when 23ml of 0.100 m agno3 is combined with 27ml ml of 0.1000 m hcl in a coffe-cup calorimeter the temperature changes from 23.81 to 24.62 celcius calculate change in enthalkpy

Answers

Answer 1

The change in enthalpy for the reaction is -7.57 × 10^4 J/mol. This negative value indicates that the reaction is exothermic, meaning it releases heat to the surroundings.

To calculate the change in enthalpy, we need to use the equation:

ΔH = -q / n

where ΔH is the change in enthalpy, q is the heat absorbed or released by the reaction, and n is the number of moles of limiting reactant.

First, we need to determine the limiting reactant. This can be done by comparing the number of moles of each reactant:

moles of AgNO3 = (23 mL) x (0.100 mol/L) = 0.0023 mol

moles of HCl = (27 mL) x (0.1000 mol/L) = 0.0027 mol

Since AgNO3 has a smaller number of moles, it is the limiting reactant.

Next, we need to calculate the heat absorbed or released by the reaction. We can do this using the equation:

q = m × c × ΔT

where q is the heat absorbed or released, m is the mass of the solution, c is the specific heat capacity of the solution, and ΔT is the temperature change.

Assuming the specific heat capacity of the solution is 4.18 J/(g·K) and the density of the solution is 1.00 g/mL, we can calculate the mass of the solution:

mass of solution = (23 mL + 27 mL) × (1.00 g/mL) = 50 g

Substituting the values, we get:

q = (50 g) × (4.18 J/(g·K)) × (24.62°C - 23.81°C) = 174.5 J

Finally, we can calculate the change in enthalpy using the equation:

ΔH = -q / n

ΔH = -(174.5 J) / (0.0023 mol) = -7.57 × 10^4 J/mol

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Related Questions

How many moles of nickel (Ni) is 3.88 x 1023 atoms of nickel?

O.679 moles Ni
O .644 moles Ni
O.638 moles Ni
O.762 moles Ni

Answers

Answer:

Explanation:

We can use to convert the given number of atoms of nickel to moles.

1 mole of any element contains 6.022 x 10^23 atoms of the element

So, the number of moles of nickel can be calculated as:

moles of Ni = (number of atoms

moles of Ni = 3.88 x 10^23 / 6.022 x 10^23

moles of Ni = 0.644

Therefore, the answer is option B: 0.644 moles Ni.

What is the Molarity of a 0.5 Liter solution that contains 3.84 moles of NaCI?


SHOW WORK PLEASE​

Answers

The molarity of a 0.5 liter solution that contains 3.84 moles of NaCl would be 7.68 M.

What is molarity?

Molarity is simply the ratio of the number of moles of solutes per liter volume of a solution.

In other words, molarity is a measure of the concentration of a solute in a solution. It is commonly denoted by the symbol "M" and expressed in units of mol/L.

Molarity = mole/volume

Where the volume is in liters.

In this case:

Number of moles = 3.84 molesVolume = 0.5 liter

Molarity of the NaCl solution = 3.84/0.5

                                                = 7.68 M

Thus, the molarity of a 0.5 Liter solution that contains 3.84 moles of NaCI is 7.68 M.

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Below is the titration curve of a 50.0 mL of 0.1 M triprotic acid H3A with 0.1 M NaOH(aq). The initial pH and the equivalence points are indicated in the curve.
Calculate pKa1, pKa2, and pKa3 for the triprotic acid H3A.

Answers

In the titration curve, the initial pH of the triprotic acid H3A is given as approximately 1.8. This corresponds to the pH at which only H3A is present in solution.

The first equivalence point, where half of the H3A has been neutralized, occurs at approximately pH 4.3. This corresponds to the point where H2A^- is formed; therefore, Ka1 can be calculated as follows:

Ka1 = [H2A^-][H3O^+]/[H3A] = 10^(-pH1)

where pH1 is the pH at the first equivalence point.

Substituting the given values, we get:

Ka1 = [H2A^-][H3O^+]/[H3A] = 10^(-4.3)

At the second equivalence point, where H2A^- has been completely neutralized and HA^2- is formed, the pH is approximately 8.5. Thus, Ka2 can be calculated as follows:

Ka2 = [HA^2-][H3O^+]/[H2A^-] = 10^(-pH2)

where pH2 is the pH at the second equivalence point.

Substituting the given values, we get:

Ka2 = [HA^2-][H3O^+]/[H2A^-] = 10^(-8.5)

Lastly, at the third equivalence point, where HA^2- has been completely neutralized and A^3- is formed, the pH is approximately 12.3. Therefore, Ka3 can be calculated as follows:

Ka3 = [A^3-][H3O^+]/[HA^2-] = 10^(-pH3)

where pH3 is the pH at the third equivalence point.

Substituting the given values, we get:

Ka3 = [A^3-][H3O^+]/[HA^2-] = 10^(-12.3)

Thus, the values of pKa1, pKa2, and pKa3 for the triprotic acid H3A are:

pKa1 = -log(Ka1) = -log(10^(-4.3)) = 4.3
pKa2 = -log(Ka2) = -log(10^(-8.5)) = 8.5
pKa3 = -log(Ka3) = -log(10^(-12.3)) = 12.3


What is the molarity (M) of a bleach solution containing 9.50 grams of bleach (NaOCI) in 2,000 ml of solution?​

Answers

The molarity of the bleach solution is 0.0635 M.

How to calculate the molarity (M) of a solution ?

First we need to know the number of moles of solute (in this case, NaOCI) and the volume of the solution in liters.

First, we need to convert the mass of NaOCI to moles using its molar mass:

molar mass of NaOCI = 23.0 g/mol (for Na) + 16.0 g/mol (for O) + 35.5 g/mol (for Cl) + 1.0 g/mol (for I) = 74.5 g/mol

moles of NaOCI = mass / molar mass = 9.50 g / 74.5 g/mol = 0.127 moles

Next, we need to convert the volume of the solution to liters:

volume = 2,000 ml = 2,000 / 1,000 L = 2.0 L

Now we can calculate the molarity of the solution:

Molarity (M) = moles of solute / volume of solution in liters

M = 0.127 moles / 2.0 L = 0.0635 M

Therefore, the molarity of the bleach solution is 0.0635 M.

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What is the molarity (M) of a solution made by dissolving 75 g of Epsom salt (MgSO,) in 2.3 Liters of solution?

SHOW WORK ​

Answers

The molarity of the Epsom salt solution is 0.271 M.

Steps

To find the molarity (M) of the Epsom salt (MgSO4) solution, we need to first calculate the number of moles of MgSO4 present in the given mass of Epsom salt. We can use the formula:

moles = mass / molar mass

where the molar mass of MgSO4 is 120.37 g/mol.

mass of MgSO4 = 75 g

molar mass of MgSO4 = 120.37 g/mol

moles of MgSO4 = 75 g / 120.37 g/mol = 0.6237 mol

Next, we need to calculate the volume of the solution in liters, since molarity is defined as the number of moles of solute per liter of solution:

volume of solution = 2.3 L

Now we can calculate the molarity of the Epsom salt solution:

Molarity = moles of MgSO4 / volume of solution

= 0.6237 mol / 2.3 L

= 0.271 M

Therefore, the molarity of the Epsom salt solution is 0.271 M.

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Sulfur dioxide gas decomposes into solid sulfur (S8) and oxygen gas. How many grams of solid sulfur would be produced from 25.0g of sulfur dioxide?

Answers

Sulfur dioxide decomposition's balanced chemical equation is 2 SO2(g) 2 S(s) + 3 O2 (g). 200.00 g of solid sulphur would result from 25.0 g of sulphur dioxide.

How much aluminium will react with 25 grammes of oxygen gas?

In order to compute the mass of oxygen that will react or the mass of 02 that will react with aluminium, multiply the molar mass of oxygen molecules, 0.69 mol two, by 32 g per mole. Hence, the answer is that 25 g of aluminium and 22.22 g of cobalt will react.

First, we must determine how many moles of sulphur dioxide are contained in 25.0 g:

Number of moles of SO2 = mass / molar mass

Number of moles of SO2 = 25.0 g / 64.06 g/mol (molar mass of SO2)

Number of moles of SO2 = 0.3904 mol

The number of moles of sulphur produced can then be calculated using the mole ratio between sulphur dioxide and sulphur:

Number of moles of S = 2 x number of moles of SO2

Number of moles of S = 2 x 0.3904 mol

Number of moles of S = 0.7808 mol

Lastly, we may convert the amount of moles to grammes using the molar mass of sulphur:

Mass of S = number of moles x molar mass

Mass of S = 0.7808 mol x 256.53 g/mol (molar mass of S8)

Mass of S = 200.00 g (rounded to two decimal places)

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Ammonium phosphate ((NH4)3PO4) is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid (H3PO4) with ammonia (NH3).
What mass of ammonium phosphate is produced by the reaction of 7.73 g of ammonia?

Answers

Answer:

= 22.51 g of ammonium phosphate

Step-by-step explanation:

The balanced chemical equation for the reaction between phosphoric acid and ammonia to form ammonium phosphate is:

H3PO4 + 3 NH3 → (NH4)3PO4

From the equation, we can see that 3 moles of ammonia react with 1 mole of phosphoric acid to produce 1 mole of ammonium phosphate.

To determine the mass of ammonium phosphate produced from 7.73 g of ammonia, we need to first calculate the number of moles of ammonia, and then use the mole ratio from the balanced equation to find the number of moles of ammonium phosphate. Finally, we can convert the number of moles of ammonium phosphate to its mass using its molar mass.

The molar mass of NH3 is 17.03 g/mol, and the molar mass of (NH4)3PO4 is 149.09 g/mol.

Number of moles of NH3 = mass / molar mass = 7.73 g / 17.03 g/mol = 0.453 mol

From the balanced equation, 3 moles of NH3 react to form 1 mole of (NH4)3PO4.

Number of moles of (NH4)3PO4 = 0.453 mol NH3 / 3 mol NH3/mol (NH4)3PO4 = 0.151 mol (NH4)3PO4

Mass of (NH4)3PO4 = number of moles x molar mass = 0.151 mol x 149.09 g/mol = 22.51 g

Therefore, 7.73 g of ammonia reacts to form 22.51 g of ammonium phosphate.

Determine the magnitude of the partial charges in HBr given that the bond length is 1.41 angstroms
and the dipole moment is 0.82 debye.

Answers

HBr has a dipole moment of 7.95debye and an interatomic spacing of 1.94 x 10-om.

Is HBr's dipole moment D?

HBr (a polar covalent molecule) has a dipole moment () of 0.851D (debye) and a percentage ionic character of 12.6%.

The size of the charge multiplied by the distance between the centres of the positive and negative charges yields a dipole moment. The Greek character " is used to represent it. It is measured in Debye units ('D'). 1 D = 3.33564 10-30 C.m, where C signifies Coulomb and m a metre.

It's 1018 statcoulomb-centimeters. Traditionally, the debye moment was defined as the dipole moment produced by two charges of opposing sign but equal magnitude of 1010 statcoulomb.

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PLEASE HELP AND SHOW YOUR WORK

1) how many grams of cl2 are produced from 45 grams of aucl3?

2) calculate the grams of agcl produced from 4.75 grams alcl3.

3) calculate the mass of naoh needed to produce 25.2 grams of na2so4

4) calculate the mass of co2 produced from 25 grams of o2

Answers

1. 15.78 grams of Cl2 are produced from 45 grams of AuCl3.

2. 15.31 grams of AgCl are produced from 4.75 grams of AlCl3.

3. 3.55 grams of NaOH are needed to produce 25.2 grams of Na2SO4.

4.  34.40 grams of CO2 are produced from 25 grams of O2.

Steps

1. To determine how many grams of Cl2 are produced from 45 grams of AuCl3, we need to use the balanced chemical equation for the reaction:

2 AuCl3 + 3 Cl2 → 2 AuCl5

From this equation, we can see that 3 moles of Cl2 are produced for every 2 moles of AuCl3. To calculate the number of moles of AuCl3 in 45 grams, we divide the mass by the molar mass:

45 g AuCl3 x (1 mol AuCl3 / 303.33 g AuCl3) = 0.1482 mol AuCl3

Using the mole ratio from the balanced chemical equation, we can calculate the number of moles of Cl2 produced:

0.1482 mol AuCl3 x (3 mol Cl2 / 2 mol AuCl3) = 0.2223 mol Cl2

Finally, we can convert the number of moles of Cl2 to grams by multiplying by the molar mass:

0.2223 mol Cl2 x 70.906 g/mol = 15.78 g Cl2

Therefore, 15.78 grams of Cl2 are produced from 45 grams of AuCl3.

