The mass of sodium sulfate [tex](Na_2SO_4)[/tex] formed by the complete reaction of 137.3 grams of sodium hydroxide [tex](NaOH)[/tex] is 486.74 grams.
The balanced chemical equation for the reaction between sodium hydroxide [tex](NaOH)[/tex] and sulfuric acid [tex](H_2SO_4)[/tex] is:
[tex]NaOH[/tex] + [tex](H_2SO_4)[/tex] → [tex]Na_2SO_4[/tex] + [tex]2H_2O[/tex]
From the balanced equation, we can see that 1 mole of [tex]NaOH[/tex] reacts with 1 mole of [tex](H_2SO_4)[/tex] to produce 1 mole of [tex]Na_2SO_4[/tex] and 2 moles of water [tex](H_2O).[/tex]
The molar mass of [tex]NaOH[/tex] is 40.00 g/mol, which means that 137.3 grams of [tex]NaOH[/tex] is equal to 137.3 g / 40.00 g/mol = 3.4325 moles of [tex]NaOH[/tex].
Since 1 mole of [tex]NaOH[/tex] reacts with 1 mole of [tex](H_2SO_4)[/tex] to produce 1 mole of [tex](Na_2SO_4)[/tex] , we can say that 3.4325 moles of [tex]NaOH[/tex] will react with 3.4325 moles of [tex]H_2SO_4[/tex] to produce 3.4325 moles of [tex]Na_2SO_4[/tex].
The molar mass of [tex](Na_2SO_4)[/tex] is 142.04 g/mol, which means that 1 mole of [tex](Na_2SO_4)[/tex] has a mass of 142.04 g.
Therefore, 3.4325 moles of [tex](Na_2SO_4)[/tex] has a mass of 3.4325 moles x 142.04 g/mol = 486.74 grams.
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A 192 gram piece of copper was heated to 100.°C in a boiling water bath, then it was dropped into a beaker containing 850. mL of water at 4.00°C. What is the final temperature of the copper and water after they come to thermal equilibrium?
Note: The specific heat of copper is 0.385 J/g °C.
Do not round your answer in the middle of the problem. Round at the very end.
Round your answer to the correct number of sig figs. Your units should be degrees Celsius.
The final temperature of the copper and water after they come to thermal equilibrium is 109.8°C.
What is temperature?Temperature is a measure of the amount of thermal energy present in a substance or object. It is measured in degrees on a scale such as Fahrenheit, Celsius, or Kelvin. Temperature is important in determining the physical and chemical properties of a substance, such as its melting point, boiling point, and specific gravity. Temperature also affects the rate of a chemical reaction and the speed of diffusion.
The change in temperature of the copper can be calculated using the equation
ΔT = (Q/mc), where Q is the heat transferred, m is the mass of the copper, and c is the specific heat of copper.
Q = mcΔT = (192 g)(0.385 J/g °C)(100°C) = 74080 J
The heat transferred from the copper must equal the heat transferred to the water. Therefore,
(74080 J) = (0.85 L)(4.184 J/g°C)(ΔT)
ΔT = (74080 J)/[(0.85 L)(4.184 J/g°C)] = 109.8°C
The final temperature of the copper and water after they come to thermal equilibrium is 109.8°C.
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NaOH is the limiting reactant, producing
2.0 mol Na3PO4. What mass of
Na3PO4 forms during the reaction?
Na3PO4: 164 g/mol
[?] g Na3PO4
Report your answer to two significant figures.
g Na PO
4
Enter
The mass of Na₃PO₄ formed during the reaction is 328 g.
The balanced chemical equation for the reaction is:
[tex]3NaOH + Na_3PO_4 - > 3Na_2PO_4 + H_2O[/tex]
From the equation, we can see that 3 moles of NaOH produce 1 mole of Na₃PO₄.
