Answer:If the letters are 2 inches high in the sketch, and you want them to be 2 feet high in reality, that means you need to scale up the letters by a factor of 12 (since 1 foot = 12 inches).
So the new height of each letter will be:
2 inches/letter × 12 = 24 inches/letter
And the new length of the banner will be:
20 inches/banner × 12 = 240 inches/banner
To find out how much paper to buy, you need to know the width of the paper you'll be using. Let's say the paper is 36 inches wide (3 feet). In that case, you'll need to buy:
240 inches/banner ÷ 36 inches/roll = 6.67 rolls of paper
Since you can't buy a fraction of a roll of paper, you should round up to 7 rolls of paper to ensure you have enough.
Step-by-step explanation:
find the extremum of each function using the symmetry of its graph. Classify the etremum of the function as maximum or a minimum and state the of x at which it occurs k(x)(300+10x)(5-0.2x)
The extremum of the function is a minimum at x = -2.5
The given function is k(x)(300+10x)(5-0.2x).
To check for symmetry about the y-axis, we replace x with -x in the given function and simplify as follows:
k(-x)(300-10x)(5+0.2x)
To check for symmetry about the x-axis, we replace y with -y in the given function and simplify as follows:
k(x)(300+10x)(5-0.2x) = -k(x)(-300-10x)(5+0.2x)
To find these points, we set the function equal to zero and solve for x:
k(x)(300+10x)(5-0.2x) = 0
This equation has three solutions:
x = 0
x = -30
x = 25.
The midpoint of the line segment connecting these points is
(x1+x2) ÷ 2 = (-30+25) ÷ 2 = -2.5.
To determine the type of extremum at this point, we need to check the sign of the second derivative. The second derivative of the function is:
k(x)(-1200+x)(0.2x+15)
Since the function is symmetric about the x-axis, the second derivative will be negative at the extremum if it is maximum and positive if it is a minimum.
When x = -2.5, the second derivative is positive, which means that the function has a minimum at x = -2.5.
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You find an apartment which charges $925 a month rent. each year the rent increases by 6%.
The monthly rent for the apartment would be $1238.84 in the fifth year.
What is the monthly rent for an apartment that charges $925 initially and increases by 6% each year?The problem states that the monthly rent for an apartment is $925. To calculate the rent for the second year, we need to increase this amount by 6%.
To do this, we first need to calculate 6% of $925. We can do this by multiplying 0.06 (which is equivalent to 6%) by $925:
6% of $925 = 0.06 × $925 = $55.50
So, the rent for the second year would be:
$925 + $55.50 = $980.50
To find the rent for the third year, we need to increase the rent for the second year by 6%. We can follow the same process:
6% of $980.50 = 0.06 × $980.50 = $58.83
So, the rent for the third year would be:
$980.50 + $58.83 = $1039.33
To find the rent for any year n, we use the formula:
Rent for year n = $925 × (1 + 0.06)^n
In this formula, (1 + 0.06) represents the multiplier used to calculate the new rent each year.
For example, the multiplier for the second year is 1 + 0.06 = 1.06, and the multiplier for the third year is 1.06 × 1.06 = 1.1236 (rounded to four decimal places).
To find the rent for the fifth year, we plug in n = 5:
Rent for year 5 = $925 × (1 + 0.06)^5 = $925 × 1.3382 = $1238.84 (rounded to the nearest cent)
So, the monthly rent for the apartment would be $1238.84 in the fifth year.
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Part of the shape is drawn.
The line of symmetry of the shape is the dotted line.
complete the drawing of the shape and then rotate it by 180° about the origin
The remaining part of the given shape was drawn about to its symmetry. The complete shape obtained is similar to the Hexagon shape.
Given half shape has the following points,
(-3,-1)(-4,-1)(-5,-3)(-4,-4)(-3,-4)The points which are missing to complete the other symmetry are:
(-3,-1)(-2,-1)(-1,-3)(-2,-4)(-3,-4)By joining the above missing points, we can obtain the full symmetry of the shape.