2. The balanced chemical equation for the reaction between aluminum chloride (AlCl3) and silver nitrate (AgNO3) is:

3 AgNO3 + AlCl3 → 3 AgCl + Al(NO3)3

From this equation, we can see that 3 moles of AgCl are produced for every 1 mole of AlCl3. To calculate the number of moles of AlCl3 in 4.75 grams, we divide the mass by the molar mass:

4.75 g AlCl3 x (1 mol AlCl3 / 133.34 g AlCl3) = 0.0356 mol AlCl3

Using the mole ratio from the balanced chemical equation, we can calculate the number of moles of AgCl produced:

0.0356 mol AlCl3 x (3 mol AgCl / 1 mol AlCl3) = 0.1068 mol AgCl

Finally, we can convert the number of moles of AgCl to grams by multiplying by the molar mass:

0.1068 mol AgCl x 143.32 g/mol = 15.31 g AgCl

Therefore, 15.31 grams of AgCl are produced from 4.75 grams of AlCl3.

3. The balanced chemical equation for the reaction between NaOH and Na2SO4 is:

2 NaOH + Na2SO4 → 2 Na2SO4 + 2 H2O

From the balanced equation, we see that 2 moles of NaOH react with 1 mole of Na2SO4 to produce 2 moles of Na2SO4 and 2 moles of H2O. To calculate the mass of NaOH needed to produce 25.2 grams of Na2SO4, we need to use the molar mass of Na2SO4:

Molar mass of Na2SO4 = 142.04 g/mol

First, we need to calculate the number of moles of Na2SO4 produced from 25.2 grams:

25.2 g Na2SO4 x (1 mol Na2SO4 / 142.04 g Na2SO4) = 0.1774 mol Na2SO4

Since 2 moles of NaOH react with 1 mole of Na2SO4, we need half that amount, or 0.0887 mol NaOH, to react completely with the given amount of Na2SO4. Finally, we can calculate the mass of NaOH needed using its molar mass:

0.0887 mol NaOH x 40.00 g/mol = 3.55 g NaOH

Therefore, 3.55 grams of NaOH are needed to produce 25.2 grams of Na2SO4.

4. To determine the mass of CO2 produced from 25 grams of O2, we need to use the balanced chemical equation for the combustion of carbon:

C + O2 → CO2

From this equation, we can see that 1 mole of O2 reacts with 1 mole of carbon to produce 1 mole of CO2. To calculate the number of moles of O2 in 25 grams, we divide the mass by the molar mass:

25 g O2 x (1 mol O2 / 32.00 g O2) = 0.78125 mol O2

Since the mole ratio of O2 to CO2 is 1:1, we know that 0.78125 moles of CO2 are produced. Finally, we can convert the number of moles of CO2 to grams by multiplying by the molar mass:

0.78125 mol CO2 x 44.01 g/mol = 34.40 g CO2

Therefore, 34.40 grams of CO2 are produced from 25 grams of O2.

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A sample of 0.49 g of carbon dioxide was obtained by heating 1.22 g of calcium carbonate. What is the percent yield for this reaction

Answers

The percent yield for the reaction of a sample of 0.49 g of carbon dioxide was obtained by heating 1.22 g of calcium carbonate is 92.4%

Given the mass of carbon dioxide ([tex]CO2[/tex]) = 0.49g

The mass of calcium carbonate ([tex]CaCO3[/tex]) = 1.22g

The reaction is as follows:

[tex]CaCO3(s) -- > CaO(s)+CO2(s)[/tex]

As we see 1 mole of CaCO3 is required to produce 1 mole of [tex]CO2[/tex]

The molar mass of calcium carbonate, = 100.09 g/mol.

The molar mass of given carbon dioxide = 44g

mass of [tex]CaCO3[/tex] used = number of moles x molar mass = 1 * 100 = 100g

Mass of [tex]CO2[/tex] produced = 1 * 44 = 44g

Here for 100g of [tex]CaCO3[/tex] 44g of [tex]CO2[/tex] is produced.

Then for 1.22g of [tex]CaCO3[/tex] = 44 * 1.22/100 = 0.53g of [tex]CO2[/tex] is produced.