Given that 2.0 moles of Na₃PO₄ is produced, we can set up a proportion to find the amount of NaOH required:
3 mol NaOH / 1 mol Na₃PO₄ = x mol NaOH / 2.0 mol Na3PO4
Solving for x, we get:
x = (3 mol NaOH / 1 mol Na₃PO₄) × (2.0 mol Na₃PO₄ / 1) = 6.0 mol NaOH
So, 6.0 moles of NaOH are required to produce 2.0 moles of Na₃PO₄.
To find the mass of Na₃PO₄ produced, we can use its molar mass:
mass = moles × molar mass = 2.0 mol × 164 g/mol = 328 g
Therefore, the mass of Na₃PO₄ formed during the reaction is 328 g.
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If the average speed of an oxygen molecule is 4.37 ✕ 104 cm/s at 25°C, what is the average speed of a CO2 molecule at the same temperature?
The average speed of a gas molecule is proportional to the square root of its temperature and inversely proportional to the square root of its molar mass. Therefore, we can use the following equation to find the average speed of a CO2 molecule at the same temperature:
v2/v1 = sqrt(M1/M2)
where v1 and v2 are the average speeds of the oxygen and CO2 molecules, respectively, M1 and M2 are the molar masses of oxygen and CO2, respectively.
The molar mass of oxygen (O2) is 32 g/mol, and the molar mass of CO2 is 44 g/mol.
We are given that the average speed of an oxygen molecule is 4.37 × 10^4 cm/s at 25°C. We can convert the temperature to Kelvin by adding 273.15 to get:
T = 25°C + 273.15 = 298.15 K
Now we can solve for v2:
v2 = v1 * sqrt(M1/M2)
v2 = 4.37 × 10^4 cm/s * sqrt(32 g/mol / 44 g/mol)
v2 = 3.67 × 10^4 cm/s
Therefore, the average speed of a CO2 molecule at the same temperature is 3.67 × 10^4 cm/s.
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5. The head of matches contains an oxidizing agent such as potassium chlorate, KCIO3, together with tetraphosphorus trisulfide, P4S3.
glass, and binder. When struck either by an obect or on the side of a box of matches, the phosphorus sulfide compound is easily
ignited, causing the potassium chlorate to decompose into potassium chloride and oxygen. The oxygen in turn causes the
phosphorus sulfide to burn more vigorously.
Determine the oxidation number of chlorine in potassium chlorate.
The oxidation number of the unknown chlorine in the compound is + 5
What is oxidation number?The oxidation number of an element in a compound is determined by a set of rules based on its position in the periodic table, as well as the charges of other atoms in the compound
We know that the oxidation number of the chlorine which we want to obtain would be designated as x and the total of the oxidation numbers of the elements in the compound is zero.
Thus we have that;
1 + x + 3(-2) = 0
1 + x - 6 = 0
-5 + x = 0
x = 5
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A platinum ring is composed of 2.35×1023 atoms. Calculate the mass of the ring in grams.
The mass of the platinum ring is 76.0 grams.
To calculate the mass of the platinum ringWe need to know the molar mass of platinum and the number of platinum atoms in the ring.
The molar mass of platinum (Pt) is 195.08 g/mol.
The number of platinum atoms in the ring is 2.35×10^23.
Now we can use the following formula to calculate the mass of the ring:
mass = (number of atoms) x (atomic mass) / Avogadro's number
where Avogadro's number is 6.022 x 10^23 mol^-1.
Substituting the values:
mass = (2.35×10^23 atoms) x (195.08 g/mol) / (6.022 x 10^23 mol^-1)
mass = 76.0 g
Therefore, the mass of the platinum ring is 76.0 grams.
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A flexible container at an initial volume of 5.12 L
contains 8.51 mol
of gas. More gas is then added to the container until it reaches a final volume of 13.3 L.
Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Step-by-step Explanation:
8.51 moles is to 5.12 L as 'x' moles is to (13.3-5.12) L
8.51 moles / 5.12 L = x / ( 13.3-5.12)
x = 13.6 moles
If you mix 30 mL of cold water with 70 mL of hot water in a calorimeter, then calculate that the cold water gained 142 J of heat and the hot water lost 181 J of heat, and the temperature change of the cold water (and calorimeter) was an increase in 1.93°C, then what is the heat capacity of the calorimeter in J/°C (only enter the number, not units, and assume that no heat was lost to the environment around the calorimeter, assume the density of water to be 1.00g/mL and specific heat capacity of water to be 4.184 J/g-°C)?
First, we need to calculate the heat gained by the cold water and the heat lost by the hot water:
Qcold = mcΔT = (30 g)(4.184 J/g-°C)(1.93°C) = 242.06 J
Qhot = mcΔT = (70 g)(4.184 J/g-°C)(-1.93°C) = -546.53 J
Since energy is conserved, we can assume that the heat gained by the cold water and calorimeter is equal to the heat lost by the hot water:
Qcold + Qcalorimeter = Qhot
Qcalorimeter = Qhot - Qcold
Qcalorimeter = -546.53 J - 242.06 J = -788.59 J
Therefore, the heat capacity of the calorimeter can be calculated as:
Ccalorimeter = Qcalorimeter / ΔT
Ccalorimeter = (-788.59 J) / (1.93°C)
Ccalorimeter ≈ -408.4 J/°C
Note that the negative sign indicates that the calorimeter loses heat when the system gains heat, which is expected since the calorimeter is absorbing some of the heat from the hot water.
The Environmental Protection Agency was assigned which task? A. setting standards and governing the cleanliness of water used by Americans B. setting standards and governing the highways and interstates in the United States C. setting standards and governing the use of national parks and monuments in the United States. D. setting standards and governing the civil and commercial air transportation throughout America
Answer:
A. setting standards and governing the cleanliness of water used by Americans
Explanation:
The responsibilities of the Environmental Protection Agency (EPA) is to make sure that:
People in America should have clean air, water, and good quality soil so that land is fertile.Using Scientific information to come up with efforts on a national level and reduce risks to the environment.A fair and effective administration of federal laws centered around the protection of human health and our environment.What mass (grams) of oxygen will be released when 268.9 grams of Potassium Chlorate is thermally decomposed?
KClO3 --> KCl + O2
The centripetal acceleration experienced by the object can be calculated using the formula a = v^2/r, where v is the speed of the object and r is the radius of the circle. Substituting the given values, we get:
a = (50 cm/s)^2 / (250 cm)
a = 10 cm/s^2
Therefore, the centripetal acceleration experienced by the object is 10 cm/s^2.
To calculate the centripetal acceleration experienced by the object, you can use the formula:
Centripetal acceleration (a_c) = (velocity^2) / radius
Here, the velocity (v) is 50 cm/s and the radius (r) is 250 cm. Plugging in these values, we get:
a_c = (50^2) / 250 = 2500 / 250 = 10 cm/s²
So, the centripetal acceleration experienced by the object is 10 cm/s².
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What is the S-P difference (sec)?
What is the amplitude (mm)?
What isthe distance (km)?
What is the magnitude (M)?
The S-P difference (sec) is the time gap between the arrival of the S-wave and the arrival of the P-wave at a seismic station. The S-P discrepancy is depicted in the figure as 20 seconds.
The amplitude (mm) of a seismic wave is the largest displacement from its resting point. The amplitude of the waves is not depicted in the image and cannot be calculated based on the information provided.
Distance (km): Using the S-P time difference and the known velocity of seismic waves, the distance from the seismic station to the earthquake epicenter may be determined. Seismic wave velocity is determined by the type of wave and the features of the Earth's interior. The velocity of P-waves in the Earth's crust, for example, is around 6 km/s. We may compute the distance to the epicenter using this value and the S-P difference of 20 seconds as follows:
Distance = Speed x Time = 6 km/h x 20 seconds = 120 kilometres
As a result, the distance between the seismic station and the earthquake epicenter is about 120 km.