To rotate the obtained shape of the Hexagon to 180° about the origin, we have to inverse the above complete symmetry points. It simply means if the above points are having positive values, we can inverse it to negative and vice-versa.
By rotating the obtained shape to 180° about the origin, we can obtain the below following points,
(3,1)(4,1)(5,3)(4,4)(3,4)(2,1)(1,3)(2,4)The images are attached below for the complete symmetry shape.
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Given question is not having enough required information, so I am attaching the image of the shape which we have to work on,
13. the area of a rhombus is 484 square millimeters. one diagonal is one-half as long
as the other diagonal. find the length of each diagonal.
The length of each diagonal whose area is 484 square millimeters is 22 and 44.
Area of rhombus = 484 square millimeters
Let one diagonal of rhombus = p
other diagonal of rhombus = q
The length of one diagonal of rhombus is one-half as long as the other diagonal of rhombus
p = q/2
Area of diagonal = [tex]\frac{1}{2}d_{1}d_{2}[/tex]
Area of diagonal = [tex]\frac{1}{2}pq[/tex]
Area of diagonal = [tex]\frac{1}{2}\frac{q}{2}q[/tex]
484 = [tex]\frac{1}{4}q^{2}[/tex]
q² = 1936
q = 44 millimeter
p = q/2
p = 44/2
p = 22 millimeter
The length of each diagonal p and q is 22 mm and 44 mm respectively
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An square aquarium which is 15cm long has 1250 millilitres of water how much more water needed to fill the aquarium completely
You need to add 2125 milliliters of water to fill the square aquarium completely.
We need to find the volume of the square aquarium and then determine the additional water needed to fill it completely. Here are the steps:
1. Convert the given length to meters: 15 cm = 0.15 m
2. Calculate the volume of the square aquarium: Volume = length × width × height. Since it's a square aquarium, all sides are equal, so Volume = 0.15 m × 0.15 m × 0.15 m = 0.003375 cubic meters.
3. Convert the volume to milliliters: 0.003375 cubic meters × 1,000,000 mL/cubic meter = 3375 mL.
4. Calculate the additional water needed: Total volume - Current volume = 3375 mL - 1250 mL = 2125 mL.
You need to add 2125 milliliters of water to fill the square aquarium completely.
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Find the cosine of K.
24
Save answer
26
blo
J
10
Simplify your answer and write it as a proper fraction, improper fraction, or whole number.
cos (K) =
K
Skip to
Step-by-step explanation:
remember the original trigonometric triangle inside the norm circle (radius = 1).
sine is the up/down distance from the triangle baseline or corresponding circle diameter.
cosine is the left/right distance from the center of the circle (and the point of the angle).
for larger triangles and circles all these function results need to be multiplied by the actual radius (which we skipped for the norm circle, as a multiplication by 1 is not changing anything).
when you look at the triangle with K representing the angle, we have 10 a the cosine value, 24 as the sine value and 26 as the radius.
so,
10 = cos(K) × 26
cos(K) = 10/26 = 5/13
Mario is buying a number of hamburgers from the local store that cost \$2. 90$2. 90 each. He is also buying one packet of hamburger rolls at a cost of \$4. 75$4. 75. He has \$39. 55$39. 55 to spend at the store. Write and solve an inequality that shows how many hamburgers, hh, Mario can afford to buy. Write the inequality
Mario can afford to buy a maximum of 12 hamburgers from the local store.
How to find the number of hamburgers Mario can afford to buy given certain prices and a budget?Let's assume Mario can buy "h" hamburgers.
The cost of each hamburger is $2.90, and Mario wants to buy "h" hamburgers, so the total cost of hamburgers would be 2.90h.
He is also buying one packet of hamburger rolls, which costs $4.75.
Therefore, the total amount he can spend at the store must be less than or equal to his budget of $39.55.
