What is 1/3 a millisecond in seconds (decimal form)? (0._ s)​

Answers

Answer 1

Answer:

I don't know

Explanation:

plz

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Related Questions

I need HELP! IMMEDIATELY!!!

Answers

Answer:

Option A

Explanation:

N is Chloroplast, P is a large centralized vacuole and R is the cell wall which are found only in plant cells. Hence, the given cell is a plant cell.

S = Rough Endoplasmic Reticulum

P = Vacuole

O = Nucleus

T = Smooth Endoplasmic Reticulum

U = Golgi Apparatus

N = Chloroplast

U = Cell Membrane

M = Mitochondria

R = Cell wall

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

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While driving your car at a fast constant speed, you have to press down hard on your gas pedal than you do while driving at a slower constant speed.

In both cases, the net force on your car is zero. Explain why you have to apply a greater pressure to your gas pedal.

Answers

Answer:

You have to apply more pressure to the pedal so more gas runs through the car allowing it to reach higher speeds

To move, a car or any other object must be accelerated from rest to the desired speed; this necessitates that the engine force be greater than the friction force. The net force must be zero once the car is moving at constant velocity; otherwise, the car will accelerate (gain speed).

What forces act on a car at constant speed?All forces acting on a car moving at a constant speed (uniform motion) are balanced. In this case, the two opposing backward forces (air resistance and friction) perfectly balance the applied force of the wheels on the road.When we say constant speed, we mean that a body or object moves at a constant change in distance over time. For example, if we are walking in a straight line at 1 step per second, we can say we are moving at a constant speed. Our acceleration is equal to zero in this case.

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Una masa de aire de 20g absorbe 780 cal. Teniendo en cuenta que su temperatura inicial es de 30°C. Calcular la
temperatura que alcanzo al absorber el calor. Ce:0,24 cal/g °C

Answers

Answer:

sorry I don't know the answer

a father pulls his young daughter on a sled (where the combined mass of his daughter and the sled are 40 kg) with a constant velocity up a snowy hill that is inclined at 14 to the horizontal. a) if the coefficient of kinetic friction between the sled's runners and the snow is 0.15, what is the tension force of the rope on which the father pulls

Answers

Answer:

Explanation:

We are not told what angle the pull rope is to any other reference. That could make a huge difference in the result.

If we ASSUME that the rope pulls parallel to the slope

Then , if T is rope tension

                                  F = ma

T - mgsinθ - μmgcosθ = m(0)

                                 T = mg(sinθ + μcosθ)

                                 T = 40(9.8)(sin14 + 0.15cos14)

                                 T = 151.88677... 150 N

If the rope pulls the sled at a positive angle relative to the slope, As one might expect from an adult holding the rope, then the tension will be increased because only the Tension portion parallel to the slope causes motion in that direction, but will be decreased because the Normal force, and therefore the friction force, of the slope on the sled will be decreased.

chứng minh mặt trời là nguồn gốc của tất cả nguồn năng lượng

Answers

An Excerpt from “Optimism”

by Helen Keller

1 Could we choose our environment, and were desire in human undertakings synonymous with

endowment, all men would, I suppose, be optimists. Certainly most of us regard happiness as

the proper end of all earthly enterprise. The will to be happy animates alike the philosopher, the

prince and the chimney-sweep. No matter how dull, or how mean, or how wise a man is, he feels

that happiness is his indisputable right.

2 It is curious to observe what different ideals of happiness people cherish, and in what singular

places they look for this well-spring of their life. Many look for it in the hoarding of riches, some

in the pride of power, and others in the achievements of art and literature; a few seek it in the

exploration of their own minds, or in the search for knowledge.

3 Most people measure their happiness in terms of physical pleasure and material possession.

Could they win some visible goal which they have set on the horizon, how happy they would be!

Lacking this gift or that circumstance, they would be miserable. If happiness is to be so

measured, I who cannot hear or see have every reason to sit in a corner with folded hands and

weep. If I am happy in spite of my deprivations, if my happiness is so deep that it is a faith, so

thoughtful that it becomes a philosophy of life,—if, in short, I am an optimist, my testimony to

the creed of optimism is worth hearing....

