X to the 3rd power= 64/343

Answers

Answer 1

Answer:

x = 4/7

Step-by-step explanation:

x^3 = 64/ 343 // - 64/ 343

x^3 - ( 64/ 343 ) = 0

x^3 - 64 / 343 = 0

1*x^3 = 64/ 343 // : 1

x^3 = 64/ 343

x^3 = 64/ 343 // ^ 1/3

x = 4/ 7


Related Questions

The cost of petrol is 60 rupees per litre a petrol bunk sells 750
litre s of petrol one day. how much money do they get At The end of the day​

Answers

Answer:

45000rupees

Step-by-step explanation:

cost of 1 litre of petrol=60rupees

cost of 750 litres of petrol=750×60rupees

=45000rupees

Write an equation in slope-intercept form of the line passing through (0, 3) and (2, -1).


y=2x+3y=2x+3

y=-2x+3y=−2x+3

y=-2xy=−2x

y=-x+3y=−x+3

Answers

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

[tex]y = -2x + 3[/tex]

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Slope-Intercept Form Is:}}\\\\y=mx + b\\---------------\\\boxed{\text{Key:}}\\\\m - slope\\b - y-intercept\\---------------\\\boxed{\text{\underline{Known Information:}}}\\\\\rightarrow \text{We are given the points: } (0,3) \text{ and } (2, -1)\\---------------\\\boxed[/tex]

[tex]\boxed{\text{\underline{Y-Intercept:}}}\\\\\rightarrow \text{Since the line passes at point (0, 3), the y-intercept would be 3.}\\---------------\\\boxed{\text{\underline{Slope:}}}\\\\\rightarrow m =\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1} \\\\\rightarrow m = \frac{-1-3}{2-0}=\frac{-4}{2}=\boxed{-2}\\\\\text{The slope is: } \boxed{-2}\\---------------[/tex]

[tex]\boxed{\text{\underline{Equation:}}}\\\\\text{Our equation should be:}\\\\y = -2x + 3[/tex]

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.

pls help im a little bit sтuрid

Answers

Step-by-step explanation:

a⁴+16a²b-2ab-a²+64b²-b²

we can also write them as,

a⁴+16a²b+64b²-a²-2ab-b²

Now, from -a²-2ab-b² if we take - as common term then we get,

a⁴+16a²b+64b²-(+2ab+)

Now, by using the concept of +2ab+=(a+b)²

()²+2×a²×8b+(8b)²-{(a)²+2×a×b+(b)²}(+8b)²-(a+b)²

I hope it helped U

stay safe stay happy

What is the range with steps? f(x)=x^2+8x+8

Answers

Answer:

[-8, ∞)

Step-by-step explanation:

Given function:

f(x)=x² + 8x + 8

This is a quadratic function with positive leading coefficient, therefore it is an increasing function with its minimum at vertex. It has no maximum value.

The vertex is at x = -b/2a:

x = -8/2 = -4

The minimum value is:

f(-4) = (-4)² + 8(-4) + 8 = 16 - 32 + 8 = -8

The range of the function is:

[-8, ∞)

f(x)=x^2+8x+8

Find vertex to x

[tex]\\ \sf\longmapsto \dfrac{-b}{2a}[/tex]

[tex]\\ \sf\longmapsto \dfrac{-8}{2(1)}[/tex]

[tex]\\ \sf\longmapsto \dfrac{-8}{2}[/tex]

[tex]\\ \sf\longmapsto -4[/tex]

Find value of function at -4

[tex]\\ \sf\longmapsto f(-4)[/tex]

[tex]\\ \sf\longmapsto (-4)^2+8(-4)+8[/tex]

[tex]\\ \sf\longmapsto 16-32+8[/tex]

[tex]\\ \sf\longmapsto -16+8[/tex]

[tex]\\ \sf\longmapsto -8[/tex]

The range is

[tex]\\ \sf\longmapsto (8,\infty)[/tex]

Please help me It’s my birthday!

2. Janyce conjectured that in the visual pattern below, there would be 3n – 1 small
squares in the nth figure

Can you disprove Janyce’s conjecture?

Answers

Step-by-step explanation:

Janyce's rule doesn't work. In the case where n = 3 her rule predicts that there will be 3(3) - 1 = 8 squares but instead, there are 10 squares. Likewise, for n = 4, there are 17 squares instead of 11 that she predicted. Instead, I propose the rule [tex]n^2 + 1.[/tex] It works for all the figures shown and mostly likely, for all other values of n.