Putting it all together, the inequality representing this situation is:
2.90h + 4.75 ≤ 39.55
To find out how many hamburgers Mario can afford to buy, we need to solve the inequality:
2.90h + 4.75 ≤ 39.55
Subtracting 4.75 from both sides of the inequality:
2.90h ≤ 34.80
Next, divide both sides of the inequality by 2.90:
h ≤ [tex]\frac{34.80 }{ 2.90}[/tex]
Simplifying the right side:
h ≤ 12
Therefore, Mario can afford to buy a maximum of 12 hamburgers from the local store.
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Tim jones bought 100 shares of mutual fund abc at $4.25 with no load and sold them for $850. and 100 shares of def at $6.00 which had a load of $375 dollars, and sold them for $1,200.
*this is one where you finish the table, i looked it up and couldn't find the answer so i guessed and got a 100. so this is for yall who can't just guess it perfectly on the 1st try*
<<<<< on odyssey ware >>>>>
purchase price load total cost sales price sales price ÷ total cost
abc = $425 0 $425 ? ? % (nearest 1%)
def = $600 $375 ? ? ? % (nearest 1%)
---answers---
purchase price load total cost sales price sales price ÷ total cost
abc = $425 0 $425 $850 200 % (nearest 1%)
def = $600 $375 $975 $1200 123 % (nearest 1%)
The sales price divided by total cost is 123%.
Based on the information provided, I can help you complete the table:
Purchase Price | Load | Total Cost | Sales Price | Sales Price ÷ Total Cost (nearest 1%)
ABC = $425 | 0 | $425 | $850 | 200%
DEF = $600 | $375 | $975 | $1,200 | 123%
For mutual fund ABC, there was no load, so the total cost is equal to the purchase price. The sales price ÷ total cost is 200% (nearest 1%). For mutual fund DEF, the total cost includes the $375 load, resulting in a total cost of $975. The sales price ÷ total cost is 123% (nearest 1%).
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In ΔSTU, u = 3. 4 cm, ∠S=6° and ∠T=93°. Find the area of ΔSTU, to the nearest 10th of a square centimeter
The area of ΔSTU is approximately 6.7 square centimeters.
What is the approximate area, in square centimeters, of ΔSTU given that u = 3.4 cm, ∠S=6°, and ∠T=93°?To find the area of a triangle, we can use the formula A = (1/2)bh, where b is the base of the triangle and h is the height. In this case, we know that u is the base of the triangle, so we need to find the height.
To do this, we can use the sine function, which tells us that sin(6°) = h/u. Rearranging this equation, we get h = usin(6°). We can then substitute u and sin(6°) into the formula for the area to get
A = (1/2)(3.4)(3.4sin(6°)) ≈ 6.7 square centimeters.
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Bags of a certain brand of tortilla chips claim to have a net weight of 14 ounces. Net weights actually vary
slightly from bag to bag and are Normally distributed with mean ï. A representative of a consumer
advocacy group wishes to see if there is any evidence that the true mean net weight is less than advertised and
so intends to test the hypotheses
H0 : μ = 14
Ha : μ < 14A
Type I error in this situation would mean
a. Concluding that the bags are being under filled when they actually arenât.
b. Concluding that the bags are being under filled when they actually are.
c. Concluding that the bags are not being under filled when they actually are.
d. Concluding that the bags are not being under filled when they actually arenât.
e. None of these
Type I error in this situation would mean option a. Concluding that the bags are being under filled when they actually aren't.
A Type I error occurs when the null hypothesis (in this case, that the true mean net weight is 14 ounces) is rejected when it is actually true. In other words, it is the error of concluding that there is evidence for the alternative hypothesis (that the true mean net weight is less than 14 ounces) when there is not.
In this situation, if a Type I error is made, it would mean that the bags are being under filled (i.e. the true mean net weight is less than 14 ounces) when in reality they are not. This would lead to incorrect conclusions and potentially negative consequences for the manufacturer.
It's important to note that the probability of making a Type I error can be controlled by choosing an appropriate level of significance (usually denoted by alpha) for the hypothesis test. For example, if alpha is set at 0.05, there is a 5% chance of making a Type I error.
In summary, a Type I error in this situation would mean incorrectly concluding that the bags are being under filled when they actually are not, and the probability of making such an error can be controlled by choosing an appropriate level of significance for the hypothesis test.
