Using the avg H2O2 molarity (0.7959 M H2O2) and volume of H2O2 (49.8 ml H2O2), calculate the moles of H2O2 that were composed by the catalyst (10 mL of potassium iodine)

Answers

Answer 1

The number of mole of H₂O₂ that were composed by the catalyst (10 mL of potassium iodine) is 0.0396 mole

How do i determine the number of mole of H₂O₂?

From the question given above, the following data were obtained

Molarity of H₂O₂ solution = 0.7959 MVolume of H₂O₂ solution = 49.8 mL = 49.8 / 1000 = 0.0498 LNumber of mole of H₂O₂ solution =?

Molarity and number of mole of as substance are related according to the following equation

Molarity = number of mole / Volume

Inputting the given parameters, the number of mole H₂O₂ solution can be obtain as shown below:

0.7959 = number of mole of H₂O₂ solution / 0.0498

Cross multiply

Number of mole of H₂O₂ solution = 0.7959 × 0.0498

Number of mole of H₂O₂ solution = 0.0396 mole

Thus, the number of moles of H₂O₂ solution composed is 0.0396 mole

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The light-dependent reactions (Photosynthesis)occur in the thylakoid membranes of chloroplasts and involve the absorption of light by pigments such as chlorophyll. This energy is then used to generate ATP and NADPH, which are used in the next stage of the process. The light-independent reactions occur in the stroma of chloroplasts and involve the fixation of carbon dioxide into organic molecules using the energy generated in the previous stage. 

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