what is tofu name one tofu.
Answer:
Tofu is also known as Bean Curd .Tofu is a food prepared by coagulating soya milk.
Find the total resistance ....
The Equivalent resistance is :
[tex]\qquad \tt \dashrightarrow \: \dfrac{14}{9} \: \: ohms[/tex]
The solution is in attachment for solution ~
Please help me, Thank you
Answer:
D. 2.50
Explanation:
Frequency by definition is the number of waves that pass a fixed point in the given amount of time.
An electricAn electric field E = 100,000i N/C causes the 5.0 g point charge to hang at a 20°
angle. What is the charge on the ball?
E= 100,000i N/C
to find:the charge on the ball
solution:Using force balance on mass in vertical direction
T= tension in rope
in x-direction
Fx= T*sin A= q*E
in y-direction
Fy = T*cos A = m*g
divide both equation
tan A = q*E/(m*g)
q = (m*g*tan A)/E
Using given values:
q (5.0*10^-3*9.81*tan 20 deg)/100000
q=1.78*10^-7
therefore, the charge on the ball is 1.78*10^-7
A rock is under water in a shallow lake. As the rock sinks deeper and deeper into water, the buoyant force on it:___________
Answer:
It remains constant
Explanation:
Thats the way it works
You are pushing an 80.0 N wheelbarrow as shown in (Figure 1). You lift upward on the handle of the wheelbarrow so that the only point of contact between the wheelbarrow and the ground is at the front wheel. Assume the distances are as shown in the figure, where 0.50 m is the horizontal distance from the center of the wheel to the center of gravity of the wheelbarrow. The center of gravity of the dirt in the wheelbarrow is assumed to also be a horizontal distance of 0.50 m from the center of the wheel. Suppose that the maximum total upward force that you can apply to the wheelbarrow handles is 75 lb.
Answer:
Wl = 1740 N
Explanation:
maximum lift weight unaided = force exerted (F) = 650 N
length of the wheelbarrow (L) = 1.4 m
weight of the wheelbarrow (w) = 80 N
distance of center of gravity of the wheel barrow from the wheel = 0.5 m
distance of center of gravity of the load from the wheel = 0.5 m
find the weight of the load (Wl)
from the diagram attached we can see that there is going to be a rotation about the axis A. let clockwise rotation be positive
ΣT = (F x 1.4) - ((Wl x 0.5) + (w x 0.5) = 0
(F x 1.4) = ((Wl x 0.5) + (w x 0.5)
Wl =
Wl =
Wl = 1740 N
Temperate marine climates are normally:
a.hot
c. cold
b. cool to warm
d. warm to hot
Answer:
Temperate marine climates are humid and have mild winters. There are three kinds of temperate marine climates: marine west coast, humid subtropical, and mediterranean. Marine west coast climates are the coolest temperate marine climates. Humid ocean air brings cool, rainy summers and mild, rainy winters.
Why is it important to observe the necessary precautions in dancing??
Answer:
To Avoid accidents and injuries
Explanation:
Safety measures are vital dancing as this may prevent bad things like accidents and injuries from happening.
When dancing,the safety of dancers is a must to be observed and considered.
Dancers are also most likely to exert their full potential if they know that they are safe no matter what happen....
HAVE A GOOD DAY....
WILL MARK BRAINLIEST FOR CORRECT ANSWERS
A rocket will accelerate...
Answer:
True
False
False
Explanation:
The first answer is inferred from Newton's third law of motion. As the rocket burns fuel and ejects the products downwards, a thrust is created, which acts downwards; pushing the rocket upwards.
The second answer is gotten from the same law. Pushing against the atmosphere (action) will create a reaction (this reaction is from the atmosphere; action and reaction are equal and opposite) which acts downwards. Hence the rocket doesn't move up.
Third. When the rocket is in space (vacuum), it moves at a uniform velocity since no force acts on it. This is gotten from Newton first law of motion. Here, the rocket moves into the orbit, fuelled by the force of it's thrust (when it was on the ground).
Which standing wave has exactly three antinodes?
A.
B.
C.
D.
Answer:
Explanation:
C looks good, b/c antinodes are where the waves is at a max displament.
The wave has exactly three antinodes is option C.
What number of antinodes are in 3 status waves?
As in all status wave styles, each node is separated through an antinode. This sample with 3 nodes and two antinodes is known as the second one harmonic and is depicted within the animation.
Where are the antinodes?The other of a node is an anti-node, a factor where the amplitude of the status wave is at most. those occur midway among the nodes. In a full wavelength of a status wave, there are two loops. So, there should be nodes midway of every of the two loops.