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In the driest part of an Outback ranch, each cow needs about 40 acres for grazing. Use an equation to find how many cows can graze on 720 acres of land.
The calculated value of the number of cows that can graze on 720 acres of land is 18
From the question, the statements that can be used in our computation are given as
The area of grazing needed by each cow is 40 acres
From the above statement, the equation to use is
Cows = Area of land/Unit rate of cows
By substituting the given values in the above equation, we have the following equation
Cows = 720/40
Evaluate
Cows = 18
Hence, the calculated number of cows is 18
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The probability that sue will go to mexico in the winter and to france
in the summer is
0. 40
. the probability that she will go to mexico in
the winter is
0. 60
. find the probability that she will go to france this
summer, given that she just returned from her winter vacation in
mexico
The evaluated probability that Sue travel to France this summer is 0.67, under the condition that she just returned from her winter vacation in Mexico.
For the required problem we have to apply Bayes' theorem.
Let us consider that A is the event that Sue goes to France in the summer and B be the event that Sue goes to Mexico in the winter.
Now,
P(A and B) = P(B) × P(A|B)
= 0.40
P(B) = 0.60
Therefore now we have to find P(A|B), which means the probability that Sue traveled to France after coming from Mexico
Applying Bayes' theorem,
P(A|B) = P(B|A) × P(A) / P(B)
It is given that P(B|A) = P(A and B) / P(A), then
P(A|B) = (P(A and B) / P(A)) × P(A) / P(B)
P(A|B) = P(A and B) / P(B)
Staging the values
P(A|B) = 0.40 / 0.60
P(A|B) = 0.67
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The complete question is
The probability that Sue will go to Mexico in the winter and to France in the summer is 0. 40. the probability that she will go to mexico in the winter is 0. 60. find the probability that she will go to France this summer, given that she just returned from her winter vacation in Mexico.
The sides of the base of a right square pyramid are 3 meters in length, and its slant height is 6 meters. if the lengths of the sides of the base and the slant height are each multiplied by 3, by what factor is the surface area multiplied?
a. 12
b. 3^3
c. 3^2
d. 3
If the base and slant height both are divided by a factor of 3, the surface area will get multiplied by factor, option b, 3².
Here we are given that the square pyramid has a base of 3m and a slant height of 6 m.
The surface area formula for a square pyramid with square edge a and slant height h is
a² + 2a√(a²/4 + h²)
Here, a = 3 and h = 6. Hence we get
3² + 2X3√(3²/4 + 6²)
= 46.108
Now the base and slant height are multiplied by 3. Hence we will get
9a² + 6a√(9a²/4 + 9h²)
414.972
Now, dividing both obtained we will get
414.972/46.108
= 9
= 3²
Hence, it should be multiplied by 3².
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Find the perimeter of the semicircular region. Round your answer to the nearest hundredth
9 m
The perimeter is about
meters
The perimeter of the semicircular region is about 28.27 meters.
We know that the semicircular region is half of a circle.
Let's assume that the radius of the circle is r meters. Then the circumference of the circle is 2πr meters, and the perimeter of the semicircular region is half of that, which is πr meters.
We are given that the radius of the circle is 9 meters, so we can plug that in to get:
The perimeter of the semicircular region = πr
= π(9)
≈ 28.27
Rounding to the nearest hundredth, the perimeter of the semicircular region is about 28.27 meters.
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Patricia bought 4 apples and 9 bananas for $12. 70 Jose bought 8 apples and I bananas for $17. 70 at the same grocery store What is the cost of one apple?
The cost of one apple is $2.15.
To find the cost of one apple, we can set up a system of equations with the given information. Let's use A for the cost of one apple and B for the cost of one banana:
1) 4A + 9B = $12.70
2) 8A + B = $17.70
Now, we can solve this system of equations. We can multiply equation 1 by 2 to match the number of apples in equation 2:
1) 8A + 18B = $25.40
Now subtract equation 2 from the modified equation 1:
(8A + 18B) - (8A + B) = $25.40 - $17.70
17B = $7.70
Now, divide by 17 to find the cost of one banana:
B = $7.70 / 17 = $0.45
Now that we know the cost of one banana, we can substitute B in equation 2 to find the cost of one apple:
8A + ($0.45) = $17.70
8A = $17.25
A = $17.25 / 8 = $2.15
So, the cost of one apple is $2.15.
