Kai bought 5 bags. In each bag there is bottle of Gatorade that cost 3$ and two pacIs of gum. If Kai spent 55$ all together how much did each pack of gum cost?

The plant's height at 12 months would be 38 inches.

Assuming the plant's height follows a linear pattern, Robin can use the equation y = mx + b, where y is the height of the plant, x is the number of months, m is the slope or rate of growth, and b is the y-intercept or initial height.

To find the equation, Robin can use the data from the three months:

Using these data points, Robin can calculate the slope m:

m = (11-5)/(3-1) = 3 inches/month

Then, using the point-slope form of the equation, Robin can find the y-intercept b:

y - 5 = 3(x - 1)

y = 3x + 2

Therefore, the algebraic expression to find the plant's height for any month x is y = 3x + 2.

To find the plant's height at 12 months, Robin can substitute x = 12 into the equation:

y = 3(12) + 2 = 38 inches

So the plant's height at 12 months would be 38 inches.

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The student did not solve the problem correctly. The student only discovered one of two solutions and made the mistake of presuming that the absolute value of -3 was the other solution without investigating the second situation.

When solving absolute value equations, we have to consider both cases:

|2-9x| = 29 can be rewritten as

2-9x = 29 or 2-9x = -29

Solving the first equation as the student did:

2-9x = 29

Subtracting 2 from both sides:

-9x = 27

Dividing both sides by -9:

x = -3

This is one solution, but we also need to solve the second equation:

2-9x = -29

Subtracting 2 from both sides:

-9x = -31

Dividing both sides by -9:

x = 31/9

So the two solutions are x = -3 and x = 31/9.

Taking the absolute value of -3 gives us 3, which is one of the solutions the student found. However, the other solution is x = 31/9, not |-3|.

Therefore, the student only found one of the two solutions and made an error in assuming that the absolute value of -3 was the other solution without considering the second case.

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Kaden will earn $729.38 in interest in 30 months.

First, we need to calculate the annual interest rate equivalent to 2.5% for 1 year:

[tex]1 + r = (1 + 0.025)^1[/tex]

1 + r = 1.025

r = 0.025

So, Kaden's account earns 0.025 or 2.5% interest per year.

Next, we can calculate the amount of interest Kaden will earn in 30 months, which is 2.5 years:

n = 2.5 (number of years)

P = $5,000 (principal)

r = 0.025 (annual interest rate)

We can use the compound interest formula to calculate the final amount A:

[tex]A = P(1 + r)^n[/tex]

[tex]A = 5000(1 + 0.025)^2^.^5[/tex]

A = $5,729.38

The interest earned is the difference between the final amount and the principal:

Interest = A - P

Interest = $5,729.38 - $5,000

Interest = $729.38

Therefore, Kaden will earn $729.38 in interest in 30 months.

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The two points of intersection are (0, θ) and (0.247, θ).

The area enclosed in the intersection of the two graphs is 7π/2 square units.

To find the points of intersection of the curves:

We need to solve for θ when t = 6 cos(θ) = r/3.

We can substitute r = 2 sin(θ) into this equation to get:

6 cos(θ) = 2 sin(θ)/3
18 cos(θ) = 2 sin(θ)
9 cos(θ) = sin(θ)

Squaring both sides and using the identity sin^2(θ) + cos^2(θ) = 1, we get:

81 cos^2(θ) = 1 - cos^2(θ)
82 cos^2(θ) = 1
cos(θ) = ±sqrt(1/82)

Since we know that the curves intersect at the pole (r = 0), we only need to consider the positive root of cos(θ) to find the other point of intersection.

We can use the equation r = 2 sin(θ) to find the value of r:

r = 2 sin(θ) = 2 cos(θ) sqrt(1 - cos^2(θ)) = 2 sqrt(1/82) ≈ 0.247

So the two points of intersection are (0, θ) and (0.247, θ) where cos(θ) = sqrt(1/82) and θ is measured in radians.

To find the area enclosed in the intersection of the two graphs:

We can use the formula for the area of a polar region:

A = 1/2 ∫(r²) dθ

Since we know that the curves intersect at the pole and at (0.247, θ), we can split the integral into two parts:

A = 1/2 ∫(0 to π/2)(2 sin(θ))² dθ + 1/2 ∫(π/2 to π)(6 cos(θ))² dθ
A = π/4 + 27π/4
A = 7π/2

So the area enclosed in the intersection of the two graphs is 7π/2 square units.