4 Once I knew the depth where no hope was, and darkness lay on the face of all things. Then

love came and set my soul free. Once I knew only darkness and stillness. Now I know hope and

joy. Once I fretted and beat myself against the wall that shut me in. Now I rejoice in the

consciousness that I can think, act and attain heaven. My life was without past or future; death,

the pessimist would say, “a consummation devoutly to be wished.” But a little word from the

fingers of another fell into my hand that clutched at emptiness, and my heart leaped to the

rapture of living. Night fled before the day of thought, and love and joy and hope came up in a

passion of obedience to knowledge. Can anyone who has escaped such captivity, who has felt

the thrill and glory of freedom, be a pessimist?

5 My early experience was thus a leap from bad to good. If I tried, I could not check the

momentum of my first leap out of the dark; to move breast forward is a habit learned suddenly

at that first moment of release and rush into the light. With the first word I used intelligently, I

learned to live, to think, to hope. Darkness cannot shut me in again. I have had a glimpse of the

shore, and can now live by the hope of reaching it.

6 So my optimism is no mild and unreasoning satisfaction. A poet once said I must be happy

because I did not see the bare, cold present, but lived in a beautiful dream. I do live in a

beautiful dream; but that dream is the actual, the present,—not cold, but warm; not bare, but

furnished with a thousand blessings. The very evil which the poet supposed would be a cruel

6) Read the last sentence from the text.

Only by contact with evil could I have learned to feel by contrast the beauty of truth and love and goodness.

Explain how Helen Keller develops this idea in the text. Use specific details to

support your answer.

When converted to a household measurement, 9 kilograms is approximately equal to a

Answers

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

Lab: Motion with Constant Acceleration Assignment: Lab Report

Write your lab report


Someone please help me do this, ill give brainliest

Answers

Answer:

Table C:

Fan Speed Observations of Position vs. Time Graphs

Low:

The slope is curved and it increases as you go up . The points start off close but they spread out as the time increases.

Medium:

The speed increases quicker than the graph for low speed. The graph is less curved than the one for low speed. Also, the points spread out faster than they did for low speed as the time increases.

High:

The Graph has a smaller curve then the low and medium speed. Also, the points are the furthest apart. The slope is not as spaced out as it was for the rest of the speed graphs.

Explanation:

hope it helps

Variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.

Objective: The goal of this lab experiment was to investigate the motion of an item with constant acceleration and to examine its velocity as a function of time.

Materials:

Smooth, inclined plane

Cart or tiny wheeled object

Stopwatches and timers

Measuring tape or meterstick

Procedure:

Set up the inclined plane at a 45-degree angle () to the horizontal surface. Check that the plane is smooth and clear of obstacles.

Place the cart or small wheeled object at the bottom of the inclined plane.

Using a meterstick or measuring tape, determine the height (h) and length (L) of the inclined plane.

Ascertain that the cart is at rest at the starting point, which is located at the bottom of the inclined plane.

As soon as the cart is freed and begins to move, start the stopwatch or timer.

Calculate the time (t) it takes the cart to reach each place along the inclined plane. To ensure reliable data gathering, repeat the experiment numerous times.

Determine the time intervals (Δt) between each position for velocity analysis

Data:

Position (m) Time (s) Time Interval (Δt) (s)

0.0                   0.00           -

0.5                   0.50        0.50

1.0                   0.75        0.25

1.5                    1.10              0.35

2.0                    1.50        0.40

Analysis:

Calculate the average velocity between each position by dividing the position change by the time interval (x/t).

Create a graph that plots average velocity (V_avg) versus time (t).

Results:

A straight line emerges from the graph of average velocity against time, demonstrating that the cart's motion was subject to continuous acceleration along the inclined plane. The slope of the graph reflects the acceleration (a) of the cart.