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I NEED HELPPPPPPPPPPPP
Answer: V = 2527.2 in^3
Step-by-step explanation:
V = Bh
that is, Volume = base area x height
the base area is the hexagon, and the height is given as 12.
Think of dividing the hexagon into 6 equal triangles, with height 7.8
so the area of all 6 triangles, (effectively the area of the hexagon), will be:
6(0.5 x 9 x 7.8) = 210.6 in^2
multiply this by the height to get the volume:
210.6 x 12 = 2527.2 in^3
thats it!
V = 2527.2 in^3
To determine what students want served in the cafeteria, the cook asks students in Ms. Andrew’s first period class. Describe the sample used by the cook.
To determine what students want served in the cafeteria, the cook asks students in Ms. Andrew’s first period class. The sample used by the cook is known as Convenience.
What type of sampling method was used?The sample used is known as convenience sample. The cook only asks students in Ms. Andrews’ first period class which is a convenient and accessible group to ask but this method of sampling may not be representative of the entire student population as it only includes students in one class.
So, the results may not accurately reflect what all students want to be served in the cafeteria, hence, more representative sample could be obtained by using a simple random sample or systematic sample where student in the population has an equal chance of being selected.
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Verify that the sample standard deviations use of ANO\A allow the the means to compare the population means. What do the suggest about the effect of the subject’s gender and attractiveness of the confederate on the evaluation of the product?
On performing an ANOVA test the p-value obtained is less than the chosen significance level, hence it is verified that the sample standard deviations use of ANOVA allow the the means to compare the population means. Since ANOVA test shows significant difference therefore, it suggests that these factors play a role in influencing the evaluation of the product.
To verify that the sample standard deviations use of ANOVA allows means to compare the population means, discuss the terms ANOVA, sample standard deviation, population means.
1. ANOVA (Analysis of Variance): ANOVA is a statistical method used to compare the means of multiple groups to determine if there's a significant difference between them.
2. Sample Standard Deviation: Sample standard deviation is a measure of how spread out the values in a sample are. It helps estimate the population standard deviation, which is necessary for calculating the F statistic in ANOVA.
a. Calculate the sample means and standard deviations for each group.
b. Perform an ANOVA test using calculated means and standard deviations.
c. Interpret results: If p-value obtained from the ANOVA test is less than the chosen significance level (e.g., 0.05), it means there is a significant difference between population means.
Regarding the effect of the subject's gender and attractiveness of the confederate on the evaluation of the product, if the ANOVA test shows a significant difference, it suggests that these factors play a role in influencing the evaluation of product. You can further analyze the data by performing post-hoc tests to identify which specific groups differ significantly.
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A recent survey reveals that one of the collie owners interviewed, 54% of them regularly groom their dogs, If there are 50,000 registered poodle owners in the county, how many owners are expected to regular groom their dos
Answer:
54% × 50000= 27000, the answer is 27000
In ∆DEF, DG−→− bisects ∠EDF. Is ∆FDG similar to ∆EDG? Explain.
A. Yes; ∆FDG ≅ ∆EDG by ASA.
B. Yes; ∆FDG and ∆EDG may not be congruent, but they are similar by the ASA Similarity Postulate.
C. No; ∆FDG and ∆EDG are not similar unless DE = DF.
D. No; ∆FDG and ∆EDG are not similar unless DE = EG and DF = FG
In ∆DEF, DG−→− bisects ∠EDF. ∆FDG is similar to ∆EDG; ∆FDG and ∆EDG may not be congruent, but they are similar by the ASA Similarity Postulate. Therefore, the correct option is B.
Consider the following reasoning:1. Since DG bisects ∠EDF, it means that ∠EDG = ∠FDG. This is the Angle Bisector Theorem.