2. Part A;

Given that the number of squares obtained using Janyce conjecture for

figures 3 and 4 which are 8 and 11 squares respectively and the number of

squares in the diagram for figures 3 and 4 which are 10 and 17 squares

respectively are not the same, disproves Janyce conjecture

Part B:

The rule for the number of squares in the nth squares is n² + 1

The reasons the above conclusion and rule are correct is as follows:

2. Part A

The given number of squares in each figure are;

[tex]\begin{array}{|c|c|c|}\mathbf{Figure \ number}&\mathbf{Number \ of \ squares} &\mathbf{Janyce \ conjecture \ (3\cdot n - 1)}\\&&\\1&2 \ squares &(3 \times 1 - 1 = 2) \ squares \\2&5 \ squares&(3 \times 2 - 1 = 5) \ squares\\3&10 \ squares &(3 \times 3 - 1 = 8) \ squares\\4&17 \ squares&(3 \times 4 - 1 = 11) \ squares\end{array}[/tex]

Given that the number squares in figure 3, and 4 are;

Figure 3 = 10 squares

Figure 4 = 17 squares

Janyce conjectured number of squares are;

Figure 3 = 8 squares

Figure 4 = 11 squares

The values for the number of squares in the diagram in figures 3 and 4 are different from Janyce conjecture which disproves Janyce's conjecture for the number of squares in the nth figure

Part B

From the diagrams, we have;

The number of squares on the each figure is given by a square shape with a side length equal to the figure number of squares plus one extra square at the top right end corner, we have;

The area of the square part of the shape = = The number of squares in the square shape

The number of squares in the nth figure = n² + 1

Verifying, we have;

Figure 1 = (1² + 1) squares = 2 squares (Same as in diagram)

Figure 2 = (2² + 1) squares = 5 squares (Same as in diagram)

Figure 3 = (3² + 1) squares = 10 squares (Same as in diagram)

Figure 4 = (4² + 1) squares = 17 squares (Same as in diagram)

Therefore;

The correct formula for the number of squares in the nth figure = n² + 1

Learn more about the nth term of a sequence here:

https://brainly.com/question/12998719

https://brainly.com/question/15325765

https://brainly.com/question/21493252

For the two numbers listed, find two factors of the first number such that their product is the first number and their sum is the second number.
- 10,9

Answers

9514 1404 393

Answer:

  10, -1

Step-by-step explanation:

If you assume the numbers are integers, you can look at the factor pairs that make -10:

  -10 = 10(-1) = 5(-2) = 2(-5) = 1(-10)

The sums of these pairs are 9, 3, -3, -9, so the pair of interest is the first one:

  10, -1

Ayudaa con esa qnq

-9/4 + 3/7 x -1/11

Answers

Answer:

3x-721/44 over 7

Step-by-step explanation:

1)Combine multiplied terms into a single fraction

2)Multiply the numbers

3)Subtract the numbers

4)Find common denominator

5)Combine fractions with common denominator

6)Multiply the numbers

7)Rearrange terms

A motorboat travels 116 kilometers in 4 hours going upstream. It travels 164 kilometers going downstream in the same amount of time. What is the rate of the
boat in still water and what is the rate of the current?
Rate of the boat in still water:
Rate of the current:

Answers

9514 1404 393

Answer:

boat: 35 km/hcurrent: 6 km/h

Step-by-step explanation:

Let b and c represent the rates of the boat and current, respectively. Then the upstream rate is ...

  speed = distance/time

  b -c = (116 km)/(4 h) = 29 km/h

  b +c = (164 km)/(4 h) = 41 km/h

Adding these equations gives ...

  2b = 70 km/h

  b = 35 km/h

Substituting into the first equation, we have ...

  35 -c = 29

  c = 6

Rate of the boat: 35 km/h.

Rate of the current: 6 km/h

Factor x^2+x+6
Plz help

Answers

Answer:

2

Step-by-step explanation:

how many feet is 2160 yards?​

Answers

Answer:

6480 feet

Step-by-step explanation:

Since there’s 3 feet in one yard, we can multiply the amount of yards by 3 to find out the amount of feet

3 x 2160 = 6480 feet

The answer is 6480 feet

Calculate the area of each figure.

Answers

Answer:

230cm²

Step-by-step explanation:

We can split the shape into 2 parts - the triangle and the rectangle.