The magnitude of an earthquake (M) is a measurement of the energy generated by the earthquake based on the amplitude of the seismic waves and the distance to the epicenter. Magnitude is commonly measured on a logarithmic scale, with each whole number reflecting a factor of ten increase in energy release.
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Both chairs are the same size and have the same number of molecules. The diagram above shows the chairs before they touch.
How does the temperature of the bottom chair compare with the temperature of the top chair before the chairs touch? What will happen after the chairs have been touching for a while?
Before the chairs touch, the temperature of the bottom chair is lower than the temperature of the top chair, this is because the molecules in the bottom chair are in contact with a cooler surface.
After the chairs have been touching for a while, the heat will begin to transfer from the top chair to the bottom chair through a process called conduction. This will continue until the temperature of the two chairs equalizes, at which point there will be no more net heat transfer between them.
The final temperature of both chairs will be somewhere between the initial temperatures of the two chairs, and will depend on factors such as the thermal conductivity of the material, the size of the chairs, and the duration of the contact.
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2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)
If 538 mol
of octane combusts, what volume of carbon dioxide is produced at 31.0 ∘C
and 0.995 atm?
The volume of the carbon dioxide is produced at the 31.0 °C and the 0.995 atm is 119,786 L.
The number of moles of octane = 538 mol
The moles of carbon dioxide = 4888 mol
The temperature of the gas = 31.0 °C
The pressure of the gas = 0.995 atm
The volume of the gas = ?
The ideal gas equation is :
P V = n R T
Where,
The p is the pressure = 0.995 atm
The V is the volume = ?
The n is moles of gas = 4888 mol
The R is gas constant = 0.823 atm L / mol K
The T is temperature = 31 + 273 = 304 K
V = n R T / P
V = ( 4888 mol × 0.0823 × 304 ) / 0.995
V = 119,786 L
The volume is 119,786 L.
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Can someone help me ?
The problem requires the calculation of the volume of carbon dioxide produced at STP when 587 mol of octane combusts; ,therefore, the volume of CO₂ produced at 36.0 °C and 0.995 atm is approximately 124,700 L.
The ideal gas law is given by:
PV = nRT
P is the pressure in atm, V is the volume in L, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in K.
587 mol octane × (16 mol CO₂/2 mol octane) = 4696 mol CO2
Next, one can use the ideal gas law to calculate the volume of CO₂ produced at 36.0 °C and 0.995 atm. Then one needs to convert the temperature to kelvin by adding 273.15:
T = 36.0 °C + 273.15 = 309.15 K
Substituting the values into the ideal gas law:
PV = nRT
V = nRT/P
V = (4696 mol)(0.0821 L·atm/mol·K)(309.15 K)/(0.995 atm)
V ≈ 124,700 L
Therefore, the volume of CO2 produced at 36.0 °C and 0.995 atm is approximately 124,700 L.
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PLEASE HELP!!
351.6g of Chromium-63 is allowed to decay for 128.8 years, how much Chromium-63
is left? (The half life of 63 Cr is 32.2 days.) Please, enter your answer as a one decimal
place number with no units.
A crucial trace mineral is chromium. Trivalent chromium, which is safe for people, and hexavalent chromium, which is toxic, are the two types.
Thus, Foods and dietary supplements both contain trivalent chromium. It might assist maintain normal blood sugar levels by enhancing the body's utilization of mineral.
Chromium is used by people to treat deficiencies. Additionally, it is used to treat bipolar disorder, diabetes, high cholesterol, and a variety of other conditions, but the majority of these uses are not well-supported by science.
Chromium by mouth doesn't help control blood sugar levels in people with prediabetes. Schizophrenia. Taking chromium by mouth doesn't affect weight or mental health in people with schizophrenia.
Thus, A crucial trace mineral is chromium. Trivalent chromium, which is safe for people, and hexavalent chromium, which is toxic, are the two types.