2. In triangles FDG and EDG, we know that ∠FDG = ∠EDG (from step 1) and ∠DFG = ∠DEG (both are vertical angles and therefore congruent).
3. Now we have two pairs of congruent angles: ∠FDG = ∠EDG and ∠DFG = ∠DEG.
4. According to the (Angle-Side-Angle) or ASA Similarity Postulate, if two angles in one triangle are congruent to two angles in another triangle, then the triangles are similar. Therefore, ∆FDG is similar to ∆EDG.
Hence, the correct answer is option B: Yes; ∆FDG and ∆EDG may not be congruent, but they are similar by the ASA Similarity Postulate.
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A charity donates 40% of its proceeds to a local food bank. If the charity raised £1000, how much money did the food bank receive?
Answer:
£400
Step-by-step explanation:
first find 40% of £1000
40\100*1000
=400
Therefore answer is £400
Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it.
lim x → 0
A.x2^x
B. 2^x - 1
The limit of A. x^(2^x) as x approaches 0 is 1, and the limit of B. 2^x - 1 as x approaches 0 is ln 2.
A. To find the limit of A. x^(2^x) as x approaches 0, we can take the natural logarithm of both sides and use the fact that ln(1 + a) is approximately equal to a for small values of a. This gives us:
ln(A. x^(2^x)) = 2^x ln x
ln(A. x^(2^x)) / ln x = 2^x
Taking the limit as x approaches 0, the right-hand side goes to 1, and using the continuity of the natural logarithm, we have:
ln(A) = 0
A = 1
Therefore, the limit of A. x^(2^x) as x approaches 0 is 1.
B. To find the limit of B. 2^x - 1 as x approaches 0, we can use L'Hopital's Rule:
lim x→0 (2^x - 1)
= lim x→0 (ln 2 * 2^x / ln 2)
= ln 2 * lim x→0 (2^x / ln 2)
= ln 2 * (lim x→0 e^(x ln 2) / ln 2)
= ln 2 * (lim x→0 e^(x ln 2 - ln 2) / (ln 2 - ln 2))
= ln 2 * (lim x→0 e^(ln 2 * (x - 1)) / 1)
= ln 2 * e^0
= ln 2
Therefore, the limit of B. 2^x - 1 as x approaches 0 is ln 2.
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At a show 4 adult tickets and 1 child ticket cost £33 2 adult tickets and 7 child tickets cost £36 Work out the cost of 10 adult tickets and 20 child tickets.
Answer:
10 adult tickets cost £75 , 20 child tickets cost £60
Step-by-step explanation:
let a be the cost of an adult ticket and c the cost of a child ticket , then
4a + c = 33 → (1)
2a + 7c = 36 → (2)
multiplying (2) by - 2 and adding to (1) will eliminate a
- 4a - 14c = - 72 → (3)
add (1) and (3) term by term to eliminate a
0 - 13c = - 39
- 13c = - 39 ( divide both sides by - 13 )
c = 3
substitute c = 3 into either of the 2 equations and solve for a
substituting into (1)
4a + 3 = 33 ( subtract 3 from both sides )
4a = 30 ( divide both sides by 4 )
a = 7.5
the cost of an adult ticket is £7.50
then 10 adult tickets cost 10 × £7.50 = £75
the cost of a child ticket is £3
the cost of 20 child tickets is 20 × £3 = £60
Adding fractions
Need help
Answer:
1) 1/2 + 1/4 = 2/4 + 1/4 = 3/4
2) To add these fractions, you need to find a common denominator. The smallest common multiple of 7 and 9 is 63, so we can write:
3/7 * 9/9 + 2/9 * 7/7 = 27/63 + 14/63 = 41/63
3) To add these fractions, you need to find a common denominator. The smallest common multiple of 5 and 15 is 15, so we can write:
3/5 * 3/3 + 1/15 * 1/1 = 9/15 + 1/15 = 10/15
But we can simplify this fraction by dividing both the numerator and denominator by 5:
10/15 = 2/3
4) To add these fractions, you need to find a common denominator. The smallest common multiple of 9 and 8 is 72, so we can write:
1/9 * 8/8 + 7/8 * 9/9 = 8/72 + 63/72 = 71/72
5) To add these fractions, you need to find a common denominator. The smallest common multiple of 7 and 21 is 21, so we can write:
6/7 * 3/3 + 2/21 * 1/1 = 18/21 + 2/21 = 20/21
6) To add these fractions, we need to find a common denominator first. The smallest number that both 6 and 10 divide into is 30. So, we convert 4/6 to 20/30 by multiplying both the numerator and denominator by 5, and we convert 2/10 to 3/15 by multiplying both the numerator and denominator by 3. Now we have:
20/30 + 3/15 = (20x1 + 3x2)/(30x2) = 23/60
Therefore, 4/6 + 2/10 = 23/60.