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Answer:

The answer would be D.

(3,-5) is the original image.
To find your X, use the x from the first image and fill in the x which would be (3-1) which gives you (2,y)

to find Y, use the y from the first image and fill it it which is ( (-5) - 3 ) which gives you (x,-8)

therefore the full answer would be D. (2,-8)

Step-by-step explanation:

The distance from the gazebo to the dock is approximately 120.45 meters.

The given problem can be solved using the concept of trigonometry.

let the distance from the gazebo to the dock be "d".

According to the question it is known that the bearing from the gazebo to the dock is S 41° W which means that the angle between the line from the gazebo to the dock and due south is 41°.

Hence the angle between the line from the gazebo to the tree and due south is =(74°-41°) =33°

Similarly, the angle between the line from the dock to the tree and due south is = 28°-x =28°-41°= -13°(As it is to the west of south).

Using the trigonometry law of sines we can write,

d/ sin(41°) = 100/ sin(33°)

d=(100/sin(33°))*sin(41°)

d= 120.45 meters

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For a snowboard cost that was reduced by 40% by the end of the season, the snowboard cost $450 when it was new.

To find the original cost of the snowboard, let the original price of the snowboard be x.

After a 40% reduction in price, the snowboard costs 60% of its original price, therefore the cost remaining percentage of the original prize times the reduction percentage = the price after reduction:

100% - 40% = 60%

60/100 = 0.6

0.6x = 270

Solving for x to get:

x = 270/0.6 = 450

Therefore, the original price of the snowboard was $450.

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To produce an A note on a C string (5 notes higher) that is 70 cm long we should place a fret at a distance of 74.92cm from bridge.

To find where to place the fret, we use the formula:

distance from bridge = (string length) x [tex]2^{(n/12)[/tex]

In this case, the string length is 70 cm and we want to produce an A note on a C string, which is 5 notes higher.         So n = 5.

distance from bridge = [tex]70 * 2^{(5/12)[/tex]

Using a calculator, we get:

distance from bridge ≈ 74.92 cm

Therefore, the answer is d. 74.92 cm, rounded to the nearest hundredth.

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The fee paid by the person for a $23.50 payment with a 2% processing fee is $0.47.

As the meal program accepts online payments by the use of a credit card. for every payment processed and the processing fee for the credit card payment is 2% of the payment amount. To calculate the fee if a person made a payment of $23.50, we can multiply the payment amount by 2% or 0.02.

Fee = 23.50 x 0.02 = $0.47

Therefore, the fee paid by the person for a $23.50 payment is $0.47.

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The 90 % confidence interval is ( 19.92 , 20.18 )

A confidence interval is defined as the range of values that we observe in our sample and for which we expect to find the value that accurately reflects the population.

The relationship between a value and the mean of a set of values is expressed numerically by a Z-score. The Z-score is computed using the standard deviations from the mean. A Z-score of zero indicates that the data point's score and the mean score are identical.

The Z-score is calculated using the formula:

z = (x - μ)/σ

where z: standard score

x: observed value

μ: mean of the sample

σ: standard deviation of the sample

Given data ,

Let the number of samples n = 15

Let the mean of the sample be μ = 20.05

Let the standard deviation σ = 0.3

Now , the z score of 90 % confidence interval is z = 1.645

The 90% confidence interval is calculated by the equation

A = μ ± z ( σ / √n )

Substituting the values in the equation , we get

P = μ + z ( σ / √n )

Q = μ - z ( σ / √n )

Now , the value of P is

P = 20.05 + 1.645 ( 0.3/√15 )

P = 20.05 + ( 0.4935 / 3.873 )

P = 20.05 + 0.12742

P = 20.18

Now , the value of Q is

Q = μ - z ( σ / √n )

Q = 20.05 - 1.645 ( 0.3/√15 )

Q = 20.05 - ( 0.4935 / 3.873 )

Q = 20.05 - 0.12742

Q = 19.92

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Answer:

The range is 10, and the IQR is 13.

Step-by-step explanation:

The range is the difference between the maximum and minimum values in a dataset, and the interquartile range (IQR) is the difference between the third quartile (Q3) and the first quartile (Q1) of the dataset.

Since the range is the difference between the maximum and minimum values in the dataset, the range cannot be 14 and the IQR be 10, since 14 is greater than 10.

Therefore, the correct answer is:

The range is 10, and the IQR is 13.