But the actual yield of carbon dioxide is 0.49 g

The percent yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100.

percent yield = 0.49/0.53 * 100 = 92.4%

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Provide a condensed structure for the following compound.

(I just need help with #6, sorry for the bad picture!)

Answers

The condensed structural formula of the compound is;

(CH3)3CCH2CH(CH2CH3)CH2CH2CH(CH3)(CH2CH3)

The functional groups in norethynodrel are;  ketone, alcohol and alkyne

What is condensed structure of an organic compound?

The condensed structure of an organic compound is a simplified representation of the molecular structure of the compound that uses brackets and symbols to indicate the arrangement of atoms in the molecule.

In a condensed structure, the individual atoms are not explicitly shown, and the bonds between them are indicated by lines.

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PLS CHEM HELP
2 NH3 + 3 CuO g 3 Cu + N2 + 3 H2O

In the above equation how many grams of N2 can be made when 197 grams of CuO are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Hydrogen

1

Nitrogen

14

Copper

63.5

Oxygen

16

Answers

The mass of the nitrogen gas that is found to be produced from the reaction equation is 22.4 g.

What is a balanced reaction?

A balanced chemical equation is a representation of a chemical reaction using the formulas of the reactants and products, and the coefficients that represent the number of each species involved in the reaction.

The correct equation of the reaction is;

2 NH3 + 3 CuO → 3 Cu + N2 + 3 H2O

Number of moles of CuO consumed = 197g/80 g/mol

= 2.4 moles

Given that;

3 moles of CUO is consumed to give 1 moles of N2

2.4 moles of CUO will give 2.4 * 1/3

= 0.8 moles

Mass of N2 = 0.8 * 28 g/mol

= 22.4 g

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Convert 350mi/hr to m/sec

Answers

Answer: To convert 350 miles per hour to meters per second, we need to use the following conversion factors:

1 mile = 1609.344 meters

1 hour = 3600 seconds

Therefore, we can write:

350 miles per hour = 350 miles / 1 hour × 1609.344 meters / 1 mile × 1 hour / 3600 seconds

Simplifying the expression, we get:

350 miles per hour = 155.65104 meters per second (rounded to six decimal places)

Therefore, 350 miles per hour is equivalent to 155.65104 meters per second (approximately).

Explanation:

What is the formula for a compound composed of Cr³+ ions and SO32- ions?

Answers

Answer:

The compound composed of Cr³+ ions and SO32- ions is called chromium(III) sulfite.

The formula for this compound can be determined by balancing the charges of the Cr³+ ion and the SO32- ion so that the overall charge of the compound is neutral.

The charge of the Cr³+ ion is +3, while the charge of the SO32- ion is -2. To balance these charges, we need two SO32- ions for every Cr³+ ion:

Cr³+ + 2 SO32- → Cr2(SO3)3

Therefore, the formula for the compound is Cr2(SO3)3.

(a) A compound X contains carbon, 66.7% and hydrogen 11.1% the rest being oxygen. Determine the empirical formula of X. (b) The vapor density of X is 36; determine the molecular formula of X.

Answers

Answer:

The molecular formula of X = C4 h8 O

The combustion of ethane (C2H6)
produces carbon dioxide and steam.

2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(g)


How many moles of CO2
are produced when 5.10 mol
of ethane is burned in an excess of oxygen?

Answers

Ethane (C2H6) burns to make dioxide and steam: 2C2H6(g) + 7O2(g) (g) Ethane (C2H6) fires to give methane gas and steam: 4CO2(g) + 6H2O + 2C2H6(g) + 7O2(g) (l)

How much CO2 is created if 5.70 mol5 70 molar of ethane burns in an environment with too much oxygen?

We must determine the molecules of CO2 and CO2 that were created. According to the equation above, when 2 molecules of Online C 2 H 6 are exposed to oxygen, 4 moles of Carbon dioxide C O 2 are created.

Ethane does it emit carbon dioxide?

Oxygen gas and ethane (C2H6) react to create both water and carbon dioxide. Find the quantity of carbon dioxide created when the reaction yield is 60% when 5 mol of propane is burnt with 16 molecule of oxygen initially. 2C2H6+7O2→4CO2+6H2O.

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Peroxyacyl nitrates contain two relatively weak bonds that can be broken by low-energy photons. The weakest is the N−O
bond in the nitrate functional group of the molecule with a standard bond-dissociation energy of 201 kJ mol−1
. What is the longest wavelength of a photon, in nanometres, that has enough energy to cause the photodissociation of the weakest bond. Assume all energy of the photon is efficiently used for the photodissociation.

Answers

The longest wavelength of a photon that has enough energy to cause the photodissociation of the weakest bond in a peroxyacyl nitrate molecule is approximately 590 nm.

Given the weakest bond in Peroxyacyl nitrate is N-O bond.

The standard bond-dissociation energy of N-O = 201 kJ mol−1

Let the wavelength = l

We know that E = h c / λ, where E is the energy in joules, h is Planck's constant, c is the speed of light, and λ is the wavelength of photons

[tex]E = (6.626 * 10^{-34}) * (3 * 10^8) / \lambda[/tex]

λ =  [tex](6.626 * 10^{-34}) * (3 * 10^8)/201 kJ mol^{-1}[/tex]

λ = 590nm

In order for photodissociation to occur, the photon must have enough energy to break the N−O bond in the nitrate functional group of the molecule. All of the energy of the photon is efficiently used for the photodissociation.

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structure and function of starch?

Answers

Starch is made up of long chains of sugar molecules that are connected together. Starch's primary role is to help plants store energy. In an animal's diet, starch is a source of sugar. Amylase, an enzyme contained in saliva and the pancreas that breaks down starch for energy, is used by animals to break down starch

ASAPPPP!!!PLEASE!!!!
Explain what you know about the Oxygen atom based on the following element
symbol? (Be sure to include information about protons, neutrons, electrons, mass
number).
17
8
0

Answers

Answer:

H20 oxygen 17 8 0 gyjhf I'd

how does chemical fertilizer decrease the oxygen level in water?​

Answers

Answer: As the fertilizers enter the water systems, they cause an explosion of growth by algae and aquatic plants. When the organisms die they are decomposed by microbes that quickly deplete the oxygen in water, killing animals such as fish and shellfish.

Explanation: Excess fertilizers lead to "eutrophication".

Which of the steps in prokaryotic binary fission is correct?
Question 11 options:

a) All of these choices are correct.
b) The two replicated chromosomes remain attached to the plasma membrane.
c) The cell continues to grow outward symmetrically, separating the two chromosomes.
d) Cell wall material is laid down at the midpoint to separate the two daughter cells.
e) DNA is replicated bidirectionally from a single point on the circular chromosome.

Answers

From a single location on the circular chromosome, DNA is copied in both directions.

The correct option is E.

What is of binary fission?

Binary fission is the process of asexual reproduction in which one organism is divided into two separate ones. An organism's genetic material, or deoxyribonucleic acid (DNA), doubles when it splits into two halves (cytokinesis) through binary fission, with each new species inheriting one copy of the latter.

What cells use binary fission?

Bacterial binary fission is the method by which bacteria split their cells. Find out how binary fission functions, including how to make a new cell wall and a copy of a bacterial chromosome. Mitosis and binary fission, two types of asexual reproduction, both entail the division of a parent cell into two identical daughter cells.

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On a spring morning (20C) you fill your tires to a pressure of 2.25 atmospheres. As you ride along, the tire heats up to 45C from the friction on the road. What is the pressure in your tires now?

Answers

Assuming the volume of the tire remains constant, we can use the ideal gas law to determine the pressure of the tire at the higher temperature:

P1/T1 = P2/T2

where P1 is the initial pressure, T1 is the initial temperature, P2 is the final pressure (what we're trying to find), and T2 is the final temperature.

Converting the temperatures to Kelvin (as the ideal gas law requires temperatures in Kelvin), we have:

P1/T1 = P2/T2

P1 = 2.25 atm

T1 = 20 + 273.15 = 293.15 K

T2 = 45 + 273.15 = 318.15 K

Solving for P2, we get:

P2 = P1(T2/T1)

P2 = 2.25 atm (318.15 K / 293.15 K)

P2 = 2.44 atm (rounded to two significant figures)

Therefore, the pressure in your tires at 45°C would be approximately 2.44 atm.