7) To add these fractions, we need to find a common denominator first. The smallest number that both 11 and 22 divide into is 22. So, we convert 1/11 to 2/22 by multiplying both the numerator and denominator by 2, and we convert 3/22 to 3/22 (it is already in terms of 22). Now we have:
2/22 + 3/22 = (2 + 3)/22 = 5/22
Therefore, 1/11 + 3/22 = 5/22.
8) To add these fractions, we need to find a common denominator first. The smallest number that both 4 and 20 divide into is 20. So, we convert 1/4 to 5/20 by multiplying both the numerator and denominator by 5, and we convert 8/20 to 8/20 (it is already in terms of 20). Now we have:
5/20 + 8/20 = (5 + 8)/20 = 13/20
Therefore, 1/4 + 8/20 = 13/20.
9) To add these fractions, we need to find a common denominator first. The smallest number that both 7 and 9 divide into is 63. So, we convert 4/7 to 24/63 by multiplying both the numerator and denominator by 3, and we convert 2/9 to 14/63 by multiplying both the numerator and denominator by 7. Now we have:
24/63 + 14/63 = (24 + 14)/63 = 38/63
Therefore, 4/7 + 2/9 = 38/63.
10) To add these fractions, we need to find a common denominator first. The smallest number that both 10 and 30 divide into is 30. So, we convert 6/7 to 18/30 by multiplying both the numerator and denominator by 3, and we convert 2/30 to 1/15 by multiplying both the numerator and denominator by 15. Now we have:
18/30 + 1/15 = (18x1 + 1x2)/(30x2) = 37/30
Therefore, 6/7 + 2/21 = 37/30.
HURRY PLEASE IF YOU CAN PLEASE EXPLAIN WHY
Answer:
B) Unique
Step-by-step explanation:
J coordinates = (0,6)
K coordinates = ( 9, -9)
L coordinates = ( -9, -9)
Unique rule: 1/3x , 1/3y
Which means 1\3 times the x coordinate and 1/3 times the y coordinate
J,K,L after applying the unique rule equals
J= (0,2)
K= (3,-3)
L= (-3,-3)
Which lines up with J’ and K’ and L’.
Making the “unique” statement true, dilation= (1/3x, 1/3y)
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2.1.2. What is the sum of handshakes that will be made by the first and second
67 is the sum of handshakes given by the first and second participants.
Let n be the total number of participants in the workshop venue.
i.e, here n= 35
For the first participant, the number of handshakes is = (n-1)
= (35-1)
= 34
The number of handshakes by the second participant is also same as that of the first participant = 34
The number of handshakes given by the first and second participants together = (first participant handshake + second participant handshake - 1)
= (34 + 34 -1)
= 68-1
= 67
Hence 67 is the sum of handshakes given by the first and second participants.
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The complete question is =
A workshop venue has 35 participants . Each participant shakes hands with each each and every other participant . How is the sum of. Handshakes that will bemade bythe first and second participant
The terminal side of angle λ intersects the unit circle at point (-0. 358, 0. 934). Based on these coordinates, what is the approximate decimal value of cot(λ)
If the terminal side of angle λ intersects the unit circle at point (-0. 358, 0. 934), the approximate decimal value of cot(λ) is -0.383.