Three pairs of coordinate points that form a line segment with a slope greater than 2 are: (x₁, y₁) = (0, 0) and (x₂, y₂) = (3, 7), (x₁, y₁) = (1, 3) and (x₂, y₂) = (5, 13), (x₁, y₁) = (-2, 1) and (x₂, y₂) = (2, 9)

To find three pairs of coordinate points that form a line segment with a slope greater than 2, we need to choose pairs of points where the difference in y-coordinates is at least twice the difference in the corresponding x-coordinates.

Here are three pairs of coordinate points that satisfy this condition:

1.  (x₁, y₁) = (0, 0) and (x₂, y₂) = (3, 7)

Using the slope formula, we get:

slope = (y₂ - y₁) / (x₂ - x₁) = (7 - 0) / (3 - 0) = 7/3, which is greater than 2.

2.  (x₁, y₁) = (1, 3) and (x₂, y₂) = (5, 13)

Using the slope formula, we get:

slope = (y₂ - y₁) / (x₂ - x₁) = (13 - 3) / (5 - 1) = 10 / 4 = 5 / 2, which is also greater than 2.

3. (x₁, y₁) = (-2, 1) and (x₂, y₂) = (2, 9)

Using the slope formula, we get:

slope = (y₂ - y₁) / (x₂ - x₁) = (9 - 1) / (2 - (-2)) = 8 / 4 = 2, which is exactly 2, but if we extend the line segment beyond these two points, the slope will become greater than 2.

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The volume of the 4th doll is approximately [tex]130.1 cm^3.[/tex]

The diameter of the smallest doll is 1.9 cm, so its radius is 0.95 cm (half of the diameter).

Similarly, the radius of the second smallest doll is (2.85/2) = 1.425 cm.

Since the scale factor is the same from one doll to the next, the ratio of the radius of the second smallest doll to the radius of the smallest doll is:

1.425 cm / 0.95 cm = 1.5

Similarly, the ratio of the radius of the third smallest doll to the radius of the second smallest doll is also 1.5.

Using this pattern, we can find the radius of the 4th doll as:

Radius of 4th doll = 1.5 × (Radius of 3rd doll) = 1.5 × 2.1375 cm = 3.2063 cm (rounded to 4 decimal places)

The volume of the 4th doll can then be calculated as:

Volume of 4th doll = (4/3) × π ×[tex](Radius of 4th doll)^3[/tex]

                           = (4/3) × π × [tex](3.2063 cm)^3[/tex]

                           ≈ [tex]130.1 cm^3[/tex]

Therefore, the volume of the 4th doll is approximately [tex]130.1 cm^3.[/tex]

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Mrs. Carter used 954 square inches of frosting.

To find the surface area of the rectangular prism cake, we need to find the area of all six sides and then subtract the bottom since frosting was not applied to it.

The area of the top and bottom sides is 24 x 15 = 360 square inches each.

The area of the two side faces is 24 x 3 = 72 square inches each.

The area of the two end faces is 15 x 3 = 45 square inches each.

So, the total surface area of the cake is:

2(360) + 2(72) + 2(45) = 720 + 144 + 90 = 954 square inches.

Since frosting was applied to all sides, including the top, we use this surface area to find the amount of frosting used.

Therefore, Mrs. Carter used 954 square inches of frosting.

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Add the given numbers: -8 + 4 + (-2) = -6. So, the sum of -8, 4, and -2 is -6.

To represent -6 on a number line, we need to find its position relative to zero. Since -6 is negative, it will be located to the left of zero. We count 6 units to the left of zero on the number line to represent -6. Therefore, the number line that shows the sum of -8, 4, and -2 is:

o----+----+----+----+----+----+----+----+----+----o

-15 -10 -5 0 5 10 15 20 25 30

-6

So, the complete answer is:

The sum of -8, 4, and -2 is -6.

To represent -6 on a number line, locate 6 units to the left of zero.