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Will we ever send humans to another planet? Most believe that if we were to travel to another planet, Mars would be the best option. Which of these would be a potential problem associated with travel to another planet?
Question 1 options:
we already know everything about Mars
no astronauts would ever volunteer for this mission
Mars has such a high gravity that it would crush humans and our spacecraft
the extended time for humans to be in space
A potential problem associated with travel to another planet is : the extended time for humans to be in space.
What is the potential problem associated with travel to another planet?It is highly likely that humans will travel to another planet, and Mars is currently considered the most viable option for human exploration. However, there are many potential problems associated with this endeavor, and one of the major issues is the extended time that humans would need to spend in space.
Traveling to Mars would take several months, and once there, astronauts would need to spend significant amount of time on planet before returning to Earth. This means that they would be exposed to high levels of radiation and would need to find ways to survive in harsh and unforgiving environment.
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What is the difference between collecting and analysing data
Answer:
Data collection is the act of obtaining information from diverse sources, and data analytics is the process of processing that information to derive practical insights.
Explanation:
Help!!!!!!!!!!!!!!!!!!!!!!!
All of the equation-related claims are not entirely true. The appropriate chemical formula should be:
Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH
Because the total mass of the reactants and products are equal, as well as the number of each type of atom in each of the reactants and products, mass is conserved in this balanced equation. Depending on the stoichiometric coefficients in the balanced equation, there may or may not be an equal amount of molecules in the reactants and products.
Iron(III) hydroxide (Fe(OH)3) and ammonium chloride (NH4Cl) are the products of the chemical reaction between iron(III) chloride (FeCl3) and ammonium hydroxide (NH4OH).
The coefficients (the numbers in front of the chemical formulae) must be changed to make sure that the number of each type of atom is the same on both sides of the equation in order to ensure that the equation is balanced. The coefficients in this instance are:
Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH
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Strychnine, a deadly poison, has a molecular mass of 334 g/mol and a percentage composition of 75.45% carbon, 6.59% hydrogen, 8.38% nitrogen, and the balance oxygen. What is the molecular formula of strychnine?
The molecular formula of the strychnine, given that it is composed of 75.45% carbon, 6.59% hydrogen, 8.38% nitrogen, and the balance oxygen is C₂₁H₂₂N₂O₂
How do i determine the molecular formula?First, we shall obtain the empirical formula of compound. Details below:
Carbon (C) = 75.45%Hydrogen (H) = 6.59%Nitrogen (N) = 8.38%Oxygen (O) = 100 - (75.45 + 6.59 + 8.38) = 9.58%Empirical formula =?Divide by their molar mass
C = 75.45 / 12 = 6.2875
H = 6.59 / 1 = 6.59
N = 8.38 / 14 = 0.5986
O = 9.58 / 16 = 0.59875
Divide by the smallest
C = 6.2875 / 0.5986 = 10.5
H = 6.59 / 0.5986 = 11
N = 0.5986 / 0.5986 = 1
O = 0.59875 / 0.5986 = 1
Multiply through by 2 to express in whole number
C = 10.5 × 2 = 21
H = 11 × 2 = 22
N = 1 × 2 = 2
O = 1 × 2 = 2
Thus, we can conclude that the empirical formula is C₂₁H₂₂N₂O₂
Now, we shall determine the molecular formula of strychnine. Details below
Empirical formula = C₂₁H₂₂N₂O₂Molar mass of compound = 334 g/molMolecular formula =?Molecular formula = empirical × n = mass number
[C₂₁H₂₂N₂O₂]n = 140.22
[(12×21) + (1×22) + (14×2) + (16×2)]n = 334
334n = 334
Divide both sides by 334
n = 334 / 334
n = 1
Molecular formula = [C₂₁H₂₂N₂O₂]n
Molecular formula = [C₂₁H₂₂N₂O₂]1
Molecular formula = C₂₁H₂₂N₂O₂
Thus, we can conclude that the molecular formula of strychnine is C₂₁H₂₂N₂O₂
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A 50.0-g sample of water at 25.0°C is mixed with 29.0 g of water at 65.0°C. The final temperature of the water is ________°C.
Answer:
39.7
Explanation:
Therefore, the final temperature of the water is 39.7°C.
A sample of air occupies 0.75 L at standard conditions. What is the pressure in atm if the volume is 100.0 mL at 25oC?
P1 = 760 mmHg P2 = ?
V1 = 0.750 L V2 = 100.0 mL
T1 = 273 K T2 = 25oC
According to the ideal gas law, a gas's pressure is inversely related to its volume and directly proportionate to its temperature. So, if a gas sample's volume is reduced, the gas sample's pressure must also increase.
As a result, in order to determine the pressure of the gas sample under the specified circumstances, we must first determine the ratio of the two volumes before multiplying the starting pressure of the sample by that ratio.
We may get the ratio of the two volumes using the ideal gas law as follows: V2/V1 = (100.0 mL/0.75 L) x (273 K/25oC) = 8.02 As a result, the gas sample's pressure at 25 oC with a volume of 100.0 mL is 8.02 times higher than the sample's original pressure.
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Acetic acid has a molar mass of 60.05 g/mol. If 16.84 grams of acetic acid are present, how many moles of acetic acid does that correspond to?
Answer:
3.566 mol
Explanation:
Since 60.05 is grams divided by mol to cancel out the grams to get only mols it must be divided by 16.84 g
[tex]\frac{60.05 g}{mol} *\frac{1 }{16.84g} =3.566[/tex] mols acetic acid
How many hydrogen molecules (h2) are needed to convert the triacylglycerol shown to saturated fat
The triacylglycerol depicted may be converted to a saturated fat by adding two hydrogen atoms (H2) to each carbon-carbon double bond. Six hydrogen atoms (H2) are required to convert the three carbon-carbon double bonds in triacylglycerol into saturated fat.
This is so that the triacylglycerol may be converted to a saturated fat by using hydrogen molecules (H2) to saturate the double bonds.
Triacylglycerol's physical characteristics, such as its melting point, will similarly be altered by the addition of hydrogen molecules (H2), making it more solid at normal temperature.
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3. Litharge, Pb0, is an ore that can be roasted (heated) in the presence of carbon monoxide, CO, to produce elemental lead. The
reaction that takes place during this roasting process is represented by the balanced equation below.
PbO(s) + CO(g) → Pb(s) + CO₂(g)
In which compound does carbon have the greater oxidation number
Answer:
Explanation:
In the given reaction, carbon has a greater oxidation number in carbon dioxide (CO₂) than in carbon monoxide (CO). In CO₂, the oxidation number of carbon is +4, while in CO it is +2.
Chemistry..... Reaction Rate
W → U + S Chemistry Reaction Rate use the table to find reaction rate
See reaction Rate Table Picture
The reaction rates for trial 1 is 8.22 x 10⁻² M⁻² s⁻¹ and 1.10 M⁻² s⁻¹ for trail 2 and 3
How to find reaction rate?Keep the concentration of W constant while varying the concentrations of U and S while measuring the reaction rate in order to determine the reaction rate with regard to U and S.
Select trial 1 as the reference trial and calculate the reaction's rate constant (k) with respect to U and S, assuming that the concentration of W is constant throughout all three trials.
For trial 1:
[W] = 0.13 M
Rate = 4.72 x 10⁻⁴ M/s
For trial 2:
[W] = 0.13 M
Rate = 1.18 x 10⁻² M/s
From the equation rate = k[U][S], set up the following ratio of rates:
Rate2/Rate1 = (k[U]2[S]2)/(k[U]1[S]1)
Simplifying:
k = (Rate2/Rate1) x (1/[U]2) x (1/[S]2) x ([U]1) x ([S]1)
Substituting the values from trials 1 and 2:
k = (1.18 x 10⁻² M/s) / (4.72 x 10⁻⁴ M/s) x (1/0.65 M) x (1/1 M) x (0.13 M) x (1 M)
k = 8.22 x 10⁻²M⁻² s⁻¹
Similarly, for trial 3:
[W] = 0.13 M
Rate = 2.95 x 10⁻¹ M/s
Again, using trial 1 as the reference trial, figure out the reaction's rate constant (k) in relation to U and S:
k = (Rate3/Rate1) x (1/[U]3) x (1/[S]3) x ([U]1) x ([S]1)
k = (2.95 x 10⁻¹ M/s) / (4.72 x 10⁻⁴ M/s) x (1/3.25 M) x (1/1 M) x (0.13 M) x (1 M)
k = 1.10 M⁻² s⁻¹
Therefore, the equation states the reaction rate in relation to U and S is k = 8.22 x 10⁻² M⁻² s⁻¹ and 1.10 M⁻² s⁻¹ for trials 2 and 3, respectively.
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At some constant temperature, the equilibrium constant for the reaction below is Kc = .76. An empty 1.00L flask is charged with 2.00 mol carbon tetrachloride and then allowed to reach equilibrium.
CCl4(g) ⇌ C (s) + 2 Cl2(g)
a. What fraction of the reactant remains at equilibrium?
b. What is the molarity of chlorine gas at equilibrium?
At some constant temperature, the equilibrium constant for the reaction below is Kc = .76. An empty 1.00L flask is charged with 2.00 mol carbon tetrachloride and then allowed to reach equilibrium. CCl4(g) ⇌ C (s) + 2 Cl2(g)
a. To find the fraction of the reactant (CCl4) remaining at equilibrium, we can start by determining the initial concentration of CCl4:
Initial concentration of CCl4 = moles/volume = 2.00 mol / 1.00 L = 2.00 M
Let x be the change in concentration of CCl4 at equilibrium. Then, the equilibrium concentrations are:
[CCl4] = 2.00 - x
[Cl2] = 2x
The equilibrium constant expression is given by:
Kc = [Cl2]^2 / [CCl4]
Plugging in the given Kc value (0.76) and the equilibrium concentrations:
0.76 = (2x)^2 / (2.00 - x)
Now, you can solve for x. The fraction of the reactant remaining at equilibrium is (2.00 - x) / 2.00.
b. To find the molarity of chlorine gas (Cl2) at equilibrium, you can use the value of x obtained in part (a). The molarity of Cl2 is equal to 2x.
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add a given instant what is the rate of appearance at this time
The rate of appearance of NOBr at the given time is 9.80 × [tex]10^-^4[/tex] M/s which is the second option as the question asks to determine the rate of appearance of NOBr, which is a product of the given chemical reaction, at the given time when the rate of disappearance of Br₂ is known.
For every 1 mole of Br₂ that disappears, 2 moles of NOBr appear. Thus, we can set up a proportion:
(2 mol NOBr / 1 mol Br₂) = (rate of appearance of NOBr / rate of disappearance of Br₂)
Substituting the given values,
(2 mol NOBr / 1 mol Br₂) = (rate of appearance of NOBr / 4.90 x [tex]10^-^4[/tex] M/s)
Solving for the rate of appearance of NOBr,
rate of appearance of NOBr = (2 mol NOBr / 1 mol Br₂) x (4.90 x [tex]10^-^4[/tex] M/s) = 9.80 × [tex]10^-^4[/tex]M/s
The rate of appearance of NOBr at the given time is 9.80 × [tex]10^-^4[/tex] M/s.
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Balance:
2. K₂O + H₂O → KOH
3.F₂ +NaBr-NaF + Br₂
4.Ba(CIO3) → BaCl2 + O2
*
5.SrBr₂ + (NH4)2CO3 → SrCO3 + NH4Br
6. C8H18 + O₂ → CO₂ + H₂O
What is the reactions to these?
the balanced equation and there reactions are as follow:
K₂O + H₂O → 2KOH
The reaction between potassium oxide and water produces potassium hydroxide (KOH).
