Plz help me fast urgent thank you :) 20 points

Answer:

ดำหเภสยาแไ_ะทบบใืกไภเืวบวมเพนยชตึภ/ภึรื

Answer:

Step-by-step explanation:

Answer:

x = 0.428571 repeating

Step-by-step explanation:

Answer:

-0.428571 repeating

Step-by-step explanation:

add 4.6 both sides

1.5 = -3.5x

divide -3.5 both sides

-0.428571 repeating

The equation of the parallel line which is passing through the point (–3, –2) will be y = (10/3)x + 8.

Let the equation of the line be y = mx + c. Then the equation of the parallel line that is parallel to the line y = mx + c is given as,

y = mx + d

Line k has an equation of y= (10/3)x+9. Line l includes the point (–3, –2) and is parallel to line k.

y = (10/3)x + d

The equation of the line is passing through (–3, –2). Then the equation of the parallel line is given as,

–2 = (10/3)(–3) + d

–2 = –10 + d

d = 10 – 2

d = 8

The equation of the parallel line which is passing through the point (–3, –2) will be y = (10/3)x + 8.

More about the equation of a parallel line link is given below.

https://brainly.com/question/402319

#SPJ5

Answer:

what the hell

Step-by-step explanation:

Answer:

43-(+13)

43-13

=30

-× + would give you -

+×- would give you -

+×+ would give you -

-×-would give you +.

Step-by-step explanation:

5x-7+3x+27=180

8x+20=180

8x=160

x=20°.

hope this helps you.

Answer:

[tex]5x - 7 + 3x + 27 = 180 \\ 5x + 3x + 27 - 7 = 180 \\ 8x + 20 = 180 \\ 8x = 180 - 20 \\ 8x = 160 \\ d \: b \: s \: by \: 8 \\ 8x \div 8 = 160 \div 8 \\ x = 20[/tex]

Answer:

664.94

Step-by-step explanation:

Give me brainlyest please

Answer:

664.94 is the answer to this question. I hope this helps.

Step-by-step explanation:

[tex] \bf \underline\red{Question}[/tex]

Name the jelly like fluid that the other organelles float around in a cell?

[tex] \bf \underline\red{Answer}[/tex]

Cytoplasm.

Answer:

cytoplasm

step by step explanation

Answer:

(2,8)

Step-by-step explanation:

m (4,2)

(6,-4)

(2,8)

I think it is B

It makes the most sense to me to do that

Answer:

bxjfjxucjkkdndjkjhkjjnn

Answer:

Step-by-step explanation:

Answer :

D

Step By Step Explanation :

Answer:

x-intercept = 3.6

y-intercept = -1.2

Step-by-step explanation:

Step-by-step explanation:

hope this helps you dear sis.....

Answer:

Answer:

6

Step-by-step explanation:

When you need to estimate, if the number is .4 or below, bring it down (1.4 will now be 1.)

This goes for both 1.4

so, 1 + 1.

Next, you have 4.1 (which is also below .5, so .4 or below.)

It is 1 + 1 + 4.

That is 6. Hope this helps a bit ^^ :>

Answer:

(see explanation)

Step-by-step explanation:

Rounding to whole numbers,

1.4 rounds to 1

4.1 rounds to 4.

1+1+4 = 6

However, if you're rounding to the nearest 0.5,

1.4 rounds to 1.5

4.1 rounds to 4.0

1.5 + 1.5 + 4.0 = 7

Answer:

This prism has: 5 Faces. 6 Vertices (corner points) 9 Edges.

Step-by-step explanation:

Answer:

Sean paid 0.25 more cents than Cal.

Step-by-step explanation:

Cal's problem: 2.4 * 2.55 = 6.12

Sean's problem: 2.6 * 2.45 = 6.37

Answer:

I think 0.25

Step-by-step explanation:

Multipled 2.4 and 2.55 then multipled 2.6 and 2.45. I got 6.12 and 6.37 Then subtracted them and got 0.25

Answer:

22.28

Step-by-step explanation:

first add the decimals then the other number.

Answer:

x = 10

Step-by-step explanation:

a² + b² = c²

(5√2)² + (5√2)² = x²

50 + 50 = x²

x² = 100

x= 10

Given :

To find :-

Solution :-

As we know ,

Determine the independent variable and dependent variable in the situation

The independent variable is the "amount of water the plant receives", and the dependent variable is the "height of the plant".

Therefore, the independent variable from the phenomena is "amount of water" and the dependent variable is the "height of the plant".