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To help you with the journal entries and preparation of the stockholders' equity section for Sikie Shoe Manufacturing Co, let's start with the journal entries for the given transactions:

On January 15, the authorization date:

Journal entry:

Common Stock (200,000 shares * $2 par value) $400,000

Preferred Stock (100,000 shares * $25 par value) $2,500,000

Authorized Capital Stock $2,900,000

On January 20, 50,000 preferred stock were sold for cash at $70 per share:

Journal entry:

Cash $3,500,000

Preferred Stock (50,000 shares * $25 par value) $1,250,000

Common Stock $1,250,000

Paid-in Capital in Excess of Par - Preferred Stock $2,250,000

On February 1, 70,000 common shares were issued with a market price of $8:

Journal entry:

Cash $560,000

Common Stock (70,000 shares * $2 par value) $140,000

Paid-in Capital in Excess of Par - Common Stock $420,000

On February 15, 4,000 common shares were issued to Delkab Consulting Co. in settlement of professional services provided at a fee of $100,000:

Journal entry:

Common Stock (4,000 shares * $2 par value) $8,000

Paid-in Capital in Excess of Par - Common Stock $92,000

Accounts Payable/Professional Services $100,000

On March 20, Mr. Park exchanged a piece of land with a fair value of $150,000 for 10,000 common shares:

Journal entry:

Land (fair value) $150,000

Common Stock (10,000 shares * $2 par value) $20,000

Paid-in Capital in Excess of Par - Common Stock $130,000

On July 1, 45,000 common shares were issued for cash at a market price of $25:

Journal entry:

Cash $1,125,000

Common Stock (45,000 shares * $2 par value) $90,000

Paid-in Capital in Excess of Par - Common Stock $1,035,000

Now let's move on to the questions regarding common shares issued and outstanding:

As of July 31, the number of common shares issued is:

Calculation: 70,000 (February 1) + 4,000 (February 15) + 10,000 (March 20) + 45,000 (July 1) = 129,000 common shares

As of July 31, the number of common shares outstanding is the same as the number of common shares issued since there are no repurchases or retirements mentioned.

Moving on to the treasury stock transactions:

On August 1, purchased 5,000 shares of its own $2 par value common stock at $20 per share:

Journal entry:

Treasury Stock $100,000

Cash $100,000

On September 1, sold 1,500 shares of treasury stock purchased on August 1 for $30 per share:

Journal entry:

Cash $45,000

Treasury Stock $30,000

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None of the given expressions (A, B, C, D, E) are equal to 45 x 67.

To find which expressions are equal to 45 x 67, we simply need to simplify each of the expressions given.

Therefore, none of the expressions are equal to 45 x 67.

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The values of a, b, and c in the matrix equation are a = 3, b = 1 and c = 8

To determine the values of a, b, and c in the matrix equation:

4 a  +  3  0    = 7  3

3 4      5  b       c   5

By addition operation, we have

a + 0 = 3

3 + 5 = c

4 + b = 5

When the equations evaluated, we have

a = 3

c = 8

b = 1

The above are the values of a b and c

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Complete question

Determine the values of a, b, and c in the following matrix equation.

4 a  +  3  0    = 7  3

3 4      5  b       c   5

AB is dilated by a scale factor of 3 to form A'B'. Point O, which lies on AB, is the center of dilation.

The slope of AB is 3. The slope of A'B' is 3. A'B' passes through point O.

Dilation is a process of transformation used to resize an object.

The items are enlarged or shrunk through dilation. An image that retains the original shape is created by this alteration. The size of the form does differ, though.

By multiplying the x and y coordinates of the original figure by the scale factor, you may locate locations on the dilated image when a dilation in the coordinate plane has the origin as the center of dilation.

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Answer:

x=10 and y=20, 2x=20=y

Step-by-step explanation:

2x=20 | Divide by 2 on both sides

x=10

4y=80 | Divide by 4 on both sides

y=20

Answer: 40

80 ÷ 2 = 20, so x = 40.

To check your answer;

40 x 2 = 80

Answer: x = -3

Step-by-step explanation:

Hope this helps.

Answer:

Not enough info

Step-by-step explanation:

Volume of cone formula is: V = 1/3 π r²h

You did not give the radius so it is not possible to find the solution

If radius is given, isolate h by dividing the V by 1/3 π r²

Then simplify the left side of the equation and that is what h is

We can use the Pythagorean theorem to solve this problem, which states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.

Let x be the length of the slide. Then we have a right triangle with legs of length 5 (the height of the ladder) and x, and hypotenuse of length 12 (the distance from the ladder to the bottom of the slide).

Using the Pythagorean theorem:

12^2 = 5^2 + x^2

144 = 25 + x^2

Subtracting 25 from both sides:

119 = x^2

Taking the square root of both sides:

x ≈ 10.91

Therefore, the slide needs to be about 10.91 feet long.

The correct answer is "No, P(A) ≠ P(A|B)".

If the occurrence of one event has no bearing on the likelihood that the other will also occur, then the two events are independent.

The likelihood that both occurrences A and B will occur is defined mathematically as being equal to the product of the probabilities of A and B (i.e., P) (A and B).