F₂ + 2NaBr → 2NaF + Br₂
The reaction between fluorine gas and sodium bromide produces sodium fluoride and bromine.
2Ba(CIO3)₂ → 2BaCl₂ + 3O₂
The decomposition of barium chlorate produces barium chloride and oxygen gas.
SrBr₂ + (NH₄)₂CO₃ → SrCO₃ + 2NH₄Br
The reaction between strontium bromide and ammonium carbonate produces strontium carbonate and ammonium bromide.
C₈H₁₈ + 12O₂ → 8CO₂ + 9H₂O
The combustion of octane with oxygen produces carbon dioxide and water.
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What is the net ionic charge of an oxygen ion ?
( + 0₂ (0₂ 1 Is the molecular mas of carbon is 12 and that of oxygen is 32, Calculate the mass of carbon dioxide formed when 24kg of carbon is burnt completely in oxygen and determine the heat thereby released in MJ if the complete combustion of 1kg of carbon releases 33.8MJ of heat
The mass of carbon dioxide formed when 24 kg of carbon is burnt completely in oxygen is 88 kg, and the heat released is 811.2 MJ.
What is Molar Mass?
Molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol). It is calculated by adding up the atomic masses of all the atoms in a molecule or formula unit of a compound. The molar mass is used in stoichiometry calculations to convert between mass and moles of a substance.
The balanced equation for the combustion of carbon is:
C + O₂ → CO₂
From the equation, we can see that one mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide. The molar mass of carbon dioxide is 12 + (2 × 16) = 44 g/mol.
First, let's find the number of moles of carbon in 24 kg:
n(C) = m/M = 24000 g / 12 g/mol = 2000 mol
Therefore, 2000 mol of CO₂ will be produced.
The mass of CO₂ produced can be calculated as:
m(CO₂) = n(CO₂) × M(CO₂) = 2000 mol × 44 g/mol = 88,000 g = 88 kg
Now, let's calculate the heat released during combustion:
Heat released = 33.8 MJ/kg × 24 kg = 811.2 MJ
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What concentration results from the dilution of 500.0 mL of 4.267 M to a volume of 1.85 L?
To calculate the concentration resulting from the dilution of 500.0 mL of 4.267 M to a volume of 1.85 L, we can use the equation:
M1V1 = M2V2
where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.
Plugging in the given values, we get:
4.267 M)(500.0 mL) = M2(1.85 L)
Simplifying this equation, we get:
M2 = (4.267 M)(500.0 mL) / (1.85 L)
M2 = 1.153 M
Therefore, the concentration resulting from the dilution is 1.153 M.
To calculate the concentration after dilution, you can use the dilution formula: C1V1 = C2V2, where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume.
Given:
C1 = 4.267 M
V1 = 500.0 mL = 0.5 L (converted to liters)
V2 = 1.85 L
Now, find C2:
C2 = (C1 * V1) / V2
C2 = (4.267 M * 0.5 L) / 1.85 L
C2 ≈ 1.153 M
The concentration after dilution is approximately 1.153 M.
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To find the concentration resulting from the dilution, we can use the equation:
M1V1 = M2V2
where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.
Plugging in the given values, we get:
(4.267 M)(500.0 mL) = M2(1.85 L)
Simplifying and converting units, we get:
M2 = (4.267 M)(500.0 mL) / (1.85 L)
M2 = 1.16 M
Therefore, the concentration resulting from the dilution is 1.16 M.
To find the concentration after dilution, you can use the dilution formula:
C1V1 = C2V2
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Given:
C1 = 4.267 M
V1 = 500.0 mL (0.5 L)
V2 = 1.85 L
Rearrange the formula to solve for C2:
C2 = (C1V1) / V2
Now, plug in the given values:
C2 = (4.267 M * 0.5 L) / 1.85 L
C2 ≈ 1.154 M
So, the resulting concentration after dilution is approximately 1.154 M.
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