To find the approximate decimal value of cot(λ), we first need to determine the values of x and y on the unit circle. Since the given point (-0.358, 0.934) lies on the unit circle, we can use the Pythagorean theorem to find the missing side:
x² + y² = 1
(-0.358)² + (0.934)² = 1
0.128 + 0.872 = 1
1 = 1
Therefore, we have x = -0.358 and y = 0.934. Since cot(λ) = cos(λ)/sin(λ), we can use the values of x and y to calculate the cosine and sine of λ:
cos(λ) = x = -0.358
sin(λ) = y = 0.934
Substituting these values into the formula for cot(λ), we get:
cot(λ) = cos(λ)/sin(λ) = -0.358/0.934 ≈ -0.383
Therefore, the approximate decimal value of cot(λ) is -0.383.
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Simplify the expression. 3.7 – 1.8 – 3.67 + 4.4 – 1.34 –1.29 1.29 8.63 –7.51
Answer:
2.41
Step-by-step explanation:
postive = add negative = subtract
how many paths are there from point (0,0) to (90,160) if every step increments one coordinate and leaves the other unchanged and you want the path to go through (80,70)?
There are 4.097 x [tex]10^43[/tex] paths from (0,0) to (90,160) that pass through (80,70).
To calculate the number of paths from (0,0) to (90,160) while passing through (80,70), we need to break down the problem into smaller steps.
First, we can calculate the number of paths from (0,0) to (80,70) and then
multiply that by the number of paths from (80,70) to (90,160).
To go from (0,0) to (80,70), we need to take 80 steps to the right and 70 steps up, which gives us a total of 150 steps. The order in which we take these steps doesn't matter, so we can think of it as choosing 70 steps out of 150 to be up. This can be calculated using the binomial coefficient, which gives us (150 choose 70) = 2.364 x [tex]10^43[/tex]
To go from (80,70) to (90,160), we need to take 10 steps to the right and 90 steps up, which gives us a total of 100 steps. Using the same method as above, the number of paths from (80,70) to (90,160) is (100 choose 10) = 17,310,309.
Multiplying these two values together, we get the total number of paths from (0,0) to (90,160) that pass through (80,70):
(2.364 x 10^34) x (17,310,309) = 4.097 x [tex]10^43[/tex]
Therefore, there are 4.097 x [tex]10^43[/tex] paths from (0,0) to (90,160) that pass through (80,70).
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Calculating the relative frequencies from the data given in the table. Choose all that correctly describe an association between favorite subject and grade
From the given data, the statement "A higher percentage of 8th graders than 7th graders prefer Math/Science" is correct. So, correct option is C.
To calculate the relative frequencies, we need to divide the frequency of each category by the total number of responses.
For 7th grade:
Relative frequency of English: 38/116 = 0.3276
Relative frequency of History: 36/116 = 0.3103
Relative frequency of Math/Science: 28/116 = 0.2414
Relative frequency of Other: 14/116 = 0.1207
For 8th grade:
Relative frequency of English: 47/182 = 0.2582
Relative frequency of History: 45/182 = 0.2473
Relative frequency of Math/Science: 72/182 = 0.3956
Relative frequency of Other: 18/182 = 0.0989
From the data, we can see that a higher percentage of 8th graders prefer Math/Science than 7th graders. Therefore, the statement "A higher percentage of 8th graders than 7th graders prefer Math/Science" correctly describes the association between favorite subject and grade.
The statements "A higher percentage of 8th graders than 7th graders prefer History" and "A higher percentage of 7th graders than 8th graders prefer English" are incorrect as the relative frequencies for these subjects are similar in both grades.
Overall, we can conclude that the choice of favorite subject is not strongly associated with the grade level of the students.
So, correct option is C.
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Complete question is:
Calculating the relative frequencies from the data given in the table. Choose all that correctly describe an association between favorite subject and grade.
A) A higher percentage of 8th graders than 7th graders prefer History.
B) A higher percentage of 7th graders than 8th graders prefer English.
C) A higher percentage of 8th graders than 7th graders prefer Math/Science.