What's a wave in technology?Wave, propagation of disturbances from location to vicinity in a ordinary and prepared manner. maximum acquainted are floor waves that journey on water, however sound, mild, and the movement of subatomic particles all exhibit wavelike residences.
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According to the HR diagram below, blue giants are in what temperature range?
A. 2,500 k - 5,000 k
B. 5,000 k - 10,000 k
C. 10,000 k - 20,000 k
D. 20,000 k - 40,000 k
Answer:
20 000 - 40 000 K from the graph
Explanation:
Look straight down from blue giants and read the temps
what are the equivalent celsius and kelvin temperatures of -128 f?
Answer:
128 Kelvin = 128 - 273.15 = -145.15 Celsius. Temperature conversion chart Sample temperature conversions 103.55 Kelvin to degrees Fahrenheit 39.82 degrees Fahrenheit to Kelvin
Explanation:
hope this helps have a good day
How does microwave technology cook food?
Question 4 options:
By heating all the water molecules which changes the thermal energy of the food
By heating surface water or fat molecules only, and the remaining food is cooked by conduction.
Microwaves cannot cook food.
By heating the internal water molecules, the food cooks from the inside out.
Answer:
By heating all the water molecules which changes the thermal energy of the food
Explanation:
Answer ASAP and only if you know its correct
this is science btw also, brainliest to the correct answer
Answer:
scientists see emission spectra 'shifted' towards the red end of the electromagnetic spectrum—
Explanation:
hoped this helped
the doppler effect shows stars with red shifted light
Age, height, and weight are examples of numerical data.
A 3m plank AB of mass 20kg has a center of gravity 2m from end A and rests on supports R1 and R2 both 0,5m from either end. It also carries a 10kg block at end A. Calculate the reactions at R1 and R2
Answer:
130.7 N
Explanation:
The radius of the aorta is about 1.4cm , and the blood passing through it has a speed of about 40cm/s .
Calculate the average speed of blood flow in the major arteries of the body, which have a total cross-sectional area of about 2.1cm2 .
Express your answer to two significant figures and include the appropriate units.
For the average speed of blood flow in the major arteries of the body is mathematically given as
v2 = 117.29m/s
What is the average speed of blood flow in the major arteries of the body?Generally, the equation for the average speed is mathematically given as
A1 v1 = A2 v2
(pi r1^2) v1 = A2 v2
(3.14x(1.4)^2 )x 40 = (2.1) xV2
v2 = 117.29m/s
In conclusion, the average speed of blood flow
v2 = 117.29m/s
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By 2005, the world's tallest building will be the International Finance Center in Taipei,
Republic of China. Suppose a 1.00 C charge is placed at both the base and the top of the
International Finance Center. If the magnitude of the electric force stretching the building
is 4.48 x 104N, how tall is the International Finance Center?
Electric field refers to the region in space where the influence of a charge is felt, the height of the building is 447 m.
What is electric field?
The term electric field refers to the region in space where the influence of a charge is felt.
Since we know that;
E = F/q = 4.48 x 104N/1C = 4.48 x 10^4 N/C
E = Kq/r^2
4.48 x 10^4 = 9 * 10^9 * 1/r^2
r = √9 * 10^9/4.48 x 10^4
r = √2 * 10^5
r = 447 m
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If two runners are running in a 500 meter dash and runner #1 finishes in 25 seconds and runner #2 finishes in 27 seconds. What are the speeds of both runners? Which one is faster
For two runners running in a 500 meter dash and runner, the speeds of both runners is mathematically given as
v1=25m/s
v2=20m/s
and the first runner is faster
What are the speeds of both runners?Generally, the equation for the speed is mathematically given as
v=d/t
Therefore, for first runner
v=500/20
v1=25m/s
For 2nd runner
v=500/25
v2=20m/s
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What are some uses of thermal energy in everyday life?
Choose all that apply.
moving objects
cooking food
heating water
making light bulbs work
Answer:
b) cooking food
c) heating water
Explanation:
cooking and heating use thermal energy to transfer heat from the source to another object, in the examples provided; the food and the water. on the other hand, moving objects uses kinetic energy and lightbulbs utilize electrical energy.
Answer:
cooking food
heating water
i think making a light bulb work
Explanation:
A p.d. of 6 V is applied across a 2 resistor. What current flows?
Answer: current is 3 A.
Explanation:
V = 6V
R = 2Ω
I = ?
