, the only possible value of m that would make the ranges of f(x) and g(x) the same is any positive real number.
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what principal will earn $67.14 interest at 6.25% for 82 days?
Answer: attach an image
Step-by-step explanation:
To find the principal, we can use the formula for simple interest:
I = P*r*t
where I is the interest, P is the principal, r is the interest rate, and t is the time in years.
We need to convert 82 days to years by dividing it by 365 (the number of days in a year):
t = 82/365
t = 0.2247
Now we can plug in the values we know and solve for P:
67.14 = P*0.0625*0.2247
P = 67.14/(0.0625*0.2247)
P = 1900
Therefore, the principal is $1900.
(1 point) Write an equivalent integral with the order of integration reversed ST 2-3 F(x,y) dydc = o g(y) F(x,y) dedy+ So k(y) F(x,y) dardy Jh(v) a- he C- f(y) = g(y) = h(g) = k(y) =
equivalent integral with the order of integration reversed ST 2-3 F(x,y) dydc = o g(y) F(x,y) dedy+ So k(y) F(x,y) dardy Jh(v) a- he C- f(y) = g(y) = h(g) = k(y) = By reversing the order of integration, you've found an equivalent integral to the original one provided.
step-by-step explanation to achieve this, using the terms "integral," "reversed," and "equivalent" in the answer.
Step 1: Identify the original integral
The original integral is given as ∫∫ F(x, y) dy dx, where the integration limits are not explicitly provided. In this case, let's assume the limits of integration for y are from a(x) to b(x), and for x, they are from c to d.
Step 2: Sketch the region of integration
To reverse the order of integration, it's helpful to sketch the region of integration, which is the area in the xy-plane where the function F(x, y) is being integrated.
Step 3: Determine the new limits of integration
After sketching the region, determine the new limits of integration by considering the range of x for a given y value, and the range of y values. Let's assume the new limits for x are from g(y) to h(y), and for y, they are from e to f.
Step 4: Write the equivalent reversed integral
Now, you can write the equivalent integral with the order of integration reversed. In this case, it will be ∫∫ F(x, y) dx dy, with the new limits of integration. The complete reversed integral will look like:
∫(from e to f) [ ∫(from g(y) to h(y)) F(x, y) dx ] dy
By reversing the order of integration, you've found an equivalent integral to the original one provided.
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A tray of lasagna comes out of the oven at 200°F and is placed on a table
where the surrounding room temperature is 70°F. The temperature T (in °F) of
the lasagna is given by the function (0) -e(486753-1) +70, 0 s t, where tis time
(in hours) after taking the lasagna out of the oven. What is the rate of change
in the temperature of the lasagna exactly 2 hours after taking it out of the
oven?
Rate of change in the temperature of lasagna given by function T(t) = 70 + (200 - 70) × [tex]e^{(-0.0001t)}[/tex] exactly 2 hours after taking it out of oven is -0.013 °F/hour.
Surrounding room temperature is equal to 70°F
Temperature at which lasagna comes out of the oven = 200°F
The temperature T (in °F) of the lasagna at time t (in hours) after taking it out of the oven is equal to,
T(t) = 70 + (200 - 70) × [tex]e^{(-0.0001t)}[/tex]
To find the rate of change in the temperature of the lasagna exactly 2 hours after taking it out of the oven,
Find the derivative of the temperature function with respect to time t.
T'(t) = -0.013[tex]e^{(-0.0001t)}[/tex]
Substituting t = 2 into this expression gives:
T'(2) = -0.013[tex]e^{(-0.0001\times 2)}[/tex]
= -0.013[tex]e^{-0.0002}[/tex]
= -0.013 × 0.99980
= -0.0129974
= -0.013
Therefore, the rate of change in the temperature of the lasagna exactly 2 hours after taking it out of the oven is approximately -0.013 °F/hour.
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The given question is incomplete, I answer the question in general according to my knowledge:
A tray of lasagna comes out of the oven at 200°F and is placed on a table where the surrounding room temperature is 70°F. The temperature T (in °F) of the lasagna is given by the function T(t) = 70 + (200 - 70) × [tex]e^{(-0.0001t)}[/tex] where t is time(in hours) after taking the lasagna out of the oven. What is the rate of change in the temperature of the lasagna exactly 2 hours after taking it out of the oven?