Read more:

https://brainly.com/question/23700645

Answer:

dy/dx = - (y/x)^4

Step-by-step explanation:

We are given the equation:

[tex] \displaystyle \large{ \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} } = {a}^{3} }[/tex]

Recall important differential formulas such as:

[tex] \displaystyle \large{ \frac{d}{dx} (f(x) + g(x)) = \frac{d}{dx} f(x) + \frac{d}{dx} g(x)} \\ \displaystyle \large{ \frac{d}{dx} k = 0 \: \: \tt(k \: \: is \: \: a \: \: constant.)}[/tex]

Above is a basic property of differential. Looking at the equation above, differentiate both sides with respect to x. (dy/dx)

[tex] \displaystyle \large{ \frac{d}{dx}( \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} } )= \frac{d}{dx} {a}^{3} }[/tex]

Apply the distribution property in.

[tex] \displaystyle \large{ \frac{d}{dx} \frac{1}{ {x}^{3} } + \frac{d}{dx} \frac{1}{ {y}^{3} } = \frac{d}{dx} {a}^{3} }[/tex]

We treat x^3 and y^3 as function to one another, this type of differential will be called implicit once another variable of function is involved f(x,y).

But we treat a^3 as a constant so we just put 0.

[tex] \displaystyle \large{ \frac{d}{dx} \frac{1}{ {x}^{3} } + \frac{d}{dx} \frac{1}{ {y}^{3} } = 0 }[/tex]

Recall the quotient rules for the numerator = 1.

[tex] \displaystyle \large{ \frac{d}{dx} (\frac{1}{f(x)}) = -\frac{ \frac{d}{dx} (f(x))}{ {(f(x))}^{2} } }[/tex]

Thus:

[tex] \displaystyle \large{ - \frac{ \frac{d}{dy} ( {x}^{3} )}{ ({x}^{3})^{2} } + \frac{d}{dx} \frac{1}{ {y}^{3} } = 0 } \\ \displaystyle \large{- \frac{ 3 {x}^{2} }{ {x}^{6} } + \frac{d}{dx} \frac{1}{ {y}^{3} } = 0 }[/tex]

Make sure to recall power rules for differential and exponent laws.

From 3x^2 / x^6.

[tex] \displaystyle \large{ - \frac{ 3 }{ {x}^{4} } + \frac{d}{dx} \frac{1}{ {y}^{3} } = 0 }[/tex]

Now what do we do with 1/y^3? We just differentiate it normally but we multiply with dy/dx once we differentiate the y function.

[tex] \displaystyle \large{- \frac{ 3 }{ {x}^{4} } -\frac{ \frac{d}{dx}( {y}^{3}) }{ ({y}^{3})^{2} } = 0 } \\ \displaystyle \large{ -\frac{ 3 }{ {x}^{4} } - \frac{ 3 {y}^{2} }{ {y}^{6}} = 0 } \\ \displaystyle \large{ - \frac{ 3 }{ {x}^{4} } - \frac{ 3 }{ {y}^{4}} \frac{dy}{dx} = 0 }[/tex]

Solve for dy/dx, add both sides by 3/x^4.

[tex] \displaystyle \large{ - \frac{ 3 }{ {x}^{4} } + \frac{3}{ {x}^{4} } - \frac{ 3 }{ {y}^{4}} \frac{dy}{dx} = 0 + \frac{3}{ {x}^{4} } } \\ \displaystyle \large{ - \frac{ 3 }{ {y}^{4}} \frac{dy}{dx} = \frac{3}{ {x}^{4} } } \\ [/tex]

Divide both sides by - 3/y^4.

[tex] \displaystyle \large{ \frac{- \frac{3}{ {y}^{4} } \frac{dy}{dx} }{ - \frac{3}{ {y}^{4} } } = \frac{ \frac{3}{ {x}^{4} } }{ - \frac{3}{ {y}^{4} } } } \\ \displaystyle \large{ \frac{dy}{dx} = \frac{3}{ {x}^{4} } \times (-\frac{ {y}^{4} }{3} )} \\ \displaystyle \large{ \frac{dy}{dx} = \frac{1}{ {x}^{4} } \times (- \frac{ {y}^{4} }{1}) } \\ \displaystyle \large{ \frac{dy}{dx} = - \frac{ {y}^{4} }{ {x}^{4} } } \\ \displaystyle \large{ \frac{dy}{dx} = - ( { \frac{y}{x} })^{4}}[/tex]

Answer:

D

Step-by-step explanation:

Edmentum:))

Answer:

make a chart and it will be easy for you

Answer:

Grapgical charts and data plots

Step-by-step explanation:

Step-by-step explanation: