find an equation for the line passing through (4, 1) and perpendicular to the line 2y+4=6x

Answers

Answer 1

Answer:

y = 3x - 11

Step-by-step explanation:

2y+4=6x

2y = 6x - 4

y = 3x - 2

y = 3x + b

1 = 3(4) + b

1 = 12 + b

-11 = b


Related Questions

A wall is 1200 sq ft.
A gallon of paint covers 200 sq ft.
Complete the conversion factor: 1 gallon / ? sq ft

Answers

200 because a gallon of paint covers 200 square feet

100 yojan=how much km?​

Answers

Answer:

100 yojan=how much km

1287.48

please brainlist

what is the zero turn for the arithmetic sequence 128,96,64,32

Answers

You are falling by [tex]32[/tex],

[tex]128, 128 - 32, 128 - 32\cdot2,\dots[/tex]

In general your sequence is defined as,

[tex]a_n=128-32\cdot n[/tex] where [tex]0\leq n \lt\infty[/tex].

The question is at which [tex]n[/tex] does the value [tex]a_n=0[/tex].

If you divide [tex]128[/tex] with [tex]32[/tex] you get the number of steps needed to stuff [tex]128[/tex] with [tex]32[/tex], [tex]4[/tex].

If you plug in [tex]n=4[/tex], you get [tex]a_4=128-32\cdot4[/tex], since [tex]32\cdot4=128[/tex] you get [tex]a_4=0[/tex].

The zero turn of the arithmetic sequence is thus at [tex]n=4[/tex].

Hope this helps :)

Which of the following is NOT true about the hypotenuse of a triangle?
A. It is across from the right angle
B. It is always greater than 1
C. IT is always across from the largest angle in the triangle
D. It is the longest side

Answers

Depending on the length of the two sides of the triangle the length could be smaller than 1.

The answer that is not true is :

B. It is always greater than 1

Let A={1,2,3,4,5,6,7,8}A={1,2,3,4,5,6,7,8}. Define a relation ∼∼ on AA by a∼ba∼b if and only if 33 divides a−ba−b for all a,b∈Aa,b∈A.  1. Find all the pairs (a,b)∈A×A(a,b)∈A×A such that a∼ba∼b. 2. Show that ∼∼ is an equivalence relation on AA. 3.  Find the equivalence classes [2][2] and [3][3].​

Answers

Define relation.

Let A and B are only two non-empty set,then A*B is cartesian product of A*B.Then any subset of A*B is known as the relation fromA to B.

write as an expression :the quantity 10 less than x, divided by 4​

Answers

Answer:

(x-10)/4

Step-by-step explanation:

10 less than x means,

x - 10

and the divide by 4.

=> (x-10)/4

Answer:

x-10/4

10 less than x

x-10

divided by 4

/4

write a clear instructions explaining how to perform the following calculation (125+47-2.5)÷140+37×249​

Answers

Answer:

It is 9214.2

Step-by-step explanation:

[tex](125 + 47 - 2.5) \div 140 + 37 \times 249[/tex]

first solve the bracket:

[tex] = (169.5) \div 140 + 37 \times 249[/tex]

form brackets of division and multiplication:

[tex] = (169.5 \div 140) + (37 \times 249)[/tex]

solve the brackets:

[tex] = 1.211 + 9213[/tex]

then add:

[tex] = 9214.211[/tex]

Anton joined a golf club. He pays an annual membership fee of $895 and greens fee of $30 each time he plays golf. Last year he paid $2,065 as a total golfing fee. How many games did he play? Write and solve the equation.

Answers

So last year Anton paid $2,065 as a total golfing fee, that’s one year. Anton pays an annual membership fee of $895, that means he pays $895 each year for membership fee.
So subtract $895 from $2,065, you get $1,170 left.
Now every time Anton plays golf, he pays $30 for greens fee, he will be spending $30 each time he play.
So we would use division here, $1,170 divided by $30, you get 39.
Anton played 39 games last year.

what values of x satisfy the equation 2x^2 -3x +4 =0

Answers

Answer:

(3 ± √23 * i) /4

Step-by-step explanation:

To solve this, we can apply the Quadratic Equation.

In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)

Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4

Plugging these values into our equation, we get

x = (-b ± √(b²-4ac))/(2a)

x = (-(-3) ± √(3²-4(2)(4)))/(2(2))

= (3 ± √(9-32))/4

= (3 ± √(-23))/4

= (3 ± √23 * i) /4

6. The unit circle with center at the origin is a relation but not a function.
Find the two functions which are semicircles of the unit circle, and determin
e
their domains and ranges?
b. Are these functions onto functions? Justify.
c. Find the two functions which are lie in one of the semicircle in part a, and
determine their domains and ranges?
d. Are these functions one to one correspondence functions? Justify.
Whi​

Answers

Answer:

Step-by-step explanation:

given the equation 4x + 3y = 18. find the value of y when x = −3

Answers

9514 1404 393

Answer:

  y = 10

Step-by-step explanation:

Put -3 where x is and solve for y.

  4(-3) +3y = 18

  -4 +y = 6 . . . . . . . divide by 3

  y = 10 . . . . . . . . . add 4

Kristen is creating a rectangular garden in her back yard. The length of the garden is 13 feet. The perimeter of the garden must be at least 54 feet and no more than 82 feet.

Answers

So what’s the question?

A mountain is 15,062 feet above sea level, and a valley is 350 feet below sea level, what is the difference in elevation between the mountain and the valley?

Answers

Answer:

14,712 ft difference

Step-by-step explanation:

15,062 - 350 = 14,712

Answer:

Step-by-step explanation:

Difference in elevation is 15,062-(-350)=15,062+350=15,412

8 thousands + 4 thousands
What is the answer in standard form?

Answers

Answer:

12000

Step-by-step explanation:

8000+4000=12000

8000
4000

8,000+4,000= 12,000

Answer this question.

Answers

Answer:

B) Both functions have a y-intercept of -2.

Step-by-step explanation:

Hi there!

A) Both functions are always increasing.

⇒ False

Let's first take a look at the given equation, [tex]y=3x-2[/tex]. This is a linear equation, and it is organized in slope-intercept form: [tex]y=mx+b[/tex]. m is the slope and b is the y-intercept. When m is positive, it is always increasing.

In [tex]y=3x-2[/tex], 3 is m, and because it's positive, this line is always increasing on a graph.

However, when we take a look at the given graph, this isn't the case. It is decreasing for values of x below 0 (on the left side of the y-axis).

B) Both functions have a y-intercept of -2.

⇒ True

In the given equation [tex]y=3x-2[/tex], this is true. -2 is the y-intercept.

On the given graph, we can see that the graph intercepts the y-axis at -2, so this is also true for the graph.

C) Both functions are symmetric about the y-axis.

⇒ False

The given graph is symmetric about the y-axis, but the line is not. Any line that would be symmetric about the y-axis would be in the form [tex]y=b[/tex], which isn't the case here with [tex]y=3x-2[/tex]. [tex]y=3x-2[/tex] has a slope.

D) Both functions are linear relationships.

⇒ False

Sure, [tex]y=3x-2[/tex] is a linear equation, making it a line, but not the given graph. The graph does not resemble a straight line, so it is not a linear relationship.

I hope this helps!

4 2/3 - (1 4/5). PLEASE HELP MEEEEE

Answers

Answer: 2 13/ 15

Step-by-step explanation:

2. STEM A circuit board manufacturer rejects a 100-ohm resistor if its measured resistance is 0.15 ohm more than or less than 100 ohms. Resistors A and B are rejected. Resistor A's resistance differs from 100 ohms by 0.15 ohm. Resistor B's resistance differs from 100 ohms by -0.78 ohm. How do the resistances of these two resistors compare? Explain.​

Answers

The comparison of both resistors is defined by an inequality. Resistor A has a higher resistance than resistor B because [tex]100.15\Omega > 99.22\Omega[/tex]

Given that:

[tex]R = 100 \Omega[/tex] ---- the reference resistor

First, we calculate the resistance of both resistors

Resistor A differs by [tex]0.15\Omega[/tex] means that:

[tex]R_A = 100\Omega + 0.15\Omega[/tex]

[tex]R_A = 100.15\Omega[/tex]

Resistor A has a resistance of [tex]100.15\Omega[/tex]

Resistor B differs by [tex]-0.78\Omega[/tex] means that:

[tex]R_B = 100\Omega -0.78\Omega[/tex]

[tex]R_B = 99.22\Omega[/tex]

Resistor B has a resistance of [tex]99.22\Omega[/tex]

By comparing the calculated values, we can conclude that:

Resistor A has a higher resistance than resistor B because [tex]100.15\Omega > 99.22\Omega[/tex]

Read more about inequality comparison at:

https://brainly.com/question/11772136

If AB is parallel to DE, then CD is:

Answers

Answer:

4

Step-by-step explanation:

because BC=CD as it is parallel that means all the sides are equal

The value of CD is 20/3.

The correct option is (A).

What is Similarity in Triangles?

Similar triangles are triangles that have the same shape, but their sizes may vary. All equilateral triangles, squares of any side lengths are examples of similar objects. In other words, if two triangles are similar, then their corresponding angles are congruent and corresponding sides are in equal proportion.

In ACB and ECD,

angle CAB= angle DEC

angle CBA= angle EDC

angle DCE = angle ACB

By, AA similarity criteria,

ΔACB~ΔECD

Now,

AC/CE= BC/CD

3/5=4/CD

CD= 20/3

Learn more about similarity property here:

https://brainly.com/question/25882965

#SPJ2

please help!!! what is the interquartile range?

Answers

The interquartile range is 10.The lowest quartile is 20.The highest one is 30.30-20 is equal to 10.

On the first day of December, 34,789 people went to the mall. On the second day 63,587 people went to the mall. How many people went to the mall over the two days

Answers

Answer:

98376

Step-by-step explanation:

PLEASE HELP ASAP! FAST! Thank you xoxo

Answers

Answers and Step-by-step explanation:

Question 8:

Since angle BCD is opposite angle DAB, this means that they are similar angles as the shape is a parallelogram, and so BCD is 115 degrees, or answer D

Question 3:

We can use process of elimination on this question - The first choice is all squares are rhombuses, which is true. The second question is all rectangles are squares, which is not true, therefore the answer is B

Question 4:

m angle 2 is equal to 106, as it is similar to question 8, and angle 3 is equal to 360 (the total degrees of the shape) - 106 - 106, then divided by 2 and divided by 2 again.

This will equal to angle 3 being 37 degrees, and the answer will be C

Question 5:

We can draw a rectangle from this graph. We can also tell that, in theory, the diagonals are the same, that rules out answer B, and also 5x-5 = x+11

We can then find out x.

+5 on both sides

5x = x+16

-x on both sides

4x = 16

x = 4.

Therefore, each of the sides will be 4+11 = 15, and the answer being C

I need help, NO LINKS

Answers

If you distribute each side of the equation, you’d get 12g+18 = 12g+18
This statement is always true, no matter what you put in place of g.
That means any and every real number will be a solution.
Therefore there are infinitely many solutions.

If the equation had worked out to be 12g+18 = 12g+7 or something else where the variable terms were identical, but the numbers weren’t, then there’d be no solution, since there’s no way to make 18=7.

Help please! thank you xoxo!
2 math problems

Answers

3. x = 45

4. 73°

Step-by-step explanation:

3. The sum of the interior angles of a pentagon is 540° so

90° + 112° + 2x + (2x + 10) + 148° = 540°

Simplifying this, we get

4x + 360 = 540 => 4x = 180 or x = 45

4. The sum of the interior angles of a pentagon is 540° which means that the unknown interior angle is 107°. This angle is a supplementary angle to [tex]\angle{A}[/tex] so [tex]\angle{A}[/tex] is

180° - 107° = 73°.