Conclusion:

The experiment successfully demonstrated motion along an inclined plane with constant acceleration. The graph of average velocity vs time revealed important information about the cart's speed, with a linear relationship suggesting steady acceleration. This experiment emphasizes kinematic principles and the significance of using velocity-time data to understand the motion of objects under constant acceleration.

Hence, variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.

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Which graph uses bars to show data that are broken into intervals?
O A. Scatter plot
O B. Bar graph
O C. Box-and-whisker plot
O D. Histogram

Answers

Answer:

A. scatter plot?

Explanation:

I dont really know if I'm right... sorry.

An 80 kg box is accelerated to the right at a rate of 3 m/s2. What is the applied force?

Answers

As we know,

F= ma

Here,

applied force(f)= mass × acceleration

=80kg×3m/s2

=240kgm/s2

=240N

A car’s velocity as a function of time is given by Vx (t) = α.t + β.t 2 , where α= 3m/s and β= 0.1m/s 3 . Calculate the average acceleration for the time interval

b) t= 5 to t = 10 s

Answers

The definition of average acceleration allows to find the result for the average acceleration in the given time interval is:

          [tex]a_{average}= 1.5 \ \frac{m}{s^2}[/tex]

Instantaneous acceleration is defined as the derivative of velocity with respect to time.

           a =   [tex]\frac{dv}{dt}[/tex]

Where a is the acceleration, v the velocity and t the time.

They indicate that the speed of the car is given by the relation.

          v = α t + β t²

With α = 3 m / s and β = 0.1 m / s³

Let's make  the derivative.

           a = α + 2β t

Let's substitute

            a = 3 + 2 0.1 t

Average acceleration is the change in velocity in the time interval.  

          [tex]a_{average} = \frac{\Delta v}{\Delta t }[/tex]

Let's find the velocity at the indicated time.

For t = 5 s

         v₅ = 3 + 0.1 5²

         v₅ = 5.5 m / s

For t = 10 s

          v₁₀ = 3 + 0.1 10²

          v₁₀ = 13 m / s

Let's calculate the average acceleration.

           [tex]a_{average} = \frac{13 - 5.5 }{ 10 - 5 }\\[/tex]

           [tex]a_{average}= 1.5 \ m/s^2[/tex]

In conclusion using the definition of mean acceleration we can find the result for the mean acceleration in the given time interval is:

           [tex]a_{average} =[/tex]  1.5 m / s²

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A baseball is hit so that it travels straight upward after being struck by the bat. If its initial velocity is 29 m/s , then what is the maximum height that it will reach?

Answers

Answer:

Explanation:

Use kinematic equation v² = u² + 2as

Rearrange for distance

s = (v² - u²) / 2a

Realize that at the top of its flight, the ball has zero velocity and gravity is acting downward in an assumed upward positive reference frame.

s = (0² - 29²) / (2(-9.8))

s = 42.90816...

s = 43 m

Suppose a ball is dropped from a building. What is the change of velocity between the first and fifth seconds of its flight

Answers

Answer: 39.2m/s

Explanation:

Due to the free falling body, the acceleration of the ball is 9.8 m/s^2, and its initial velocity is 0 m/s.

V(t) = g*t

The change of velocity from t=1 to t=5:

Delta V = 9.8*(5-1) = 39.2 m/s

Technician a says that the piston engine starts and stops several times per 2nd technician B says that with the rotary engine each rotor has 3 working chambers so it acts like a 3 cylinder engine while it is at operating

Answers

Answer:

Explanation:

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HELPPP


Which of the following statements about friction is FALSE .
1 ) Friction involves objects that are in physical contact .
2) Friction is less if surfaces are very smooth .
3 ) Friction is always in the direction of the motion .
4) Friction is caused by the uneven surfaces of touching objects

Answers

Friction is caused by the uneven surfaces of touching objects

A toy car on a string is pulled across a table horizontally. The string is at an
angle of 30°. Which is the correct free-body diagram for this situation?
EN
w
w
w
w
А
B
с
D
A. A
ОВ. В
ОО Ο Ο
O C. C
D. D

Answers

(C)

...........................

Answer:

Hope this helps!