The area of the retangle is 10*17cm = 170cm²

The area of the triangle  = 1/2 * (22-10) * (17-7)

                                         =  1/2 * 12 * 10 = 60

Therefore the total area is equal to 170+60 = 230cm²

8x – 3 = 11 + 6x
What is x

Answers

Answer:

x = 7

Step-by-step explanation:

[tex]8x-3=11+6x\\\\2x-3=11\\\\2x=14\\\\x=7[/tex]

Answer:

x = 7

Step-by-step explanation:

8x - 3 = 11 + 6x

8x - 3 + 3 = 11 + 6x +3

8x = 6x + 14

8x - 6x = 6x + 14 - 6x

2x = 14

2x/2 = 14/2

x = 7

PLEASE HELP

1= a-13/-6

Show your work in details if you can, I have a hard time understanding this.

Answers

Answer: 7

Step-by-step explanation:

1. multiply both sides by -6 so the -6 on the right side could cancel out and the left side would be -6:  1= a-13/-6 ==> -6=a-13

2. add both sides by 13 so -13 on the right side could cancel out and the left side would be -6+13: -6=a-13 ==> -6+13=a-13+13

3. you know -6+13 equals 7 right? so the answer is a=7

Hey there! I'm happy to help!

We want to get the a all by itself. For me, I always like to have the variable on the left side, so first, let's just flip this around.

[tex]\frac{a-13}{-6} =1[/tex]

What we want to do is get all of the constants (numbers without variables) on the right side. This will leave a all on its own.

We see that the quantity a-13 is being divided by -6. To undo this, we will just multiply both sides by -6. This will cancel out that -6 and get us closer to having the a isolated.

[tex]\frac{a-13}{-6} *-6=1*-6\\\frac{a-13}{1}=-6\\a-13=-6[/tex]

Now we add 13 to both sides to undo the -13 on the left side.

[tex]a-13+13=-6+13[/tex]

[tex]a+0=7\\a=7[/tex]

Have a wonderful day and keep on learning! :D

You move left 4 units. You end at (-5, -5). Where did you start?

Answers

Answer:

(-1,-5)

Step-by-step explanation:

To understand where this point was before the transformation you must first understand the transformation itself. Shifting left is a horizontal translation, this means that it will affect the x-coordinate. The x-coordinate is the first digit in the pair. Therefore, in the case of (3,5), 3 would be the x-coordinate. Additionally, moving left is moving towards the negative, so it is the same as subtracting. Thus, to find where you started, work backward. Do this by adding 4 to the x-coordinate. This means the beginning coordinate was (-1,-5).

9(y-4) -3y = 2(3y-2 need solved as fast as possible

Answers

Step-by-step explanation:

did you give us all the information ? the equating looks cut off.

so, from what I can see we have

9(y-4) - 3y = 2(3y-2)

let's try :

9y - 36 - 3y = 6y - 4

0 = 32

so, no, this can't be it. this does not have a solution. you must have cut off some additional information.

2. The product of 7 and a number

Answers

I think the answer you are looking for is 7n, which also means 7 times n.

Answer:

7x

Step-by-step explanation:

Product refers to multiplication. "A number" refers to an unknown number otherwise known as a variable. In this case, I use x.

Pre-algbra worksheet!!Please help!! will give brainliest!!

Answers

Answer:

1/4= 0.5=0.125, 2/4=0.5=0.125, 3/4= 0.75=0.1878

Please help me solve that question

Answers

Step-by-step explanation:

steps are in picture above.

if you need to ask questions I'll give you answers gladly.

Please solve the equation for z

Answers

Answer:

z = 2y - 4x

Step-by-step explanation:

[tex]{ \sf{x = \frac{2y - z}{4} }} [/tex]

multiply both sides by 4:

[tex]{ \sf{(4 \times x) = ( \frac{2y - z}{4}) \times 4 }} \\ \\ { \sf{4x = 2y - z}} \\{ \sf{z = 2y - 4x}}[/tex]

create a improper fraction with the number 10 as the denominator

Answers

Answer:

Decimal Fraction Percentage

0.101 101/1000 10.1%

0.1 100/1000 10%

0.1013 101/997 10.13%

0.1012 101/998 10.12%

Step-by-step explanation:

Let the (x; y) coordinates represent locations on the ground. The height h of
a particle is governed by the function described below. Classify all the critical
points of height and find the value(s) of height h at those points.
h(x; y) = 8x + 10y - 4xy - 4x^2 - 4y^3

Answers

The critical points of h(x,y) occur wherever its partial derivatives [tex]h_x[/tex] and [tex]h_y[/tex] vanish simultaneously. We have

[tex]h_x = 8-4y-8x = 0 \implies y=2-2x \\\\ h_y = 10-4x-12y^2 = 0 \implies 2x+6y^2=5[/tex]