Let event A = heavy traffic and event B = bad weather.

P(A)=  25/30 and P(B)=25/30

Two events are independent if the occurrence of one does not change the probability of the occurrence of the other.

This means P(A) = P(A|B) or P(B) = P(B|A).

For event A (heavy traffic), P(A) = 80/100 = 0.8.

For event B (bad weather), P(A|B) = 25/30 = 0.833.

Since P(A) ≠ P(A|B), events A and B are not independent.

So, the correct answer is "No, P(A) ≠ P(A|B)".

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The solutions for f(x) = g(x) are x = 5 and x = 3.

To solve f(x) = g(x) using substitution method, we need to substitute g(x) in place of x in the equation f(x) = x² - 7x + 13.

So, we have:

f(x) = g(x)
x² - 7x + 13 = x - 2   (Substituting g(x) = x - 2)

Now, we can solve for x by simplifying and solving the resulting quadratic equation:

x² - 8x + 15 = 0

Factoring the quadratic equation, we get:

(x - 5)(x - 3) = 0

So, x = 5 or x = 3.

Therefore, the solutions for f(x) = g(x) are x = 5 and x = 3.

To check, we can substitute each value back into the equations:

f(5) = 5² - 7(5) + 13 = 25 - 35 + 13 = 3
g(5) = 5 - 2 = 3

f(3) = 3² - 7(3) + 13 = 9 - 21 + 13 = 1
g(3) = 3 - 2 = 1

So, both solutions satisfy the original equation f(x) = g(x).

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Answer:

Step-by-step explanation:

There are 8 equally likely sandwich options: rye and ham, rye and turkey, white and ham, white and turkey, rye and ham with cheese, rye and turkey with cheese, white and ham with cheese, white and turkey with cheese.

Since each type of sandwich was made in equal number, there are 4 sandwiches with cheese.

Therefore, the chances that Mary will get a sandwich with cheese is 4/8 or 1/2.

Answer: one half

The equation that represents the statement is

50 = x/3 and x is 150

A word problem in math is a math question written as one sentence or more. This statements are interpreted into mathematical equation or expression.

Word problem are brain teaser that allows people to think properly. The first step is to represent the unknown by a letter.

Representing the number by x

therefore:

The product of 5 and 10 is 5 × 10

5 × 10 = 1/3 × x

50 = x/3

therefore the equation is 50 = x/3 and the value of x is 150.

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The children's library has 75 science books, 125 picture books, and 125 storybooks.

z = 5x/3 (5 storybooks for every 3 science books)

y = x (the same number of picture books as science books)

y + 50 = z (the library added 50 more picture books so now there are the same number of picture books as storybooks)

Now, we can substitute the equations to solve for the number of each type of book:

From equation 2, we know that y = x. So, we can rewrite equation 3 as:

x + 50 = z

Now, we can substitute equation 1 into this equation:

x + 50 = 5x/3

Multiply both sides by 3 to eliminate the fraction:

3(x + 50) = 5x

3x + 150 = 5x

Subtract 3x from both sides:

150 = 2x

Divide both sides by 2:

x = 75

So, there are 75 science books in the library. Now we can find the number of picture books (y) and storybooks (z):

y = x = 75 (75 picture books before adding 50 more)

y = 75 + 50 = 125 (125 picture books after adding 50 more)

z = 5x/3 = (5 * 75) / 3 = 375 / 3 = 125 (125 storybooks)

So, the children's library has 75 science books, 125 picture books, and 125 storybooks.

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The expected cost of Bob's lunch is $9.69, rounded to the nearest cent.

To figure out the probability of Bob and Anna successfully meeting up, we need to use a unitary method. The probability of Bob choosing a specific time is 1/4, and the probability of Anna choosing the same time is also 1/4. Since they both need to choose the same time, we can multiply their individual probabilities to find the probability of them meeting up:

1/4 x 1/4 = 1/16

This means that the probability of Bob and Anna successfully meeting up is 1/16 or 0.0625.

Now we can use this probability to find the expected cost of Bob's lunch. If Bob and Anna meet up, Bob will get a discount on his lunch and pay $5. If they don't meet up, he'll have to pay the full price of $10. So the expected cost of Bob's lunch is:

(Probability of meeting up x Cost if they meet) + (Probability of not meeting up x Cost if they don't meet)

(1/16 x $5) + (15/16 x $10) = $0.3125 + $9.375 = $9.69

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