Explanation:

Computes average speed when a person walk for 1 minute at speed of 1.5 m/s and another 1 minute at speed of 3.5 m/s along a straight road

Answers

Answer:

2.5 m/s

Explanation:

(60*1.5+60*3.5)/120=2.5

or

(1.5+3.5)/2=2.5

name a substance which will undergo change E​

Answers

Answer:

Water

Explanation:

At 0 degrees it's solid...Then it melts into a liquid and at 100 degrees it's gas Simple

Indicate whether each of the following statements about car collisions is true or false. Select all that are True.

a. If two identical cars with identical speeds collide head on, the magnitude of the impulse received by each car and each driver is the same as if one car at the same speed had collided head on with a concrete wall.
b. Car 1 has mass m, and car 2 has mass 2m. In a head-on collision of these cars while moving at identical speeds in opposite directions, car 1 experiences a bigger acceleration than car 2.
c. The essential safety benefit of crumple zones (parts of the front of a car designed to receive maximum deformation during a head-on collision) is due to their absorbing kinetic energy, converting it into deformation, and lengthening the effective collision time, thus reducing the average force experienced by the driver.
d. Car 1 has mass m, and car 2 has mass 2m. In a head-on collision of these cars while moving at identical speeds in opposite directions, car 1 receives an impulse of bigger magnitude than that received by car 2. If car 1 has mass m and speed v, and car 2 has mass 0.5m and speed 1.5v, then both cars have the same momentum.

Answers

Answer:

True statements a, b, and c

Explanation:

Answer d is false because in any collision, each object receives the same impulse. Also the momentum of car 1 is mv, while the momentum of car 2 is 0.5m(1.5v) = 0.75mv

The impulse of collision of cars depends on the mass and velocity of the cars. The statements which are true about the car collisions are option a, b, c.

What is impulse?

Impulse is a physical quantity expressed as the product of force and time. The change in momentum mΔV is numerically equals to the impulse F t.

If two identical cars with identical speeds collide head on, the magnitude of the impulse received by each car and each driver is the same as if one car at the same speed had collided head on with a concrete wall. Because they have equal mass and velocity.

The bigger acceleration is experienced by the one which have lighter mass thus car 1 with lower mass experience higher acceleration .

The essential safety benefit of crumple zones (parts of the front of a car designed to receive maximum deformation during a head-on collision) is due to their absorbing kinetic energy.

Converting this energy into deformation, and lengthening the effective collision time, thus reducing the average force experienced by the driver.

The momentum change is proportional to the velocity. The one which have higher velocity is having the higher momentum. Thus car 2 have higher velocity. Thus option d is false.

Therefore, the statements which are true are a, b and c.

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I really need your help I will mark you brainliest!
I have been stuck for 15 minutes!!

Answer the following questions about Hurricane Harvey:
a. Why did hurricane Harvey travel from the east (Africia) twards the west (Florida) when our weather starts in the west and travels east?
B. why did hurricane harvey rotate counterclockwise? Do all hurricanes rotate counterclockwise?

Answers

https://www.lsop.colostate.edu/wp-content/uploads/sites/6/2014/10/HurricanesGoCounterclockwise.pdf

Discuss How are the acceleration, the net force, and the mass of
an object related? SC.6.P.13.3
13 SEBS

Answers

According to Newton's second law

[tex]\\ \sf\longmapsto Force=Mass\times Acceleration[/tex]

[tex]\\ \sf\longmapsto Mass=\dfrac{Force}{Acceleration}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{Force}{Mass}[/tex]

PHYSICISTS NEEDED, THANK YOU, (10 POINTS)

Answers

Answer:

would it be 2.66666666667 or 2.7

Explanation:

What is the kinetic energy of a 36N toy car which is moving at 5 m/s?

Answers

Answer : I think the answer is 45 J
Explanation: in the picture

1. According to the picture, which is the least dense?
O A. the chess piece
O B. the toy soldier
O C. the liquid in the container
O D. There is no way to tell,

Answers

A chess piece is the less dense

According to the picture, the chess piece is the least dense. The correct option is A.