Show that 5x^2 + 2x - 3 < 0 can be written in the form | x + 1/5 | < 4/5

if possible with the explanation as well ​

Answers

Step-by-step explanation:

First let solve the inequality

[tex]5 {x}^{2} + 2x - 3 < 0[/tex]

Factor by grouping

[tex]5 {x}^{2} + 5x - 3x - 3 < 0[/tex]

[tex]5x(x + 1) - 3(x + 1)[/tex]

So the factor are

[tex](5x - 3)(x + 1)[/tex]

So the factor are

[tex]x = \frac{3}{5} [/tex]

and

[tex]x = - 1[/tex]

Solutions to a quadratic can be represented by a absolute value equation because remeber quadratics

creates 2 roots and/or double roots.

The inequality

[tex] |x - b| < c[/tex]

works as

b is the midpoint between 2 roots. And c is the

[tex] |x + b| = c[/tex]

We know that the midpoint between both roots is-1/5.

so

[tex] |x - ( - \frac{1}{5} )| < c[/tex]

[tex] |x + \frac{1}{5} | < c[/tex]

Let use roots 3/5

[tex] | \frac{3}{5} + \frac{1}{5} | = \frac{4}{5} [/tex]

-1 works as well.

[tex] | - 1 + \frac{1}{5} | = | - \frac{4}{5} | = \frac{4}{5} [/tex]

So the absolute value equation is

[tex] |x + \frac{1}{5} | < \frac{4}{5} [/tex]

Use the order of operations to evaluate the expression below.
3 + 5 x 5 - 50 ÷ 2 + 3 - 4

Answer here

Answers

Answer:

2

Step-by-step explanation:

=3+5×5-25+3-4

=3+25-25+3-4

=28-22-4

=28-26

=2

Answer:

2

Step-by-step explanation:

3 + 5 * 5 - 50 / 2 + 3 - 4

3 + (5 * 5) - 50 / 2 + 3 - 4  => Multiplication what ever comes first

3 + 25     (-50 / 2) + 3 - 4  => Division left to right

(3 + 25)     - 25  +( 3 - 4)  => Addition what ever comes first

28  - 25 - 1 => Substraction  left to right

2

Leave comment if you're curious.

HELP!! TRUTH TABLE

I would really appreciate it, if someone could walk me through how they did it! Thanks.

Answers

pq (i.e. "p and q") is true only if both p and q are true. This is the case for the first two rows, but not the third.

Similarly, (pq) ∧ r is true only if both pq and r are true. We know when pq is true, so (pq) ∧ r is true only when all three of p, q, and r are true. This happens only in the first row.

All other cases are false.

The table should look like this:

[tex]\begin{array}{c|c|c|c|c}p&q&r&p\land q&(p\land q)\land r) \\---&---&---&---&--- \\T&T&T&\boxed T&\boxed T\\&&&&\\T&T&F&\boxed T&\boxed F\\&&&&\\T&F&T&\boxed F&\boxed F\end{array}[/tex]

Rewrite as a product of the GCF and another sum 36 + 48

Answers

Answer:

72+12

Step-by-step explanation:





What is the value of the digit 6 in 873,261?
What is the value of the digit 6 in 137,2617?

Answers

Answer:

Step-by-step explanation:

60  

600

please help will bark brainliest

Answers

Answer:

A.

Step-by-step explanation:

Find a quadratic function that includes the set of values below.
(0,7), (2,17), (3,16)
The equation of the parabola is

Answers

Answer:

f(x) = -3x^2 + 10x + 3

Step-by-step explanation:

(0,3) (2,11)(3,6)

Using the form ax^2 + bx + c = y

From the first set we know that c = 3

Write an equation for the last two sets

x=2; y=11

a(2^2) + b(2) + 3 = 11

4a + 2b = 11 - 3

4a + 2b = 8

simplify divide by 2

2a + b = 4

and

x=3, y=6

9a + 3b + 3 = 6

9a + 3b = 6 - 3

9a + 3b = 3

simplify divide by 3

3a + b = 1

:

Use elimination to find a

3a + b = 1

2a + b = 4

--------------subtracting eliminate b

a = -3

Find b using the equation 2a + b = 4

2(-3) + b = 4

b = 4 + 6

b = 10

:

The equation: f(x) = -3x^2 + 10x + 3

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