∴ V = IR
I = V/R
I = 6V/2Ω
I = 6/2
I = 3 A ...answer...
hope that helps...
Answer:
3 amps
Explanation:
V = IR
V/R = I
6/2 = 3 amps
Bob creates an instrument that is able to play C4 (261.63 Hz). He does some analysis with the sound equipment and it shows that when he plays it, he also gets the frequencies 523.26 Hz, 784.89 Hz, and 1308.15 Hz. What could be true about the instrument? It’s a stringed instrument, it’s a closed pipe, or it’s an open pipe?
Answer:
It could be a stringed instrument or an open pipe.
Explanation:
Let v be the speed of sound, y be wavelength and f be frequency.
v = yf
f= v/y; v is constant.
In a stringed instrument, the fundamental frequency note is heard when the length of the string, l = y/2; y= 2l
f′= v/2l
The second harmonic is heard when l= y
f"= v/y
...
f'''= 3v/2l
We can infer that f"= 2f'
f'''= 3f'
This is similar to the values in the question as;
523.26 =2(261.63) and so on.
Same thing happens with open pipes.
cart a having a mass of 150 kg initially moving to the right at a speed of 8 m/s collides with cart b with a mass of 150 kg, initially moving to the right at 6 m/s after a collision cart a continues to move to the right but with a speed of 5 m/s
a. what is the speed of cart b after collision
b. what is the total momentum of the system before and after collision
The speed of cart b is 6m/s while the total momentum of the systmen is 4200 kg m/s
Conservation of Linear MomentumGiven Data
Mass of cart one M1 = 150kgInitial Velocity U1 = 8m/sFinal VelocityV1 = 5 m/sMass of cart two M2 = 150kg
Velocity U2 = 6m/s
Applying the principle of conservation of linear momentum we have
M1U1+M2U2 = M1V1+ M2V2
a. what is the speed of cart b after collision
substituting our given data we have
150*8+ 150*6 = 150*5+150*V2
1200 + 900 = 1200+ 150V2
2100 - 1200 = 150V2
900 = 150V2
Divide both sides by 150
V2 = 900/150
V2 = 6m/s
b. what is the total momentum of the system before and after collision
Total Momentum in the system is
Total momentum = Momentum before Impact+ Momentum after Impact
Total momentum = M1U1+M2U2 + M1V1+ M2V2
Total momentum = 1200 + 900 + 1200+ 900
Total momentum = 4200 kg m/s
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Refer to the image shown to answer the question.
If a light ray strikes the shiny surface at 70 degrees, what is the measurement of the reflected ray?
170 degrees
110 degrees
70 degrees
10 degrees
Answer:
the reflected ray will be 110 degree
When scientists look at very distant galaxies through powerful telescopes, they see the galaxies as they were millions or billions of year ago. Why is this?
Answer:
speed of light
Explanation:
the sun's light is 8 mins behind imaging that a billion fold
what is acceleration due to gravity?
the speed at which the gravity pulls a freely falling object is known as it's acceleration due to gravity, it is represented by the letter (g)
the acceleration due to gravity on Earth is 9.8m/s²
HELP PLEASE
a person standing on the roof of a building throws a rubber ball down with a velocity of 8m/s
what is the acceleration(magnitude and direction) of the ball? does the ball slow down while falling? after 0.25 seconds how far has the ball fallen?
Answer:
2.30625m
Explanation:
The acceleration of the ball is the acceleration of gravity g.
By definition
g = constant = + 9.8 m?s^2 and is directed towards the centre of the earth
The ball does not slow down while falling
The position function is:
P(t) = 1/2 a t^2 + Vo t
In this specific case: P(t) = 4.9 t^2 + 8t
P(0.25s) = 4.9 (0.25)^2 + 8*0.25 = 2.30625m
Which of the following was NOT one of Ghana's chief trading exports?
A. Gold
B. Ivory
C. Horses
Changing the thickness of the myelin sheath surrounding an axon changes its capacitance and thus the conduction speed. A myelinated nerve fiber has a conduction speed of 53 m/s . If the spacing between nodes is 1.0 mm and the resistance of segments between nodes is 26 MΩ , what is the capacitance of each segment?