The amount of mass that a substance has in relation to its volume is referred to as its density. It is a measurement of how closely together the molecules or particles are arranged within a given object or material.

Typically, floating objects are less dense than the liquid they are in. The fact that the chess piece is floating on the water suggests that it is less dense than the liquid.

It might be an alternative, though, if the toy soldier is also floating and not submerged. More visual context is necessary for precise determination.

Thus, the correct option is A.

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Tell me any 5 importance of medicinal plants​

Answers

Answer:

Aloe, Tulsi, Neem, Turmeric, and Ginger are medicinal plants that can help with a variety of diseases. Ginger, green tea, walnuts, aloe, pepper, and turmeric are just a few of these plants. Some plants and their derivatives are key sources of active compounds used in aspirin and toothpaste, among other things.

Explanation:

Plant name:                                    Uses:

1. Marshmallow:      ////  Relief from aching muscles and pain in muscle, Heals insect bite.             ////

2.California poppy ////  Relieves tension, Removes nervous system

3. Tulsi                ////   Cures sore throat, Cures fever and asthma

4. Neem               ////       Cures skin diseases, Cures diabetics

5. Aloevera      ////             Heals burns, Relieves constipation

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if two masses 5.2kg and 4.8kg are attached to ends of inextensible string passed over a friction less pulley then acceleration of system

Answers

Answer:

If two masses 5.2 kg and 4.8 kg are attached to the ends of inextensible strings passed over a frictionless pulley then the acceleration of system is 0.4 ms-2.

Explanation:

Based on your observations, what can you say about your prediction in Parts A and B above concerning the potential and kinetic energy?

Answers

Answer:

Explanation:

My perdiction was correct. I predicted in Part A that the Kinetic Energy would increase. In Part B I predicted that the potential energy would decrease due to the kinetic energy increasing.

When converted to a household measurement, 9 kilograms is approximately equal to a

Answers

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

HELP PLEASE
What is the correct definition of amplitude?

A. the height of a wave

B. the distance between two crests or troughs

C. the number of complete waves that pass a point in a second

D. the time it takes for one complete wave to pass a given point

Answers

Answer:

correct answer is A) the height of a wave

Explanation:

i just did the test:)

The amplitude is used represent the height of the wave.

What is wave?

A wave is a disturbance in a medium that carries energy without a net movement of particles. In general, waves are classified into two types as Longitudinal and Transverse

Given is the amplitude of a wave.

Amplitude of a wave is equal to measure of the length of crest or trough. Crest and trough are the points that represents the maximum and minimum displacement of the wave with respect to the reference axis. The crest and the trough points are both at a equal straight line distance from the reference axis. This distance is also called height of the wave. The amplitude is the distance between the centerline and the Crest or trough. The general equation representing the amplitude of wave is x = A sin (ωt + ϕ) or x = A cos (ωt + ϕ) is the formula.

Therefore, the amplitude represents the height of the wave.

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The function of which system is to transport food, oxygen and enzymes, etc. to all cells and to remove carbon dioxide and wastes from cells?

Answers

Answer:

the cardiovascular system

A car with a mass of 1500 kg is pulled by a rope that is horizontal to the ground. The tension in the rope is 2000 N and a friction force of 350 N opposes the car's motion. What is the magnitude of the car's acceleration?

Answers

Answer:

Explanation:

Assuming the ground is level as well.

F = ma

a = F/m

a = (2000 - 350) / 1500

a = 1.1 m/s²

The acceleration of the car is 1.1 m/s².

To calculate the magnitude of the acceleration of the car, we use the formula below.

F-F' = ma................ Equation 1

Where:

F = Tension in the ropeF' = Friction forcem = mass of the cara = acceleration of the car

Make a the subject of the equation

a = (F-F')/m................. Equation 2

From the equation,

Given:

F = 2000 NF' = 350 Nm = 1500 kg

Substitute these values into equation 2

a = (2000-350)/1500a = 1650/1500a = 1.1 m/s²

Hence, the acceleration of the car is 1.1 m/s².

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