3. What is the molarity of a solution that contains 0.50 moles of NaOH dissolved in 500 mL solution? ​

Answers

Answer:

1M

Explanation:

To find molarity, we use the formula [tex]\frac{n}{v}[/tex], where n is the moles of solute, and v is the volume in liters.

This formula is fairly straightforward. When we input our values we get a formula of [tex]\frac{0.50 moles}{0.5 liters}[/tex]. Simplifying yields 1M. (Hint: Don't forget that occasionally we do have to convert between units. In this case, the 500mL was converted to liters using the known conversion factor that 1000mL= 1 liter.)

Without checking and reporting their boiling points, rank the boiling points of H2O, MgCl2, HBr, and HF H2S from the lowest to highest based on your knowledge of intermolecular forces, hydrogen bond, and ionic bond. Explain how you make your predictions without checking a reference.

Answers

As HF is hydrogen bonded, it has a highest boiling point of 19 oC or less, when it becomes liquid. The boiling points of the remaining hydrogen halides, which are gaseous, are determined by the van der Waal forces.

H2O or HF, which has the higher boiling point?

Hydrogen fluoride (H 2 F) has a lower boiling point than water (H 2 O) ( ). H2O has a boiling point of 100 °C while only having a boiling point of 5 °C. Despite the fact that water and hydrogen fluoride have stronger hydrogen bonds than each other, water only forms two hydrogen bonds per molecule whereas hydrogen fluoride only forms one.

Which has the highest boiling point between H2O and HCL?

Furthermore, water creates hydrogen bonds between nearby molecules. The extremely electronegative oxygen on the other molecule interacts with hydrogen. This is a strong type of interaction that takes more energy than dipole-dipole interactions. As a result, water boils at a greater temperature than HCL.

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She measured the mass of the metal to be 352.3 grams. Then she dropped the metal into a measuring cup and found that it displaced 18.0 mL of water

Answers

The metal has a density of 19.3g/mL.

A material's density is determined by how much mass there is in a given volume of that material. We must divide the metal's mass by its volume to determine its density. Density of gold is 19.3 g/mL.Since the volume of the metal is equal to the volume of water it displaced, we can calculate the density of the metal by dividing the mass of the metal (352.3 grams) by the volume of water it displaced (18.0 mL).

Density = [tex]\frac{Mass}{Volume}[/tex]

Density = [tex]\frac{352.3 g}{18.0 mL}[/tex]

Density = 19.3 g/mL

Therefore, the density of the metal is 19.3 g/mL.

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complete question:

She measured the mass of the metal to be 352.3 grams. Then she dropped the metal into a measuring cup and found that it displaced 18.0 mL of water

calculate the density  of metal

densities of some common substances for comparison

Density of water = 1.00 g/mL

Density of air = 1.225 g/mL

Density of iron = 7.86 g/mL

Density of aluminum = 2.7 g/mL

Density of gold = 19.3 g/mL

How many moles of sodium hydroxide are needed to completely neutralize 25.0 moles of sulfuric acid?

Answers

Answer:

50.0moles

Explanation:

The balanced equation of the reaction is:

2NaOH + H2SO4____ Na2SO4 +2H2O

2moles of NaOH reacted with 1mole of H2SO4

x moles of NaOH will react with 25moles of H2SO4

2moles______1mole

xmoles______25

x=25×2

x=50moles of NaOH

Calculate the amount of heat needed to melt 148. g of solid ethanol and bring it to a temperature of -26.8C. Be sure your answer has a unit symbol and the correct number of significant digits.

Answers

Explanation:

The amount of heat required to melt a solid substance is given by the formula:

Q = m * ΔHf

where Q is the amount of heat required, m is the mass of the substance, and ΔHf is the heat of fusion of the substance. The heat of fusion of ethanol is 111.3 J/g.

So, for melting 148 g of solid ethanol, the amount of heat required is:

Q1 = 148 g * 111.3 J/g = 16499.6 J

The amount of heat required to raise the temperature of the liquid ethanol from -26.8°C to its melting point of -114.1°C is given by the formula:

Q2 = m * C * ΔT

where Q2 is the amount of heat required, m is the mass of the substance, C is its specific heat capacity, and ΔT is the change in temperature.