Substitute y in the second equation and solve for x, then for y :

[tex]2x+6(2-2x)^2=5 \\\\ 24x^2-46x+19=0 \\\\ \implies x=\dfrac{23\pm\sqrt{73}}{24}\text{ and }y=\dfrac{1\mp\sqrt{73}}{12}[/tex]

This is to say there are two critical points,

[tex](x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)[/tex]

To classify these critical points, we carry out the second partial derivative test. h(x,y) has Hessian

[tex]H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}[/tex]

whose determinant is [tex]192y-16[/tex]. Now,

• if the Hessian determinant is negative at a given critical point, then you have a saddle point

• if both the determinant and [tex]h_{xx}[/tex] are positive at the point, then it's a local minimum

• if the determinant is positive and [tex]h_{xx}[/tex] is negative, then it's a local maximum

• otherwise the test fails

We have

[tex]\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0[/tex]

while

[tex]\det\left(H\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)\right) = 16\sqrt{73}>0 \\\\ \text{ and } \\\\ h_{xx}\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-8 < 0[/tex]

So, we end up with

[tex]h\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-\dfrac{4247+37\sqrt{73}}{72} \text{ (saddle point)}\\\\\text{ and }\\\\h\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)=-\dfrac{4247-37\sqrt{73}}{72} \text{ (local max)}[/tex]

how many inches is 10560 feet?​

Answers

Answer:

126720

Step-by-step explanation:

a bakery sells 17 cups of coffee for every 3 cups of hot chocolate they sell. At the end of the day the bakery sold 406 more coffee than hot chocolates. How many of the two drinks did they sell in all?

Answers

Answer:

Step-by-step explanation:

helpppppppppppppopnanannsnsnnsnakaknfnsn

Answers

Step-by-step explanation:

y=107(vertically opposite angles)

x=180-107=73(angles on a straight line)

z=73(vertically opposite angles)

Answer:

[tex]{ \sf{y = 107 \degree}} \: \{ \sf{alternate \: angles} \}[/tex]

[tex]{ \sf{z + 107 \degree = 180 \degree}} \: \{ \sf{straight \: line \: angles \}} \\ z = 180\degree - 107\degree \\ z = 73\degree[/tex]

[tex]{ \sf{x = z}} \: \{ \sf{alternate \: angle \}} \\ x = 73\degree[/tex]

What is the solution to the system of equations below?

4x-2y=10
y=-2x-5

show your work! :)

Answers

Answer:

(0,-5)

Step-by-step explanation:

4x-2(-2x-5)+10

x=0

y=-2*0-5

y=-5

x=-9 y=-8 evaluate the expression 8 x^2 - 6 y^2

Answers

Answer:

264

Step-by-step explanation:

Let x= -9 y= -88x² - 6y² = ?8(-9)² - 6(-8)² = ?8(81) - 6(64) = ?648 - 384 = ?264

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

Evaluate: 24 - ( 5 - 3)^ 4
______________
4​

Answers

24 - (5 - 3)⁴ = 24 - 2⁴ = 24 - 16 = 8

8 : 4 = 2 ← the end solution

In the number 6.253
(a) What is the place value of 2 ...................................................................
(b) What is the value represented by 5 ...................................................................

Answers

Answer:

place value of 2 is 100

Step-by-step explanation:

please brainleist my answer

Answer:

The place value of 2 in 6.253 is 200

Step-by-step explanation:

Place value of 2 is occurring in hundreds

Let C be the positively oriented square with vertices (0,0), (3,0), (3,3), (0,3). Use Green's Theorem to evaluate the line integral
∫C 8y^2 x dx + 6x^2 y dy

Answers

Let D denote the region whose boundary is C. By Green's theorem,

[tex]\displaystyle \int_C 8y^2x\,\mathrm dx + 6x^2y\,\mathrm dy = \iint_D \frac{\partial(6x^2y)}{\partial x} - \frac{\partial(8y^2x)}{\partial y} \,\mathrm dx\,\mathrm dy \\\\ = \int_0^3 \int_0^3 (12xy-16yx)\,\mathrm dx\,\mathrm dy \\\\ = -4 \int_0^3 \int_0^3 xy\,\mathrm dx\,\mathrm dy = \boxed{-81}[/tex]

help me plz branniest to whoever right

Answers

(3x+7)+(4x+9)=-58
first add like terms
7x+16=-58
subtract 16 from both sides
-7x=-74
divide -7 from both sides
x=10.6
its 10.6 units long
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