For a myelinated nerve fiber has a conduction speed of 53 m/s, the capacitance of each segment is mathematically given as
C=8.2*10^{-13}F
What is the capacitance of each segment?Generally, the equation for the Constant is mathematically given as
t=RC
Therefore
t=V/d
Hence
C=V/Rd
C=1.2*1)^-3/26*10^6*56
C=8.2*10^{-13}
In conclusion, the capacitance
C=8.2*10^{-13}F
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55. A projectile of mass 2.0 kg is fired in the air at an angle of 40.0° to the horizon at a speed of 50.0 m/s. At
the highest point in its flight, the projectile breaks into three parts of mass 1.0 kg, 0.7 kg, and 0.3 kg. The 1.0-
kg part falls straight down after breakup with an initial speed of 10.0 m/s, the 0.7-kg part moves in the original
forward direction, and the 0.3-kg part goes straight up.
At peak after explosion
V3,f = (V3,1))
At peak before explosion
V₁
=
(V₁.x)x
m3 = 0.3 kg
m₂ = 0.7 kg
V2,1 = (v₂,1)
m₁ = 1.0 kg
V₁ = (50.0 m/s)v₁
₁,f= -(10.0 m/s)
40°
Launch
a. Find the speeds of the 0.3-kg and 0.7-kg pieces immediately after the break-up.
b. How high from the break-up point does the 0.3-kg piece go before coming to rest?
c. Where does the 0.7-kg piece land relative to where it was fired from?
The total moment in an islated system remains constant through time. a) V₂ = 109.43 m/s and V₃ = 33.33 m/s. b) h = 56.67 m. c) d = 480 m.
What is the law of conservation of momentum?First let us remember that momentum or lineal momentum is a motion quantity. In physics it is the fundamental quantity that characterizes the motion of any object.
The momentum is a vectorial quantity that can be calculated as the product of the object mass by its lineal velocity ⇒ mv
The total lineal moment of a system constituted by a group of objects is the sum of the vectorial moments of each of the objects.
In an isolated system -the one that does not interact with the exterior environment-, the moment remains constant through time. This is the law of conservation of momentum. The initial moment is equal to the final moment ⇒ Pinitial = Pfinal
Objects involved in crushes, explosions, collitions, and others, are considered to be isolated systems.
.......................
So, in the exposed example we know that,
Projectile mass ⇒2kg.Velocity = 50 m/s.Angle⇒ 40°.Smaller masses ⇒ 1 kg with 10m/s speed, 0.7 kg, and 0.3 kg.a) We need to calculate the speed of the 0.7 and 0.3 kg objects.
So, 0.7 kg object moves in the original forward direction, meaning that we can use the following formula to calculate its velocity,
m₀v₀ = m₂v₂
Where
m₀ = projectile mass = 2kgv₀ = horizontal component of projectile velocitym₂ = object mass = 0.7 kgv₂ = object velocity = ??So first, we need to get the horizontal component of projectile velocity, V₀.
V₀ = V cosθ
V₀ = 50 cos40º
V₀ = 38.3 m/s
Now we can calculate the velocity of the 0.7 kg object.
m₀v₀ = m₂v₂
2 kg x 38.3 m/s = 0.7 kg x v₂
v₂ = (2 x 38.3) / 0.7
v₂ = 109.43 m/s
Now we need to calculate the velocity of the 0.3 kg object. Since this part goes exactly in the opposite direction of the 10 kg object, their addition will equal zero. So we can use the following equation to calculate the velocity of the 0.3 kg object.
m₁v₁ + m₃v₃ = 0
Where
m₁ = 1 kg object mass v₁ = 1 kg object velocity = 10m/sm₃ = 0.3 kg object mass v₃ = object velocity = ??m₁v₁ + m₃v₃ = 0
(1 kg x 10m/s) + (0.3 kg x v₃ ) = 0
(0.3 kg x v₃ ) = - (1 kg x 10m/s)
v₃ = - (1 kg x 10m/s) / 0.3
v₃ = - 33.33 m/s
The - sign is indicating the opposite direction concerning the 1 kg object.
ANSWER:
The speed of the 0.7 kg object is 109.43 m/sThe speed of the 0.3 kg objects is 33.33 m/s.........................
b) We need to get the high from the break-up point where the 0.3-kg piece go before rest
At rest,
1/2 m₃v₃² = m₃gh
Where,
m₃ = 0.3 kg object mass v₃ = object velocity = 33.33m/sg = gravity = 9.8 m/s²h = high = ??1/2 m₃v₃² = m₃gh
h = 1/2 (v₃²) /g
h = 1/2 (33.33²) / 9.8
h = 56.67 m
ANSWER: The high from the break-up point where the 0.3-kg piece go before coming to rest is 56.67 m.
........................
c) Finally, we need to get where does the 0.7-kg piece land
ANSWER: The distance at which the 0.7 piece lands, concerning the point from which it was fired is 480 m.
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