The specific heat capacity of ethanol is 2.44 J/g°C. The change in temperature is:

ΔT = (-114.1°C) - (-26.8°C) = -87.3°C

Since we want to bring the ethanol to its melting point, we assume that it is still in the liquid state. Therefore, we use the specific heat capacity of liquid ethanol for this calculation.

So, for raising the temperature of 148 g of liquid ethanol from -26.8°C to -114.1°C, the amount of heat required is:

Q2 = 148 g * 2.44 J/g°C * (-87.3°C) = -30834.8 J

Note that the negative sign indicates that heat is lost from the ethanol as it cools.

The total amount of heat required to melt 148 g of solid ethanol and bring it to a temperature of -26.8°C is the sum of Q1 and Q2:

Qtotal = Q1 + Q2 = 16499.6 J + (-30834.8 J) = -14335.2 J

The answer is -14335 J (rounded to three significant digits), which means that 14335 J of heat energy must be removed from the system (or the surroundings must supply 14335 J of heat energy) to carry out the process as described.

an alpha particle (6.70×10-27 kg) moving at a speed of 1.52×107 m/s (34000000 miles per hour).
whats the m?

Answers

According to the given statement the alpha particle's wavelength is 6.48×10⁻¹⁵ meters.

What is alpha particle made of?

The positively charged alpha particles (α) are created when the nucleus of an atom's two protons as well as two neutrons join forces. Alpha particles are created by the radioactivity of the most dangerous radioactive elements, including uranium, radium, and polonium.

The de Broglie wavelength equation may be used to determine the alpha particle's wavelength:

λ = h / p

where p is the particle's momentum, h is its Planck constant (6.626 * 10⁻³⁴ J s), and is its wavelength.

The mass (m) and velocity (v) of an alpha particle may be used to compute its momentum:

p = m * v

Inputting the values provided yields:

p = (6.70×10⁻²⁷ kg) * (1.52×10⁷ m/s) = 1.02×10⁻¹⁹ kg m/s

Now we can determine the wavelength using this value:

λ = h / p = 6.626 x 10⁻³⁴ J s / 1.02×10⁻¹⁹ kg m/s

λ = 6.48 x 10⁻¹⁵ m

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The complete question is -

Calculate the wavelength of -

An alpha particle (6.70×10⁻²⁷ kg) moving at a speed of 1.52×10⁷ m/s (34000000 miles per hour). What is the m ?

A Sample of helium occupies a volume of 160 cm³ at 100 KPa and 25°C. what Volume will it occupy if the pressure is adjusted to 80 KPa and the temperature remains unchanged?. -273 ​

Answers

Boyle's Law-

[tex]\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}\\[/tex]

(Pressure is inversely proportional to the volume)

Where-

[tex]\sf V_1[/tex] = Initial volume[tex]\sf V_2[/tex] = Final volume[tex]\sf P_1[/tex] = Initial pressure[tex]\sf P_2[/tex] = Final pressure

As per question, we are given that -

[tex]\sf V_1[/tex] = 160 cm³[tex]\sf P_1[/tex] = 100KPa[tex]\sf P_2[/tex] = 80KPa

Now that we have all the required values and we are asked to find out volume which will be occupied if the pressure is adjusted to 80 KPa and the temperature remains unchanged. For that we can put the values and solve for the final volume of helium-

[tex]\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf 100 \times 160 = 80 \times V_2\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf V_2 = \dfrac{100 \times 160}{80}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf V_2 =100\times \cancel{\dfrac{ 160}{80}}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf V_2 = 100 \times 2\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{V_2 = 200 \:cm^3 }\\[/tex]

Therefore, 200 cm³ will be occupied if the pressure is adjusted to 80 KPa and the temperature remains unchanged.

Objects found at the bottom of the ocean are often covered in coral is this a physical or chemical change por favor necesito ayuda contestar pls

Answers

The growth of coral on objects found at the bottom of the ocean is a physical change, not a chemical change.

chemical change por favor necesito ayuda contestar ?

This is because the coral is simply attaching itself to the surface of the object through a physical process, rather than changing the chemical composition of the object itself. The coral is able to attach itself to the surface due to physical forces such as adhesion, cohesion, and surface tension.

However, it is worth noting that over time, the growth of coral on an object can lead to chemical changes in the object as the coral secretes calcium carbonate, which can gradually alter the object's composition.

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